Related
Summary
I need an array formula that takes a row of data of certain length from Sheet1. For that row, in each column that is not blank, I need to grab the Sheet1 header value for that column and display that data in a continuous row on Sheet2 (without any spaces in between the row's cells).
Background
I have a table of data (employees and industry certifications with expiration date being the table's cell data) on sheet 1, with a row for each employee the spreadsheet is tracking. The certifications are the columns.
We are using this information to link to ID Badge Printer software (Bodno Silver), where we are limited to linking columns of data to a particular textbox.
The problem lies in the fact that not everyone has every certification. The rows are peppered with blanks separating the certifications that each employee does have. While setting up the required text boxes in the badge software template, that each link to a specific column, I quickly realized that since not everyone has every certification if we used the data how it was we would have a bunch of strange looking blanks in between the listed certifications rather than a continuous list.
What I did
My solution to this (which I'm open to a better one if anyone knows of one, other than "use better software"), was to create a new sheet and array formulas that no one would use except for me and the id printer software. This sheet would have a similar data table that took the rows of data interspersed with blank cells between expiration dates, and put the matching column headers for cells that had a date in them into a continuous row of the same maximum length (eliminating the blank cells).
Essentially, this would allow me to circumvent the restrictions of the badge software and each textbox would be MatchedCert1, MatchedCert2, MatchedCert3, etc. up to the original maximum number of certifications.
Pictures are probably better than my words at explaining what I am going for:
Sheet1 (source)
Sheet2 (result)
The array formulas
I worked on this one for a while. What I thought would be a simple INDEX, MATCH, ISBLANK formula (that I could create using the appropriate relative and absolute cell linking) and then expand to the whole sheet turned into a witch hunt and me praying for forgiveness for my sins to all that may be holy. Also a lot of googling.... I realized quickly that this one may not be so simple after all.
Finally, I arrived at the following two array formulas in order to correctly show what I was going for:
First Column of training section
{=IFERROR(INDEX(Sheet1!$E$2:$P3,1,MATCH(FALSE,ISBLANK(Sheet1!E3:Q3),0)),"")}
(easy enough, right? I thought so...)
I felt good about this until I tried to think through what would be required to get the formula to be universal so that I could use it on the entire table.
I feel dirty just putting the following in public, but here goes...
Second column through last column array formula
{=IFNA(INDEX(INDIRECT(ADDRESS(ROW($E$2),(MATCH(E3,Sheet1!$2:$2,0)+1),1,1, "Sheet1")&":"&ADDRESS(ROW(E3),COLUMN($Q3),1)),1,MATCH(FALSE, ISBLANK(INDEX(INDIRECT("Sheet1!"&ADDRESS(ROW(E3),(MATCH(E3,Sheet1!$2:$2,0)+1),1)&":"&ADDRESS(ROW(E3),COLUMN($Q3),1)),0,0)), 0)),"")}
(please don't call the police...)
[ninja edit] While this array formula works for 2nd result column through the final column, it doesn't work if there's not a blank column following the result range. The actual spreadsheet has 4 different groups of certifications that run horizontally, but I was able to just add a blank column in the corresponding data from the other sheet easily enough, so I just let it go. I'd give somebody a nickle for the answer to why that's the case here too [/edit]
Results
The first array formula, and INDEX MATCH using ISBLANK is rather straightforward.
The biggest question for me here, and the thing that drove me absolutely nuts for a couple of days, is why the second array formula requires the additional INDEX function nested inside of the ISBLANK function.
While taking the function apart and experimenting I realized that if I have any INDIRECT reference inside a ISBLANK function, which is itself inside of a MATCH function, the result of the match was ALWAYS 1:
{=MATCH(FALSE,ISBLANK(INDIRECT("$E3:$Q3")), 0)}
The above ALWAYS returns 1, whereas if I put the range in explicitly, the function would work just fine. That wasn't an option for me, since I needed to dynamically return the starting position for the match using the previous cell's address.
However, adding an INDEX function (with a column and row value of 0) to encapsulate the INDIRECT function provides the correct answer. I figured this out just by trial and error.
Questions
Can someone with more knowledge please let me know what is causing this behavior?
As a broader question, given I am limited to using formulas (no VBA), I would also like to know if I'm going about this in the wrong way or if there is a much simpler way of accomplishing this without this behemoth of a formula?
I know this sheet will probably require maintenance in a year - good luck future self!
