I have tried to make a sound file work, and from the IDLE 3.6, it works fine.
However when I try to run it from the actual file it breaks and crashes.
The error only says:
'Couldn't open 'Sounds/music.ogg'
This code has the same effect (runs fine from IDLE, breaks from file):
try:
import pygame
pygame.init()
pygame.mixer.pre_init(44100, 16, 2, 4096)
screen = pygame.display.set_mode((600, 300))
pygame.mixer.music.load("Sounds/music.ogg")
pygame.mixer.music.play(loops = -1)
except Exception as E:
print(E)
input()
I've tried other file formats, .mp3 and .wav, and they have the same outcome.
So basically, how can I make the music work fine from the file?
Most likely, the problem is that the sound file is not in the right place. You should have a folder "Sounds" in the same location as you .py file. And of course, the Sounds folder should contain a file "music.ogg".
Another option is to use absolute file paths. This means doing something like this: pygame.mixer.music.load("C:/SomeFolder/MainFolder/Sounds/music.ogg"). This tells the program to look at that exact location instead of relative to its position.
Interestingly enough relative paths doesn't seem to work when running outside of Idle. When changing to use the full path to the file everyhing works fine.
Related
I have script which reading txt file (only numbers inside) and this script starting with system (before Raspbian Gui start). Everything's work fine, I can send text in byte:
def send_serial_stop(self):
self.serialport.write(b'stop')
When I try to run this action - reading txt file and send data over serial, my script crash.
When I start script in Raspbian, everything works fine, and script not crashing. What's wrong with this code? I cannot read any errors because this app is in fullscreen mode. Have some tips?
Please help me, because I should finish this project until end of this week :(
def send_serial(self):
file = open('testprog.txt').read()
self.serialport.write(file.encode())
EDIT
When I use button with connected code (example above), script is terminated, and GUI application is closing.
Application is based on PyQt5 framework and GUI also.
Tere are around 150 lines of code in total.
Txt file has 24 characters (only numbers)
If I trying to run this script in Pycharm, everything works fine, when I start from terminal, situation is the same as during startup.
Probably problem is that you use relative path when opening text file.
Change it to absolute path:
file = open('/absolute/path/to/your/file/testprog.txt').read()
As an assignment for one of my classes, the professor had us download a file containing python code as well as a couple of text files that the python code will analyze.
The problem is, when I click to open the python file, the command window opens, then immediately closes. I can get it to stop from closing if I click on it fast enough, but that stops the code from loading, and any keystroke causes it to close again.
It's the same file every other student downloaded and used with no issue. I've tried re-downloading the file, re-installing python, even trying on a different computer. I've also tried opening it by entering the path file name in the command window with no success. Also no luck trying it in Jupyter Notebook or CodeLab. (And of course, no luck experimenting with the slew of possible solutions on previous Stack Overflow, Reddit, etc. questions).
Any ideas on the potential cause and/or solution?
Edit: cause unknown, but the solution was opening the file with Sypder console.
the file closes immediately because It ended and returned 0, to stop that from happening you can add at the end of the python code something like that:
ending = input("press key to exit")
or just import time and use
time.sleep(5)
you can open your file in the cmd/terminal window and you will be able to see the results
I have a python program and it seems that whenever I open it with this line of code active:
content = open('Word_list.txt').read().splitlines() it just closes itself (by open I mean double clicking it from file explorer, works fine every other way). I tried with a small list variable and my program works file when it's like that so I need to convert a 4MB file (4,250,000 lines) into a python list variable. Is there any way to do that and will there be any slowdowns because of what i'm doing here?
Oh, and I should mention that I tried other ways of importing the text file (for loops and whatnot) and that seemed to crash instantly too. Thanks!
Because you are running it through Explorer the window is closing before you can see an error message, so add some error handling code:
try:
content = open('Word_list.txt').read().splitlines()
except Exception as exc:
import traceback
print(traceback.format_exc())
input()
I managed to use Notepad++ and their macro system to put the required " ",'s over all of the words, completing my objecting using another program instead of python.
When running an interactive session, PyCharm thinks of os.getcwd() as my project's directory. However, when I run my script from the command line, PyCharm thinks of os.getcwd() as the directory of the script.
Is there a good workaround for this? Here is what I tried and did not like:
going to Run/Edit Configurations and changing the working directory manually. I did not like this solution, because I will have to do it for every script that I run.
having one line in my code that "fixes" the path for the purposes of interactive sessions and commenting it out before running from command line. This works, but feels wrong.
Is there a way to do this or is it just the way it is supposed to be? Maybe I shouldn't be trying to run random scripts within my project?
Any insight would be greatly appreciated.
Clarification:
By "interactive session" I mean being able to run each line individually in a Python/IPython Console
By "running from command line" I mean creating a script my_script.py and running python path_to_myscript/my_script.py (I actually press the Run button at PyCharm, but I think it's the same).
