I have 2 data sources and i want to lookup data using Vlookup by using unique ID,
1st data source will show "X" if the ID locate there,
2nd data source will show "Y" if the ID locate there,
the other responses of ID lookup will show nothing ""
Data source 1:
20000543
10056577
10032255
10008287
10011657
10008119
10008212
10007880
10052842
10007959
10062445
10011361
10008079
10008836
10007792
10052651
10007793
10047404
10007913
10007528
10008252
10007388
10007311
10057445
10036263
20004767
20004010
20001276
20010704
10039655
10062427
20010703
10048331
Data source 2:
20003695
20010673
10011463
10021645
10007439
20001123
10008276
10055885
10007718
10007587
10007364
10055257
10007651
10056216
10054797
10052500
10059984
10027674
10010153
10007808
10008182
10007763
10007428
10008102
10050130
10037579
10021909
10009539
10057979
I want to lookup value by using ID "10008102" which is locate in Data source 2 than it will show "Y" for final result,
How can I achieve this?
Much appreciate that.
Thank you
Please don't kill me for the overkill, but I came up with this:
=IF(IFNA(MATCH(A1,Sheet2!A$1:A$29,0),"N")="N","N","Y")
The story:
Match(...,...,0) searches for an exact match (hence the zero).
you need to look for a relative reference, like A1 (without dollarsigns), so that you can drag down and use another cell reference at any time
you need to look inside a fix array, like A$1:A$29, so that, when you drag down, you don't modify the array you're looking in.
Match() either gives a number or an #N/A error in case not found.
IFNA() translates #N/A to "N" (but there's no else-case in IFNA())
IF() has an else-case.
I'm inviting Excel wizards to come up with a simpler solution :-)
Do you possibly want to account for the value existing in both or none of the columns?
=IF(AND(COUNTIF(A:A,E2)>0,COUNTIF(B:B;E2)>0),"X&Y",
IF(COUNTIF(A:A,E2)>0,"X",
IF(COUNTIF(B:B,E2)>0,"Y",
"NONE")))
I have a property that contains a list of column names and I want to create a custom expression using the $map function, like this
$map("Sum(${myproperty}) as [${myproperty}]", ",")
However, I would like to change the column names dynamically when they contain a given string.
I have tried the following, which however doesn't work as it returns the expression between []
$map("Sum(${myproperty}) as [if(Find('string',${myproperty}),'new name', 'old name')]"), ",")
I have also tried the following, but it seems that $map() does not accept Concatenate()
$map(Concatenate("Sum(${myproperty}) as [",
if(Find('string',${myproperty}),'new name', 'old name'), "]"),
",")
Is it possible to realize what I am trying to do in Spotfire?
This post has an example ironpython script that can be used to change column headers, using document properties.
The script looks like this:
col=ActivedataTable.Columns["CurrentColumnName"]
ColName= ActivedataTable.Columns[col.Name].Properties["ExternalName"]
col.Name= "New Name"
It perhaps doesn't quite answer your question, but hopefully is useful.
Let's assume that I have Custom Table named Possible URL target parameters with code name xyz.PossibleTargets with 2 columns:
Explanation and Value.
How to feed drop-down field on page type with data to have Value (from table) as Value and Explanation as name in drop-down?
What I already tried and it is not working:
Generate value;name pairs divided by newline and place it as List of options:
z = ""; foreach (x in CMSContext.Current.GlobalObjects.CustomTables["xyz.PossibleTargets"].Items) {z += x.GetValue("Value"); z +=";"; z += x.GetValue("Explanation"); z += "\n" }; return z;
Validator do no allow me to do such trick.
Set option Macro expression and provide enumerable object:
CMSContext.Current.GlobalObjects.CustomTables["xyz.PossibleTargets"].Items
In Item transformation: {%Explanation%} and in Value column {%TargetValue%}.
This do not work also.
Dropdown configuration
How to do this correctly? Documentation and hints on the fields are not helpful.
Kentico v11.0.26
I think that you should do it without marking field as a macro. Just type there the macro. Take a look on screen
No need to use a macro, use straight SQL, using a macro only complicates what appears to be a simple dropdown list.
