command in terminal and in script produce different results [duplicate] - linux

Question

I have a bash script (ScreamDaemon.sh) inside which a check that example of it isn't running already is added.
numscr=`ps aux | grep ScreamDaemon.sh | wc -l`;
if [ "${numscr}" -gt "2" ]; then
echo "an instance of ScreamDaemon still running";
exit 0;
fi
Normally, if there are no another copy of script running, ps aux | grep ScreamDaemon.sh | wc -l should return 2 (it should find itself and grep ScreamDaemon.sh), but it returns 3.
So, I try to analyse what happens and after adding some echoes see this:
there are lines I have added into the script
ps aux | grep ScreamDaemon.sh
ps aux | grep ScreamDaemon.sh | wc -l
str=`ps aux | grep ScreamDaemon.sh`
echo $str
numscr=`ps aux | grep ScreamDaemon.sh | wc -l`;
echo $numscr
there is an output:
pamela 27894 0.0 0.0 106100 1216 pts/1 S+ 13:41 0:00 /bin/bash ./ScreamDaemon.sh
pamela 27899 0.0 0.0 103252 844 pts/1 S+ 13:41 0:00 grep ScreamDaemon.sh
2
pamela 27894 0.0 0.0 106100 1216 pts/1 S+ 13:41 0:00 /bin/bash ./ScreamDaemon.sh pamela 27903 0.0 0.0 106100 524 pts/1 S+ 13:41 0:00 /bin/bash ./ScreamDaemon.sh pamela 27905 0.0 0.0 103252 848 pts/1 S+ 13:41 0:00 grep ScreamDaemon.sh
3
I also tried to add the sleep command right inside `ps aux | grep ScreamDaemon.sh; sleep 1m` and see from the parallel terminal how many instances ps aux|grep ScreamDaemon.sh shows:
[pamela#pm03 ~]$ ps aux | grep ScreamDaemon.sh
pamela 28394 0.0 0.0 106100 1216 pts/1 S+ 14:23 0:00 /bin/bash ./ScreamDaemon.sh
pamela 28403 0.0 0.0 106100 592 pts/1 S+ 14:23 0:00 /bin/bash ./ScreamDaemon.sh
pamela 28408 0.0 0.0 103252 848 pts/9 S+ 14:23 0:00 grep ScreamDaemon.sh
So, it seems that
str=`ps aux | grep ScreamDaemon.sh`
contrary to
ps aux | grep ScreamDaemon.sh
found two instances of ScreamDaemon.sh, but why? Where this additional copy of ScreamDaemon.sh come from?
This is an output of pstree -ap command
│ ├─sshd,27806
│ │ └─sshd,27808
│ │ └─bash,27809
│ │ └─ScreamDaemon.sh,28731 ./ScreamDaemon.sh
│ │ └─ScreamDaemon.sh,28740 ./ScreamDaemon.sh
│ │ └─sleep,28743 2m

Answer 1

Why can a single bash script show up multiple times in ps?
This is typical when any constructs which implicitly create a subshell are in play. For instance, in bash:
echo foo | bar
...creates a new forked copy of the shell to run the echo, with its own ps instance. Similarly:
( bar; echo done )
...creates a new subshell, has that subshell run the external command bar, and then has the subshell perform the echo.
Similarly:
foo=$(bar)
...creates a subshell for the command substitution, runs bar in there (potentially exec'ing the command and consuming the subshell, but this is not guaranteed), and reads its output into the parent.
Now, how does this answer your question? Because
result=$(ps aux | grep | wc)
...runs that ps command in a subshell, which itself creates an extra bash instance.
How can I properly ensure that only one copy of my script is running?
Use a lockfile.
See for instance:
How to prevent a script from running simultaneously?
What is the best way to ensure only one instance of a Bash script is running?
Note that I strongly suggest use of a flock-based variant.

Answer 2

Of course, the reason you find an additional process is because:
One process is running the sub-shell (of the command execution `..`)
included in your line: numscr=`ps aux | grep ScreamDaemon.sh | wc -l`;
that's the simplest answer.
However I would like to make some additional suggestions about your code:
First, quote your expansions, it should be: echo "$str".
Not doing so is making several lines collapse into a long one.
Second, you may use: grep [S]creamDaemon.sh to avoid matching the grep command itself.
Third, capture the command just once in a variable, then count lines from the variable. In this case it presents no problem, but for dynamic processes, one capture and the following capture to count could give different results.
Fourth, make an habit of using $(...) command substitutions instead of the more error prone (especially when Nesting) `...`.
### Using a file as the simplest way to capture the output of a command
### that is running in this shell (not a subshell).
ps aux | grep "[S]creamDaemon.sh" > "/tmp/tmpfile$$.txt"
str="$(< "/tmp/tmpfile$$.txt")" ### get the value of var "str"
rm "/tmp/tmpfile$$.txt" ### erase the file used ($$ is pid).
numscr="$(echo "$str" | wc -l)" ### count the number of lines.
echo "$numscr" ### present results.
echo "$str"
str="$( ps aux | grep "[S]creamDaemon.sh" )" ### capture var "str".
numscr="$(echo "$str" | wc -l)" ### count the number of lines.
echo "$numscr" ### present results.
echo "$str"
### The only bashim is the `$(<...)`, change to `$(cat ...)` if needed.
#CharlesDuffy covered the point of a flock quite well, please read it.