How to keep a string of numbers from a Excel cell grabbed from the right and then the rest on the left to be deleted?:
I would like to keep the first 4 characters from right to left.
What I have:
222333444555
88
222333444
9933
The result that I am looking for:
4555
3444
9933
Less than 4 characters could be deleted. In this sample the 88 number was deleted as well.
The easy "aparently" solution is to splits the cells manually with the "Text to Columns" option, but this option start grabbing characters from the left. I need it grabbed from the right.
I tried already RIGHT and LEFT fuctions, but it deletes characters from the left or right. I have not fixed length as you can see, so it doesn't work.
Also I tried to analyze the following already answered question in a similar case, but I can not find the right answer:
Split text into different columns from the right
Any ideas?
Thank you in advance!
Related
I have an excel spreadsheet which has content I don't need, following content I do need, within each cell, with a few line breaks in between. I would like to remove the bad content, using some sort of formula which states that in each cell, the line breaks & anything that follows them should be removed, for example:
cell A1 -
Three blind mice, three blind mice
See how they run, see how they run
They all ran after the farmer's wife
She cut off their tails with a carving knife
Did you ever see such a sight in your life as three blind mice?
Star Light, Star Bright
Twinkle, Twinkle, Little Star
Jack and Jill
I’m a Little Teapot
There are multiple line breaks between the nursery rhyme & the list of nursery rhyme titles that follow, but they aren't showing that way above. The image linked below shows it better.
In the above example, how can I remove the line breaks and the list of nursery rhymes, all I want to keep are the lyrics at the top?
Here is a screenshot of an example cell
example cell
Thanks
I've tried using the replace tool, but I can't figure out how to accomplish this.
find() return the starting position of a string with a string
char(10) is the "line feed" in asci (10) getting converted to character which can be searched
LEFT() simply returns the left part of the string up to the enter.
so..
=LEFT(A1,FIND(CHAR(10)&CHAR(10)&CHAR(10),A1)-1)
we find the first occurrence of 3 line breaks in a row.
We put the formula in Cell B2 then copy and past values over your original data if you truly no longer need it. Or just reference B2... and keep original values.
Reference: https://superuser.com/questions/370066/how-to-search-for-newline-or-linebreak-characters-in-excel
So:
Gives us:
We simply look for 3 consecutive line breaks and Keep everything to the left of it.
In my job I have to enter warranty information so that POs can be cut. Vendors are very particular with how this is entered and each one has their own format.
One of them requires data be entered:
SN:
MACHTYPE:
Further, the information for this is sent in a single composite number, something like:
10Y754235FUYJ9
Requiring the final input of data to be:
SN:10Y75423
MACHTYPE:UYJ9
The first 4 digits of the composite are the MACHTYPE and the final 8 are the Serial Number.
The impasse I've reached is I can't seem to get auto-fill to replicate the skipping of lines as I've formatted. It will jump a number of lines equal to however many I've selected.
Any ideas about getting it to replicate the first four Formatted Data? I've been throwing myself at this for a couple hours now.
Thanks in advance!
I think you're over complicating it by using two rows for the Formatted Data. I'd wrap the text (Home tab > Alignment section) for the cells in column F and use the following formula to insert a new line:
=CONCATENATE("SN:",B1,CHAR(10),"MATCHTYPE:",C1)
Then just leave the formatting like you had it by row...
Okay, let's focus on the title. When A1 is 10Y754235FUYJ9,
="SN:"&LEFT(A1,8)&CHAR(10)&"MATCHTYPE:"&RIGHT(A1,4)
will give you the output:
SN:10Y75423
MATCHTYPE:UYJ9
And don't forget to set the wrap text checked at Format Cells menu.
Captain Morgan ------ Insane Journeys -------- A-
I have easily gotten the left and right side parts using Left() and Right() functions.
I want to use a function in excel (not vba) that will allow me to get the middle phrase in this sentence (The dashes are really excessive spaces). can I accomplish this with a Mid() function?
This is just 1 item on a list of 80 different things in 1 column that needs to be turned into 3 columns. Every item has different character lengths. So the length counts cannot be manually entered.
