This question already has answers here:
Iterate over a list of files with spaces
(12 answers)
How to iterate over arguments in a Bash script
(9 answers)
Closed 5 years ago.
I just started learning Bash Script.
My script is accepting 1 to n number of arguments. Each argument is pass to a function rename.
My problem is that the argument I pass does not accept space.
script.sh
#!/bin/bash
for FILE in $#
do
echo "$FILE"
rename $FILE
done
For Ex:
./script.sh /Users/xyz/Section 5/abc/ /Users/xyz/pqr/ /Users/z/abc
The above argument "/Users/xyz/Section 5/abc/" should be one even if it contains space.
But the code in script.sh will break it into two argument.
So the output is:
/Users/xyz/Section
5/abc/
/Users/xyz/pqr/
/Users/z/abc
But My Expected Output should be:
/Users/xyz/Section 5/abc/
/Users/xyz/pqr/
/Users/z/abc
Note: Different solution I tried till now:
1) "/Users/xyz/Section 5/abc/" --> Same output ie 2 different argument
2) '/Users/xyz/Section 5/abc/' --> Same output ie 2 different argument
3) /Users/xyz/Section\ 5/abc/ --> Same output ie 2 different argument
Related
This question already has answers here:
Why does shell ignore quoting characters in arguments passed to it through variables? [duplicate]
(3 answers)
How can I store a command in a variable in a shell script?
(12 answers)
Closed 2 years ago.
I have an external executable that I need to pass arguments to. With a bash script, I have code that determines these arguments. Some arguments may have escaped spaces.
I need to then execute that string, without expanding each of the arguments.
# ... some code that determines argument string
# the following is an example of the string
ARGSTR='./executable test\ file.txt arg2=true'
exec ${ARGSTR}
I must have the $ARGSTR be expanded so that I can pass arguments to ./executable, but each of the arguments should not be expanded. I have tried quoting "test file.txt", but this still does not pass it as one argument to ./executable.
Is there a way to do something like this?
Us an array instead of a string:
#!/usr/bin/env bash
ARGSTR=('./executable' 'test file.txt' 'arg2=true')
exec "${ARGSTR[#]}"
See:
BashFAQ-50 - I'm trying to put a command in a variable, but the complex cases always fail.
https://stackoverflow.com/a/44055875/7939871
This may achieve what you wanted :
ARGSTR='./executable test\ file.txt arg2=true'
exec bash -c "exec ${ARGSTR}"
This question already has answers here:
Replace a string in shell script using a variable
(12 answers)
sed substitution with Bash variables
(6 answers)
Closed 4 years ago.
I need to replace current value in configuration file with new value which is assigned to variable ,
like
file_name=abc.txt
needs to be replaced like
file_name=xyz.txt
where $file=xyz.txt
I tried
sed -i 's/file_name=.*/file_name=$file/g' conf_file.conf
however the variable is not getting expanded,
it comes like file_name=$file.
any pointers?
This should work,assuming that variable file has value:xyz.txt assigned to it:
sed "s/file_name=.*/file_name=${file}/g" file_name
Output:
file_name=xyz.txt
This question already has answers here:
Lookup shell variables by name, indirectly [duplicate]
(5 answers)
How to get a variable value if variable name is stored as string?
(10 answers)
Bash - variable variables [duplicate]
(4 answers)
Closed 4 years ago.
I have a set of directories listed inside a text file as
DIR_A= (name of directory 1)
DIR_B= (name of directory 2)
....
I have a second script to which I would like to pass an argument like sh Scriptname varname where varname could be A, B, ...
Scriptname sources the initial text file and I would like this script to accept the passed varname (using $1) to echo DIR_varname.
Any ideas? TIA
This question already has an answer here:
Execute an shell program with node.js and pass node variable to the shell command [closed]
(1 answer)
Closed 4 years ago.
I have the following code:
exec('sh cert-check-script-delete.sh', req.body.deletedCert);
console.log(req.body.deletedCert);
The console log correctly shows the req.body.deletedCert is non-empty.
And in cert-check-script-delete.sh I have:
#!/bin/sh
certs.json="./" # Name of JSON file and directory location
echo -e $1 >> certs.json
But it's just writing an empty line to certs.json
I've also tried:
exec('sh cert-check-script-delete.sh' + req.body.deletedCert)
But neither formats work
Use execFile(), and pass your arguments out-of-band:
child_process.execFile('./cert-check-script-delete.sh', [req.body.deletedCert])
That way your string (from req.body.deletedCert) is passed as a literal argument, not parsed as code. Note that this requires that your script be successfully marked executable (chmod +x check-cert-script-delete.sh), and that it start with a valid shebang.
If you can't fix your file permissions to make your executable, at least pass the arguments out-of-band:
child_process.execFile('/bin/sh', ['./check-cert-script-delete.sh', req.body.deletedCert])
This question already has answers here:
Command not found error in Bash variable assignment
(5 answers)
Variable variable assignment error -"command not found"
(1 answer)
Why does a space in a variable assignment give an error in Bash? [duplicate]
(3 answers)
Closed 4 years ago.
So I've got a shell script to do some lazy stuff for if the directory isn't changing for a user. It's below. Essentially, it should be an if statement that if the user enters "default" for the directory, it'll pull them to the default directory for the files. However, I'm getting a command not found on line 16, which is the reassignment statement.
The entire if statement below:
if [ $directory = "default" ];
then
echo Enter your ldap:
read $ldap
$directory = "/usr/local/home/google/${ldap}/Downloads"
fi
I've tried doing it without the dollar sign too...nothing. What's going on here? New to shell, couldn't find this question asked before either.
This is how you should assign a value to a variable in shell:
directory="/usr/local/home/google/${ldap}/Downloads"
No dollar ($) sign.
No space around equal (=) sign.
Also, you should wrap your variables inside double quotes ("). This way, you avoid errors with undefined variables, arguments with spaces, etc.
That gives us:
if [ "$directory" = "default" ]
then
echo "Enter your ldap:"
read $ldap
directory="/usr/local/home/google/${ldap}/Downloads"
fi