I am am new to Linux and have a question about scripts. I am interested to know how you create a new directory and copy all the files (with .txt extension) from the existing directory into it? I am familiar with the mkdir method but I am having trouble when trying to execute it within a script.
I have tried the following but there are errors. Here I am trying to copy the output to a new directory called MyTestFiles.
Any help would be much appreciated.
#!/bin/sh
cp *.[t][x][t] > MyTestFiles
It's called "glob" (to match all files that end with ".txt", for instance):
mkdir MyTextFiles
cp *.txt MyTextFiles/
Also, if you are new to Unix/Linux, man is your best friend:
man cp
Related
We have a linux server and for some transactions it is keeping the log files only for the last 10 days. After than the file gets deleted. I want to copy these files to another location using a script. I searched google but couldn't satisfactory result. I'm new to Linux also.
Can someone please guide me if this can be achieved and how ?
You can use the previous answer by nissim abehcera in a sh script:
cp -R SOURCE_DIRECTORY DESTINATION_DIRECTORY
Just paste the bash commands in a text file, name it file.sh and make sure it is executable:
chmod +x file.sh
You can just run the script and it will do whatever you wrote in there.
I am new to the site and to Linux.
I am trying to write a command line code in Linux to loop over sub directories of a given directory then over the files in these sub-directories. perform a certain function then output the result to new sub-directories with the same name in a different directory.
Here is my code
for dirname in $(ls);
do
cd $dirname
for file in $(ls)
do
mkdir -p ~/path/to/new directory/$dirname/$filname
zcat $file| ~/path/to/ptogram stdin --outdir ~/path/to/new directory/$dirname/$file
done
cd ..
done
although the code is working , i want to know if there is a simpler way.. I have a feeling my code is not clean maybe because I am not familiar with all the syntax in Linux
Thank you!
I have a problem with an Uni OS Course assignment.
Basically the task says:
Deliver now a file for assessment. The content of the file is: one line, containing a command that
copies all files with prefix "2016", from directory "ExercisesOS" to directory "OSLab".
Consider the current directory to be "~" when writing such command.
I have already tried with that code:
cp /ExercisesOS/2016* /OSLab
but it performs me two error.
How can I write the correct command?
You probably want to copy from the directory you are working.
To check where you are working:
$ pwd
/home/userdir
To copy from your working directory:
$ cp ExerciseOS/2016* OSLab/
mkdir OSLab && cp /ExercisesOS/2016* OSLab
This solution would assume that the directory 'OSLab' isn't already created.
I have a bash script, which I use for configuration of different parameters in text files in my wireless access media server.
The script is located in one directory, and because I do all of configurations using putty, I have to either use the full path of the file or move to the directory that contains the file. I would like to avoid this.
Is it possible to save the bash script in or edit the bash script so that I can run it as command, for example as cp or ls commands?
The script needs to be executable, with:
chmod +x scriptname
(or similar).
Also, you want the script to be located in a directory that is in your PATH.
To see your PATH use:
echo $PATH
Your choices are: to move (or link) the file into one of those directories, or to add the directory it is in to your PATH.
You can add a directory to your PATH with:
PATH=$PATH:/name/of/my/directory
and if you do this in the file $HOME/.bashrc it will happen for each of your shell's automatically.
You can place a softlink to the script under /usr/local/bin (Should be in $PATH like John said)
ln -s /path/to/script /usr/local/bin/scriptname
This should do the trick.
You can write a minimal wrapper in your home directory:
#!/bin/bash
exec /yourpath/yourfile.extension
And run your child script with this command ./NameOfYourScript
update: Unix hawks will probably say the first solution is a no-brainer because of the additional admin work it will load on you. Agreed, but on your requirements, my solution works :)
Otherwise, you can use an alias; you will have to amend your .bashrc
alias menu='bash /yourpath/menuScript.sh'
Another way is to run it with:
/bin/bash /path/to/script
Then the file doesn't need to be executable.
I haven't written any Shell scripts before, but i have to write a simple shell script to do the following;
I will keep all the required files in a single folder and bundle it with this shell script as a tar file; so when the user runs the shell script, it needs to copy the respective files to the respective destinations.
The execution of copy as follows:
copy the plugin.so file to /usrlib/mozilla/plugins/
copy the .so library files to /usr/local/lib/
copy some header files directories(folders) to /usr/local/include/
and finally, need to do ldconfig.
Basically, you can add in a script any command you are able to type inside the terminal itself. Then, you have two options for executing it:
Execute it from the terminal with sh your_script.sh. You don't even need to give execute permission to it with this solution.
Give it the execute permission and run it with ./your_script.sh.
For the second solution, you have to start the file with what is called a shebang. So your script will look like:
#!/bin/sh
cp path/to/source path/to/destination
cp path/to/source path/to/destination
cp path/to/source path/to/destination
ldconfig
echo "Done!"
Nothing else. Just write the commands one after the other.
The first line is the so-called shebang and tells the shell which interpreter to use for the script.
Note: the extension for shell scripts is usually .sh, but you can actually name your file however you prefer. The extension has no meaning at all.
Good scripting!