import sys
import string
import time
password = "1234"
guess = " "
count = 0
def bank():
print("TKS Bank")
print("Enter your pin below to access your TKS Bank account")
print()
def password():
global password
global guess
global count
while count != 3 and guess != password:
guess = input("Please enter your 4 digit pin: ")
count += 1
if guess == password:
menu()
elif count == 3:
print("Number of tries maxed.")
countdown()
count = 0
else:
print("Your pin is denied, Try again")
def menu():
print("Your pin has been approved")
print("_" * 80)
print("Welcome to the TKS Bank")
print("_" * 80)
print("1. Type 1 to check your account balance")
print("2. Type 2 to to deposit a chosen amount")
print("3. Type 3 to withdraw a chosen amount")
print("4. Type 4 to check your simple interest")
print("5. Type 5 to exit the menu")
print("_" * 80)
def balance():
balance = (random.randint(1,1000))
print("$", balance)
#'sys' imports the system library from the python library
def quit():
os.exit(0)
def countdown():
print("You have been locked out for 3 minutes. Please come back later
and try again")
time.sleep(3)
bank()
password()
When I have the countdown function the password does not work and just continually loops. Does anyone have a fix?
To expand with the countdown function when I input the correct password it says that it is incorrect and goes to the countdown after three tries. I really don't know what the solution is so anyone help would be appreciated.
Inside your def password(): function, there's an ambiguous name usage between password the variable and password the function.
Related
I am working on a very simple 'game' where the player gets 5 guesses to guess a random number.
It's not done yet but I have run into a couple of problems.
This is the code that generates a random number and allows the player to guess
Relevant code:
def GuessLoopFunc(guess):
import random
import sys
import time
sum_guesses = 0
rand_num = random.randrange(1, 21)
print(rand_num)
#This is just for test purposes to know the correct number and see what happens when I guess the correct number
while True:
if guess == rand_num:
print("You got it right!")
else:
sum_guesses += 1
if sum_guesses == 4:
guess = input("That's incorrect...final guess: ")
continue
elif sum_guesses == 5:
print("Oh no! You lost!")
while True:
replay = input("Do you want to play again: ")
if replay == "yes" or replay == "Yes":
pass #Temporary while I figure out how to loop back to very start (new random number)
elif replay == "no" or replay == "No":
print("Goodbye")
break
else:
print("I do not understand what you mean...")
continue
else:
guess = input("You got it wrong, guess again: ")
continue
As you can see by the comments I made, I want the game the return to the very start of the program if the player indicates they want to play again (so they get a new random number.
Also, for some reason, the game doesn't register when the correct answer was given and keeps on telling the player that his answer was incorrect...this is the code of the game where the above module is called:
import sys
import random
import time
from GuessLoop import GuessLoopFunc
print("Hello! Welcome to the guess the number game!")
name_player = input("Please enter your name: ")
print("Hello " + str(name_player) + "!")
play = input("Are you ready to play? ")
if play == "Yes" or play == "yes":
print("Great! Let's get started...")
elif play == "No" or play == "no":
print("Too bad...")
sys.exit()
else:
print("I do not understand your response...")
quit1 = input("Do you want to quit? ")
if quit1 == "yes" or quit1 == "Yes":
sys.exit()
elif quit1 == "no" or quit1 == "No":
print("Great! Let's get started!")
else:
print("I do not understand your response...quitting.")
sys.exit()
print("I am going to think of think of a number between 1 and 20...")
print("You will get 5 guesses to guess the number...")
time.sleep(1)
print("Okay, I have a number in mind")
guess = input("What is your guess? ")
GuessLoopFunc(guess)
time.sleep(1)
sys.exit()
Finally, when I try to run the program in Sublime Text it doesn't run further than the "Please enter your name: " part. If I fill in my name and press enter, nothing happens...but no error message displays either. So I have resorted to testing the program in the Python IDLE every time, but it's a bit tedious...anyone know what's up.
Your main problem is that you compare your userinput (a string) with a random number (integer) - they will never be the same as string != int.
Solution:
You need to convert the user input to a number via the int(text) function.
def getInt(text):
while True:
try:
n = input(text)
return int(n)
except ValueError: # if the input is not a number try again
print(f"{n} is not a number! Input a number")
....
guess = getInt("What is your guess?") # now that is an int
....
You have lots of duplicate "yes/no" codeparts that you can streamline:
def YesNo(text):
'''Ask 'test', returns True if 'yes' was answerd else False'''
while True:
answer = input(text).strip().lower()
if answer not in {"yes","no"}:
print("Please answer 'yes' or 'no'")
continue # loop until yes or no was answered
return answer == "yes"
This reduces
quit1 = input("Do you want to quit? ")
if quit1 == "yes" or quit1 == "Yes":
sys.exit()
elif quit1 == "no" or quit1 == "No":
print("Great! Let's get started!")
to
if YesNo("Do you want to quit? "):
sys.exit()
else:
pass # do somthing
and use that in all yes/no questions.
To play again I would move the "Do you want to play again" question out of the game loop:
# do your name questioning and greeting here
# and then enter an endless loop that you break from if not playing again
while True:
GuessLoopFunc() # move the guess input inside the GuessLoopFunk as it has
# to be done 5 times anyhow. If you spend 5 guesses or
# guessed correctly, print some message and return to here
if YesNo("Play again? "):
continue
else:
break # or sys.exit()
To fix the sublime problem: Issue with Sublime Text 3's build system - can't get input from running program
I'm new to Python and need a little help. I came across this code on here which I kind of understand and want to expand on it... but I don't know how to get out of the loop!
