I have a calculated value (in column H) which gives the number of trailing 0s I'd like to trim from the right of a cell (column E). But I only want to remove 0s; if there are other characters they should remain.
Examples:
E | H | Output
--+---------+--------
3 | 0110A00 | 0110A
3 | 0110A0B | 0110A0B
1 | 0110A00 | 0110A0
Any ideas? I'd like to avoid macros or masses of nested IFs if possible.
Use:
=LEFT(H1,MAX(AGGREGATE(14,6,ROW(INDEX(A:A,1):INDEX(A:A,LEN(H1)))/(MID(H1,ROW(INDEX(A:A,1):INDEX(A:A,LEN(H1))),1)<>"0"),1),LEN(H1)-E1))
Related
I am having a small issue with writing a formula. I have my data in this format :
NAME | EXP | SALARY
A | 0.3 | 40000
B | 4.7 | 490000
C | 2.6 | 220000
D | 3.9 | 34000
E | 1.3 | 150000
F | 3.2 | 300000
G | 0.8 | 90000
H | 1.9 | 170000
I | 2.1 | 260000
J | 4.1 | 390000
this is what i want in my output :
EXP-RANGE | MIN SALARY | MAX SALARY
0-1
1-2
2-3
3-4
4-5
i want to find the minimum and maximum salary of people in the experience range
i tried using MIN(IF(<&>)) but it returns #VALUE?
i can also push all this data in to a Database and query it but I would greatly appreciate anyone who could formulate it so that i can work on Excel itself. Data size is 20000+ so i wouldn't prefer filters
Thanks in advance
Use MAXIFS and MINIFS:
=MINIFS(C:C,B:B,">="&LEFT(G2,FIND("-",G2)-1),B:B,"<"&MID(G2,FIND("-",G2)+1,LEN(G2)))
=MAXIFS(C:C,B:B,">="&LEFT(G2,FIND("-",G2)-1),B:B,"<"&MID(G2,FIND("-",G2)+1,LEN(G2)))
If one does not have MAXIFS or MINIFS we can use AGGREGATE:
=AGGREGATE(15,7,$C$2:$C$11/(($B$2:$B$11>=--LEFT(G2,FIND("-",G2)-1))*($B$2:$B$11<--MID(G2,FIND("-",G2)+1,LEN(G2)))),1)
=AGGREGATE(14,7,$C$2:$C$11/(($B$2:$B$11>=--LEFT(G2,FIND("-",G2)-1))*($B$2:$B$11<--MID(G2,FIND("-",G2)+1,LEN(G2)))),1)
AGGREGATE is an array type formula and the references should be limited to the data set.
Assume "Lookup table" put in A1:C11
Criteria with header in G1:G6
In H2 (Min wage), formula copied right to I2(Max wage) and all copied down:
=AGGREGATE(14+(COLUMN(A1)=1),6,$C$2:$C$11/($B$2:$B$11>=IMREAL($G2&"i"))/($B$2:$B$11<-IMAGINARY($G2&"i")),1)
Edit : In convert the criteria "0-1" to complex number "0-1i", the IMREAL() extract the left side number "0", and the IMAGINARY() extract the right side number "1"
=AGGREGATE(14+(COLUMN(A1)=1),6,..., return in Column K =AGGREGATE(15,6,….) and column L =AGGREGATE(14,6,….)
So for example purposes, I have the following table:
| | A | B |
| |------------|----------|
| 1 |Description |Amount |
| 2 |------------|----------|
| 3 |Item1 | 5.00|
| 4 |Item2** | 29.00|
| 5 |Item3 | 1.00|
| 6 |Item4** | 5.00|
| 7 |------------|----------|
| 8 |Star Total | 34.00|
| 9 |------------|----------|
I want to create a formula in B8 that calculates the sum of the amounts if the description of that amount contains "**" (or some other denoting text). In this particular example I would like a formula that returns 34 since only Item2 and Item4 contain "**".
I tried to use something like this, but it only worked based on the value in A3:
=SUMIF(A3:A6, ISNUMBER(SEARCH("**", A3)), B3:B6)
Any suggestions would be appreciated!
