I am trying to do a simple add a day to my substring text that i've parsed into a date but it is not displaying correctly.
Below is the code:
def dateTimeDate = Date.parse("yyyy-mm-dd", textfromjson.substring(0,10)).format("yyyy-mm-dd")
def futureDateTimeDate = dateTimeDate + 1
When I do two logs for both defs, the original date and the future date which I want to be next day, I receive this output:
logs:
log.warn dateTimeDate
log.error futureDateTimeDate
output:
2018-02-23
2018-02-231
How can I get this to work so that it outputs: 2018-02-24 and not 2018-02-231
The answers posted already correctly point out that the date value needs to be incremented before it's formatted back into a String.
To this, I would like to add that if you're on Java 8 you can use its new Date/Time API as an alternative to java.util.Date, which can be problematic (even apart from mixing up 'm' and 'M' in format strings).
import java.time.*
def future = LocalDate.parse(textfromjson.substring(0,10)) + Period.ofDays(1)
You're parsing a String into a Date and then formatting it back into a String. Add to the Date object, not the String object.
def dateTimeDate = Date.parse("yyyy-mm-dd", textfromjson.substring(0,10))
def futureDateTimeDate = dateTimeDate + 1
log.warn dateTimeDate.format("yyyy-MM-dd")
log.error futureDateTimeDate.format("yyyy-MM-dd")
Also note that you probably want to be using MM (month in year) not mm (minute in hour).
Related
So far I have used the following code to get the date of yesterday:
def today = new Date()
def yesterday = today - 1
yesterday.format( '"yyyy-MM-dd 23:59:59"' )
Result today: "2021-02-25 23:59:59"
Now I want to get the exact same result but instead of " I only want to have a single quotation mark looking like this:
'2021-02-25 23:59:59'
Therefore, I tried mutliple ways to modify the code above for example:
def today = new Date()
def yesterday = today - 1
yesterday.format( '''yyyy-MM-dd 23:59:59''' )
However, so far all my trials lead to this result: 2021-02-25 23:59:59
As you can see in this result there is no quotation mark at all.
What do I need to change to the result including the single quotation mark?
This will give you the output you want:
yesterday.format( "''yyyy-MM-dd 23:59:59''" )
I am trying to figure out how to pass a date inputted at a prompt by the user to pandas to search by date. I have both the search and the input prompt working separately but not together. I will show you what I mean. And maybe someone can tell me how to properly pass the date to pandas for the search.
This is how I successfully use pandas to extract rows in an excel sheet if any cell in column emr_first_access_date is greater than or equal to '2019-09-08'
I do this successfully with the following code:
import pandas as pd
HISorigFile = "C:\\folder\\inputfile1.xlsx"
#opens excel worksheet
df = pd.read_excel(HISorigFile, sheet_name='Non Live', skiprows=8)
#locates the columns I want to write to file including date column emr_first_access_date if greater than or equal to '2019-09-08'
data = df.loc[df['emr_first_access_date'] >= '2019-09-08', ['site_name','subs_num','emr_id', 'emr_first_access_date']]
#sorts the data
datasort = data.sort_values("emr_first_access_date",ascending=False)
#this creates the file (data already sorted) in panda with date and time.
datasort.to_excel(r'C:\\folder\sitesTestedInLastWeek.xlsx', index=False, header=True)
However, the date above is hardcoded of course. So, I need the user running this script to input the date. I created a very basic working input prompt with the following:
import datetime
#prompts for input date
TestedDateBegin = input('Enter beginning date to search for sites tested in YYYY-MM-DD format')
year, month, day = map(int, TestedDateBegin.split('-'))
date1 = datetime.date(year, month, day)
Obviously I want to pass TestedDateBegin to pandas, changing the pertinent code line:
data = df.loc[df['emr_first_access_date'] >= '2019-09-08', ['site_name','subs_num','emr_id', 'emr_first_access_date']]
to something like:
data = df.loc[df[b]['emr_first_access_date'] >= 'TestedDateBegin', ['site_name','subs_num','emr_id', 'emr_first_access_date']]
Obviously this doesn't work. But how do I proceed? I am very new to programming so I not always clear how to proceed. Does the date inputted in TestedDateBegin need to be added to a return? Or should it be put in a single item list? What is the right approach? Thx!
This is resolved.
I had to remove the single quotes around TestedDateBegin as python, of course, interpreted that as a string and not a variable. Living and learning. :-)
data = df.loc[df[b]['emr_first_access_date'] >= TestedDateBegin,['site_name','subs_num','emr_id', 'emr_first_access_date']]
Hi I have a date format that i am getting from my Jira Sprint Environment 2019-03-29T06:56:00.000-04:00
I am using groovy Script.
I have tried to use multiple format to make similar format like the above .
But Unable to do it.
Here are the below solution i have tried.
1 --
`def sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss'Z'")
sdf.setTimeZone(TimeZone.getTimeZone("GMT"))
log.debug("Printing Current time stamp date : "+sdf)
solution 1 is printing text only.
2 --
def now = new Date()
println now.format("yyyy-MM-dd'T'HH:mm:ss'Z'",TimeZone.getTimeZone('UTC'))
this one is printing
Printing Current time stamp date : Thu Sep 26 08:00:35 EDT 2019"
Can anyone help me on this?
