Python 3: How to exit loop without stopping function - python-3.x

Question

I am a complete newbie and have tried solving this problem (with my own head and with online research) for the last 5 hours.
Below is a snippet of a function we have written to simulate a game. We want to offer the ooportunity to start a new round - meaning if a player hits "b", the game should start again at the beginning of the range (0, players). But right now it just goes onto the next player in the range (if player 1 enters "b", the program calls player 2)
players = input(4)
if players in range(3, 9):
for player in range(0, players):
sum_points = 0
throw_per_player_counter = 0
print("\nIt is player no.", player+1, "'s turn!\n")
print("\nPress 'return' to roll the dice.\n"
"To start a new round press 'b'.\n"
"Player", player+1)
roll_dice = input(">>> ")
if roll_dice == "b":
player = 0
throw_per_player_counter = 0
sum_points = 0
print("\n * A new round was started. * \n")
I have tried return and break, also tried to put it all in another while-loop... failed. Break and return just ended the function.
Any hints highly appreciated!

Answer 1

you could change the for loop to a while loop. instead of using a range, make player a counter
players = 4
if 3 <= players < 9:
player = 0 # here's where you make your counter
while player < players:
sum_points = 0
throw_per_player_counter = 0
print("\nIt is player no.", player+1, "'s turn!\n")
print("\nPress 'return' to roll the dice.\n"
"To start a new round press 'b'.\n"
"Player", player+1)
roll_dice = input(">>> ")
player += 1 # increment it
if roll_dice == "b":
player = 0 # now your reset should work
throw_per_player_counter = 0
sum_points = 0
print("\n * A new round was started. * \n")