I am in TextWrangler, trying to grep for all sets of more than one consecutive space. I want to replace all these instances of multiple spaces with a single space. E.g.,
Find "Cognitive Impenetrability of Visual Perception"
Replace with "Cognitive Impenetrability of Visual Perception"
I've checked all the recommended threads on this and none of them are working for me.
"Regex to replace multiple spaces with a single space"
"How to replace multiple white spaces with one white space"
"replacing spaces with just one “_”"
Any advice on how to search (or Grep) for multiple spaces is welcome.
In TextWrangler
From menu Search go select Find... to get to the Find & Replace box.
In Find you type: "*" (i.e. two spaces followed by *)
In Replace you type "" (one space)
Don't forget to select box grep, and then press Replace all.
Here is what worked:
I would look for an instance of multiple spaces, copy two consecutive space-looking characters, and then paste the characters into the "Find" textbox, and add a star:
[mystery character][mystery character]*
Then I clicked the "Replace All" button. This fixed about one-third of the spacing issues.
I continued this method (two more times, I think) until the rest of the space issues (that I found) were fixed.
Related
I have a text like this:
this is any text
Could sublime text convert it to?
this-is-any-text
insert hyphens between each space
In addition to the suggestions given in the comments, there is another option - the Case Conversion plugin. Edit → Convert Case contains Title Case, Upper Case, Lower Case, and Swap Case. Case Conversion provides:
snake_case
SCREAMING_SNAKE_CASE
camelCase
PascalCase
dot.case
dash-case
separate words
separate with forward slashes
separate with backslashes
To use it, simply highlight the section of text you want to convert and select the desired operation from the menu, or use the assigned keyboard shortcut, which will show up on the menu. You can combine this with Find by using a regex pattern to only select certain areas.
Note: While I have contributed to the Case Conversion repo (I added the backslash feature), I am not its author, just a very satisfied user.
I have done as indicated by #odatnurd in sublime text I have selected the first space, then the following with CTRL + D and finally when they have all been selected I put a hyphen - and they have all been converted to a hyphen
I am translating a game, and the game's text box only supports 50 characters max per line. Is there a way to use a formula to split the entire sentence every 50 characters or whole word (49, 48, 47, etc)?
I am currently working with this formula.
=JOIN(CHAR(10),SPLIT(REGEXREPLACE(A1, "(.{50})", "/$1"),"/"))
The problem with this code, is that it splits at exactly 50 characters (one time), and will split in the middle of the word.
So again, my goal is to have it not split on the 50th character IF the 50th character is in the middle of the word, and for the rule to apply for the rest of the lines too because it only applies on the first line.
Please take a look at this test google sheet to get an example of what I am talking about.
If it's impossible to do it on Google Sheets, I don't mind moving to Excel provided I get a functioning code.
For the record, I did ask in Google's product forums 2 days ago, and still haven't received an answer.
=REGEXREPLACE(A1, "(.{1,50})\b", "$1" & CHAR(10))
{50} matches exactly 50 times, but what you need is 50 or less.
\b is word boundary that matches between alphanumeric and non-alphanumeric character.
= REGEXEXTRACT(A1,"(?ism)^"&REPT("([\w\d'\(\),. ]{0,49}\s)", ROUNDUP(LEN(A1)/50,0))&"([\w\d'\(\),. ]{0,49})$")
Tested with various expressions and works as intended. Note that only these characters [a-zA-Z0-9_'(),.] are allowed, Which means - and other characters not mentioned will not work. If you need them, add them inside the REPT expression and finishing regexp formula. Otherwise, This will work perfectly.
You are pretty close. I'm not an expert in Sheets, so not sure if this is the best way, but your Regex is wrong for what you want.
Also, you need to be certain that you don't use a split character that might appear in the phrase itself. However, using CHAR(10) for the replace character allows you to insert LF without going through the JOIN SPLIT sequence.
replace any line feeds, carriage returns and spaces with a single space
Match strings that start with a non-Space character followed by up to 49 more characters which are followed by a space or the end of the string.
replace the capture group with the capturing group followed by the CHAR(10) (and delete the space following).
There will be extra CHAR(10) at the end which you can strip off.
EDIT Regex changed slightly due to a difference in behavior between Google's RE and what I am used to (probably has to do with how a non-backtracking regex works). The problem showed up on your example:
=regexreplace(REGEXREPLACE(REGEXREPLACE(A1 & " ","[\r\n\s]+"," "),"(\S.{0,49})\s","$1" & char(10)),"\n+\z","")
My question is very simple:
Is there a shortcut in Sublime Text 3 which allows to remove blank lines in a selected text? (same for blanks in a line)
For instance, how to make this text:
a
b
c
To become:
a
b
c
And this line:
I need to remove these blanks.
to become this line:
Ineedtoremovetheseblanks.
