Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 5 years ago.
Improve this question
Given the list of lists duplicates = [[1,1,1],[2],[1,1,1]]
How to remove the duplicates so that the result is [[2]]?
Like this:
Data.MultiSet> [a | (a, 1) <- toOccurList (fromList [[1,1,1],[2],[1,1,1]])]
[[2]]
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 9 days ago.
Improve this question
https://scratch.mit.edu/projects/editor/?tutorial=getStarted
Here is a drag and drop feature, which is I would like to implement in my game.
What I have to do for this.
Now, I just finished drag function with pixi-viewport.
Closed. This question is opinion-based. It is not currently accepting answers.
Want to improve this question? Update the question so it can be answered with facts and citations by editing this post.
Closed 10 months ago.
Improve this question
instance Monad M where
m >>= k = ...
Also is there a name for functions which are used as this second argument to bind?
Answered in the comments
I'd guess that k stands for something like "kontinue with the kontinuation k
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 2 years ago.
Improve this question
I have this file name:
ABCD1B02.C50.N1995009.2019353.dat
I would like to extract the final 7 numbers and put space like this
extr=2019 353;
In bash script:
fname='ABCD1B02.C50.N1995009.2019353.dat'
extr="${fname:${#fname}-11:4} ${fname:${#fname}-7:3}"
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 3 years ago.
Improve this question
I am trying to speed up my calculator. How would i got about that?
You can't use fib as the name of the function that gets the nth Fibonacci number and the name of the generating list.
This should work:
fibList = 0:1:zipWith (+) fibList (tail fibList)
fib n = fibList !! n
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 4 years ago.
Improve this question
What is the simplest way to combine several maps in list elements into one map. For instance: list1 -> list2
def list1 = [[a:'apple'],[b:'orange'],[c:'pear'],[a:'watermelon'],[b:'banana'],[c:'grape'],[a:'lychee'],[b:'guava'],[c:'starfruit']]
def list2 = [[a:'apple', b:'orange', c:'pear'],[a:'watermelon', b:'banana', c:'grape'],[a:'lychee', b:'guava', c:'starfruit']]
Try this:
list1.groupBy{it.values()[0].intdiv(10)}.collect{it.value.collectEntries()}