When you run the code and enter the specified username and password, it runs the defined function logged()... but then loops back to asking for the username again because it run the main() function again!... how can I get past this. When the correct username & password is entered, I would like to be at a point where I can add new code! Does this make sense?
import os
import time
#Must Access this to continue.
def main():
while True:
UserName = input ("Enter Username: ")
PassWord = input ("Enter Password: ")
if UserName == 'Bob' and PassWord == 'rainbow123':
time.sleep(1)
print ("Login successful!")
logged()
else:
print ("Password did not match!")
def logged():
time.sleep(1)
print ("Welcome to ----")
main()
When all matches, break out of loop and call logged outside the loop. Or else once the logged is over, you return back to the infinite loop again.
def main():
while True:
UserName = input ("Enter Username: ")
PassWord = input ("Enter Password: ")
if UserName == 'Bob' and PassWord == 'rainbow123':
time.sleep(1)
print ("Login successful!")
break
else:
print ("Password did not match!")
logged()
After I finish my hangman game, when I clear the console, it clears everything. However, I want it to not clear the menu. How do I fix this?
Here is my code:
import random, os
import time
print("^^^^^^^^^^THIS IS HANGMAN^^^^^^^^^^")
print("1. Play Game ")
print("2. Quit Game ")
choice = input("Please enter option 1 or 2")
if choice == "1":
words = ["handkerchief", "accommodate", "indict", "impetuous"]
word = random.choice(words)
guess = ['_'] * len(word)
guesses = 7
while '_' in guess and guesses > 0:
print(' '.join(guess))
character = input('Enter character: ')
if len(character) > 1:
print('Only enter one character.')
continue
if character not in word:
guesses -= 1
for i, c in enumerate(word):
if c == character:
guess[i] = character
if guesses == 0:
print('You LOST!')
break
else:
print('You have only', guesses, 'chances left to win.')
else:
print(''.join(guess))
print('You WON, well done')
time.sleep(2)
import os
os.system('clear')
I don't know how to make the code so that it only clears down to the menu
simply wrap your menu in a function
def menu():
print("^^^^^^^^^^THIS IS HANGMAN^^^^^^^^^^")
print("1. Play Game ")
print("2. Quit Game ")
and reprint it after you clear the console
import os
os.system('clear')
menu()
if you want your menu to still work after the clear, just include all the code you use to make your menu work into the menu() function. Good luck on your project
Hello am very new to python and ive atempted my first code like this but something seems to be wrong and one of the steps keeps looping. I am very confused on what to do so could someone please help me out.
Thank you!
import os
import time
def main():
while True:
print("Welcome To Amazon")
search = input("Search.... ")
if 'search == registration':
reg()
if 'search == login':
login()
#Must Register to continue
def reg():
while True:
print("Display Name")
reg_user = input()
print("Password")
reg_pass = input()
def registered():
time.sleep(1)
print("Registration Successful!")
main()
#Must Login to continue
def login():
while True:
print("Enter Username: ")
username = input()
print("Enter Password: ")
password = input()
if 'username == reg_user' and 'password == reg_pass':
time.sleep(1)
print("Login Successful!")
logged()
else:
print("Try Again!")
def logged():
time.sleep(1)
print("Welcome To CityRP Gaming")
main()
The while loop loops for as long as the condition is true. You used While True, and True will always be True. This means the loop will continue forever. To break out of a loop you can use 'break'.
Can anyone see why I get "UnBoundLocal Error" for my score varible?
import random
Score=0
def Main_Menu(Score):
print("=============================")
print("WELCOME TO MY QUIZ")
print("=============================")
while True:
Username=input("What is your name?")
if Username.isalpha():
if len(Username)>11:
print("You are only a maximum of 11 characters")
else:
Username=Username.title()
break
else:
print("Letters only")
while True:
while True:
Option=input("What do you want to do?\n1 For Quiz\n2 To Quit.")
if Option.isdigit():
Option=int(Option)
break
else:
print("Numbers Only.")
if Option==1:
for x in range(10):
Quiz(Username)
print("You have scored",Score,"point out of 10!!\n")
elif Option==2:
input("Press Enter to quit the program")
break
else:
print("You only have 2 options")
Quiz(Username)
def Quiz(Username):
Tries=3
Number_One=random.randint (0,10)
Number_Two=random.randint (0,10)
Arithmetic_Operator=random.choice(["+","-","*",])
if Arithmetic_Operator=="+":
print(Username,"\nWhat is",Number_Two,"+",Number_One,"?")
Answer=Number_Two+Number_One
elif Arithmetic_Operator=="-":
print(Username,"\nWhat is",Number_Two,"-",Number_One,"?")
Answer=Number_Two-Number_One
elif Arithmetic_Operator=="*":
print(Username,"\nWhat is",Number_Two,"*",Number_One,"?")
Answer=Number_Two*Number_One
while Tries!=0:
while True:
Guess=input("Answer: ")
if Guess.isdigit():
Guess=int(Guess)
break
else:
print("Numbers Only.")
if Guess==Answer:
print("Well Done.You got it right.\nYou have a point")
Score=Score+1
break
elif Guess!=Answer:
Tries=Tries-1
print("You have",Tries,"tries left")
if Tries==0:
print("The answer is",Answer)
Main_Menu(Score)
You are getting the UnboundLocalError: local variable 'Score' referenced before assignment error because the Quiz method doesn't have a local variable Score but is trying to read from it. You probably meant to use the the global variable Score, but it's not available in the method scope without using the global statement. You can fix this by adding global Score in the beginning of the Quiz method.
However, using globals in python code is another discussion, I would strongly recommend avoiding them, unless there's really a proper reason to use them. Please see this SO for more details and discussion.