i wanna search for the catalogs which have the "program" in their names and echo these names in console. I have wrote this, but isn't working:
find usr -type d -name "program" -exec echo {}
The error is find: missing argument to `-exec'.
find usr -type d -name "program"
usr/lib64/libreofice/program
How to fix my command?
Some tiny example with the * wildcard.
find /my/path -name "*program*"
If you don' use wildcards, it will try to find exactly the files named program. Also, echoing is done automatically, you don't need the exec command.
Update
Answering to your comment. You can get the base name (name without the path) with:
find . -name "*program*" -exec basename {} \;
Related
I am trying to move all files with names starts with SML from directory to another.
Tried with
find /var/.../Images/ -name SML\* mv /var/.../Images/Small but doesnt work
try find /var/.../Images/ -name SML\* -exec mv {} /var/.../Images/Small/ \;
I guess you want something like this:
dir=/path/to/your/Images
mkdir -p "$dir/Small"
find "$dir" -name "SML*" -not -wholename "$dir/Small/*" -exec mv {} "$dir/Small/" \;
Since the directory you move the files to is a subdirectory of the one you seach in, you need to exclude the files already moved there. So I added -not -wholename "$dir/Small/*"
To execute a command for each found file, you need -exec .... The alternative would be to pipe your find results to a while read loop.
When using -exec, the found name can be referenced by {}.
See man find for a lot more information.
I have a find string that finds all the instances of a particular filename in a path, like so:
find /opt/logs* -type f -name "deploy.log" -exec ls {} \;
I need to return the result with 'FINENAME=' prepended on each line. Having a hard time figuring the best way.
find /opt/logs* -type f -name deploy.log | sed 's/^/FILENAME=/'
Note that if you have a directory named /opt/logs (and you're not trying to look in /opt/logs-foo/ and /opt/logs-date, or the like) you can drop the * and write find /opt/logs -type ...
Use the -printf option:
find /opt/logs* -type f -name "deploy.log" -printf='FILENAME=%p\n'
%p will get expanded to the file's name.
I just started to study Bash. I want to do a script to find some specific folders in a directory and its subdirectories and if it exist, rename it into the same folder where we have found it. The same specific folder can be in some subdirectories.
I use this:
file=`find . -name a`
if [ -d $file ]
then
rename 's/a/b/' $file
fi
But don't work. Is there anyway to do this process?
Thanks.
Finally, i solved the problem with this:
find . -name "a" -type d -execdir rename 's/a/b/' {} \; &>/dev/null
You can do this with oneliner:
find . -name "a" -type d -execdir rename 's/a/b/' {} \;
The parameter to name might be regex.
With -type d it will find all directories.
-execdir changes to a matching item's directory and then executes the rename command, passing the filename of the item at hand as an argument ({}).
OK, probably a stupid question, but why doesn't this work?
find . -name Orna* -ls
It seems that "find" should be able to handle this simple request... Am I missing something here? This should be a basic execution of the "find" command, but linux is being stupid, or maybe I am.
correct way of using Find Command are the following phrases
find . -type f -name "filename" # this command used to find files from the curent dir
find . -type d -name "dir name" # this command used to find dirs from the curent dir
find /. -type f -name "filename" # this command used to find files from the system
find /. -type d -name "dir name" # this command used to find dirs from the system
I wish it be a helpful for you
You need to quote the name parameter so the shell doesn't expand the wildcard, e.g.
find . -name "Orna*" -ls
To explain the "why" a little more than existing answers do -- wildcards are expanded by the shell before the command being invoked is run. Thus, let's say your current directory contains files Orna1 and Orna2.
In that case, when you run
find . -name Orna* -ls
...what's actually invoked by the shell is:
find . -name Orna1 Orna2 -ls
...thus, find never sees the wildcard expression at all!
Quoting the expansion, as in:
find . -name 'Orna*' -ls
...prevents the shell from trying to expand the wildcard before running your command, thus preventing this issue.
How do I get the name of a folder from a linux find commnad.
I have a command like this:
find /root/wgetlog -name -type d -empty
Whic produces the following results:
/root/wgetlog/smil3
/root/wgetlog/smil5
/root/wgetlog/smil4
how do I get just the name of the folder:
Example:
smil3
smil4
smil5
find /root/wgetlog -type d -empty -printf "%f\n"
If all you need is a relative path, then
{ pushd /root/wgetlog/; find . -name -type d -empty; popd; }
is the approach, especially if you do care about subdirectories of /root/wgetlog/*.
Use basename:
find /root/wgetlog -type d -empty -exec basename {} \;
You don't need -name.
You could also use sed to filter out the leading elements of each path:
$ find /usr/bin -type d
/usr/bin
/usr/bin/multiarch-i386-linux
/usr/bin/multiarch-x86_64-linux
/usr/bin/gda_trml2pdf
/usr/bin/gda_trml2html
...
$ find /usr/bin -type d | sed 's|.*/||'
bin
multiarch-i386-linux
multiarch-x86_64-linux
gda_trml2pdf
gda_trml2html
...
This might be more portable than using the -printf option of find, although that should not be an issue if you stick to Linux.
Disclaimer: this will fail horribly if you have newlines in your file/folder names. On the other hand, this snippet is probably not the only thing that would fail in that case...