SELECT '', '-- select one --' AS Explanation
UNION
SELECT TargetValue, Explanation
FROM xyz_PossibleTargets -- make sure to use the correct table name
ORDER BY ExplanationText
This should populate exactly what you're looking for without the complication of a macro.
I have data in a csv file as follows:
60,27702,1938470,13935,18513,8
60,32424,1933740,16103,15082,11
60,20080,1946092,9335,14970,2
60,28236,1937936,13799,16871,6
60,22717,1943455,10809,16726,4
120,37702,2938470,23935,28513,8
120,42424,2933740,26103,25082,11
120,30080,2946092,2335,24970,2
120,38236,2937936,23799,26871,6
120,32717,2943455,20809,26726,4
180,47702,3938470,33935,8513,8
180,52424,3933740,36103,5082,11
180,40080,3946092,3335,4970,2
180,48236,3937936,33799,6871,6
180,42717,3943455,30809,6726,4
I then used the following code to insert column heading:
df = pd.read_csv("contikiMAC_new_out.csv", names=['Energest','CPU','LPM','Transmit','Listen','ID'])
I used df.groupby(['ID']) to see the data in group according to column 'ID'.
The problem is the data in column 'LPM' gets reset after some time so I would like to add the previous value with the new value whenever the new value in LPM column is smaller for specific 'ID' .
I tried doing :
for x in df.groupby(['ID']):
for i in df.ID:
if (df.loc[i, 'LPM'] < df.loc[i - 1, 'LPM']):
df.loc[i, 'LPM'] = df.loc[i, 'LPM'] + df.loc[i - 1, 'LPM']
But actually not getting the fruitful result I desire because it mixes with the 'LPM' value of different 'ID' and the process takes a long time. Can anyone please help me in suggesting a way to write the data group wise in a csv file based on 'ID' after performing the sum operation ?
The data structure I like to see is as follows:
60,27702,1938470,13935,18513,8
120,37702,2938470,23935,28513,8
180,47702,3938470,33935,37026,8
60,32424,1933740,16103,15082,11
120,42424,2933740,26103,25082,11
180,52424,3933740,36103,30164,11
60,20080,1946092,9335,14970,2
120,30080,2946092,2335,24970,2
180,40080,3946092,3335,29940,2
60,28236,1937936,13799,16871,6
120,38236,2937936,23799,26871,6
180,48236,3937936,33799,33742,6
60,22717,1943455,10809,16726,4
120,32717,2943455,20809,26726,4
180,42717,3943455,30809,33452,4
If I understood your problem correctly, DataFrame.shift is what you're looking for.
Something like:
df['LPM_prev'] = df.groupby(['ID'])['LPM'].shift(1)
And then you can work with that column
I have the following table with these columns:
shortName, fullName, ChangelistCount
Is there a way to group them by a string literal within their fullName? The fullname represents file directories, so I would like to display results for certain parent folders instead of the individual files.
I tried something along the lines of:
GROUP BY fullName like "%/testFolder/%" AND fullName like "%/testFolder2/%"
However it only really groups by the first match....
Thanks!
Perhaps you want something like:
GROUP BY IF(fullName LIKE '%/testfolder/%', 1, IF(fullName LIKE '%/testfolder2/%', 2, 3))
The key idea to understand is that an expression like fullName LIKE foo AND fullName LIKE bar is that the entire expression will necessarily evaluate to either TRUE or FALSE, so you can only get two total groups out of that.
Using an IF expression to return one of several different values will let you get more groups.
Keep in mind that this will not be particularly fast. If you have a very large dataset, you should explore other ways of storing the data that will not require LIKE comparisons to do the grouping.
You'd have to use a subquery to derive the column values you'd like to ultimately group on:
FROM (SELECT SUBSTR(fullname, ?)AS derived_column
FROM YOUR_TABLE ) x
GROUP BY x.derived_column
Either use when/then conditions or Have another temporary table containing all the matches you wish to find and group. Sample from my database.
Here I wanted to group all users based on their cities which was inside address field.
SELECT ut.* , c.city, ua.*
FROM `user_tracking` AS ut
LEFT JOIN cities AS c ON ut.place_name LIKE CONCAT( "%", c.city, "%" )
LEFT JOIN users_auth AS ua ON ua.id = ut.user_id