Async Await Promise <Pending> - node.js

Question

I know this question been asked for many times but as I'm still very new i dont quite understand the answers on previous places.
const publicIp = require('public-ip');
// getting ip address
async function GetIpAddress() {
var a = await publicIp.v4();
return await a;
// it will return my public ip as string
}
however ,as its non blocking i understand if i do something like this as below
var a = GetIpAddress();
console.log(a);
it will probably go promise pending. so what i did was
async function hi(){
var a = await GetIpAddress();
console.log(a);
}
hi();
But here's my question. How do i return it back to my variables without making another function to cover it up? please see code below
var zmq = require('zmq'),
requester = zmq.socket('req'),
publicIp = require('public-ip');
const PORT = "3222";
var IP = GetIpAddress();
console.log(`${IP}:${PORT}`);
// IP will return promise pending?? how i do fix this without making another
// function?
requester.connect('tcp://127.0.0.1:5433');
requester.on('message', function (msg) {
// arr = str.split(",");
console.log(msg.toString());
});
requester.send(
`${IP}:${PORT}`
);
async function GetIpAddress() {
var a = await publicIp.v4();
return a
}
As the full code above shown.. var IP will definitely be promise pending as it will take time. therefore how do it get the function return value without making another function?
EDIT: please understand the duplication is entirely not what i want.. I understand that my knowlege on callbacks , promises and async await wasnt strong but from a guy who comes from synchronous language such as Python itself . I'm very curious onto how do i take variable out. as what i research and saw are mostly
promises within promises or callbacks within callbacks.
what i want is if i can rereplicate what was shown as per below ( python )
def f(x):
return x+1
var1 = 5
var1 = f(var1)
# var1 is now 6
which is bringing callbacks / promises / async await variable out of its own function rather than
var IP = GetIpAddress().then((IP) => {
requester.connect('tcp://127.0.0.1:5433');
console.log('Worker connected to port 5433');
requester.on('message', function (msg) {
// arr = str.split(",");
console.log(msg.toString());
});
requester.send(
`${IP}:${PORT}`
);
console.log(`${IP}:${PORT}`);
});

Answer 1

Change:
var IP = GetIpAddress();
console.log(`${IP}:${PORT}`);
to:
GetIpAddress().then((IP) => {
console.log(`${IP}:${PORT}`);
}
);
You can read 6 Reasons Why JavaScript’s Async/Await Blows Promises Away (Tutorial)
Update:
Option 1 put everything in the then:
GetIpAddress().then((IP) => {
requester.connect('tcp://127.0.0.1:5433');
console.log('Worker connected to port 5433');
requester.on('message', function (msg) {
// arr = str.split(",");
console.log(msg.toString());
});
requester.send(
`${IP}:${PORT}`
);
console.log(`${IP}:${PORT}`);
});
Option 2 is to wrap everything in an async function:
async function hi(){
var a = await GetIpAddress();
console.log(a);
}
hi();
Option 2 is the one I would opt for as it provides a cleaner way of writing things.

Answer 2

you need to add await before the method call. the main method also need to async.
var IP = await GetIpAddress();
try to use
new promise(function (accept, reject){ // if Ip found
accept("ipaddress") //else reject("error log")
}).then(function(response){ // this is accept , print IPaddress
}).catch(function(err){ // this is reject. } );