I recently went from windows to Linux (Debian based) and I imported all my files from a backup drive. The problem is that now all the files are named with the original name + an appendix with the date of the backup inside a pair of brackets.
Example:
index (2017_12_01 15_56_03 UTC).html
Instead of index.html
How do I delete from all the files the informations added by the backup?
I am searching for a function that could go trough all the files in a directory and delete the brackets part.
Or is there a way I can reimport without it?
The shell solution, assuming everything after the first ( should be replaced with .html, is
for f in *.html; do
mv "$f" "${f%%\(*}.html"
done
which is easily extended to work recursively:
find . -name '*.html' |
while read f; do
mv "$f" "${f%%\(*}.html"
done
Related
Maybe i'm just going about this wrong and making it harder than it has to be.
This is my problem. I have 2 different scripts that download various picture files. the first downloads from email and the downloaded files go into the /attachments/ directory. The second script copies the contents of google drive, all files and folders get copied into ~/gdrive/ directory. i want to be able to move all picture files from both these folders as well as any subfolders to ~/Pictures/$today and prevent any overwriting in the case of duplicate file names. I don't mind having 2 separate scripts to handle the pictures in the 2 different directories, but I do need it to be able to get all files in subdirectories of the starting point. it also needs to be able to handle a variety of file extensions. my current solution adds a numbered extension such as .~1~ after the files normal extension .jpg, .png, .tiff, etc. I dont lose any files this way but any that wind up with a backup number after the extension are rendered useless to my project. This is what I am currently using
TODAY=$(date +"%m-%d-%Y")
mkdir -p ~/Pictures/$TODAY &&
sudo find /attachments -type f -exec mv --backup=numbered -t ~/Pictures/$TODAY {} +
My result if there are duplicate file names looks like this:
DSC07286.JPG
DSC07286.JPG.~1~
Is there a better approach than what i am doing? Is there a way to dissect the filename parts and reorganize them and do it recursively for all files in the directory? Thanks
Something like this should do it (untested; uses standard lowercase variable names and puts the index just before the extension to not mess with sorting):
for path in ~/Pictures/"$today"/*.JPG
do
index=0
for duplicate_path in "$path".~[0-9]*
do
new_path="${duplicate_path%%.*}${index}.JPG"
echo "$duplicate_path" "$new_path"
((++index))
done
done
When you're confident it's doing the right thing, simply replace echo with mv to actually move the files.
Here is my solution.
#!/bin/bash
TODAY=$(date +"%m-%d-%Y")
NOW=$(date +"%D %T")
sudo mkdir -p /home/pi/Pictures/emailpics/$TODAY &&
sudo find /attachments -type f -exec mv --backup=numbered -t /home/pi/Pictures/emailpics/$TODAY/ {} + &&
for f in /home/pi/Pictures/emailpics/$TODAY/*.~?~
do
fullfilename=$f
filepath=$(dirname "$fullfilename")
filename=$(basename "$fullfilename")
fname="${filename%.*}"
bkpnum="${filename##*.}"
file="${fname%.*}"
ext="${fname##*.}"
sudo mv $f $filepath/$file$bkpnum.$ext
done
Can't say i fully understand all the syntax for the parsing bits, but it works. maybe someone else can explain what is going on.
I have a directory that is filled with subdirectories exceeding 450 GBs. Inside of these subdirectories is an instruction file in each subdirectory. I have a script that copies the instruction file in the directory I am currently in and puts it inside every subdirectory via:
#!/bin/bash
for d in */; do cp "INSTALLATION INSTRUCTIONS.rtf" "$d"; done
I need to remove all of these files in the subdirectories and replace them with new instructions. Can I simple write another script that does this:
#!/bin/bash
for d in */; do rm "INSTALLATION INSTRUCTIONS.rtf" "$d"; done
I am very hesitant and wanted to make sue as these files are vitally important and I don't want to accidentally remove anything and making a backup of 450+ GBs is very taxing.
find . -mindepth 2 -name "INSTALLATION INSTRUCTIONS.rtf" -exec rm -f '{}' +
Since this is "vitally important" data, I would first list all files that match the file name you want to delete/overwrite, without taking any action on it (other than listing):
find /folder/ -type f -name "INSTALLATION INSTRUCTIONS.rtf" -print > /tmp/holder
That would create a list of matches on /tmp/holder. Then you could analyze this list before taking any action (either visually or programatically) to make sure that the list does not include anything you don't want to delete (when dealing with big amounts of data, strange things can happen, so be proactive on protecting the data).
If you are happy with what the list shows, then you could delete the old instructions, or if possible, overwrite them with the new file. Here's an example to overwrite the old file with the new one:
while read -r line; do cp --no-preserve=all /folder/newfile "$line"; done < /tmp/holder
The cp --no-preserve=all command (available on GNU bash) would ensure that the new file has permissions that are "adequate" to the folder where they are located. You may change that to a simple cp if you don't want that to happen.