Put this in E3, Copy over and down
=IFERROR(INDEX(Sheet1!$2:$2,AGGREGATE(15,6,COLUMN(INDEX($E:$P,MATCH($C3,Sheet1!$C:$C,0),0))/(INDEX(Sheet1!$E:$P,MATCH($C3,Sheet1!$C:$C,0),0)<>""),COLUMN(A:A))),"")
As to why your formula is not working, it is too convoluted to parse. One note, unless the sheets is the variable, one should avoid INDIRECT as much as possible. INDEX can almost always be used in its place.
Both INDIRECT and ADDRESS are volatile functions. Volatile functions will re-calculate every time Excel re-calculates, leading to a lot of unnecessary computations.
Not a solution but to answer why you are seeing this behavior:
EDIT: PREVIOUS EXPLANATION WAS JUST PLAIN WRONG
This confused me so, I did a bit of investigation:
I think that your problem is actually coming from the ISBLANK function because it is intended to be used with single values, and cannot handle ranges. Any BLANKs which are returned by functions are only converted to numeric values (0), when the BLANK is returned to (or displayed on) the sheet. If the function is returning to another function, the BLANK value seems to be preserved.
EDIT: ADDING A SOLUTION WITHOUT ARRAY FORMULAS
This is probably more complex than using an array formula... but I strongly dislike them, so do all I can to remove them.
Firstly, I would add an index to your positions in the results sheet:
=IF(F$7>COUNTIFS($F3:$L3,"<>"),
"",
IF(
MINIFS(
$F$7:$L$7,$F$7:$L$7,
">" & IFNA(INDEX($F$7:$L$7,MATCH(E9,$F$2:$L$2,0)),0),
$F3:$L3,
"<>"
)=0,
"",
INDEX(
$F$2:$L$2,
MATCH(
MINIFS(
$F$7:$L$7,$F$7:$L$7,
">" & IFNA(INDEX($F$7:$L$7,MATCH(E9,$F$2:$L$2,0)),0),
$F3:$L3,
"<>"
),
$F$7:$L$7,
0
)
)
)
)
Basically, the formula looks at the cert in the previous cell, and looks for the next, minimum index, greater than that.
I have a bank export of Credit card vendors. As these vary, I use unique strings contained in each to identify them. For example here is a lookup table excerpt.
First Lookup
I then apply a formula =INDEX(First_level,MATCH(TRUE,ISNUMBER(SEARCH(Keywords,C3374)),0)) to produce this:
First calc
I found this formula here https://exceljet.net/formula/get-first-match-cell-contains
Then I reapply the formula to the result ie the First_Level using this formula =INDEX(Second_Level,MATCH(TRUE,ISNUMBER(SEARCH(Frst_Lev_Check,H44)),0)) with this Lookup.
Second Lookup
Most of the time it works, but for this I get the following
Second calc, where the first level classification is correct, but the second level one is completely wrong.
When I've gone into the depths of the formula, the issue is that the Search function is returning the wrong value.
This appears to be a known issue: https://answers.microsoft.com/en-us/msoffice/forum/all/how-to-use-named-range-in-search-function/14c8c989-bed0-48f9-bce0-c0894571b557
Ideas welcome on workarounds/how to solve the problem.
Cheers Jon
Would you consider:
=MATCH("Apple",List)
and
=MATCH("Pear",List)
to return 1 and 2 respectively.
A couple of things in regards to your question:
The correct syntax for search is =SEARCH(find_text,within_text), so the correct formula would be =SEARCH("Pear",List).
The reason why you are getting the #Value is, because you are applying search to a range, but the function is only intended for cells.
The best ways to see if a value exists in a range are the countif and match function:
The countif function shows you how many times the a value is in a range:
The match function shows you in which row the the first value is:
I have been working on this issue for over two hours and I am beginning to question my sanity. I have used vlookup many times in the past, but now it is just not working as expected. I am trying to replicate a LEFT-JOIN (from SQL) in Excel using vlookup.
Here is the formula I am using on cell G2:
Here is the table of all the values I want to lookup values for.
Here is the table I am using as a reference:
I am only searching one column to simplify the example. Cell G2 contains the formula which is applied to the cells under it as well. As you can see from the first image, not only is it not matching but there is some pretty weird behavior going on.
I have removed duplicates for both tables.
I have unformatted the data to plain text values
I have tried this formula on three different computers
Regardless, I keep kept getting the same result! I am starting to lose sanity.
Does anyone have any idea?
Thank you
If you want exact matches, you should be using FALSE as the last parameter
The lookup table must be sorted in ascending order. Cell A369 appears to have a value lower than the row before it, A368. There are several instances of "lower" values occurring after a higher value.
