I am using the latest version of pyRevit, v45.
I'm writing some info in temporary files with
myTempFile = script.get_instance_data_file("id")
This creates a file named pyRevit_2018_xxxx_id.tmp in which I store useful info. If I'm not mistaken, the "xxxx" part is changing every time I reload Revit. Now, I need to get access to this information from another pyRevit script.
How can I retrieve the name of the temp file I need to read? In other words, how do I access "myTempFile" from within the second script, which has no idea of the name of "myTempFile"?
I guess I can share somehow that variable between my script, but what's the proper way to do this? I know this must be a very basic programming question, but I'm indeed not a programmer ;)
Thanks a lot,
Arnaud.
Ok, I realise now that my variables in the 1st script cease to exist after its execution.
So for now I wrote the file name in another file, of which I know the name.. That works.
But if there's a cleaner way to do this, I'd be glad to learn ;)
Arnaud
pyrevit.script module provides 4 different methods for creating temporary files based on their use case:
get_instance_data_file:
for data files marked with Revit instance pid. This means that scripts running on another instance will not see this temp file.
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_instance_data_file
get_universal_data_file:
for temp files accessible to all Revit instances and versions
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_universal_data_file
get_data_file:
Base method to get a standard temp file for current revit version
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_data_file
get_document_data_file:
temp file marked with active document (so scripts working on another document will not see this)
http://pyrevit.readthedocs.io/en/latest/pyrevit/script.html#pyrevit.script.get_document_data_file
Each method uses a pattern to create the temp file name. So as long as the call to the method is the same of different scripts, the method generates the same file name.
Example:
Script 1:
from pyrevit import script
tfile = script.get_data_file('mydata')
Script 2:
from pyrevit import script
tempfile = script.get_data_file('mydata')
In this example tempfile = tfile since the file id is the same.
There is documentation on each so make sure you take a look at those and pick the flavor that serves your purpose.
Related
I wanted to create a job where I need to consider the latest file available as input file.
File format is as below: FILE1.TEST.TYYMMDD
is there any way to identify latest file based on date present in file name via JCL.
P.S. GDG versions are not created in existing process . Only PS file is created.
Thank you
I wanted to create a job where I need to consider the latest file available as input file. File [name] format is as below: FILE1.TEST.TYYMMDD is there any way to identify latest file based on date present in file name via JCL.
No.
You indicate that GDGs are not created in the existing process. GDGs would be the best way to accomplish your goal. Absent GDGs, you must write code.
You could accomplish your goal by writing (C, clist, COBOL, PL/I, Rexx) code using the LMDINIT and LMDLIST ISPF services. Then you would execute your code by running ISPF in batch. Many mainframe shops have a cataloged procedure to execute ISPF in batch.
Agree with #cschneid that there is not a platform way to handle this. However, I want to point out that GDGs are the platform way of managing PS files for access in a relative form.
Your comment
GDG versions are not created in existing process . Only PS file is
created.
That statement didn't make sense to me. GDGs are not a file type like physical sequential (PS) or partitioned (PO). It's a convention to allow relative reference to files created over time which sounds like what you want. I've only seen the use of GDGs for PS files.
Putting the date in the file name can have its uses but to z/OS its only part of the filename and not meta information that it operates on (like G0000v00's in GDGs.
I am trying to read a file content after executing a class GetContentsAPI, basically this class GetContentsAPI will write into the file /etc/api/token.
class Main{
require GetContentsAPI
file("/etc/api/token")
}
When I did the above steps, its says Evaluation Error: Error while evaluating a Function Call, Could not find any files from /etc/api. Not sure how to make sure the file is already created before trying to read.
Thanks James
The file() function reads the contents of a file during catalog building. You don't present any details of class GetContentsApi, but all of the standard puppet facilities that write to files (especially, but not limited to, File resources) write during catalog application. Unless you've cooked up something highly customized, the file() function will always read before GetContentsApi writes.
Moreover, in a master / agent setup (which is the only kind supported in current Puppet), catalog building happens on the master, whereas catalog application happens on the target node, which is usually a different machine, so you're unlikely even to be able to read what was written during a previous catalog-building run.
Also, file() just returns the file contents as a string, so it's not very useful to call it without using the return value somehow.
It's not at all clear what you're trying to achieve, but from what I can see, you are not going in a fruitful direction. Perhaps you should take a step back and ask a different question about that.
In the piece of code I have, there are many instances where I have the following line
'/home/myname/directory'
For example, I have the following lines of code
filepath = os.listdir('/home/myname/directory')
for content in filepath
# do something
In the next part of the project, I have to share the code with some one else. I know this person runs openSUSE. If I want code to create that specific directory with the same path to the directory as mine, what do I need to include?
I know its going to involve the OS module but i am not sure which functions and methods to use.
Your code can check the existence of the directory and create it if not found:
if not os.path.exists("/home/myname/directory"):
os.makedirs("/home/myname/directory")
# do something
I'm processing a data set and running into a problem - although I xlswrite all the relevant output variables to a big Excel file that is timestamped, I don't save the code that actually generated that result. So if I try to recreate a certain set of results, I can't do it without relying on memory (which is obviously not a good plan). I'd like to know if there's a command(s) that will help me save the m-files used to generate the output Excel file, as well as the Excel file itself, in a folder I can name and timestamp so I don't have to do this manually.
In my perfect world I would run the master code file that calls 4 or 5 other function m-files, then all those m-files would be saved along with the Excel output to a folder names results_YYYYMMDDTIME. Does this functionality exist? I can't seem to find it.
There's no such functionality built in.
You could build a dependency tree of your main function by using depfun with mfilename.
depfun(mfilename()) will return a list of all functions/m-files that are called by the currently executing m-file.
This will include all files that come as MATLAB builtins, you might want to remove those (and only record the MATLAB version in your excel sheet).
As pseudocode:
% get all files:
dependencies = depfun(mfilename());
for all dependencies:
if not a matlab-builtin:
copyfile(dependency, your_folder)
As a "long term" solution you might want to check if using a version control system like subversion, mercurial (or one of many others) would be applicable in your case.
In larger projects this is preferred way to record the version of source code used to produce a certain result.
I'll explain the task requested from me:
I have two containers in Azure, one called "data" and one called "script". In the "data" container there's a txt file with data, and in the "script" container there's a script file.
Now, I need programatically (with WorkerRole) to execute the script file, with the content of the data file as parameters (Example: a script file that accepts a string 's' and returns to the screen "Hello, 's'", when 's' in the string given, and in the data file there's a string), and save the result of the run into another file which needs to be saved in another container called "result".
How do I do all these? I've already uploaded the files and created the blobs programatically, but I can't seem to understand how to execute the file of how to save its result to another file?
Can I please have some help?
Thanks in advance
Here are the steps in pseudo code:
Retrieve the script from the blob(using DownloadToStream())
Compile the script(I will leave this to you as I have no idea what
format your script is)
Load parameters from blob(same as step 1)
Execute script with those parameters.
If your script's can be written as lambda expressions then this becomes a lot easier as you can turn them into Action's
Edit based on your questiions:
DownloadText() is no longer included in Azure Storage 2.0, you only have access to DownloadToStream(). Even if you are using an older version(say 1.7) I would recommend using DownloadToStream() in the event you ever upgrade in the future. This will prevent having to refactor your code.
In terms of executing your script, depending on what type of script it is(if it is c# code you can use this example: Is it possible to dynamically compile and execute C# code fragments?. If you need to execute a different type of script you would need to run it using Process.Start and you can look at this example: http://www.dotnetperls.com/process-start
I do not have much experience with point number 2 but those are the processes I have heard and seen used.