I need your help with this problem I'm facing using Excel. Basically I need to populate a table, or better, a given group of cells (dimensions 3x3), and my starting point is:
row numb. column name. value
2 A 10
3 C 4
4 B 20
so I would need to obtain a group of cell like this:
1 A B C
2 10 0 0
3 0 0 4
4 0 20 0
where the cells that have no value can be 0 or whatever. In other words, I have the coordinates where I need to insert the value, and I need to be insert the value corresponding to the coordinates in the right cell.
I already tried many times using functions like MATCH, VLOOKUP and INDEX (also ROW and COLUMN) but without success, because it inserts the correct values but also other combinations of coordinates that I don't want.
My idea was to start from cell A2 and, with the formula, check if there's a match with the coordinates of row and column in the data, and finally print the value.
PS: I would prefer to avoid VBA.
Try this array formula: (Of course, change your cell ranges as necessary)
= IFERROR(INDEX($G$2:$G$4,MATCH(TRUE,ADDRESS(ROW(),COLUMN(),4)=($F$2:$F$4&$E$2:$E$4),0)),0)
Note this is an array formula, so you must press Ctrl+Shift+Enter rather than just Enter after typing the formula.
See working example below.
Related
I have 7 columns to choose from and I need to pick 4 of those columns and generate a total for each row. I also need every combination of 4, which means I'll have 35 new columns with the totals for each of those combinations showing in each row. I need the code for this and if it can be done only using Excel. Here is an image of the columns and the grayed ones are the 7 columns I'm talking about. My knowledge of Excel is very limited. There are over 1,500 rows if that matters.
multi step approach that is going to use some helper rows. there may be a more elegant formula that will do this, and much slicker options in VBA, but this is a formula only approach.
Step 1 - Generate List of Column Combination
To generate the list 4 helper rows will need to be insert at the top of your data. either above or below you header row. These 4 rows will represent the column number you are going to pick. To keep the math simpler for me I just assumed the 1 for the first column and 7 for the last column. those numbers will get converted to later to account for column in between in your spreadsheet. For the sake of this example The first combination sum will occur in column AO and the first helper row will be row 1. The first combination will be hard coded and it will seed the pattern for the remainder of column combinations. Enter the following values in the corresponding cells:
AO1 = 1
AO2 = 2
AO3 = 3
AO4 = 4
In the adjacent column a formula will be placed and copied to the right. It will automatically augment the bottom value by 1 until it hits its maximum value at which point the value in the row above will increase by 1 and the the value of the current will be 1 more than the cell above. This will produce a pattern that covers all 35 combinations by the time column BW is reached. Place the formulas below in the appropriate cell and copy to the right:
AP1
=IF(AO2=5,AO1+1,AO1)
AP2
=IF(AO2=5,AP1+1,IF(AO3=6,AO2+1,AO2))
AP3
=IF(AO3=6,AP2+1,IF(AO4=7,AO3+1,AO3))
AP4
=IF(AO4=7,AP3+1,AO4+1)
Step2 - Sum The Appropriate Columns
I was hoping to use a some sort of array type operation to read through the column reference numbers above, but I could not get my head around it. Since it was just 4 entries to worry about I simply added each reference manually in a SUM function. Now the important thing to note is that we will be using the INDEX function over the 13 columns that cover the range of your columns so to convert the index number we figured out above, to something that will work to grab every second row, the number that was calculated will be multiplied by 2 and then 1 will be subtracted. That means 1,2,3,4 for the first column combination becomes 1,3,5,7. You can see this in the following formula. Place the following formula in the appropriate cell and copy down and to the right as needed.
AO5
=INDEX($AB5:$AN5,AO$1*2-1)+INDEX($AB5:$AN5,AO$2*2-1)+INDEX($AB5:$AN5,AO$3*2-1)+INDEX($AB5:$AN5,AO$4*2-1)
pay careful attention to the $ which will lock row or column reference and prevent them from changing as the formula is copied.
Now you may need to adjust the cell references to match your sheet.
I want to write numbers in excel starting from 000001 till 999999
I have done like this =TEXT(A2,"000001") but i am not been able to generate series even though not able to separate this in different attributes
Further I want to distribute each number in each different cell for example like this
A B C D E F G
000001 0 0 0 0 0 1
000002 0 0 0 0 0 2
till
999999 9 9 9 9 9 9
Use following formuls to B1 cell and drag then right and down as needed.