I agree with Text to Columns but the image in the other answer only has one space per row while OP has some spaces that are redundant and some that are not. For this I’d suggest a modified approach:
Replace all pairs of spaces with a character unlikely to be encountered – I’d suggest a pipe.
Apply Text to Columns with pipe as delimiter.
Apply TRIM to the middle column to remove any remaining redundant spaces (eg =TRIM(B1) copied down and then that column pasted as values over the source).
But to answer can I accomplish this with a Mid() function? I think yes though not cost effective for a mere 80 entries when there is a viable alternative.
Try to use "Text to columns" from Data Tab. It has option to split data to different columns using various criteria.
All you need to do is select data you want to split to columns and select criteria you need.
In your case it can be either Space or Other:. When you select Other: you can add your own criteria like "space dot space" or anything you need.
For more detailed information you can enter this link.
I've got a long list of codes and text in the same cell. I need to return all the text from the right BUT the first five characters
ex. V2341 something here
I need to return the something here
=RIGHT(LEN(A1)-5)
That's what I've tried, but no luck with it. I know it's gotta be close to correct, what am I missing?
Thanks.
You're looking for MID.
If column A contains
A C D
==================== ====================== ==============
1 ABCDE12345 D1=MID(A1, 6, LEN(A1)) 12345
2 ABCDE1234567890ABCD D2=MID(A2, 6, LEN(A2)) 1234567890ABCD
REPLACE function can also be used to replace a designated number of characters with nothing, i.e.
=REPLACE(A1,1,5,"")
You can also select the whole column, use ctrl+f, then find and replace the 'v' with nothing. This will work easily if you have the same first amounts you are trying to get rid of.
If you are trying to get rid of the same number of characters, but they are different characters, you can go to Data -> Text to Columns (in Data Tools Sections). Then select the radio button fixed width. Click Next. Move the line in the graphic to the position you want it in, click Finish.
There are many, many questions and quality answers on SO regarding how to prevent leading zeroes from getting stripped when importing to or exporting from Excel. However, I already have a spreadsheet that has values in it that were truncated as numbers when, in fact, they should have been handled as strings. I need to clean up the data and add the leading zeros back in.
There is a field that should be four characters with lead zeros padding out the string to four characters. However:
"23" should be "0023",
"245" should be "0245", and
"3829" should remain "3829"
Question: Is there an Excel formula to pad these 0's back onto these values so that they are all four characters?
Note: this is similar to the age old Zip Code problem where New England-area zip codes get their leading zero dropped and you have to add them back in.
=TEXT(A1,"0000")
However the TEXT function is able to do other fancy stuff like date formating, aswell.
The more efficient (less obtrusive) way of doing this is through custom formatting.
Highlight the column/array you want to style.
Click ctrl + 1 or Format -> Format Cells.
In the Number tab, choose Custom.
Set the Custom formatting to 000#. (zero zero zero #)
Note that this does not actually change the value of the cell. It only displays the leading zeroes in the worksheet.
I hit this page trying to pad hexadecimal values when I realized that DEC2HEX() provides that very feature for free.
You just need to add a second parameter. For example, tying to turn 12 into 0C
DEC2HEX(12,2) => 0C
DEC2HEX(12,4) => 000C
... and so on
I know this was answered a while ago but just chiming with a simple solution here that I am surprised wasn't mentioned.
=RIGHT("0000" & A1, 4)
Whenever I need to pad I use something like the above. Personally I find it the simplest solution and easier to read.
I am not sure if this is new in Excel 2013, but if you right-click on the column and say "Special" there is actually a pre-defined option for ZIP Code and ZIP Code + 4. Magic.
If you use custom formatting and need to concatenate those values elsewhere, you can copy them and Paste Special --> Values elsewhere in the sheet (or on a different sheet), then concatenate those values.
Even this will work nicely
REPT(0,2-LEN(F2)&F2
where 2 is total number of digits, for 0 ~ 9 -> it will display 00 to 09 rest nothing will be added.
Assuming that the number you want to pad is in cell A1, and the "padding number of zeros" is 4 ,
e.g.
"23" should be "0023",
"245" should be "0245", and
"3829" should remain "3829"
then
=TEXT(A1,REPT("0",4))