I'd like to achieve the following with a CronExpression.
Start at: 04.06.2017
Fire every Day at 01:00:00
End at: 09.09.2018 23:59:59
So far I only can say:
Start at 04.06.2017
Fire every Day (at 01:00:00)
End at: 31.12.2018 23:59:59
I achieve this with the following expression:
0 0 1 4/1 6 ? 2017-2018
Is there a possibility to set a specific finishing date?
I could think about something like this:
1) 0 0 1 4/1 6 ? 2017
2) 0 0 1 * 7-12 ? 2017
3) 0 0 1 * 1-8 ? 2018
4) 0 0 1 1-9 9 ? 2018
Related
i want to add +2 days to column based on other column i use this table :
Company Type Joinning Date Starting day
1 1 19/01/2019
2 0 19/01/2019
3 0 19/01/2019
4 1 20/01/2019
5 0 20/01/2019
6 1 21/01/2019
i want to add +2 DAYS in column Starting day which is Joining day + 2 days if the company have type 1 how can i do it ?
What i've tried ?
pic
Desired Results
Company Type Joinning Date Starting day
1 1 19/01/2019 21/01/2019
2 0 19/01/2019
3 0 19/01/2019
4 1 20/01/2019 22/01/2019
5 0 20/01/2019
6 1 21/01/2019 23/01/2019
Just to show my comment of:
=IF(B2=1,C2+2,"")
Works. The output cell must be formatted in the desired method:
I am trying to use offset function in excel to dynamically calculate sales since launch of products (3 months after, 6 months after etc.). For eg. for item 1 first 3 months of sale is 2557+10000+14487= 27044 and similarly for item 2 first 3 months sale will be 2557+11853+14487=28897
Any guidance on this is super appreciated!!
Items
Item1
Item2
Jan-20
0
0
Feb-20
0
0
Mar-20
0
0
Apr-20
0
0
May-20
0
2557
Jun-20
0
11853
Jul-20
0
14487
Aug-20
0
11375
Sep-20
0
10938
Oct-20
0
10842
Nov-20
0
15132
Dec-20
0
19820
Jan-21
2557
20726
Feb-21
10000
25072
Mar-21
14487
28897
Apr-21
11375
28665
May-21
10938
42358
Jun-21
10842
25619
Jul-21
15132
20575
Aug-21
19820
23315
Sep-21
20726
21346
Oct-21
25072
19377
Yes, avoid offset. You could use index/match for example:
=SUM(INDEX(B:B,MATCH(0,B:B)+1):INDEX(B:B,MATCH(0,B:B)+3))
Hello I have to count how many people were scheduled on each hour in excel so I transformed starting and ending data/time to only contain time and basing on it I tried to substract these two information but I only get an hour then but what I need is the hours to be like this:
instead
starting on 9:00
ending on 17:00
this
9:00
10:00
11:00
12:00
13:00
14:00
15:00
16:00
17:00
to count every hour that employee was at work. But I don't know how :(
Or is there a better way of doing that?
Assuming your table looks something like this:
Person
Start
End
09:00
10:00
11:00
12:00
13:00
14:00
15:00
Alice
08:35
16:35
1
1
1
1
1
1
1
Bob
09:35
17:35
0
1
1
1
1
1
1
Carl
10:35
18:35
0
0
1
1
1
1
1
Dan
11:35
19:35
0
0
0
1
1
1
1
Ed
12:35
20:35
0
0
0
0
1
1
1
Total present
1
2
3
4
5
5
5
You can compute the entries 0 or 1 in each cell under the times using the formula
=IF(AND((E$4>$C6);(E$4<=$D6));1;0)
In the formula, E$4 is a reference to the column header, e.g. "9:00", $C6 and $D6 are references to the start and end times of the person. They are defined using partial absolute references ($) so the same formula can be copied and pasted in all the cells.
The result will be 1 if the person was present at that time and 0 if not.
The "Total present" formulas just sum up the 1's and 0's in the column.
I have two questions for calibrate with cph function.
My data have 5 independent variables(from BMI to RT), and 2 dependent variables (time, event).
> head(data)
BMI Taxanes Surgery LND RT Event Time
1 19 0 0 2 5 0 98
2 20 0 0 3 3 0 97
3 21 0 0 8 2 0 17
4 18 0 0 1 3 0 35
5 20 1 0 3 1 0 27
6 20 1 0 2 3 1 2
> str(data)
$ BMI : num 19 20 21 18 20 20 20 ...
$ Taxanes: int 0 0 0 0 1 1 1 0 0 0 ...
$ Surgery: num 0 0 0 0 0 0 1 0 0 0 ...
$ LND : int 2 3 8 1 3 2 2 2 5 2 ...
$ RT : Factor w/ 7 levels "0","1","2","3",..: 5 3 2 3 1 3 ...
$ Event : int 0 0 0 0 0 1 0 0 0 0 ...
$ Time : num 98 97 17 35 27 2 22 ...
(1) With this data, I did survival analysis with cph model. And I want to make a calibration plot using this data. But I got an error which "Error in x(x) : argument "y" is missing, with no default". I was finding lots of material. But I don't know the reason for this error. Even if I found the calibrate function in web, But I can't find for the element 'y'. please help me for this question.
> ddist <- datadist(data)
> options(datadist='ddist')
>
> fit = cph(Surv(Time,Event) ~ BMI + Surgery + Taxanes + RT + LND, data=data, x=TRUE, y=TRUE, surv=TRUE, dxy=TRUE, time.inc=36)
> plot(calibrate(fit))
Using Cox survival estimates at 36 Days
**Error in x(x) : argument "y" is missing, with no default**
(2) Eventually I want to do external validation for this cph model(fit).
If new data name is kind of dat2 (which has the same variable with data), then what is the observed and predicted survival? I know that the predicted value calculate like this code
val<-val.surv(fit, newdata=dat2, S=Surv(dat2$Time,dat2$Event))
But how I get a actual(observed) survival in new data(dat2)? Please help for this problem. Thank you so much in advance!
So say I had a table like this that has the score of 3 different teams for the week.
Day Team1 Team2 Team3
Mon 5 2 2
Tue 0 7 7
Wed 6 3 2
Thu 0 0 1
Fri 13 6 5
I want a formula that can find the highest score for the day and mark it on a identical table with a value of 1 and mark the other teams 0.
If there are 2 values that are the highest I want them to both be marked 1.
There will never be day with all 0's
Using the data from the table above my other table would look like this.
Day Team1 Team2 Team3
Mon 1 0 0
Tue 0 1 1
Wed 1 0 0
Thu 0 0 1
Fri 1 0 0
I have a working formula
=IF(AND(B2>=$C2,B2>=$D2,B2>=$E2),1,0)
I was just hoping there was a better way to write this formula, so that I can drag it across the teams and have it still work.
If I try to drag my formula now. I have to update the formula for each column. Sometimes I might have 20 + teams.
Any advice is appreciated.
Use MAX():
=IF(B2=MAX($B2:$D2),1,0)
Then copy/drag over and down.