Crontab for every odd Saturday - linux

How do I set the crontab for every odd saturday (or other weekday) ?
Few crontabs I have tried:
0 22 */7 * 6
0 22 * * 6 (This is every saturday)

Related

Crontab expression for a 8 and a half hour range

Crontab to run a job every minute from 11pm to 7:30am
I have this so far which is every minute from 11pm to 7:00am
the problem is the half hour.
* 23,0-7 * * *
You can play around with it here crontab_guru
Any ideas?
#Dunski : I have checked in many ways this *,0-30 23,0-7 * * * expression could stop at 07:59 min only but not yet 07:30 am.
As #jordanm suggested we have only a way to run two jobs from :
11 pm to 7 am expression * 23,0-7 * * * (“At every minute past hour 23 and every hour from 0 through 7.”) and then
7 am to 7:30 am 0-30 7 * * * (“At every minute from 0 through 30 past hour 7.”).

To run in a time window until midnight

I have an AirFlow scheduler that I want to run at 13 until midnight from Monday to Saturday. I wrote an expression like this:
0 13-0 * * 1-6
While trying to validate this in crontab.guru for example I get an error since 0 is smaller than 13:
https://crontab.guru/
Does anyone know how can I write a valid cron-expression for this type of schedule?
If you would like to run your command at minute 00 from 13:00 onwards till midnight (inclusive) on all days except Sundays, then you have to play a trick. It is not possible to define the hour 24 in a crontab. You can define the hour 00, but a crontab of the form
0 0,13-23 * * 1-6
will run on Monday 00:00 and not on Sunday 00:00 which is what the OP really wants.
Here are two methods you can use:
Run two crontabs:
0 13-23 * * 1-6
0 0 * * 2-7
Run a single crontab a minute earlier:
59 12-23 * * 1-6
How about: 0 13-23 * * 1-6
“At minute 0 past every hour from 13 through 23 on every day-of-week from Monday through Saturday.”
Source: https://crontab.guru/#0_13-23___1-6

Run first and last 3 days of the every month

How to run a job on the first and last 3 days of the month. What's the cron (linux) syntax to make this happen?
Thanks!
There is no way to indicate the last days, rather than checking which ones.
These are the days to check:
29, 30, 31 - months with 31 days --> 1,3,5,7,8,10,12
28, 29, 30 - months with 30 days --> 4,6,9,11
26, 27, 28 - February --> 2
First 3 days of the month:
0 0 1,2,3 * 0
Last 3 days of month:
* * 26,27,28 2 * # February
* * 28,29,30 4,6,9,11 * # 30 days months
* * 29,30,31 1,3,5,7,8,10,12 * # 31 days months
First 3 days of month
Cron expression :- 0 0 0 1-3 * ?
Description :- At 00:00:00am, every day between 1st and 3rd, every month
Last 3 days of month
Cron expression :- 0 0 0 L-3 * ?
Description :- At 00:00:00am, 3 days before the end of the month, every month
This cron config worked well for me, thanks to Crontab Guru's easy to understand interface. https://crontab.guru/#0_8_1-6,28-31__
0 8 1-3,28-31 * *
Run every day at 8am from 1st to the 3rd and 28th to 31st. '-' represents range.

Quartz Cron expression :Run every 15 days ie twice in a month

I want to set the scheduler with a quartz cron expression which will trigger every 15 days ,for example 1st and 15th of every month.The 0 15 10 15 * ? is triggering only on 15th of every
month.
I have tested this and the following expression works fine
"0 0 0 1,15 * ?"
the 1,15 statement fires triggers on 1st and 15th of every month at 00:00 hours.
You can change the first three zeroes to fire them at a particular time you want.
the 1st zero -> seconds
the 2nd zero -> minutes
the 3rd zero -> hours
0 0 1,15 * *
“At 00:00 on day-of-month 1 and 15.”
0 0 1,15 1 *
“At 00:00 on day-of-month 1 and 15 in January.”
0 0 1,15 1 6
“At 00:00 on day-of-month 1 and 15 and on Saturday in January.”
The following also works fine, it executes your command on the 15th and the 30th at 02:00 AM of every month:
0 2 */15 * * <yourCommand>
You just need to append 1 with a comma to your expression at 'Day of Month' block.
Rest is fine !
0 15 10 1,15 * ?
This will schedule to run every 1st and 15th day of the month and 10:15 am.

Cron Expression to execute cron triggers for 12 hours of a day?

I need a cron-expression (0 0/60 * * * ?) to fire application every 12 hours (twice a day).
Use e.g. 0 0 3,15 * * ? That'll run a job at 3am and 3pm. That's twice a day, with 12 hours between.
You could use 0 0 0/12 * * ? which means every 12 hours. Here's some examples.
Some examples that fit your criteria:
30 */12 * * *
runs at 00:30:00 and 12:30:00 each day
0 3-15/12 * * *
runs at 03:00:00 and 15:00:00 each day
23 4,16 * * *
runs at 04:23:00 and 16:23:00 each day

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