Other facts that might prove worth mentioning:
I have created a PyCharm project. This contains (among other things) the package Graphs, which contains the module Graph and some .txt files. When I do something within my Graph module (e.g. read a graph from a file), I like to test that things worked as expected. I do this by running a selection of lines (interactively). To read a .txt file, I have to go (using os.path.join()) from the current working directory (the project directory, ...\\project_name) to the module's directory ...\\project_name\\Graphs, where the file is located. However, when I run the whole script via the command line, the command reading the .txt file raises an Error, complaining that no file was found. By looking on the name of the file that was not found, I see that the full file name is something like this:
...\\project_name\\Graphs\\Graphs\\graph1.txt
It seems that this time the current working directory is ...\\project_name\\Graphs\\, and my os.path.join() command actually spoils it.
I user various methods in my python scripts.
set the working directory as first step of your code using os.chdir(some_existing_path)
This would mean all your other paths should be referenced to this, as you hard set the path. You just need to make sure it works from any location and your specifically in your IDE. Obviously, another os.chdir() would change the working directory and os.getcwd() would return the new working directory
set the working directory to __file__ by using os.chdir(os.path.dirname(__file__))
This is actually what I use most, as it is quite reliable, and then I reference all further paths or file operations to this. Or you can simply refer to as os.path.dirname(__file__) in your code without actually changing the working directory
get the working directory using os.getcwd()
And reference all path and file operations to this, knowing it will change based on how the script is launched. Note: do NOT assume that this returns the location of your script, it returns the working directory of the shell !!
[EDIT based on new information]
By "interactive session" I mean being able to run each line
individually in a Python/IPython Console
By running interactively line-by-line in a Python console, the __file__ is not defined, afterall: you are not executing a file. Hence you cannot use os.path.dirname(__file__) you will have to use something like os.chdir(some_known_existing_dir) to reference a path. As a programmer you need to be very aware of working directory and changes to this, your code should reflect that.
By "running from command line" I mean creating a script my_script.py
and running python path_to_myscript/my_script.py (I actually press the
Run button at PyCharm, but I think it's the same).
This, both executing a .py from command line as well as running in your IDE, will populate the __file__, hence you can use os.path.dirname(__file__)
HTH
I am purposely adding another answer to this post, in regards the following:
Other facts that might prove worth mentioning:
I have created a PyCharm project. This contains (among other things)
the package Graphs, which contains the module Graph and some .txt
files. When I do something within my Graph module (e.g. read a graph
from a file), I like to test that things worked as expected. I do this
by running a selection of lines (interactively). To read a .txt file,
I have to go (using os.path.join()) from the current working directory
(the project directory, ...\project_name) to the module's directory
...\project_name\Graphs, where the file is located. However, when I
run the whole script via the command line, the command reading the
.txt file raises an Error, complaining that no file was found. By
looking on the name of the file that was not found, I see that the
full file name is something like this:
...\project_name\Graphs\Graphs\graph1.txt It seems that this time
the current working directory is ...\project_name\Graphs\, and my
os.path.join() command actually spoils it.
I strongly believe that if a python script takes input from any file, that the author of the script needs to cater for this in the script.
What I mean is you as the author need to make sure you know the following regardless of how your script is executed:
What is the working directory
What is the script directory
These two you have no control over when you hand off your script to others, or run it on other peoples machines. The working directory is dependent on how the script is launched. It seems that you run on Windows, so here is an example:
C:\> c:\python\python your_script.py
The working directory is now C:\ if your_script.py is in C:\
C:\some_dir\another_dir\> c:\python\python.exe c:\your_script_dir\your_script.py
The working directory is now C:\some_dir\another_dir
And the above example may even give different results if the SYSTEM PATH variable is set to the path of the location of your_script.py
You need to ensure that your script works even if the user(s) of your script are placing this in various locations on their machines. Some people (and I don't know why) tend to put everything on the Desktop. You need to ensure your script can cope with this, including any spaces in the path name.
Furthermore, if your script is taking input from a file, the you as the author need to ensure that you can cope with changes in working directory, and changes of script directory. There are a few things you may consider:
Have your script input from a known (static) directory, something like C:\python_input\
Have your script input from a known (configurable) directory, use ConfigParser, you can search here on stackoverflow on many posts
Have your script input from a known directory related to the location of the script (using os.path.dirname(__file__))
any other method you may employ to ensure your script can get to the input
Ultimately this is all in your control, and you need to code to ensure it is working.
HTH,
Edwin.
I'm trying to open a windows media file on my desktop although it doesn't seem to open anything at all, what is the issue please?
elif action == "Tutorial":
os.system("C:\\Program Files (x86)\Windows Media Player\wmplayer.exe" "C:\\Users\Angus\Desktop\Test.mkv"
there are so many things wrong here,
you did not provide a MCVE.
You don't show any evidence of checking that the elif branch ever
executed in the first place.
You are missing a close ) on os.system(.
You use os.system instead of something in subprocess so you get no error information except the return code which you do not do anything with.
you do not specify a command for os.system like start, just a file which is not valid in bash, just try it in a cmd prompt.
You did not escape the file path so every space makes the program treat it as a seperate argument, you need to add '' quotes around the file name for it to be a valid single path.
You are clearly on windows but not making use of the os.startfile function to do exactly what you are trying to do.