I'm trying write a script in linux. Where I have some csv files in Two different folders(A and B) and then after some processing copy of rejected files are moving to Bad Folder.
SO I want bad files to be deleted from Table A and B which have copied to Bad Folder.
Can you help me to write this script for linux?
Best
lets say name of Bad Folder is 'badFolder' and considering 'A', 'B' and 'badFolder' are in same directory
Steps to delete files from folder A and B:
step 1: change current directory to your 'badFolder'
cd badFolder
step 2: delete identical files
find . -type f -exec rm -f ../A/{} \;
find . -type f -exec rm -f ../B/{} \;
The argument -type f tells to look for files, not directories.
The -exec ... \; argument tells that, once it finds a file in 'badFolder', it should run the command rm -f on its counterpart in the A subdirectory.
Because rm is given with the -f option, it will silently ignore files that don't exist.
Also, it will not prompt before deleting files. This is very handy when deleting a large number of files. However, be sure that you really want to delete the files before running this script.
#!/bin/bash
#Set the working folder in which you want to delete the file
Working_folder=/<Folder>/<path>
cd $Working_folder
#command to delete all files present in folders
rm <filenames seperated by space>
echo "files are deleted"
#if you want to delete all files you can use wild card character
# e.g. command rm *.*
# if you want to delete a particular file say for deleting .csv file you can use command rm *.csv command
Set variables containing the paths of your A, B and BAD directories.
Then you can do something along the lines of
for file in ls ${PATH_TO_BAD}
do
rm ${PATH_TO_A}/$file
rm ${PATH_TO_B}/$file
done
This is iterating over the BAD directory and any file it finds, it deletes from the A and B directories.
I need to do some testing and need the same file names as I have in directory /home/recordings in /home/testing folder.
For example, if i have a file recording01.mp4 in /home/recordings, i would want to have the an empty file recording01.txt or recording01.mp4 or in /home/testing
I understand I can use the following command?
for i in /home/recordings/*; do touch "$i"; done
Not sure how to specify extension or the destination directory in this case?
A simple addition of /home/testing/ to touch command will do it.
for i in /home/recordings/*; do
temp=`echo $i|cut -f3 -d'/'`
cd /home/testing/
touch "$temp";
cd ../..
done
I assume you are not in home directory and running this script file from anywhere else.
You can also do this without a loop
find /home/recordings/ -type f -printf /home/testing/%f'\n' | xargs -n1 touch
Try this:
for i in /home/recordings/*; do touch "/home/testing/$i"; done
You need only specify absolute paths and things will work fine. A bunch of 0-length files are created, their names corresponding to those in /home/recordings.
i'm trying to elaborate a command that will find files that haven't been modified in over 6 months and zip them with one command. Afterwards i want to delete all those files and i just archived.
My current command to find the directories with the files is
find /var/www -type d -mtime -400 ! -mtime -180 | xargs ls -l > testd.txt
This gave me all the directories including the files that are older than 6 months
Now i was wondering if there was a way of zipping all the results and deleting them afterwards. Something amongst the line of
find /var/www -type f -mtime -400 ! -mtime -180 | gzip -c archive.gz
If anyone knows the proper syntax to achieve this i'd love to know. Thakns!
Edit, after a few tests this command results in a corrupted file
find /var/www -mtime -900 ! -mtime -180 | xargs tar -cf test4.tar
Any ideas?
Break this into several distinct steps that you can implement and thoroughly test separately:
Build a list of files to be archived and then deleted, saved to a temp file
Use the list from step 1 to add the files to .tar.gz archives. Give the archive file a name following a specific pattern that won't appear in the files to be archived, and put it in a directory outside the hierarchy of files being archived.
Read back the files from the .tar.gz and compare them (or their hashes) to the original files to ENSURE that you got them all without corruption
Use the list from step 1 to delete the files. Do not use a wildcard for deletion. Put in some guard code to prevent deletion of any file matching the name pattern of the archive .tar.gz file(s) created in step 2.
When testing a script that can do irreversible damage, always code the dangerous command with a leading echo and leave it that way until you are sure everything works. Only then remove the echo.
Consider zip, it should meet your requirements.
find ... | zip -m# archive.zip
-m (move) deletes the input directories/files after making the specified zip archive.
-# takes the list of input files from standard input.
You may find more options which are useful to you in the zip manual, e. g.
-r (recurse) travels the directory structure recursively.
-sf (show-files) shows the files that would be operated on, then exits.
-t or --from-date operates on files not modified prior to the specified date.
-tt or --before-date operates on files not modified after or at the specified date.
This could possibly make findexpendable.
zip -mr --from-date 2012-09-05 --before-date 2013-04-13 archive /var/www