The asterisk is the wildcard symbol that can be used in Sumif(), so you may want to change the denoting text to some other symbols, for example ##. Then this formula will work:
=SUMIF(A2:A10,"*##*",B2:B10)
If you want to keep the asterisks, the formula gets a bit curlier.
=SUMIF(A2:A10,"*~*~**",B2:B10)
The two middle asterisks are escaped with the tilde character.
You can escape the wildcard character and turn it into a literal * by prefixing it with a swung dash (tilde, ~) and so leave your data unchanged:
=SUMIF(A2:A7,"*~*~*",B2:B7)
IMO worthwhile because astrisks are relatively 'elegant'.
Am encountered an issue on openOffice Calc.
I need to get a range of values from a formula, that can be used in a dropdownlist/validity.
I have a sheet with following data.
A B C
+---------------
1 | 10 x
2 | 20 x
3 | 30 y
4 | 40 z
5 | 50 x
6 |---------------
Here I need a list of values of 'A' where values 'B' equals 'x'.
I have checked with LOOKUP/INDEX functions, but it returns a single value(first occurrence) not a range.
Try this formula:
=IFERROR(INDEX($A$1:$A$5, SMALL(IF($B$1:$B$5="x",ROW($B$1:$B$5),9^99),ROW())),"")
^-------^ ^-------^ ^ ^-------^ ^--^
| | | | +-> Random big number
| | | +-> Range to check
| | +-> Value to check
| +-> Range to check
+-> Range to return
You'll need to use Ctrl+Shift+Enter to make it work, then drag the formula down.
If you start on row 2, you'll have to use ROW()-1 for it to work. It's generally ROW()-(k-1) where k is the row number you're using the formula first.
Consider the following (partial) Excel worksheet:
A | B | C | D
---+-------------+-------+-------
id | date | var_a | var_b
1 | 2011-03-12 | 200 | 34.22
1 | 2011-03-13 | 203 | 35.13
1 | 2011-03-14 | 205 | 34.14
1 | 2011-03-15 | 207 | 54.88
1 | 2011-03-16 | 208 | 12.01
1 | 2011-03-18 | 203 | 76.10
1 | 2011-03-19 | 210 | 14.86
1 | 2011-03-20 | 200 | 25.45
. | . | . | .
. | . | . | .
2 | 2011-03-12 | 200 | 34.22
2 | 2011-03-13 | 203 | 35.13
2 | 2011-03-14 | 205 | 34.14
2 | 2011-03-15 | 207 | 54.88
2 | 2011-03-16 | 208 | 12.01
2 | 2011-03-18 | 203 | 76.10
2 | 2011-03-19 | 210 | 14.86
2 | 2011-03-20 | 200 | 25.45
. | . | . | .
. | . | . | .
In reality, there are over 5.000 rows. I need to delete all rows which date falls on a saturday or sunday. In the example, March 12 and 13 (2011-03-12/13) and March 19 and 20 are Saturdays and Sundays. I cannot just delete every nth rows, since there might be days missing in the list (as is the case here with 2011-03-17).
Is this possible to do with either a formula or VBScript? I have never written a VBScript macro before (I have never had a use for it) so I would appreciate some help.
If you only need to do this once, this is what I would do. This should preserve the order, but if you're really worried about it, read very end of the post:
Add a new column, call it "Is Weekend". In it, put =if(WEEKDAY(B2, 2) > 5, 1, 0). Drag that formula down for the entire table.
Filter the columns. To do that, select the entire table (click on any table cell then hit Ctrl-A), then
On Excel 2007+, go to Data-> click "Filter"
On Excel 2003, go to Data->Filter->Auto Filter.
Sort everything by last column (Is Weekend) in descending order. This should put all weekend rows together without altering the order among the other rows.
Delete all rows with 1 in "Is Weeked" column. Delete that column.
If you're really worried about preserving order, before you do the above, you can do the following:
Add a new column called "Position". Put 1 in the first row, 2 in the second row, select them and drag it down to the bottom so every row has its own position number in increasing order.
Perform the filtering as above.
After you're done, sort everything in ascending order by "Position" column.
The trick is that you don't need to delete those rows, you need to replace their values for C and D with 0. This is easiest done with IF() and WEEKDAY() within two new columns C' and D' referencing C and D. Feel free to then just delete C and D.
