COUNTIF returns 0 when expected 1 - excel

=IF(COUNTIF(A28:AJ28,"*"&automation&"*")
, "need", "no need")
i expect this formula to return 'need'
but i get 'no need'.
how should I change it?

Encapsulate the text in double quotes:
=IF(COUNTIF(A28:AJ28,"*" & "automation" & "*"), "need", "no need")

You've made your formula unnecessarily complex.
Because automation is outside the string it's not treated as a literal string, and inside the COUNTIF function you're getting a #NAME! error, which the IF function regards as false.
The following does work:
=IF(COUNTIF(A28:AJ28,"*automation*"), "need", "no need")

Related

Why am I getting a value error in excel while using the ifs function?

=IFS(SEARCH("C*",A9),"Cake",SEARCH("K*",A9),"Cookies",SEARCH("B*",A9),"Bread & Bun",SEARCH("Y*",A9),"Pastry")
It works for the first criteria and returns "cake" but won't work for the others. I keep getting a #VALUE error.
Can help please??
SEARCH isn't a Boolean-valued function. It doesn't return FALSE if the string isn't found -- it returns a #VALUE! error which isn't coerced to FALSE.
What you could do is wrap everything like SEARCH("C*",A9) with ISNUMBER(): ISNUMBER(SEARCH("C*",A9)) since Excel can tell that #VALUE! isn't a number.

Pass function argument as formula

Here is a code of my VBA script:
Function custom_if_formula(condition)
MsgBox(condition)
End Function
I am pasting the formula to any cell:
=custom_if_formula(B1="something")
The result in MsgBox is: TRUE or FALSE. Is it possible get in MsgBox as a result B1="something" as instead?
A pseudo-code of what I would like to achieve:
Function custom_if_formula(condition)
condition = condition.formula 'any method which take a literal string
MsgBox(condition)
End Function
P.S. My goal is to implement my own IFS function who behave identically like in Excel 2016. I am just curious if its possible. Tha'ts why I don't want to pass a string as an argument.
I think you're looking for:
Function custom_if_formula(condition)
If condition.Value = "something" Then MsgBox "something"
End Function
Where B1 is taken as the argument: =custom_if_formula(B1). Putting this in any cell (when B1 contains the string "something") will return:
You should really clarify what your intent is here, though. A UDF should return a value to its cell. Right now, it will just say 0 in the UDF's cell. Additionally, looking for "something" could be interpreted as looking for anything, and using this kind of verbiage leads to the "Who's on first, what's on second" ordeal...
Ok, I found a way how to do it:
Function custom_if_formula(condition)
cell_formula = Range(Application.Caller.Address).Formula 'I get an adress of a cell which call an UDF, and then take all string it contains
arg = Mid(cell_formula, 12, 100)
MsgBox(arg)
End Function

WorksheetFunction.value() missing in Excel

In a spreadsheet formula, =VALUE("$100") will evaluate to the numeric value of 100. I then tried to access this function in VBA via WorksheetFunction object, however it is missing.
In VBA I tried the conversion function Val("$100"), however that returns 0. So how can I accomplish this via VBA?
Val() only really works if the string is all numbers I'm afraid - currency signs cause it a problem.
If you're always going to have the same currency sign in the string, it might be worth using something like
StringName = replace(StringName, "$", "")
to take out the $ by replacing it with "" - otherwise if your strings aren't always going to be this predictable the below question might help:
How to find numbers from a string?
see https://learn.microsoft.com/en-us/office/vba/api/excel.worksheetfunction.numbervalue
example of using above, which will return a value of -1234.56:
MsgBox WorksheetFunction.NumberValue("-$1,234.56", ".", ",")
Note that if the result is non-numeric, it throws an error. For example (swapping the comma grouping and decimal character params which is invalid in this case):
MsgBox WorksheetFunction.NumberValue("-$1,234.56", ".", ",")
I don't understand why the above link doesn't have any version info. It is currently dated 2019‎-‎05‎-‎23 - no idea if that's because it is new or if it was recently updated.

How do I sum results of two if statements in the same cell?

I'm looking to have the results of two If statements calculated and added in the same cell. I'm getting #VALUE! error.
=IF(ISERROR(GETPIVOTDATA("Sum of CHARGES",'Ship City'!$A$3,"ship_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29)),"",GETPIVOTDATA("Sum of CHARGES",'Ship City'!$A$3,"ship_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29))+IF(ISERROR(GETPIVOTDATA("Sum of CHARGES",'Recipient City'!$A$4,"recipient_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29)),"",GETPIVOTDATA("Sum of CHARGES",'Recipient City'!$A$4,"recipient_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29))
=IF(ISERROR(GETPIVOTDATA("Sum of CHARGES",'Ship City'!$A$3,"ship_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29)),"",GETPIVOTDATA("Sum of CHARGES",'Ship City'!$A$3,"ship_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29))
+
IF(ISERROR(GETPIVOTDATA("Sum of CHARGES",'Recipient City'!$A$4,"recipient_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29)),"",GETPIVOTDATA("Sum of CHARGES",'Recipient City'!$A$4,"recipient_city",$B$7,"carrier_type",$A$27,"INV_month_id",D$6,"INV_year_id",$D$5,"Company Name",$B29))
Your both IF functions return an empty string "". Using + operator with strings returns #VALUE!. There are different methods to fix it:
use 0 instead of ""
use SUM instead of + (it ignores strings).
And as #John Bustos mentioned in his comment, you can simplify your formula with
IFERROR(value,value_if_error)
IFERROR description

select case with variable boolean operator

This is my first question on the forum, but reading previous questions has been enormously helpful in the project I'm working on, so already my thanks. I couldn't find an answer to this, but apologies if I overlooked something.
I am writing an excel macro in vba, and am trying to create a select case... statement in which the expression has a variable boolean and numeric component. For example, the macro can pull "> 3" or "< 3" from another worksheet.
My hope had been that I could assign to a string all of these parameters, i.e.:
test1 = "is " & BoolOperator1 & " " & NumericValue1
and then
Select case ValuetoCompare
Case test1
'Do something
Case test2
'...
Is there a way to do this? I suppose the alternative would be to nest the case with the numeric variable inside a select function that determines the operator, but I thought this would be more elegant.
Thanks in advance for your guidance--
Josh
Assuming that you'll get a string BoolOperator1 that is a valid operator, e.g. >=, =, and a numeric value NumericValue1, the easiest way to execute this comparison on another numeric value ValueToCompare is to use the Evaluate function. This will execute a string as VBA and return it's result.
In your case, you could simply use:
If Evaluate(ValueToCompare&BoolOperator1&NumericValue1) Then ...
If you want to use this in a Select Case statement, you'd either need to use a simple If ... ElseIf ... statement - or use this trick:
Select Case True
Case Evaluate(ValueToCompare&BoolOperator1&NumericValue1): ...
Case Evaluate(ValueToCompare&BoolOperator2&NumericValue2): ...
Case Else ...
End Select

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