You don't need a plugin to do this, a simple regex search and replace will do. First, select the text where you'd like to delete the blank lines. Then, select Find → Replace… (or, hit CtrlH on Windows/Linux, ⌘⌥F on OS X). Make sure the "Regular Expression" and "In selection" buttons are selected:
In Find What:, enter ^\n, and make sure the Replace With: field is empty. Then, simply hit "Replace All" and this:
becomes this:
As a bit of explanation, the regular expression ^\n searches for the beginning of a line (^) immediately followed by a newline character (\n). If you suspect that some of your "blank" lines contain whitespace, like space or tab characters, you can use ^\s*\n instead - \s* matches 0 or more whitespace characters, including newline characters.
For your second example, use the same Find/Replace settings as above, except your regular expression should simply be \s*.
There is a package called Trimmer. You can install it via Package control.
After you got the package you can use its functionalities. Just highlight the text you want to change (or don't select anything if you want to change the entire file) and then choose:
1) Edit > Line > Delete Empty Lines
2) Edit > Line > Remove Blank Spaces
Alternatively, as Chris's answer already pointed out you can use the classic search & replace functionality that is already present in the editor.
AS my original answer was incorrect, I have found this package which will be suitable for your needs.
The package is called DeleteBlankLines, for Sublime Text 3, has the ability to delete blank lines for the entire document and within the selected text only, all from a key stroke just like you were after.
The package can be found here:
https://packagecontrol.io/packages/DeleteBlankLines
I prefer using \s+, which will get one or more (i.e., the + character) whitespace characters (i.e., the \s escape sequence).
The * character will do zero or more, which on some versions can break up the individual words into letters.
What's the easiest way to delete the first 2 spaces for each line using VIM? Basically it's repeating "2x" for each line.
Clarification: here the assumption is the first 2 characters are spaces. So the question is about doing indentation for multiple lines together.
Enter visual block mode with Ctrl-V (or Ctrl-Q if you use Ctrl-V for paste);
Select the area to delete with the arrows;
Then press d to delete the selected area.
Press Esc
Some more options. You can decided which is the "easiest way".
Remove the first 2 characters of every line:
:%normal 2x
Remove first 2 characters of every line, only if they're spaces:
:%s/^ /
Note that the last slash is optional, and is only here so that you can see the two spaces. Without the slash, it's only 7 characters, including the :.
Move indentation to left for every line:
:%normal <<
You could also use a search and replace (in the ex editor, accessed via the : character):
Remove first two characters no matter what:
%s/^.\{2}//
Remove first two white space characters (must be at the beginning and both must be whitespace... any line not matching that criteria will be skipped):
%s/^\s\{2}//
Assuming a shiftwidth=2, then using shift with a range of %
:%<
Two spaces, or two characters? (2x does the latter.)
:[range]s/^ //
deletes two blanks at the beginning of each line; use % (equivalent to 1,$) as [range] do to this for the entire file.
:[range]s/^..//
deletes the first two characters of each line, whatever they are. (Note that it deletes two characters, not necessarily two columns; a tab character counts as one character).
If what you're really doing is changing indentation, you can use the < command to decrease it, or the > command to increase it. Set shiftwidth to control how far it shifts, e.g.
:set shiftwidth=2
I'd try one of two approaches:
Do column editing on the block to delete using Ctrl+V (often mapped to Ctrl+Q).
Record a macro on the first row using q1 (or any other number/letter you want to denote the recording register), then replay that macro multiple times using #1 (to use my previous example. Even better, use a preceding number to tell it how many times to run - 10#1 to run that macro 10 times, for example. It does, however, depends on what you recorded - make sure to rewind the cursor 0 or drop one line j, if that's relevant.
I'd also add: learn how to configure indentation for vim. Then a simple gg=G will do the trick.
I have word lists where the word or expression in Spanish is separated by its translation with a colon (":"). I want to make two columns, one for Spanish, the other for English. In vim I tried with
:%s/:/^I^I^I/g
But it does not give the desired output. The different columns are not aligned.
When deleting the colon by hand and inserting the number of tabs with the same amount of tab strokes, it always ends up aligned.
Any idea how to solve this, preferably in vim?
On a Linux/*nix system I use column(1)
:%!column -s':' -t
followed by
:%retab!
I'd probable do a
:s/:/^I/g
followed by a
:set ts=25
Where 25 is the length of the longest word expected + 2. So, if you expect the longest word of your input (on the left side of the colon) to be 12 characters, I'd choose something around 14 instead.
With Tabular.vim it's quite easy, just type :Tab /:\zs and it does the rest.
When in insert mode a setting of yours makes tab to reach a nth column. This is set with the 'softtabstop' settings if I am right.
For those tasks you could use a plugin like Align.vim or Tabularize.
Another option is to insert a huge number of spaces, and then use Visual Block with < operator as many times as necessary, if you have to do it once. Otherwise prefer reusable methods.