I want to retrieve the value of column 2 in x workbook on the basis of 20700 so if I directly give lookup value, formula is working fine but if I replace my lookup value with the range like A2[having the 20700 in A column] so It gives me N/A error.
VLOOKUP(20700,'[X.xlsx]Sheet1'!$A:$B,2,0)- working fine
VLOOKUP(K2,'[X.xlsx]Sheet1'!$A:$B,2,0) - gives error
Kindly suggest me what to do. Thanks in advance.
When Vlookup returns #N/A that means that the lookup value is not found in the first column of the lookup table.
Reasons can be that numbers are stored as text (they look the same, but they are different data types), or leading/trailing spaces, or the numbers have decimals but have been formatted not to show decimals.
If you can type 20700 into the formula and get a result, but plugging in K2 fails, chances are that K2 does NOT contain the NUMBER 20700, but something that just looks like it.
Use a formula like =K2=20700 and if that returns FALSE, it proves my case.
I suggest you check your data for such inconsistencies and clean it up.
Teylyn hit the spot, but in case you can't change k2 for whatever reason, perhaps you could use one of the following to solve your issue.
VLOOKUP(value(K2),'[X.xlsx]Sheet1'!$A:$B,2,0)
VLOOKUP(trim(K2),'[X.xlsx]Sheet1'!$A:$B,2,0)
VLOOKUP(clean(K2),'[X.xlsx]Sheet1'!$A:$B,2,0)
Related
I am trying to write a formula that checks the status and name to be ongoing and joe blogs (in this example), and once finding a match, will identify the oldest date of a ticket raised.
My formula currently includes:
=MIN(IF('Sheet2'!AA:AA="ONGOING",IF('Sheet2'!Q:Q="Joe Bloggs",'Sheet2'!B18:B49)))
I also tried:
=IF((AND(sheet2!$AA:$AA="ongoing", 'Sheet2'!$Q:$Q="Joe Bloggs")), MIN('Sheet2'!B18:B49),"No")
In Column B contains dates. Q contains names, AA contains the status.
At the moment when this runs I get the result '00/01/1990'.
I have done some checks to find the error, and appears to be around the targets name, as when the second formula is tried, the output is "no". The name is definitely in the Q column, and I have completed other formulas including countifs which have worked perfectly fine.
I have done a lot of searching to find nested ifs and min statements to have no joy , would be grateful of any advice / tips. It may be a simple error to some.
Try entering this as an array formula:
=MIN(IF(sheet2!AA:AA="ongoing",IF(sheet2!q:q="Joe Bloggs",sheet2!B:B)))
FYI I found the solution here.
You will have to apply a date format to the result.
Your first formula works well on my data (as below). If I close the formula with ENTER only, I get the result '37128' and if I close the formula with CTRL+SHIFT+ENTER I get the expected result, '25/08/2001'.
Edit: As #FocusWiz said in the comments, the only major difference (other than different column names) between my formula and yours is the the last range in your formula (B18:B49) is a different sized range to the other two, which are referring to full columns.
*This could be solved either by using the same row range for all three column references (AA18:AA49, Q18:Q49, B18:B49) or referencing the full column range for all three ranges (AA:AA,Q:Q,B:B).
This is your formula I'm talking about:
=MIN(IF('Sheet2'!AA:AA="ONGOING",IF('Sheet2'!Q:Q="Joe Bloggs",'Sheet2'!B18:B49)))
And this is the formula in my workbook F7:
=MIN(IF(B:B="ONGOING",IF(A:A="Joe Bloggs",C:C)))
As you can see in the formula editor, squiggly brackets '{}' show around the formula when it has been closed as an array formula.
If that doesn't work for you, please post some sample data with datatypes so we can help figure out what is causing the lookup value to miss the data.
While I like the technique offered by Patrick (I have frequently forgotten an "else" portion of a formula and gotten "false" as a value in a cell but never thought of a use for that...thank you!), I think this question highlights an issue we all can have with array formulas. As girlvsdata indicates, your original formula:
=MIN(IF(Sheet2!AA:AA="ONGOING",IF(Sheet2!Q:Q="Joe Bloggs",Sheet2!B:B)))
(modified above to be more generic for column B) will also work when entered as an array formula.
