Python with Flask
This is my code:
word=input("Type Something: ")
listofwords=word.split()
wordfreq = []
for w in listofwords:
wordfreq.append(listofwords.count(w))
print("Word: "+str(listofwords)+ "\n")
print("Count: "+str(wordfreq) + "\n")
My code works fine. My only problem is that it prints it out horizontally:
Word: ['is', 'the', 'bus', 'at', 'the', 'terminal']
Count: [1, 2, 1, 1, 2, 1]
How do I have my results printout vertically like this:
Word Count
"is" 1
"the" 2
"bus" 1
"at" 1
"the" 2
"terminal" 1
Also, which parts of my code should I put under "tr" and "td" in the table section of my html. I already have Word and Count under "th" and it works fine.
In python 3.x: You must call additional the function:
print()
For example:
for w in listofwords:
wordfreq.append(listofwords.count(w))
print("Word: "+str(listofwords))
print()
print("Count: "+str(wordfreq))
print()
More information you can get here.
Related
I have an assignment where If I input a string for example
food food games hi food
it would print out like this:
food: 3
games: 1
hi: 1
the code I made right now is
def count_word(string1):
counts = {}
words = string1.split()
for word in words:
if word in counts:
counts[word] += 1
else:
counts[word] = 1
return counts
string1 = str(input())
print(count_word(string1))
If I input the same string as above it prints out:
{'food': 3, 'games': 1, 'hi': 1}
how do I make it so it prints out like this:
food: 3
games: 1
hi: 1
Following should work:
d = {'food': 3, 'games': 1, 'hi': 1} # generated by counter function
for word, count in d.items():
print(f'{word}: {count}')
if you want this sorted alphabetically replace d.items() with sorted(d.items()).
dsic = {'food': 3, 'games': 1, 'hi': 1}
you could try somthing like this maybe:
import json
print(json.dumps(dsic, sort_keys=False, indent=4))
or this one:
for i,x in dsic.items():
print(str(i)+': ' + str(x))
You should do your research before posting on stackoverflow.
For now, Hint is to use two loops. One for the list and one for printing the string.
I'm trying to find a way to iterate through a text file and list to find character frequency. I understand that I could use Count() for this. But Count() gives everything including spaces periods and whatnots. Also it does not show the character frequency in alphabetical order. I found a way to do it and it works but not really. I'll explain later. Also when I try to put the frequency I get a KeyError. I'll also explain.
I don't want to put my whole project on here so I'll explain some stuff first. I have a separate list called alphabet_list which includes the alphabet. There's a text file that is already read through and converted into uppercase called new_text.
Character frequency Code:
for i in range(len(alphabet_list)):
for c in new_text:
if c == alphabet_list[i]:
count += 1
else:
count = 0
print(alphbet_list[i] + " " + str(count)
i += 1
Output
A 0
A 0
.
.
.
A 1
A 0
.
.
.
B 0
.
.
.
B 1
B 2
B 0
.
.
.
Z 0
P.S the str(count) is temporarily there because I want to see how it looks like print out, I needed to store the result in dictionary
My output would be that, like I said it works but not really. It will iterate but it iterates through every letter and prints out the result already and does not iterate the whole text file and just print final result. It will add to the result if there is another letter same as before right next to each other. Ex (... bb...) it will be B 1, B 2 like shown in my output. And for some reason when I use return it doesn't work. It returns nothing and just ends the program.
Second Code with KeyError:
I skipped the problem on top because I couldn't find the answer and didn't want to waste my time but ran into another problem lol*
for i in range(len(alphabet_list)):
for c in new_text:
if c == alphabet_list[i]:
count += 1
else:
count = 0
c_freq[alphabet_list[i]] == count
print(c_freq)
i += 1
This one was pretty simple I got a KeyError: 'A'.
I tried only doing the
i = 3 #just random number to test
count = 50
c_freq[alphabet_list[i]] == count
print(c_freq)
and it works, so I'm thinking that problem is also related to the problem above(? maybe). Anyways any help would be great. Thanks!
Sorry for long question but I really needed help.
This should help you:
lst = ['A', 'Z', 'H', 'A', 'B', 'N', 'H', 'Y', '.' , ',','Z'] #Initial list. Note: The list also includes characters such as commas and full stops.
alpha_dict = {}
for ch in lst:
if ch.isalpha(): #Checks if the character is an alphabet
if ch in alpha_dict.keys():
alpha_dict[ch] += 1 #If key already exists, value is incremented by 1
else:
alpha_dict[ch] = 1 #If key does not exist, a new key is created with value 1
print(alpha_dict)
Output:
{'A': 2, 'Z': 2, 'H': 2, 'B': 1, 'N': 1, 'Y': 1}
Since you want the output to be sorted in alphabetical order, add these lines to your code:
key_list = list(alpha_dict.keys()) #Creates a list of all the keys in the dict
key_list.sort() #Sorts the list in alphabetical order
final_dict = {}
for key in key_list:
final_dict[key] = alpha_dict[key]
print(final_dict)
Output:
{'A': 2, 'B': 1, 'H': 2, 'N': 1, 'Y': 1, 'Z': 2}
Thus, here is the final code:
lst = ['A', 'Z', 'H', 'A', 'B', 'N', 'H', 'Y', '.' , ',','Z']
alpha_dict = {}
for ch in lst:
if ch.isalpha():
if ch in alpha_dict.keys():
alpha_dict[ch] += 1
else:
alpha_dict[ch] = 1
key_list = list(alpha_dict.keys())
key_list.sort()
final_dict = {}
for key in key_list:
final_dict[key] = alpha_dict[key]
print(final_dict)
Output:
{'A': 2, 'B': 1, 'H': 2, 'N': 1, 'Y': 1, 'Z': 2}
I've been trying to solve this homework problem for days, but can't seem to fix it. I started my study halfway through the first semester, so I can't ask the teacher yet and I hope you guys can help me. It's not for grades, I just want to know how.