So, the goal is to have date in format
2019-03-29T06:56:00.000-04:00
the following code does the formatting with timezone GMT-4
def now=new Date().format("yyyy-MM-dd'T'HH:mm:ss.SSSXXX",TimeZone.getTimeZone('GMT-4'))
println now
prints
2019-09-26T16:33:18.462-04:00
note that the variable now will contain String with formatted date
Check for all available date & time patterns:
https://docs.oracle.com/javase/8/docs/api/java/text/SimpleDateFormat.html
Given that you’ve got a Java 8 or newer underneath, all you need is
OffsetDateTime.now(ZoneId.systemDefault()).toString()
In my time zone (Europe/Copenhagen) I just got
2019-09-27T21:46:53.336204+02:00
If your default time zone is America/Montreal or America/New_York, you will get the time at offset -04:00 as long as summer time (Daylight Saving Time) is in effect, then -05:00.
And you can easily parse.
OffsetDateTime.parse( "2019-09-27T21:46:53.336204+02:00" )
See this code running at IdeOne.com.
def currentDate = new Date()
def date = currentDate.format('yyyy-MM-dd')
def time = currentDate.format('HH:mm:ss.SSS')
def dateTime = date.toString() + 'T' + time.toString() + 'Z'
Using a Tkinter input box, I ask a user for a date in the format YYYYMMDD.
I would like to check if the date has been entered in the correct format , otherwise raise an error box. The following function checks for an integer but just need some help on the next step i.e the date format.
def retrieve_inputBoxes():
startdate = self.e1.get() # gets the startdate value from input box
enddate = self.e2.get() # gets the enddate value from input box
if startdate.isdigit() and enddate.isdigit():
pass
else:
tkinter.messagebox.showerror('Error Message', 'Integer Please!')
return
The easiest way would probably be to employ regex. However, YYYYMMDD is apparently an uncommon format and the regex I found was complicated. Here's an example of a regex for matching the format YYYY-MM-DD:
import re
text = input('Input a date (YYYY-MM-DD): ')
pattern = r'(19|20)\d\d[- /.](0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])'
match = re.search(pattern, text)
if match:
print(match.group())
else:
print('Wrong format')
This regex will work for the twentieth and twentyfirst centuries and will not care how many days are in each month, just that the maximum is 31.
Probably you've already solved this, but if anyone is facing the same issue you can also convert the data retrieved from the entry widgets to datetime format using the strptime method, and using a try statement to catch exceptions, like:
from datetime import *
def retrieve_inputBoxes():
try:
startdate = datetime.strptime(self.e1.get(), '%Y-%m-%d')
enddate = datetime.strptime(self.e2.get(), '%Y-%m-%d')
except:
print('Wrong datetime format, must be YYYY-MM-DD')
else:
print('startdate: {}, enddate: {}').format(startdate, enddate)
Note that the output string that will result will be something like YYYY-MM-DD HH:MM:SS.ssssss which you can truncate as follows the get only the date:
startdate = str(startdate)[0:10] #This truncates the string to the first 10 digits
enddate = str(enddate)[0:10]
In my opinion, this method is better than the Regex method since this method also detects if the user tries to input an invalid value like 2019-04-31, or situations in which leap years are involved (i.e. 2019-02-29 = Invalid, 2020-02-29 = Valid).
I have a date string as follows:
201805041235040000000
Which I would like to convert to timestamp with zone in Groovy.
Tried this:
def timestamp = Date.parse("yyyyMMddHHmmss", timstamp).format("yyyy-MM-dd'T'HH:mm:ssZ");
But failed, got error:
No signature of method: static java.util.Date.parse() is applicable for argument types.
Let me know where am I going wrong.
Try this:
String t2,st = "16/08/2007 09:04:34"
SimpleDateFormat sdf = new SimpleDateFormat("dd/mm/yyyy hh:mm:ss")
Date date = sdf.parse(st)
Timestamp timestamp = new Timestamp(date.getTime())
t2 = timestamp.toString()
Hope it helps....
This works...
String input = '201805041235040000000'
String timestamp = Date.parse('yyyyMMddHHmmss', input).format("yyyy-MM-dd'T'HH:mm:ssZ")
It is a bit unclear what you are looking for. If you just need a time stamp from parsing your date string, you can use the groovy extension Date.toTimestamp():
def ts = Date.parse("yyyyMMddHHmmssSSS", "201805041235040000000".take(17)).toTimestamp()
where the take(17) is there to discard any trailing zeros not included in the date pattern yyyyMMddHHmmssSSS. I made the assumption that three of the tailing zeros were milliseconds. If that's not the case:
def ts = Date.parse("yyyyMMddHHmmss", "201805041235040000000".take(14)).toTimestamp()
what is unclear is what you mean when you say "with zone". So assuming you just want to include the current time zone information and generate a String, I don't see a reason why you should convert from date to timestamp in the first place (Timestamp after all is a Date as it inherits from Date). If you just need the timezone spelled out you can do:
def withZone = Date.parse("yyyyMMddHHmmss", "201805041235040000000".take(14)).format("yyyy-MM-dd'T'HH:mm:ssZ")
println withZone
which on my machine where I'm sitting in Sweden prints out:
~> groovy withTimeZone.groovy
2018-05-04T12:35:04+0200
timestamp must be string. Try this:
Date.parse("yyyyMMddHHmmss", timstamp?.toString()[0..13])
.format("yyyy-MM-dd'T'HH:mm:ssZ")