sed -e "s/${MyToken}/${arg}/g" file
Value Of 'arg' working fine till 9th argument.after 10th arguments its failing
Here is an example :
#!/bin/ksh
echo There is $# parameters
while [ $# -ne 0 ]; do
echo $1
shift
done
The output :
Will:/home> ./script a b c d e f g h i j k l m n o p q r s t u v w x y z
There is 26 parameters
a
b
c
d
e
f
g
h
i
j
k
l
m
n
o
p
q
r
s
t
u
v
w
x
y
z
$#count the number of parameters passed to your script.
Shift is moving the param to the left so after one loop $1 become b and so on.
Related
The program must accept a character matrix of size RxC as the input. The program must print the number of diagonals that parallel to the top-left to bottom-right diagonal and having the same characters in the matrix.
def lower_diagonals(row,matrix):
# a list to store the lower diagonals
# which are || to top left to bottom right
d=[]
# Iterating from the second row till the last row
for i in range(1,row):
nop,dummy = [],0
for j in range(i,row):
try:
nop.append(matrix[j][dummy])
except:
break
dummy+=1
d.append(nop)
return d
def upper_diagonals(col,matrix):
# a list to store the lower diagonals
# which are || to top left to bottom right
d=[]
# Iterating from 1st column till the last column
for i in range(1,col):
dum , nop = i,[]
# Iterating till the last before row
for j in range(row-1):
try:
nop.append(matrix[j][dum])
except:
break
dum+=1
d.append(nop)
return d
def diagonals(matrix,row,col):
return lower_diagonals(row,matrix) + upper_diagonals(col,matrix)
row,col = map(int,input().input().split())
matrix =[input().strip().split(' ') for i in range(row)]
new_matrix = diagonals(matrix,row,col)
t=0
for i in new_matrix:
if len(list(set(i))) == 1 : t+=1
print(t)
Example :
Input :
4 4
u m o a
h n a o
y h r w
b n h e
Output:
4
Input :
5 7
G a # z U p 3
e G b # n U p
a e G m # e U
L l e g k # t
j L a e G s #
Output:
6
My code works perfect for all the above mentioned cases but it fails for the below case
Input :
2 100
b h D k 2 D 9 I e Q # * B 5 H Z r q u n P C 4 a e K l 2 E p 6 R V v 0 d 8 x C F P M F C e m K H O y # 0 I T r P 8 P N 9 Z 7 S J J P c L g x X f 5 1 o i Y V Y G Y 9 A E O 2 r 2 # S 8 z D 6 a q r i k r
V o 4 T M m z p 6 G H D Y a 6 t O 7 # w y t 2 m A 1 a + 0 p t P D z 7 V N T x + I t 4 x x y 1 Q G M t M 0 v d G e u 4 b 8 m D # I v D i T 1 u L f e 1 Y E Y q Y c A 8 P 2 q 2 A 8 y b u E 3 c 1 s M n X
Expected Output:
9
My Output:
100
Can anyone help me in structuring the logic for this case Thanks in advance
Note :
2<=R,C<=100
Time limit : 500ms
I think i probably found a logic for my problem
r,c = map(int,input().strip().split())
mat = []
for i in range(r):
l = list(map(str,input().strip().split()))
mat.append(l[::-1])
count = 0
for i in range(r+c-1):
l = []
for row in range(r):
for col in range(c):
if row+col == i:
l.append(mat[row][col])
l = list(set(l))
if len(l) == 1:
count+=1
print(count)
How to add new line in python. for example, I would like to print the rest of a sentence in a new line. but instead of putting "\n", I will automate it to type to a new line for every six words.
Morse code translator
sth like:
def wrapper(words, n):
to_print = ''
for i in range(0, len(words.split()), n):
to_print += ' '.join(words.split()[i:i+n]) + '\n'
return to_print
and result is:
print(wrapper('a b c d e f g h i j k l m n o p r s t u w x y z', 6))
a b c d e f
g h i j k l
m n o p r s
t u w x y z
I have a tab separated file A containing several values per row:
A B C D E
F G H I
J K L M
N O P
Q R S T
U V
X Y Z
I want to remove from file A the elements contained in the following file B:
A D
J M
U V
resulting in a file C:
B C E
F G H I
K L
N O P
Q R S T
X Y Z
Is there a way of doing this using bash?
In case the entries do not contain any special symbols for sed (for instance ()[]/\.*?+) you can use the following command:
mapfile -t array < <(<B tr '\t' '\n')
(IFS='|'; sed -r "s/(${array[*]})\t?//g;/^$/d" A > C)
This command reads file B into an array. From the array a sed command is constructed. The sed command will filter out all entries and delete blank lines.
In your example, the constructed command ...
sed -r 's/(A|D|J|M|U|V)\t?//g;/^$/d' A > C
... generates the following file C (spaces are actually tabs)
B C E
F G H I
K L
N O P
Q R S T
X Y Z
awk solution:
awk 'NR == FNR{ pat = sprintf("%s%s|%s", (pat? pat "|":""), $1, $2); next }
{
gsub("^(" pat ")[[:space:]]*|[[:space:]]*(" pat ")", "");
if (NF) print
}' file_b file_a
The output:
B C E
F G H I
K L
N O P
Q R S T
X Y Z
I want to split a row of data into multiple columns like
a.dat
A B C D E F G H I J K L M N O P Q R S T U
into
b.dat
A B C D E F G
H I J K L M N
O P Q R S T U
I have tried using the pr function
pr -ts" " --columns 7 --across a.dat > b.dat
But it doesn't work, b.dat is the same as a.dat
I like fold for these thingies:
$ fold -w 14 file
A B C D E F G
H I J K L M N
O P Q R S T U
With -w you set the width you desire to have.
Although xargs is more useful if you want to split based on number of fields instead of characters:
$ xargs -n 7 < file
A B C D E F G
H I J K L M N
O P Q R S T U
Regarding your attempt in pr: I don't really know why it is not working, although from some examples I see it doesn't look like the tool for such job.
This question already has answers here:
How to perform a for loop on each character in a string in Bash?
(16 answers)
Closed 8 years ago.
I want to get this string -> Example example1
in this form:
E
x
a
m
p
l
e
e
x
a
m
p
l
e
1
Use fold utility with width=1:
echo 'Example example1' | fold -w1
E
x
a
m
p
l
e
e
x
a
m
p
l
e
1
Another option is grep -o:
echo 'Example example1' | grep -o .
E
x
a
m
p
l
e
e
x
a
m
p
l
e
1
Using standard unix tools, you can do, for example:
echo "Example example1" | sed 's/\(.\)/\1\n/g'
Using pure bash:
echo "Example example1" | while read -r -n 1 c ; do echo "$c"; done