I need to write a program that reads a string and converts the triplets abc into bca. Per group of three you need to do this. For examplekatzonbecomesatkonz`.
The closest I've gotten is this:
string=(input("Give a string: "))
for i in range(0, len(string)-2):
a = string[i]
b = string[i + 1]
c = string[i + 2]
new_string= b, c, a
i+=3
print(new_string)
The output is:
('a', 't', 'k')
('t', 'z', 'a')
('z', 'o', 't')
('o', 'n', 'z')
The code below converts for example "abc" to "bca". It works for any string containing triplets. Now, if input is "abcd", it is converted to "bcad". If you input "katzon", it is converted to "atkonz". This is what I understood from your question.
stringX = input()
# create list of words in the string
listX = stringX.split(" ")
listY = []
# create list of triplets and non-triplets
for word in listX:
listY += [[word[i:i+3] for i in range(0, len(word), 3)]]
# convert triplets, for example: "abc" -> "bca"
for listZ in listY:
for item in listZ:
if len(item)==3:
listZ[listZ.index(item)] = listZ[listZ.index(item)][1:] + listZ[listZ.index(item)][0]
listY[listY.index(listZ)] = "".join(listZ)
# create final string
stringY = " ".join(listY)
print(stringY)
Q)After executing the code Need to print the values [1, 12, 123, 2, 23, 3, 13], but iam getting [1, 12, 123, 2, 23, 3]. I have missing the letter 13. can any one tell me the reason to overcome that error?
def get_all_substrings(string):
length = len(string)
list = []
for i in range(length):
for j in range(i,length):
list.append(string[i:j+1])
return list
values = get_all_substrings('123')
results = list(map(int, values))
print(results)
count = 0
for i in results:
if i > 1 :
if (i % 2) != 0:
count += 1
print(count)
Pretty straight forward issue in your nested for loops within get_all_substrings(), lets walk it!
You are iterating over each element of your string 123:
for i in range(length) # we know length to be 3, so range is 0, 1, 2
You then iterate each subsequent element from the current i:
for j in range(i,length)
Finally you append a string from position i to j+1 using the slice operator:
list.append(string[i:j+1])
But what exactly is happening? Well we can step through further!
The first value of i is 0, so lets skip the first for, go to the second:
for j in range(0, 3): # i.e. the whole string!
# you would eventually execute all of the following
list.append(string[0:0 + 1]) # '1'
list.append(string[0:1 + 1]) # '12'
list.append(string[0:2 + 1]) # '123'
# but wait...were is '13'???? (this is your hint!)
The next value of i is 1:
for j in range(1, 3):
# you would eventually execute all of the following
list.append(string[1:1 + 1]) # '2'
list.append(string[1:2 + 1]) # '23'
# notice how we are only grabbing values of position i or more?
Finally you get to i is 2:
for j in range(2, 3): # i.e. the whole string!
# you would eventually execute all of the following
list.append(string[2:2 + 1]) # '3'
I've shown you what is happening (as you've asked in your question), I leave it to you to devise your own solution. A couple notes:
You need to look at all index combinations from position i
Dont name objects by their type (i.e. dont name a list object list)
I would try something like this using itertools and powerset() recipe
from itertools import chain, combinations
def powerset(iterable):
s = list(iterable)
return chain.from_iterable(combinations(s, r) for r in range(len(s) + 1))
output = list(map(''.join, powerset('123')))
output.pop(0)
Here is another option, using combinations
from itertools import combinations
def get_sub_ints(raw):
return [''.join(sub) for i in range(1, len(raw) + 1) for sub in combinations(raw, i)]
if __name__ == '__main__':
print(get_sub_ints('123'))
>>> ['1', '2', '3', '12', '13', '23', '123']
I need to insert a number (user input) as an integer to a Python list.
My code:
count = 0
list1 = []
for number in input():
if number != ' ':
list1.append(int(number))
Input: 10 11 12
Output: [1, 0, 1, 1, 1, 2]
Expected Output: [10, 11, 12]
Looping over a string (such as the one returned by input()) will loop over the individual characters in the string:
>>> s = 'hi guys'
>>> for char in s:
... print(char)
...
h
i
g
u
y
s
>>>
To loop over the "words" (i.e. substrings separated by spaces), you want to split() the user's input instead:
>>> s = 'hi guys'
>>> words = s.split()
>>> words
['hi', 'guys']
>>> for word in words:
... print(word)
...
hi
guys
>>>
So in your case, that would be:
for number in input().split():
list1.append(int(number))
We can leave the if number != ' ': out because split() already gets rid of all the spaces and simply returns a list of the numbers.
Here You Go
input_array = []
c_input = input('please enter the input\n')
for item in c_input.split():
input_array.append(int(item))
print (input_array)
input: - 1 11 23 23 456
Output:- [1, 11, 23, 23, 456]
i hope you find it useful
You should use split method to split the values as a list with string:
str_nums = input.split() #will give ['10','11','12']
then
lst_nums = []
for i in str_nums.split():
lst_nums.append(int(i))
print(lst_nums)
#output [10,11,12]
You can also use map and split together.
inp = "10 11 12"
print(list(map(int,inp.split(" "))))
#Output
[10,11,12]
Or
print([int(i) for i in input().split()])