How to do a PyGame countdown without overlaps? [duplicate] - python-3.x

Question

I started using pygame and I want to do simple game. One of the elements which I need is countdown timer.
How can I do the countdown time (eg 10 seconds) in PyGame?

Answer 1

Another easy way is to simply use pygame's event system.
Here's a simple example:
import pygame
pygame.init()
screen = pygame.display.set_mode((128, 128))
clock = pygame.time.Clock()
counter, text = 10, '10'.rjust(3)
pygame.time.set_timer(pygame.USEREVENT, 1000)
font = pygame.font.SysFont('Consolas', 30)
run = True
while run:
for e in pygame.event.get():
if e.type == pygame.USEREVENT:
counter -= 1
text = str(counter).rjust(3) if counter > 0 else 'boom!'
if e.type == pygame.QUIT:
run = False
screen.fill((255, 255, 255))
screen.blit(font.render(text, True, (0, 0, 0)), (32, 48))
pygame.display.flip()
clock.tick(60)

Answer 2

On this page you will find what you are looking for http://www.pygame.org/docs/ref/time.html#pygame.time.get_ticks
You download ticks once before beginning the countdown (which can be a trigger in the game - the key event, whatever).
For example:
start_ticks=pygame.time.get_ticks() #starter tick
while mainloop: # mainloop
seconds=(pygame.time.get_ticks()-start_ticks)/1000 #calculate how many seconds
if seconds>10: # if more than 10 seconds close the game
break
print (seconds) #print how many seconds

Answer 3

In pygame exists a timer event. Use pygame.time.set_timer() to repeatedly create an USEREVENT. e.g.:
timer_interval = 500 # 0.5 seconds
timer_event = pygame.USEREVENT + 1
pygame.time.set_timer(timer_event , timer_interval)
Note, in pygame customer events can be defined. Each event needs a unique id. The ids for the user events have to be between pygame.USEREVENT (24) and pygame.NUMEVENTS (32). In this case pygame.USEREVENT+1 is the event id for the timer event.
To disable the timer for an event, set the milliseconds argument to 0.
Receive the event in the event loop:
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
elif event.type == timer_event:
# [...]
The timer event can be stopped by passing 0 to the time parameter.
See the example:
import pygame
pygame.init()
window = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
counter = 10
text = font.render(str(counter), True, (0, 128, 0))
timer_event = pygame.USEREVENT+1
pygame.time.set_timer(timer_event, 1000)
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
elif event.type == timer_event:
counter -= 1
text = font.render(str(counter), True, (0, 128, 0))
if counter == 0:
pygame.time.set_timer(timer_event, 0)
window.fill((255, 255, 255))
text_rect = text.get_rect(center = window.get_rect().center)
window.blit(text, text_rect)
pygame.display.flip()

Answer 4

pygame.time.Clock.tick returns the time in milliseconds since the last clock.tick call (delta time, dt), so you can use it to increase or decrease a timer variable.
import pygame as pg
def main():
pg.init()
screen = pg.display.set_mode((640, 480))
font = pg.font.Font(None, 40)
gray = pg.Color('gray19')
blue = pg.Color('dodgerblue')
# The clock is used to limit the frame rate
# and returns the time since last tick.
clock = pg.time.Clock()
timer = 10 # Decrease this to count down.
dt = 0 # Delta time (time since last tick).
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
timer -= dt
if timer <= 0:
timer = 10 # Reset it to 10 or do something else.
screen.fill(gray)
txt = font.render(str(round(timer, 2)), True, blue)
screen.blit(txt, (70, 70))
pg.display.flip()
dt = clock.tick(30) / 1000 # / 1000 to convert to seconds.
if __name__ == '__main__':
main()
pg.quit()

Answer 5

There are several ways you can do this- here's one. Python doesn't have a mechanism for interrupts as far as I know.
import time, datetime
timer_stop = datetime.datetime.utcnow() +datetime.timedelta(seconds=10)
while True:
if datetime.datetime.utcnow() > timer_stop:
print "timer complete"
break

Answer 6

There are many ways to do this and it is one of them
import pygame,time, sys
from pygame.locals import*
pygame.init()
screen_size = (400,400)
screen = pygame.display.set_mode(screen_size)
pygame.display.set_caption("timer")
time_left = 90 #duration of the timer in seconds
crashed = False
font = pygame.font.SysFont("Somic Sans MS", 30)
color = (255, 255, 255)
while not crashed:
for event in pygame.event.get():
if event.type == QUIT:
crashed = True
total_mins = time_left//60 # minutes left
total_sec = time_left-(60*(total_mins)) #seconds left
time_left -= 1
if time_left > -1:
text = font.render(("Time left: "+str(total_mins)+":"+str(total_sec)), True, color)
screen.blit(text, (200, 200))
pygame.display.flip()
screen.fill((20,20,20))
time.sleep(1)#making the time interval of the loop 1sec
else:
text = font.render("Time Over!!", True, color)
screen.blit(text, (200, 200))
pygame.display.flip()
screen.fill((20,20,20))
pygame.quit()
sys.exit()

Answer 7

This is actually quite simple. Thank Pygame for creating a simple library!
import pygame
x=0
while x < 10:
x+=1
pygame.time.delay(1000)
That's all there is to it! Have fun with pygame!

Answer 8

Another way to do it is to set up a new USEREVENT for a tick, set the time interval for it, then put the event into your game loop
'''
import pygame
from pygame.locals import *
import sys
pygame.init()
#just making a window to be easy to kill the program here
display = pygame.display.set_mode((300, 300))
pygame.display.set_caption("tick tock")
#set tick timer
tick = pygame.USEREVENT
pygame.time.set_timer(tick,1000)
while 1:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.USEREVENT:
if event.type == tick:
## do whatever you want when the tick happens
print('My tick happened')