What likely happened is that somehow the formula got edited and was not re-entered as an array formula.
While I do not dislike array formulas, I do try to avoid them because I have fat fingers and will frequently mess them up by accidentally hitting the wrong key as I am modifying other cells.
Here is an alternative without using an array formula:
=INDEX(LARGE((Sheet2!Q:Q&Sheet2!AA:AA="Joe bloggs"&"ongoing")*(Sheet2!B:B),COUNTIFS(Sheet2!Q:Q,"Joe Bloggs",Sheet2!AA:AA,"ongoing")),1)
What it does is basically create a candidate date value for every row that has "joe bloggs" and "ongoing" which is equal to the date in column B for all such rows. All other rows get a zero candidate date value. The LARGE function takes the smallest nonzero date by counting the n valid candidates with the COUNTIFS function and taking the nth largest such candidate.
I have been working on this issue for over two hours and I am beginning to question my sanity. I have used vlookup many times in the past, but now it is just not working as expected. I am trying to replicate a LEFT-JOIN (from SQL) in Excel using vlookup.
Here is the formula I am using on cell G2:
Here is the table of all the values I want to lookup values for.
Here is the table I am using as a reference:
I am only searching one column to simplify the example. Cell G2 contains the formula which is applied to the cells under it as well. As you can see from the first image, not only is it not matching but there is some pretty weird behavior going on.
I have removed duplicates for both tables.
I have unformatted the data to plain text values
I have tried this formula on three different computers
Regardless, I keep kept getting the same result! I am starting to lose sanity.
Does anyone have any idea?
Thank you
If you want exact matches, you should be using FALSE as the last parameter
The lookup table must be sorted in ascending order. Cell A369 appears to have a value lower than the row before it, A368. There are several instances of "lower" values occurring after a higher value.
Before you go insane, consider sorting the range $A$368 thru $A$679, and see if that makes a difference.
Otherwise, time to ditch VLOOKUP, and use instead INDEX and MATCH.
Sometimes you can get the #N/A error if your lookup_value isn't "clean". If that's the case, try this formula:
=VLOOKUP(TRIM(CLEAN(A2)),$A$368:$A$697,1,FALSE)
Additionally, your table_array may have "unclean" data, so you'll need to scrub that first before you're able to find a match. To do that, use this array formula, committing it with Ctrl + Shift + Enter:
=VLOOKUP(A2,TRIM(CLEAN($A$368:$A$697)),1,FALSE)
Have you tried doing a MATCH? does it need to be VLOOKUP?
if you are happy using match try:
=IF(MATCH(A2,$A$368:$A$697,0),A2,"NO MATCH")
I am working with an excel file and I am trying to "map" some values with the vLookUp function.
The first parameter of the vLookUp function is giving me headaches: The function works with certains values (typed by hand in a text format)...but doesnt work with pre-generated values (the sames ones...but generated from an ERP system..). I checked to make sure that I was looking for "same nature" values ( text vs text ) ...but I can't find out why the first 3 values (typed by hand) are fine... but the last 3 (pre generated) gives me a #N/A error: It has to be a difference of "format" ..but I can't find out where's the difference...
This is the formula used: =VLOOKUP(D1;$A$1:$B$219;2;FALSE)
The actual file
1008600 379.99 1008600 379.99
1008601 379.99 1008601 379.99
1010600 449.99 1010600 449.99
1010601 449.99 1010601 #N/A
1013600 489.99 1013600 #N/A
1014601 509.99 1014601 #N/A
1015600 569.99
1018603 679.99
1019600 809.99
Thank you !
Using this formula will address the issue highlighted by RocketDonkey
=VLOOKUP(TEXT(D1,"#"),$A$1:$B$219,2,FALSE)
The issue is that you haven't converted you values in column A to numbers. Since the first three values in your lookup range are themselves strings, they are matching the stringified numbers.