You can do this in one go using an array formula. In cell E2, enter the following formula (on one line), and confirm with Ctrl-Shift-Enter (as opposed to the regular Enter)
=INDEX($A$2:$D$5000, SMALL(IF(WEEKDAY($B$2:$B$5000,2)>5, "",
ROW($B$2:$B$5000)-MIN(ROW($B$2:$B$5000))+1), ROW(A1)),COLUMN(A1))
5000 indicates the number of rows in your spreadsheet. After this, the formula should have curly braces around it to indicate it is an array formula. E2 should have the value 1. Then select cell E2 and drag the lower-right corner of the cell to the right until 4 cells are covered. Then drag the lower-right corner of the 4-cell-selection all the way down. At the bottom you will see rows containing #NUM!, one for each deleted row. You can delete those in the regular way.
In stead of starting off in cell E2, you could start off in cell A2 of a new sheet. In that case, you need to prepend the original sheet name to each reference in the formula, as in OriginalSheet!$A$2
This formula is an adaption from the one given in Excel: Remove blank cells
In case you decide to delete the rows, please make sure to run the VBA code from the last row to the first row. Here is a piece of code just written from memory to show you the idea of running from bottom to the top.
For i = Selection.Rows.Count To 1 Step -1
If WEEKDAY(Cells(r, 2),2) > 5 Then
Selection.Rows(i).EntireRow.Delete
End If
Next i
I have a table of people with points. The more points, the higher your position. If you have the same points you are equal first, second etc.
| A | B | C
1 | name | position | points
2 | person1 | 1 | 10
3 | person2 | 2 | 9
4 | person3 | 2 | 9
5 | person4 | 2 | 9
6 | person5 | 5 | 8
7 | person6 | 6 | 7
Using an Excel formula, how can I automatically determine the position? I'm currently using an IF statement that works fine for 5 or 6 matching positions, but I can't add 30+ if statements because there's a limit to the formula.
=IF(C7=C2,B2,IF(C7=C3,B2+5,IF(C7=C4,B3+4,....
So if the points column is the same as the position above then it's the same position value. If the points are less than above then it drops a position so the previous row position +1. But if the row above that is the same then it's the previous position +2 and so on.
You could also use the RANK function
=RANK(C2,$C$2:$C$7,0)
It would return data like your example:
| A | B | C
1 | name | position | points
2 | person1 | 1 | 10
3 | person2 | 2 | 9
4 | person3 | 2 | 9
5 | person4 | 2 | 9
6 | person5 | 5 | 8
7 | person6 | 6 | 7
The 'Points' column needs to be sorted into descending order.
Type this to B3, and then pull it to the rest of the rows:
=IF(C3=C2,B2,B2+COUNTIF($C$1:$C3,C2))
What it does is:
If my points equals the previous points, I have the same position.
Othewise count the players with the same score as the previous one, and add their numbers to the previous player's position.
You can use the RANK function in Excel without necessarily sorting the data. Type =RANK(C2,$C$2:$C$7). Excel will find the relative position of the data in C2 and display the answer. Copy the formula through to C7 by dragging the small node at the right end of the cell cursor.
Try this in your forth column
=COUNTIF(B:B; ">" & B2) + 1
Replace B2 with B3 for next row and so on.
What this does is it counts how many records have more points then current one and then this adds current record position (+1 part).
If your C-column is sorted, you can check whether the current row is equal to your last row. If not, use the current row number as the ranking-position, otherwise use the value from above (value for b3):
=IF(C3=C2, B2, ROW()-1)
You can use the LARGE function to get the n-th highest value in case your C-column is not sorted:
=LARGE(C2:C7,3)
The way I've done this, which is a bit convoluted, is as follows:
Sort rows by the points in descending order
Create an additional column (D) starting at D2 with numbers 1,2,3,... total number of positions
In the cell for the actual positions (D2) use the formula if(C2=C1), D2, C1). This checks if the points in this row are the same as the points in the previous row. If it is it gives you the position of the previous row, otherwise it uses the value from column D and thus handle people with equal positions.
Copy this formula down the entire column
Copy the positions column(C), then paste special >> values to overwrite the formula with positions
Resort the rows to their original order
That's worked for me! If there's a better way I'd love to know it!