VBA - Copy Range if cell not empty - excel

Question

I currently have this code:
Sub createSheets(range_Copy As Range, range_Paste As Range)
'Copy the data
range_Copy.Copy
'Paste the data into the new worksheet
With range_Paste
.PasteSpecial xlPasteValues
.PasteSpecial xlPasteFormats
End With
End Sub
...and this...
Call createSheets(Sheets("Export from QB - Annual Sales").Range("E:T"), Sheets("Sales - " & Sales_Date_Annual).Range("A1"))
It works great but what I actually want to do is... when copying the range E:T, I only want to copy the rows that do not have a blank value in column E... regardless if there is anything in the other columns.

Answer 1

I think below code will help you. Useful information here is, that you can reference a cell in a range using relative reference, i.e. Range("D4:E6").Cells(1, 1) is reference to cell D4. This way you can easily loop through given range.
Sub LoppthroughRange()
Dim i As Long, j As Long, rng As Range
Set rng = Range("E:T")
For i = 1 To rng.Rows.Count
If Not IsEmpty(rng.Cells(i, 1)) Then
For j = 1 To rng.Columns.Count
'copy all cells in a row
Next
End If
Next
End Sub
Putting it all together, you should use:
Sub createSheets(range_Copy As Range, range_Paste As Range)
Dim i As Long, j As Long, k As Long
k = 1
For i = 1 To range_Copy.Rows.Count
If Not IsEmpty(range_Copy.Cells(i, 1)) Then
With range_Copy
.Range(Cells(i, 1), Cells(i, .Columns.Count)).Copy
End With
With range_Paste
.Range(Cells(k, 1), Cells(k, .Columns.Count)).PasteSpecial xlValues
.Range(Cells(k, 1), Cells(k, .Columns.Count)).PasteSpecial xlFormats
End With
k = k + 1
End If
Next
End Sub