bash script while loop with read input from user [duplicate] - linux

Question

This question already has answers here:
How to create a dynamic variable and assign value to it?
(2 answers)
Closed 5 years ago.
Wondering if there is an easy way to do what im attempting and the best way to go about something like this.
answer=y
while [ "$answer" = y ]
do
echo "type name of the file you wish to delete"
IFS= read -r file
echo "would you like to delete another file [y/n]?"
IFS= read -r answer
done
echo "Exiting Program"
exit 0
My questions here is when an input is entered it gets stored in file but I would like when the answer is y that it can then get stored to another variable like file1.
Im then left with variables containing all the filenames someone wishes to delete which I can echo back.
How can I use a loop in this to keep adding the input until someone types n
Thanks for the help.

Answer 1

I wouldn't use a realtime read loop to delete files. Too many things can go wrong. Rather, maybe take a file of input and check each.
But for a simplistic answer to your question -
typeset -l answer=y # force to lowercase
lst=/tmp/file.list.$$
while [[ y == "$answer" ]]
do
echo "type name of the file you wish to delete"
IFS= read -r file
if [[ -e "$file" ]]
then echo "$file" >> $lst
else echo "That file does not exist/is not accessible."
fi
echo "would you like to delete another file [y/n]?"
IFS= read -r answer
done
echo -e "Files to be deleted:\n===\n$(<$lst)"
echo -e "\n===\n Delete all listed files [y/n]?"
IFS= read -r answer
if [[ y == "$answer" ]]
then rm $(<$lst)
fi
rm $lst

Answer 2

Maybe this helps:
while :; do
read -s -n 1 answer
if [ $answer = "y" || $answer = "Y" ]; then <your code>
elif [ $answer = "n" || $answer = "N" ]; then echo; echo; break
elif [ $answer = "" ]; then continue # pressed: return key
fi
done
depending the shell you use, you might use: [[ ${answer} =~ (Y|y) ]]