I have a users.txt file with the following content:
[builders.ca]
UniqueID=DB#LqlFP
Login=buildca
Pass=5nFvZLwx
RelativePath=1
[DeluxeDoors.ca]
UniqueID=RgOkvU4Z
Login=DeluxDSM
Pass=L9pP3iaK
RelativePath=1
[Sonicwall.com]
UniqueID=JVpFoXad
Login=firewall
Pass=azasadsa
RelativePath=1
I wrote a script to replace all the passwords with random passwords in the file.
The script is:
users=($(cat users.txt | grep 'Login=' | cut -c 7-))
for user in "${users[#]}"; do
pass=$(cat users.txt | grep -A 2 $user | grep 'Pass' | cut -c 6-)
new_pass=$(cat /dev/urandom | env LC_CTYPE=C tr -cd 'a-zA-Z0-9' | head -c 8)
echo $pass;
echo $new_pass;
#perl -pi -e 's/$pass/$new_pass/g' users.txt
sed -i '' 's/"${pass}"/"${new_pass}"/g' users.txt
done
But it is not updating the passwords in the users.txt.
Any help would be highly appreciated.
sed -i '' 's/'"${pass}/${new_pass}"'/g' users.txt
^ ^
These seem to be missing, so the sed was getting ${pass} and ${new_pass} as literal strings, not the expanded variables.
Related
I have a command to grep a file with fullpath that contain a "TypeId: 0", here is the command
grep -rnw /home/username/app/data/store/0/part/.mv -e "TypeId: 0" | awk -F ":" '{print $1}'
and here is the result:
/home/username/app/data/store/0/part/.mv/521/1673332792072/segmentconfig.yaml /home/username/app/data/store/0/part/.mv/521/1673333077920/segmentconfig.yaml /home/username/app/data/store/0/part/.mv/521/1673333077920/segmentconfig.yaml.old /home/username/app/data/store/0/part/.mv/515/1672993850766/segmentconfig.yaml /home/username/app/data/store/0/part/.mv/515/1672993850766/segmentconfig.yaml.old /home/username/app/data/store/0/part/.mv/703/1672987004847/segmentconfig.yaml /home/username/app/data/store/0/part/.mv/703/1672987004847/segmentconfig.yaml.old
Now I confuse how to grep "numofvertice" from each file from that list.
Anyone have an idea to solve this?
You could try this:
grep -rnw /home/username/app/data/store/0/part/.mv -e "TypeId: 0" | awk -F ":" '{print $1}'|xargs -I{} grep "numofvertice" {}
Like this (GNU grep):
<STDIN> | grep -oP '\b\S+\.yaml' | xargs cat
Or with ack:
cd /home/username/app/data/store/0/part/.mv
ack -wl -e "TypeId: 0" | xargs cat
From ack --help:
-l, --files-with-matches
Only print filenames containing matches
I need to save into a bash variable a string after a grep and sed treatment.
Here my code :
echo ${plan} | grep -e '^\S' -e 'Home directory:' | sed -e 's/Home directory: //'
/home/james
That's what I need to save into a variable... so I tried :
HOME_DIRECTORY=$(${plan} | $(grep -e '^\S' -e 'Home directory:') | $(sed -e 's/Home directory: //'))
and
HOME_DIRECTORY=`${plan} | grep -e '^\S' -e 'Home directory:' | sed -e 's/Home directory: //'`
But both give me :
line 121: Home: command not found
Change you command to ,
HOME_DIRECTORY=$(echo ${plan} | grep -e '^\S' -e 'Home directory:' | sed -e 's/Home directory: //')
That is, you need to include the whole command inside $().
When I am trying to run the below Script it says invalid option 3 for cat..Whats the problem?
I am tried to use index file which specifies which file is ham and which is spam...to read the files and train spamfilter
#!bin/bash
DirBogoDict=$1
BogoFilter=/home/gunna/Downloads/bogofilter-1.2.4/src/bogofilter
x=0
for i in 'cat index | fgrep spam | head -300 | awk -F "/" '{print$2"/"$3}''
do
x=$((x+1)) ; echo $x
cat /home/gunna/Downloads/db-6.1.19.NC/build_unix/ceas08-1/$i| $BogoFilter -d $DirBogoDict -M -k 1024 -s
done
for i in 'cat index | fgrep ham | head -300 | awk -F "/" '{print$2"/"$3}''
do
x=$((x+1)) ; echo $x
cat /home/gunna/Downloads/db-6.1.19.NC/build_unix/ceas08-1/$i | $BogoFilter -d $DirBogoDict -M -k 1024 -n
done
This part
'cat index | fgrep spam | head -300 | awk -F "/" '{print$2"/"$3}''
needs to be in back-ticks, not single quotes
`cat index | fgrep spam | head -300 | awk -F "/" '{print$2"/"$3}'`
And you could probably simplify it a little with
for i in `fgrep spam index | head -300 | awk "/" '{print$2"/"$3}'`
Kdopen has explained the error you got , here is the improved code for similar for-loop function.
