How to show full tilemap using phaser? - sprite

I have created tilemap using Tiled software of pixel size 1200x1000. While rendering it using phaser I have set width equal to 500 and height equal to 400.After this only map of 500x400 area is loading and remaining part is missing. How can I show the full map in 500x400 area on my webpage?

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Setting the size of a SVG file (via Batik)

If I render to a bitmap then the bitmap has a specific number of pixels and a DPI. That combination makes it easy to draw a square that is 1" x 1" - I render lines for each side that are DPI pixels long.
When I create a SVG, I think it should still be able to be set this way. Where I set the units per inch and also the size in those units of the object as a whole. Yes you can zoom on a SVG file as it's all vectors, but it should still have a 100% zoom size to render to.
In my case I am using EMUs for my units. So 914400 units/inch. So question #1 is, how do I set the scaling using Batik. For a bitmap it's:
AffineTransform scaleToEmus = AffineTransform.getScaleInstance(dpi / (float) DrawingSurface.EPI, dpi / (float) DrawingSurface.EPI);
graphics.transform(scaleToEmus);
But there is no dpi equivalent for SVG.
And then for a given width & height that is in EMUs, do I set the size (or maximum extent) of the image using:
svgGraphics.setSVGCanvasSize(new Dimension(width, height));
I think I'm not fully understanding SVG, or at least Batik as I don't see how to set the units to render at for a 100% zoom.

AndroidPlot - Position TextLabelWidget not consistently on different devices

I have a chart show info of apps, but when run it on devices android. The position of text on chart not consistently.
These images illustrate the problem: https://drive.google.com/folderview?id=0B7-CxJHQ5ZnjYjVlTlFQdElWRGM&usp=sharing
I use TextLabelWidget in AndroidPlot. How to keep position of TextLabelWidget on chart with the same image1 in link above on devices?
The problem appears to be that your plot area is set to fill the width of the screen and since the bars are evenly distributed in that space, their x positions are essentially fractions of the screen width.
At the same time you have labels that appear to be positioned using absolute positioning. As an example, this code will position 4 labels at 0%, 25%, 50% and 75% screen width, 80 pixels down from the top of the screen:
txtWidget1.position(0, XLayoutStyle.RELATIVE_TO_LEFT, PixelUtils.dpToPix(80), YLayoutStyle.ABSOLUTE_FROM_TOP, AnchorPosition.LEFT_TOP);
txtWidget2.position(0.25f, XLayoutStyle.RELATIVE_TO_LEFT, PixelUtils.dpToPix(80), YLayoutStyle.ABSOLUTE_FROM_TOP, AnchorPosition.LEFT_TOP);
txtWidget3.position(0.50f, XLayoutStyle.RELATIVE_TO_LEFT, PixelUtils.dpToPix(80), YLayoutStyle.ABSOLUTE_FROM_TOP, AnchorPosition.LEFT_TOP);
txtWidget4.position(0.75f, XLayoutStyle.RELATIVE_TO_LEFT, PixelUtils.dpToPix(80), YLayoutStyle.ABSOLUTE_FROM_TOP, AnchorPosition.LEFT_TOP);
There are some other factors that you are also probably going to need to deal with such as bar width but this should get you closer. You may find this doc useful as far as a guide for the different positioning methods.
Another tool to consider using if you aren't using it already is the Configurator. This will let you set your positions etc. inside xml and override values based on screen size, orientation, etc.

How can i force the imagemagick module of nodejs to output one single image only?

I am using the imagemagick module with Nodejs
im = require('imagemagick');
The imagemagick module uses the imagemagick command line tools.
I use the convert method to crop an image
im.convert([image_path, '-crop', '200x150', '-gravity', 'center', target_path],
function(err, stdout){}
);
This results in two images. The one with the cropped image area - the second with the image garbage i tried to get rid of.
How can i force imagemagick to output one image file only?
Per the imagemagick documentation for cropping, which is admittedly a little obtuse (emphasis added):
The width and height of the geometry argument give the size of the image that remains after cropping, and x and y in the offset (if present) gives the location of the top left corner of the cropped image with respect to the original image.
...
If the x and y offsets are present, a single image is generated, consisting of the pixels from the cropping region.
...
If the x and y offsets are omitted, a set of tiles of the specified geometry, covering the entire input image, is generated.
... so, you just need to specify your x and y offsets as part of your geometry argument, like so: 200x150-100-75
Notice that I've specified -100 and -75 for the upper left corner of your crop region, this is because you set your gravity to center, but it appears that imagemagick tries to intelligently determine the appropriate distance target based on your gravity, and I don't see exactly how it behaves when you choose center. So you may have to play around with this one a bit, or you could omit the gravity and use the actual offset from the top left corner of your original image.
I had to use the +delete parameter to remove the last image from the image sequence.
im.convert([image_file.path, '-crop', geometry, '+delete', thumb_path], ...

Ignoring touches on transparent areas cocos2dx

I have an image of size 480x800 pixels and there is a icon on one corner which I need to place. What I want is that to ignore all touches on the transparent areas and detect only the area where the icon is.
I found a solution in SO to this problem but it just tells the code to be used. I need to know exactly where to put that code since I am a beginner and don't know much about cocos2d so I expect a step by step solution.
Cocos2d 2.0 - Ignoring touches to transparent areas of layers/sprites
Do not use glReadPixels because it affected by bugs in android drivers. You can translate CCTouch to CCPoint in image coordinates using convertTouchToNodeSpace, and read image pixel at given point.
Create CCImage from file that contains semi-transparent picture, and read one pixel at tap point; it should be {0,0,0,0} for transparent area.
Don't forget to check that tap is not outside picture, and create pixel index in CCImage::getData() array with formulae unsigned index = x * imageWidth + y.

Incorrect coordinates retrieved from image using ABBYY OCR SDK

I'm trying to process an image using ABBYY OCR SDK using the sample code placed in this question but I'm not able get the co-ordinates right for a specific word say "OCR" on the screenshot below.
I want to draw an overlay (yellow rectangle over the word "OCR") and sometimes the rectangle is placed very far away from the actual word.
The XML you get is synthesised according to this schema.
For each recognized character it will contain an instance of charParams element as shown in the answer you linked to. The element will contain the coordinates in page pixels - the same XML also contains a page element:
<page width="..." height="..." resolution="..." originalCoords="...">
where the image width and height are stored. So l and r for each charParams element is in range 0..width-1 of the corresponding page and t and b for each charParams element is in range 0..height-1 of the corresponding page.
Also it's worth mentioning explicitly that all coordinates are in pixels - they are completely resolution-agnostic. This is why whenever you try to highlight anything on an image you have to take zoom into account - the image will likely not be always displayed as is by your device software, but will be downscaled and so you have to map page coordinates onto your zoomed-out image coordinates and highlight appropriately.
Have you checked the DPI of the original image and also check the documentation to make sure the OCR engine is using the same DPI and not returning the image in points or some other measurement system.
It could be that rectangle you are drawing in iOS is not based on pixels but on some other measurement system also.
You just need to work through the process, testing as you go, and work out where the problem is coming from. It is most likely a uniform scaling and the distance from the actual word is proportional to the distance of the word from the top left of the page.

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