load items where relation is null in sequelize - node.js

Question

I'm new to sequelize, i'm trying to load all entries in my user table where the task relation is null. but its not working. here is what i have tried:
const express = require('express');
const app = express();
const Sequelize = require('sequelize');
const sequelize = new Sequelize('sequelize', 'mazinoukah', 'solomon1', {
host: 'localhost',
dialect: 'postgres',
pool: {
max: 5,
min: 0,
acquire: 30000,
idle: 10000,
},
});
const Task = sequelize.define('Task', {
name: Sequelize.STRING,
completed: Sequelize.BOOLEAN,
UserId: {
type: Sequelize.INTEGER,
references: {
model: 'Users', // Can be both a string representing the table name, or a reference to the model
key: 'id',
},
},
});
const User = sequelize.define('User', {
firstName: Sequelize.STRING,
lastName: Sequelize.STRING,
email: Sequelize.STRING,
TaskId: {
type: Sequelize.INTEGER,
references: {
model: 'Tasks', // Can be both a string representing the table name, or a reference to the model
key: 'id',
},
},
});
User.hasOne(Task);
Task.belongsTo(User);
app.get('/users', (req, res) => {
User.findAll({
where: {
Task: {
[Sequelize.Op.eq]: null,
},
},
include: [
{
model: Task,
},
],
}).then(function(todo) {
res.json(todo);
});
});
app.listen(2000, () => {
console.log('server started');
});
if i have three users, and 2 of those users have a task each, i want to load just the last user without a task. is this possible in sequelize ?

Answer 1

after much debugging i found the solution
app.get('/users', (req, res) => {
User.findAll({
where: {
'$Task$': null,
},
include: [
{
model: Task,
required: false,
},
],
}).then(function(todo) {
res.json(todo);
});
});
by adding this where clause
where: {
'$Task$': null,
},
i was able to load only users without a task