DirBogoDict=$1
BogoFilter=/home/gunna/Downloads/bogofilter-1.2.4/src/bogofilter
awk '/spam/&&++myctr<=300{print $2 FS $3}' FS="/" index |while read i
do
cat /home/gunna/Downloads/db-6.1.19.NC/build_unix/ceas08-1/"$i"| $BogoFilter -d ${DirBogoDict} -M -k 1024 -s
done
awk '/ham/&&++myctr<=300{print $2 FS $3}' FS="/" index |while read i
do
cat /home/gunna/Downloads/db-6.1.19.NC/build_unix/ceas08-1/"$i"| $BogoFilter -d ${DirBogoDict} -M -k 1024 -s
done
Also look at your file names , since cat is giving an error and an option is invalid. To demonstrate this, Let say you have a file a name -3error
executing the following command
cat -3error
will gave
cat: invalid option -- '3'
cat therefore is thinking the "-" is followed by one of its command line arguments. As a result you probably get an invalid option error.
I get the following error:
> echo "${$(qstat -a | grep kig):0:7}"
-bash: ${$(qstat -a | grep kig):0:7}: bad substitution
I'm trying to take the number before. of
> qstat -a | grep kig
1192530.perceus- kigumen lr_regul pbs.sh 27198 2 16 -- 24:00:00 R 00:32:23
and use it as an argument to qdel in openPBS so that I can delete all process that I started with my login kigumen
so ideally, this should work:
qdel ${$(qstat -a | grep kig):0:7}
so far, only this works:
str=$(qstat -a | grep kig); qdel "${str:0:7}"
but I want a clean one-liner without a temporary variable.
The shell substring construct you're using (:0:7) only works on variables, not command substitution. If you want to do this in a single operation, you'll need to trim the string as part of the pipeline, something like one of these:
echo "$(qstat -a | grep kig | sed 's/[.].*//')"
echo "$(qstat -a | awk -F. '/kig/ {print $1}')"
echo "$(qstat -a | awk '/kig/ {print substr($0, 1, 7)}')"
(Note that the first two print everything before the first ".", while the last prints the first 7 characters.) I don't know that any of them are particularly cleaner, but they do it without a temp variable...
qstat -u palle | cut -f 1 -d "." | xargs qdel
Kills all my jobs... normally I grep out the jobname(s) before cut'ing...
So I use a small script "idlist":
qstat -u palle | grep -E "*.in" | grep -E "$1" | cut -f 1 -d "." | xargs
To see all my "map_..." jobs:
idlist "map_*"
For killing all my "map_...." jobs:
idlist "map_*" | xargs qdel
yet another ways :
foreach m1 in $(qstat -a );do
if [[ $m1 =~ kig ]];then
m2=${m1%.kig}
echo "kig found $m2 "
break
fi
done
I am trying to get the max version number from a directory where i have several versions of one program
for example if output of ls is
something01_1.sh
something02_0.1.2.sh
something02_0.1.sh
something02_1.1.sh
something02_1.2.sh
something02_2.0.sh
something02_2.1.sh
something02_2.3.sh
something02_3.1.2.sh
something.sh
I am getting the max version number with the following -
ls somedir | grep some_prefix | cut -d '_' -f2 | sort -t '.' -k1 -r | head -n 1
Now if at the same time i want to check it with the version number which i already have in the system, whats the best way to do it...
in bash i got this working (if 2.5 is the current version)
(ls somedir | grep some_prefix | cut -d '_' -f2; echo 2.5) | sort -t '.' -k1 -r | head -n 1
is there any other correct way to do it?
EDIT: In the above example some_prefix is something02.
EDIT: Actual Problem here is
(ls smthing; echo more) | sort
is it the best way to merge output of two commands/program for piping into third.
I have found the solution. The best way it seems is using process substitution.
cat <(ls smthing) <(echo more) | sort
for my version example
cat <(ls somedir | grep some_prefix | cut -d '_' -f2) <(echo 2.5) | sort -t '.' -k1 -r | head -n 1
for the benefit of future readers, I recommend - please drop the lure of one-liner and use glob as chepner suggested.
Almost similar question is asked on superuser.
more info about process substitution.
Is the following code more suitable to what you're looking for:
#/bin/bash
highest_version=$(ls something* | sort -V | tail -1 | sed "s/something02_\|\.sh//g")
current_version=$(echo $0 | sed "s/something02_\|\.sh//g")
if [ $current_version > $highest_version ]; then
echo "Uh oh! Looks like we need to update!";
fi
You can try something like this :
#! /bin/bash
lastversion() { # prefix
local prefix="$1" a=0 b=0 c=0 r f vmax=0
for f in "$prefix"* ; do
test -f "$f" || continue
read a b c r <<< $(echo "${f#$prefix} 0 0 0" | tr -C '[0-9]' ' ')
v=$(((a*100+b)*100+c))
if ((v>vmax)); then vmax=$v; fi
done
echo $vmax
}
lastversion "something02"
It will print: 30102