Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 5 years ago.
Improve this question
How can I remove all the 'www.' with awk in my output file.
e.g.: my output file has multiple sites like
abc.com
www.def.com
blabla.org
www.zxc.net
I would like to remove all the www. in my output file:
abc.com
def.com
blabla.org
zxc.net
Probably better done in sed:
sed -i 's/^www\.//g' outputFile
In awk:
awk '{gsub(/^www\./,"",$0)}1' outputFile
This is probably what you're looking for:
$ cat file
abc.com
www.def.com
blabla.org
www.zxc.net
www.org
www.acl.lanl.gov
$ sed -E 's/^www\.(([^.]+(\.|$)){2,})/\1/' file
abc.com
def.com
blabla.org
zxc.net
www.org
acl.lanl.gov
The above uses a sed that has -E for ERE support, e.g. GNU or OSX sed. Note the need for a more comprehensive input file to test if a proposed solution really works or not.
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 2 years ago.
Improve this question
I have a string "config"
and want to replace with
"server"
using sed in Linux. I tried the below one. But It did not work.
sed -i "s#$"config"#$"server"#g" setup.xml-->
How can I do that? If not sed other options are fine too.
before "config"
after "server"
One example:
sed 's/"config"/"\s\e\r\v\e\r"/' setup.xml
The replacement string has characters with special meaning in sed such as ; # and &. These will all need to be escaped and so:
sed -n 's/"config"/"\&\#115\;\&\#101\;\&\#114\;\&\#118\;\&\#101\;\&\#114\;"/p' <<< '"config"'
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 3 years ago.
Improve this question
Here's my config file
#comment 1
--longoption1
#comment 2
--longoption2
#comment 3
-s
#comment 4
--longoption4
I want to write a bash script that will read this .conf file, skip comments and serialize the commandline options like so.
./binary --longoption1 --longoption2 -s --longoption4
Working off of this post on sed, you just need to pipe the output from sed to xargs:
sed -e 's/#.*$//' -e '/^$/d' inputFile | xargs ./binary
As Wiimm points out, xargs can be finicky with a lot of arguments and it might split it up across multiple calls to binary. It may be better off to use sed directly:
./binary $(sed -e 's/#.*$//' -e '/^$/d' inputFile)
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 5 years ago.
Improve this question
I have two text file like below:
File1.txt
A|234-211
B|234-244
C|234-351
D|999-876
E|456-411
F|567-211
File2.txt
234-244
999-876
567-211
And I want to compare both files and get containing values like below:
Dequired output
B|234-244
D|999-876
F|567-211
$ grep -F -f file2.txt file1.txt
B|234-244
D|999-876
F|567-211
The -F makes grep search for fixed strings (not patterns). Both -F and -f are POSIX options to grep.
Note that this assumes your file2.txt does not contain short strings like 11 which could lead to false positives.
Try:
grep -f File2.txt File1.txt
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
In my Bash script, I have to change a name to a path address(new address) in a text file:
(MYADDREES) change to ( /home/run1/c1 ) and save it as new file.
I did like this: defined a new variable = new address and tried to replace it in previous address in text file.
I use sed but it has problem.
My script was:
#!/bin/bash
# To debug
set -x
x=`pwd`
echo $x
sed "s/MYADDRESS/$x/g" < sample1.txt > new.txt
exit
The output of pwd is likely to contain / characters, making your sed expression look something like s/MYADDRESS//home/user/somewhere/. This makes it impossible for sed to sort out what should be replaced with what. There are two solutions:
Use a different delimiter for sed:
sed "s,MYADDRESS,$x,g" < sample1.txt > new.txt
...although this will have the same problem if the current path contains a comma character or something else that is a special character for sed, so the more robust approach is to use awk instead:
awk -v curdir="$(pwd)" '{ gsub("MYADDRESS", curdir); print }' < sample1.txt > new.txt
Closed. This question is off-topic. It is not currently accepting answers.
Want to improve this question? Update the question so it's on-topic for Stack Overflow.
Closed 10 years ago.
Improve this question
I know that I can use cat to print all content from a file from beginning to end on Linux.
Is there a way for doing that backward (last line first)?
Yes, you can use "tac" command.
From man tac:
Usage: tac [OPTION]... [FILE]...
Write each FILE to standard output, last line first.
With no FILE, or when FILE is -, read standard input.
Mandatory arguments to long options are mandatory for short options too.
-b, --before attach the separator before instead of after
-r, --regex interpret the separator as a regular expression
-s, --separator=STRING use STRING as the separator instead of newline
--help display this help and exit
--version output version information and exit
sed '1!G;h;$!d' file
sed -n '1!G;h;$p' file
perl -e 'print reverse <>' file
awk '{a[i++]=$0} END {for (j=i-1; j>=0;) print a[j--] }' file
tac is one way, but not default available on all linux.
awk could do it like:
awk '{a[NR]=$0}END{for(i=NR;i>=1;i--)print a[i]}' file