Before you go insane, consider sorting the range $A$368 thru $A$679, and see if that makes a difference.
Otherwise, time to ditch VLOOKUP, and use instead INDEX and MATCH.
Sometimes you can get the #N/A error if your lookup_value isn't "clean". If that's the case, try this formula:
=VLOOKUP(TRIM(CLEAN(A2)),$A$368:$A$697,1,FALSE)
Additionally, your table_array may have "unclean" data, so you'll need to scrub that first before you're able to find a match. To do that, use this array formula, committing it with Ctrl + Shift + Enter:
=VLOOKUP(A2,TRIM(CLEAN($A$368:$A$697)),1,FALSE)
Have you tried doing a MATCH? does it need to be VLOOKUP?
if you are happy using match try:
=IF(MATCH(A2,$A$368:$A$697,0),A2,"NO MATCH")
The vlookup function appears to be broken. It is returning the same value for all lookups, but it should not.
I have it set like so:
=VLOOKUP(A3, Asset_Mapping!A$2:B$673, 1)
Where the lookup value is in the B column and the result is in the A column.
I use the $ so the rows are not auto-updated to A3:B674 etc as I paste the formula down the rows. However, even if I manually enter that formula into the next row, it is not finding the correct value.
IF i remove the "$", the correct values are found for the first rows where the values fall within the modified range (e.g. Asset_Mapping!A3:B674) but eventually as expected it stops finding the values as the range is invalid.
What am I doing incorrectly here? I have formulas set to auto-calculate.
Without testing on your actual data it's hard to confirm this will work but add the false parameter. This will find exact matches and not the first partial match.
=VLOOKUP(A3, Asset_Mapping!A$2:B$673, 1, false)
Collating the points together and clarifying the formula
Parameter 1: The value you are looking for
Parameter 2: The table with the data. First column is the value you are looking for.
Parameter 3: The column number of the value you want to show.
Parameter 4: If you want an exact match or partial match.
#Jeeped made the point of ordering data to get more reliable results. Good advice.
Andres has the right idea, but there is a faster way to fix the problem.
If it is returning the same value over and over again for your whole range, you probably have your Calculation Options set to "Manual".
Go into Formulas on the top ribbon and choose Calculation Options. There, you can change your calc method to "Automatic".
Also lookup value must be in first column.
Where the lookup value is in the B column and the result is in the A column.
VLOOKUP always lookup in the left-most column and returns a value from the column number specified. If you want to reverse the lookup/return order then use INDEX(..., MATCH(...))
=INDEX(Asset_Mapping!A$2:A$673, MATCH(A3, Asset_Mapping!B$2:B$673, 0))
Note that you were using a sorted, binary lookup; I've changed this to an exact match lookup which does not require sorted data.
Just in case adding a solution to this topic.
Don't know why in big tables Vlookup and Index+Match tend to show just the value of the first result in all the other cells.
In my case to fix this, after I've copied the formula in the whole range, I choose any cell containing it, press F2 and then Enter. It kind of forces excel to process everything.
I've been working on this for a week with no results. I've created this same spreadsheet for another apartment community without any issues, but for some reason, I cannot get the proper results in this spreadsheet. I've tried vlookup as well, but that didn't help either. any more advice?
Formula
Result and lookup vectors
Does anyone know the formula to find the value of the last non-empty cell in a column, in Microsoft Excel?
Using following simple formula is much faster
=LOOKUP(2,1/(A:A<>""),A:A)
For Excel 2003:
=LOOKUP(2,1/(A1:A65535<>""),A1:A65535)
It gives you following advantages:
it's not array formula
it's not volatile formula
Explanation:
(A:A<>"") returns array {TRUE,TRUE,..,FALSE,..}
1/(A:A<>"") modifies this array to {1,1,..,#DIV/0!,..}.
Since LOOKUP expects sorted array in ascending order, and taking into account that if the LOOKUP function can not find an exact match, it chooses the largest value in the lookup_range (in our case {1,1,..,#DIV/0!,..}) that is less than or equal to the value (in our case 2), formula finds last 1 in array and returns corresponding value from result_range (third parameter - A:A).
Also little note - above formula doesn't take into account cells with errors (you can see it only if last non empty cell has error). If you want to take them into account, use:
=LOOKUP(2,1/(NOT(ISBLANK(A:A))),A:A)
image below shows the difference:
This works with both text and numbers and doesn't care if there are blank cells, i.e., it will return the last non-blank cell.