=MID($A1,COLUMNS($A$1:A$1),1)
See the screenshot.
Here is a better way:
In cell A1, type 1.
Select A1 and from Home tab, choose Fill > Series (top-right).
Choose Columns; Linear; set Step Value to 1 and Stop Value to 999999 or whatever you want. Click OK.
Use AutoFill feature to fill up to the number you want.
Right-click column A header and choose Format Cells.
Choose Custom formatting and type 000000 in the custom format type textbox.
Click OK. Your cells will now show 000001, 000002, ... and so on.
In cell B1, type the following formula:
=INT(MOD($A1/(POWER(10, 7- COLUMN())), 10))
Copy B1 to columns C1 through G1.
Copy range B1:G1 to all subsequent rows B2:G999999 or whatever.
Notes
One advantage of this approach is that column A is numeric, not text, so you can enter any 6-digit (or less) integer in it directly from keyboard and the cells will update themselves correctly.
Column A will adjust number of leading zeros automatically for 6-digits or smaller numbers.
The formula simply divides the number in column A by 10, 100, 1000 and so on and then takes remainder by 10, to get the corresponding digit at that decimal place.
You can easily modify this formula to work with larger or smaller numbers. You simply need to replace 7 by (maximum number of digits in your number + 1).
Might be a bit easier with a VBA macro. Right-click the sheet tab, select View Code, paste the below code, and Run (F5)
Sub fill()
[a1:a999999] = "=text(row(), ""000000"")"
[b1:g999999] = "=mid($a1, column()-1, 1)"
End Sub
(Write this formula in Column A and extend it down to row 999999)
generating the series:
=RIGHT(10^6, 6-LEN(ROW(A1)))&ROW(A1)
Write this formula in Column B and extend it to Column G, then
extend the range of B1:G1 to B999999:G999999
Distributing digits
=MID($A1,COLUMN(A1),1)
I need to automatically obtain a sorted column of values from another given column values, like in the sample:
I have I need A unchanged, and also B obtained from A
A A B
-----------------
1 1 0
0 0 0
3 3 1
8 8 3
0 0 8
I mean if the values from A changes, the B should change accordignly...
Is that possible in MS Excel?
Here a sandbox and sample:
http://1drv.ms/1SkqMhS
If you put The formula =SMALL(A:A,ROW()) in B1 and copy down then the cells in B will be linked to the cells in A in such a way that the numbers in B will be the numbers in A in sorted order. This won't be efficient for larger ranges but will work fine for small to medium size ranges.
If you want the numbers to start in a lower row, say B2 because you have a header in B1, adjust ROW() to something like ROW()-1.
A word of warning: Use of ROW() can make a spreadsheet somewhat fragile in that formulas that involve it can change their meaning if rows are inserted or deleted or the block containing the formula is moved to somewhere else. Rather than using ROW(), there is something to be said for adding a helper column which numbers the data in A (which would then be in e.g. B) and referring to these numbers rather than small. For example, in:
If I put the formula
=SMALL($B$2:$B$5,A2)
In C1 and copy down, it works as intended. In response to a question you raised in the comments, I added still another column which gives an index where the corresponding value occurs. To do this I wrote in D2 (then copied) the formula
=MATCH(C2,$B$2:$B$5,0)
Of course. Highlight your range and in the Data tab, click "Sort", then you can choose how you want to sort your data:
If column B has information that is to be used with Column A (like next to A1 is "Car"), and you want to sort the whole table, based on Column A, then just select Columns A and B, then sort by column A.
Found the answer, thanks to John Coleman !
Just some minor details like cell value fixing (with $, like A$2)and the -1+ROW adjustment for the 1 header row!
In Excel, I am trying to make a cell based of the values contained in two other cells.
I need Cells X and Y to have data based on Cells L and #, like so....
X Y L 1 2 3 4 5 6
A 6 1 1 6;1 6;1 7;1 7;2 7;2 8;1
B 7 2 4 6;1 6;1 7;1 7;2 7;2 8;1
So row A, has columns X and Y filled based of the values in the number columns. The specific number needed is what is filled in in column L.
I am not sure the best way to phrase this question. If my example doesn't make sense, I can try to clarify or provide more examples.
I have no idea if this can be done with fancy formulas or with a VBA macro or two. I am an excel noob.