In order to fix, click on one of the numbers in column A, press Ctrl+Space to select the entire column, and then click on the exclamation mark and select Convert to number:
After that, you'll notice that your previous values now show errors, so follow the same process to conver them to numbers as well. #nutsch's solution is does not require you to modify your data, so if the type of your data is not crucial, that is a good fix as well :)
This has been a major pain for me as well(Excel is full of stupid assumptions). What I do is copy the entire column to a text editor, change the column to match the lookup column, and copy and paste the data back into the column. This has worked well for me.
May I highlight the little noticeable reply that Barry Houdini came with in 2012 above:
=VLOOKUP(D1&"",$A$1:$B$219,2,FALSE)
that really works (for me in Excel 2010), despite you are dealing with Numbers or a mix of Numbers or Text strings.
Cudos to Barry, you are a truely Houdini
I have a list of numbers in a table that I would like to search for and bring back the cell reference of where that number resides. For example the data looks like:
A B C D
1 1 2 3 4
ok it doesn't come out very well as the first one is the row number and then each number below sits under each letter, so C1 would contain '3'....
If I wanted to return the reference number of C1 in a cell I am using the formula of =CELL("address",MATCH(AU14,C1:AG1)) but this just errors. I have tried to put an Index in there too, but I believe that index only works vertically so this bring back a #N/A result.
Can anyone assist as I've wasted too much time on this already! :)
You are indeed missing an INDEX. And INDEX works vertically, horizontally, or both depending on how it's called.
Here is a formula that works for the ranges in the pictures. Should be easy to modify.
Formula in C5
=CELL("address",INDEX(B2:F2,MATCH(C4,B2:F2,0)))
formula
results
To make CELL work you need a cell reference, e.g.
CELL("address",C1)
The trouble is that MATCH just gives you a number, not a cell reference.
Probably the easiest way is to use the ADDRESS function, so a first try might be
=ADDRESS(1,MATCH(AU14,C1:AG1,0)+2)
That would give you the right answer if AU14 contained 3, but isn't considered to be very good because it wouldn't update if you deleted/inserted rows or columns.
A better one would be
=ADDRESS(ROW(C1),MATCH(AU14,C1:AG1,0)+COLUMN(C1)-1)
Then you might want to put in some error handling for the case where it's not found
=IFERROR(ADDRESS(ROW(C1),MATCH(AU14,C1:AG1,0)+COLUMN(C1)-1),"Not found")
In Excel, I have a cell value as number format, say 10/2. It displays as 10/2 but I would like 5.00.
It evaluates to 5.00 if I add an = before it i.e, =10/2, but I don't want to have to edit around 500 rows of that column.
I tried to use VALUE function but it evaluates it to 42279.00:
Cell B1 10/2
Cell B2 42279.00
Another data example is: 100/20.
Can you please tell me what has gone wrong, or is there any approach to get the cell value 10/2 to be evaluated to 5.00?
Please try applying a formula of the following kind to all your data:
=MONTH(B1)/DAY(B1)
Having done so you may select the results, Copy and Paste Special over their source (assumed to be ColumnB) and then delete the formulae.
Excel has, trying to be helpful, interpreted your entries as dates - the above should reverse the coercion.
Since now it seems not all entries have been coerced into dates, I suggest for those that have not:
=LEFT(B1,FIND("/",B1)-1)/MID(B1,FIND("/",B1)+1,LEN(B1))
The problem is that you’re putting in what you’re thinking of as a calculation (ten divided by 2), but you’re not saying it’s a calculation (no “=”) so excel is looking at it as a value. When it looks at “10/2” it thinks “that’s a date, October second!” and it treats it as a date.
Dates are actually kept as numbers. If you had the column formatted as date or general, it could display as a date. But I’m guessing you have the column formatted as a number so it’s giving you the numeric representation of October 2, 2015.
The bad news is that as far as I know you would have to get the “=” in somehow, or do the calculation and replace it with 5 (10 divided by two would never be other than 5. If the latter you could select the column and do a replace 42279 with 5.