I have this Nodejs lambda function where some files are in a subfolder, like this:
- index.js
- connectors/
- affil.js
I have a Cannot find module error when trying to require the affil.js file. Trying to read it with fs.readFile returns an access denied error.
When I move the file to the root folder, it is accessible. Is there a requirement that Lambda functions files must all be at the root directory? How can I fix that?
Mostly it is because of the way zipping the files making the problem. Instead of zipping the root folder you have to select all files and zip it like below,
Please upload all files and subfolders like below. Please include node_modules folder as well in the zip.
As pointed by #Vijayanath Viswanathan, the issue is with how the zip file is created rather than Lambda.
I used to feed gulp-zip with this:
var src = gulp.src('src/**/*')
The correct way is to prevent folders from being included:
var src = gulp.src('src/**/*.js')
or (if you need to include file with other file extensions)
var src = gulp.src('src/**/*', {nodir: true})
Related
My folder structure is:
\gitclone\SConstruct
\gitclone\level1\level2\SConscript.3dn
Now in SConscript.3dn I am creating empty folder: e.Execute(Mkdir('#/testDir'))
How to define the file path to create the folder in \gitclone\ (where root SConstruct file is)? I was reading manual, but somehow I can not manage it.
I have found solution here, so my code is:
e['SCONS_ROOT'] = Dir('#')
e.Execute(Mkdir('${SCONS_ROOT.abspath}/win_b64/code/bin/testDir'))
I'm using node.js and want to send file to the frontend. So I specified the direct path to my file like:
path = "c:/app/A"
and when I run res.sendFile(path, fileName);
I'm getting the Error: ENOENT: no such file or directory, stat '/home/projects/c:/app/A'
How I can disable this auto path adding "/home/projects" part?
I want to download file that is not in my project folder with my code. File is in my computer in different folder.
Try to use \\ as path delimiter for Windows (c:\\app\\A) and read about Node.js module "path".
so I need use just new URL(file:${"c:/app/A"});
so it will be like that:
let filename = "someName.com"
let absPath = "c:/app/someName.com";
fs.writeFileSync(`${filename}`, fs.readFileSync(new URL(`file:${absPath}`)));
res.download(`${filename}`, `${filename}`)
I'm trying to create a folder within the temp folder that doesn't have a random name.
Here is how I was trying to create the folder within the temp folder.
if not DirExists(ExpandConstant('{%tmp}\Utilities\SDK')) then
CreateDir(ExpandConstant('{%tmp}\Utilities\SDK'));
Log('Temp\Utilities\SDK Folder Has Been Created.');
I had a look at this thread, but even with the %, unfortunately, it still doesn't create the folder.The script compiles and runs as expected, however the folder doesn't create even though it says it has in the log file, I understand that the log file will say that because its told too, however, if the folder was unable to be created, wouldnt it crash? or return a false if an if statement was present?
With CreateDir() You must create dirs one after the other and not a dir structure at once.
if not DirExists(ExpandConstant('{tmp}\Utilities')) then
CreateDir(ExpandConstant('{tmp}\Utilities'));
if not DirExists(ExpandConstant('{tmp}\Utilities\SDK')) then
CreateDir(ExpandConstant('{tmp}\Utilities\SDK'));
if DirExists(ExpandConstant('{tmp}\Utilities\SDK')) then
Log('Temp\Utilities\SDK Folder Has Been Created.') else
Log('Temp\Utilities\SDK Folder ERROR : NOT Created.');
Inno Setup has a function to create a dir structure at once
function ForceDirectories(Dir: string): Boolean;
Example:
if not DirExists(ExpandConstant('{tmp}\Utilities\SDK')) then
ForceDirectories(ExpandConstant('{tmp}\Utilities\SDK'));
Also keep in mind :
{tmp} all is related to the Inno Setup Temp folder is-XXXXX.tmp
C:\Users\...\AppData\Local\Temp\is-XXXXX.tmp
{%temp} is the users Temp folder
C:\Users\...\AppData\Local\Temp
I think you want the Windows Temp and not the tmp from InnoSetup
{tmp}:
Temporary directory used by Setup or Uninstall. This is not the value of the user's TEMP environment variable. It is a subdirectory of the user's temporary directory which is created by Setup or Uninstall at startup (with a name like "C:\WINDOWS\TEMP\IS-xxxxx.tmp"). All files and subdirectories in this directory are deleted when Setup or Uninstall exits. During Setup, this is primarily useful for extracting files that are to be executed in the [Run] section but aren't needed after the installation.
So I think you want to do somethink like this:
if not DirExists(ExpandConstant('{%temp}\Utilities\SDK')) then
CreateDir(ExpandConstant('{%temp}\Utilities\SDK'));
Log('Temp\Utilities\SDK Folder Has Been Created.');
Using path.resolve we can resolve paths using Node.js.
I want to have a directory containing files and other directories and so on. From the client I receive a path as string and I have to resolve it in this directory.
Because of security, I have to prevent the result path to be outside of the directory:
// This comes from the client
let filePath = "/../../../some-sensitive-data-from/disk";
/* Here I have to check if the path is inside of the directory */
path.resolve(ABSOLUTE_PATH_TO_MY_DIR + filePath);
How to prevent the access to parent directories of ABSOLUTE_PATH_TO_MY_DIR?
Obviously a solution would be to check if the final path is still inside of the ABSOLUTE_PATH_TO_MY_DIR path. But maybe there are other better solutions.
I have a file that is required in many other files, that are on different folders, inside the main directory.
Is there a way to just require the filename without having to write the relative path, or the absolute path? Like require('the_file'). And without having to go to npm and install it?
Create a folder inside your main directory , put the_file.js inside and set the NODE_PATH variable to this folder.
Example :
Let's say you create a ./libs folder within your main directory, you can just use :
export NODE_PATH = /.../main/lib
after that, you can require any module inside this directory using just :
var thefile = require('the_file')
To not have to do that every time, you'd have to add the variable to your .bashrc (assuming you're running a Unix system).
Or you can set a global variable inside your app.js file and store the path of your 'the_file' in it like so :
global.rootPath = __dirname;
Then you can require from any of your files using :
var thefile = require(rootPath+'/the_file')
These are the most convenient methods for me, short of creating a private npm, but there are a few other alternatives that I discovered when looking up an answer to your question, have a look here : https://gist.github.com/branneman/8048520