It needs to be array-entered, meaning that you press Ctrl-Shift-Enter after you type or paste it in. The below is for column A:
=INDEX(A:A,MAX((A:A<>"")*(ROW(A:A))))
Here is another option: =OFFSET($A$1;COUNTA(A:A)-1;0)
I know this question is old, but I'm not satisfied with the answers provided.
LOOKUP, VLOOKUP and HLOOKUP has performance issues and should really never be used.
Array functions has a lot of overhead and can also have performance issues, so it should only be used as a last resort.
COUNT and COUNTA run into problems if the data is not contiguously non-blank, i.e. you have blank spaces and then data again in the range in question
INDIRECT is volatile so it should only be used as a last resort
OFFSET is volatile so it should only be used as a last resort
any references to the last row or column possible (the 65536th row in Excel 2003, for instance) is not robust and results in extra overhead
This is what I use
when the data type is mixed: =max(MATCH(1E+306,[RANGE],1),MATCH("*",[RANGE],-1))
when it's known that the data contains only numbers: =MATCH(1E+306,[RANGE],1)
when it's known that the data contains only text: =MATCH("*",[RANGE],-1)
MATCH has the lowest overhead and is non-volatile, so if you're working with lots of data this is the best to use.
Inspired by the great lead given by Doug Glancy's answer, I came up with a way to do the same thing without the need of an array-formula. Do not ask me why, but I am keen to avoid the use of array formulae if at all possible (not for any particular reason, it's just my style).
Here it is:
=SUMPRODUCT(MAX(($A:$A<>"")*(ROW(A:A))))
For finding the last non-empty row using Column A as the reference column
=SUMPRODUCT(MAX(($1:$1<>"")*(COLUMN(1:1))))
For finding the last non-empty column using row 1 as the reference row
This can be further utilized in conjunction with the index function to efficiently define dynamic named ranges, but this is something for another post as this is not related to the immediate question addressed herein.
I've tested the above methods with Excel 2010, both "natively" and in "Compatibility Mode" (for older versions of Excel) and they work. Again, with these you do not need to do any of the Ctrl+Shift+Enter. By leveraging the way sumproduct works in Excel we can get our arms around the need to carry array-operations but we do it without an array-formula. I hope someone out there may appreciate the beauty, simplicity and elegance of these proposed sumproduct solutions as much as I do. I do not attest to the memory-efficiency of the above solutions though. Just that they are simple, look beautiful, help the intended purpose and are flexible enough to extend their use to other purposes :)
Hope this helps!
All the best!
This works in Excel 2003 (& later with minor edit, see below). Press Ctrl+Shift+Enter (not just Enter) to enter this as an array formula.
=IF(ISBLANK(A65536),INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535)))),A65536)
Be aware that Excel 2003 is unable to apply an array formula to an entire column. Doing so yields #NUM!; unpredictable results may occur! (EDIT: Conflicting information from Microsoft: The same may or may not be true about Excel 2007; problem may have been fixed in 2010.)
That's why I apply the array formula to range A1:A65535 and give special treatment to the last cell, which is A65536 in Excel 2003. Can't just say A:A or even A1:A65536 as the latter automatically reverts to A:A.
If you're absolutely sure A65536 is blank, then you can skip the IF part:
=INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535))))
Note that if you're using Excel 2007 or 2010, the last row number is 1048576 not 65536, so adjust the above as appropriate.
If there are no blank cells in the middle of your data, then I would just use the simpler formula, =INDEX(A:A,COUNTA(A:A)).
An alternative solution without array formulas, possibly more robust than that of a previous answer with a (hint to a) solution without array formulas, is
=INDEX(A:A,INDEX(MAX(($A:$A<>"")*(ROW(A:A))),0))
See this answer as an example.
Kudos to Brad and barry houdini, who helped solving this question.
Possible reasons for preferring a non-array formula are given in:
An official Microsoft page (look for "Disadvantages of using array formulas").
Array formulas can seem magical, but they also have some disadvantages:
You may occasionally forget to press CTRL+SHIFT+ENTER. Remember to press this key combination whenever you enter or edit an array formula.
Other users may not understand your formulas. Array formulas are relatively undocumented, so if other people need to modify your workbooks, you should either avoid array formulas or make sure those users understand how to change them.
Depending on the processing speed and memory of your computer, large array formulas can slow down calculations.
Array Formula Heresy.
if you search in Column (A) use :
=INDIRECT("A" & SUMPRODUCT(MAX((A:A<>"")*(ROW(A:A)))))
if your range is A1:A10 you can use:
=INDIRECT("A" & SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10)))))
in this formula :
SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10))))
returns last non blank row number ,and indirect() returns cell value.