If I've understood your question correctly you can do this with a combination of Left/Right, Index and search.
In my example images, the user inputs their value in column D, and then columns B and C use the formulea
=LEFT(INDEX($F2:$K2,1,$D2),(SEARCH(";",INDEX($F2:$K2,1,$D2))-1))
=RIGHT(INDEX($F2:$K2,1,$D2),(SEARCH(";",INDEX($F2:$K2,1,$D2))-1))
respectively
Here, the Index function returns the correct column to look at (i.e. the value chosen by the user, the Search function finds the position of the semi-colon, and the left/right functions return the values either side of the semi-colon.
Working a step higher then COUNTIFS, I appose a challenge to write a formula without VBA code. The basic data is combined from 1000s of rows with:
Column A: rows with values from 1 to 3
Column B: rows with values from 1 to 250.
For this purpose lets say, we are looking at all cells of value "1" in column A, that suit value "5" in column B. To find all matches, we'd use COUNTIFS command.
1 1
2 5
1 5
1 7
1 10
3 45
2 12
1 2
2 1
=COUNTIFS(A1:A9;1;B1:B9;5)
The answer here is 1.
Next thing, the "5" in column B belongs to a group, e.g. group from 1 to 9. What would the best way be, to count all the matches in this example, so that for all "1"'s in column A, we'd have to find all matches with values from 1 to 9 in column B?! In the upper example that would result in "4". The obvious solution is with a series of IF commands, but that's unefficient and it easy to make a mistake, that get's easily overseen.
=COUNTIFS(A1:A9;1;B1:B9;"<="&9)
Works only as the upper limit. If I give the third criteria range and condition as ">="&1 it does not work - returns 0.
Gasper
Where the data is in A1:B9, using a lookup table in D1:E10 with letters A-J in column D and numbers 0 to 9 in column E and the following formula in B11 referencing letters entered in A11 and A12:
=COUNTIFS(A1:A9,1,B1:B9,">="&VLOOKUP(A11,$D$1:$E$10,2,FALSE),B1:B9,"<="&VLOOKUP(A12,$D$1:$E$10,2,FALSE))
works, changing the letters in A11 and A12 gives the correct count according to what they correspond to in the looku in D1:E10.
When you say give third criteria range do you mean:
=COUNTIFS(A1:A9;1;B1:B9;"<="&9,B1:B9;">=1")
If so then try:
=COUNTIFS(A1:A9;1;B1:B9;AND("<="&9,;">=1"))
ie have two conditional ranges with the second range having both conditions combined with AND()
Maybe what you want(ed) is:
=COUNTIFS(A:A;1;B:B;">=1";B:B;"<=9")
Almost there. I noticed that three criteria ranges and conditions work only if I use "=" sign in a condition. As soon as I use
=COUNTIFS(A1:A9;1;B1:B9;"<="&9,B1:B9;">=1")
it returns 0. My goal is to eventualy replace the number in a condition with a VLOOKUP command, so the final equation should be smth like
=COUNTIFS(A1:A9;1;B1:B9;"<="&VLOOKUP(...),B1:B9;">=VLOOKUP(...)")
But the "<" and ">" signs mess with this. Still looking for a solution.
This is my entire line, if it offers any further indication. The AND() commands is at the end - and it still results in 0
=COUNTIFS(INDIRECT(CONCATENATE("baza!$";SUBSTITUTE(ADDRESS(1;MATCH("card_type_id";baza!$A$1:$AAA$1;0);4);"1";"");"$2:$";SUBSTITUTE(ADDRESS(1;MATCH("card_type_id";baza!$A$1:$AAA$1;0);4);"1";"");"$15000"));IF(C6="računska";1;0);INDIRECT(CONCATENATE("baza!$";SUBSTITUTE(ADDRESS(1;MATCH(IF($C$4="CC_SI_klasifikacija";"building_classification_id";0);baza!$A$1:$AAA$1;0);4);"1";"");"$2:$";SUBSTITUTE(ADDRESS(1;MATCH(IF($C$4="CC_SI_klasifikacija";"building_classification_id";0);baza!$A$1:$AAA$1;0);4);"1";"");"$15000"));AND("<="&VLOOKUP($C$5;$K$203:$N$223;4;FALSE);">="&VLOOKUP($C$5;$K$203:$N$223;3;FALSE)))