=INDEX(A:A, COUNTA(A:A), 1) taken from here
=MATCH("*";A1:A10;-1) for textual data
=MATCH(0;A1:A10;-1) for numerical data
Ive tried all the non-volatile versions but Not one version given above has worked.. excel 2003/2007update. Surely this can be done in excel 2003. Not as an array nor standard formula.
I either get just a blank, 0 or #value error.
So I resort to the volatile methods .. This worked..
=LOOKUP(2,1/(T4:T369<>""),T4:T369)
#Julian Kroné .. Using ";" instead of "," does NOT work! I think you are using Libre Office not MS excel?
LOOKUP is so annoyingly volitile I use it as a last resort only
For Microsoft office 2013
"Last but one" of a non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-2,0)
"Last" non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-1,0)
Place this code in a VBA module. Save. Under functions, User defined look for This function.
Function LastNonBlankCell(Range As Excel.Range) As Variant
Application.Volatile
LastNonBlankCell = Range.End(xlDown).Value
End Function
for textual data:
EQUIV("";A1:A10;-1)
for numerical data:
EQUIV(0;A1:A10;-1)
This give you the relative index of the last non empty cell in the range selected (here A1:A10).
If you want to get the value, access it via INDIRECT after building -textually- the absolute cell reference, eg:
INDIRECT("A" & (nb_line_where_your_data_start + EQUIV(...) - 1))
I had the same problem too. This formula also works equally well:-
=INDIRECT(CONCATENATE("$G$",(14+(COUNTA($G$14:$G$65535)-1))))
14 being the row number of the first row in the rows you want to count.
Chronic Clawtooth
I used HLOOKUP
A1 has a date;
A2:A8 has forecasts captured at different times, I want the latest
=Hlookup(a1,a1:a8,count(a2:a8)+1)
This uses a standard hlookup formula with the lookup array defined by the number of entries.
If you know that there are not going to be empty cells in between, the fastest way is this.
=INDIRECT("O"&(COUNT(O:O,"<>""")))
It just counts the non-empty cells and refers to the appropriate cell.
It can be used for a specific range as well.
=INDIRECT("O"&(COUNT(O4:O34,"<>""")+3))
This returns the last non empty cell in the range O4:O34.
This formula worked with me for office 2010:
=LOOKUP(2;1/(A1:A100<>"");A1:A100)
A1: the first cell
A100: refer to the last cell in comparing
I think the response from W5ALIVE is closest to what I use to find the last row of data in a column. Assuming I am looking for the last row with data in Column A, though, I would use the following for the more generic lookup:
=MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0))
The first MATCH will find the last text cell and the second MATCH finds the last numeric cell. The IFERROR function returns zero if the first MATCH finds all numeric cells or if the second match finds all text cells.
Basically this is a slight variation of W5ALIVE's mixed text and number solution.
In testing the timing, this was significantly quicker than the equivalent LOOKUP variations.
To return the actual value of that last cell, I prefer to use indirect cell referencing like this:
=INDIRECT("A"&MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0)))
The method offered by sancho.s is perhaps a cleaner option, but I would modify the portion that finds the row number to this:
=INDEX(MAX((A:A<>"")*(ROW(A:A))),1)
the only difference being that the ",1" returns the first value while the ",0" returns the entire array of values (all but one of which are not needed). I still tend to prefer addressing the cell to the index function there, in other words, returning the cell value with:
=INDIRECT("A"&INDEX(MAX((A:A<>"")*(ROW(A:A))),1))
Great thread!
If you are not afraid to use arrays, then the following is a very simple formula to solve the problem:
=SUM(IF(A:A<>"",1,0))
You must press CTRL + SHIFT + ENTER because this is an array formula.
INDEX returns a value by index position in an array and ROWS then is used to specify the last position of the array.
=LET(array,A1:A10,INDEX(array,ROWS(array)))
Also works for multiple columns when setting the parameter [column_num] of INDEX to 0:
=LET(array,A1:C10,INDEX(array,ROWS(array),0))
A simple one which works for me:
=F7-INDEX(A:A,COUNT(A:A))
Okay, so I had the same issue as the asker, and tried both top answers. But only getting formula errors. Turned out that I needed to exchange the "," to ";" for the formulas to work. I am using XL 2007.
Example:
=LOOKUP(2;1/(A:A<>"");A:A)
or
=INDEX(A:A;MAX((A:A<>"")*(ROW(A:A))))
For version tracking (adding the letter v to the beginning of the number), I found this one to work well in Xcelsius (SAP Dashboards)
="v"&MAX(A2:A500)