I tried the following but not adding '' this example
I want to replace FILENAME_LOGIN to 'login.php'
Tried this:
grep -r "login.php" -l | tr '\n' ' ' | xargs sed -i 's/"login.php"/'login.php'/g'
However, it gives me login.php not 'login.php'
Thanks
You only need sed for this:
sed -i -e "s/FILENAME_LOGIN/'login.php'/g" /your/file
I figured it out:
find ./ -type f -exec sed -i -e 's/FILENAME_LOGIN/'login.php'/g' {} \;
find ./ -type f -exec sed -i -e 's/FILENAME_LOGIN/'\''login.php'\''/g' {} \;
Related
I want to delete all lines begin with 'sometext' from many files:
find . -name "*.php"|xargs -I {} sed -e '/^sometext/d' {}
But this put me output to console. How to modify this files directly?
Use -i option of sed:
sed -i -e '/^sometext/d' file
Tell sed to modify the files "in place":
find . -name "*.php" | xargs sed -i '' -e '/^sometext/d'
Note that the blank '' after -i is required, otherwise a new copy with a default suffix will be created.
Also note the pruning if your unnecessary -I in xaegs
You can accomplish this with exec:
find . -name "*.php" -exec sed -i '/^sometext/d' {} \;
I am trying to delete some line in PHP files. I tried to use an find, exec combination:
find . -name '*.php' -exec sed '/#category/d' {} \;
but it only prints out the files contents. Is there anythin wrong in the syntax? Or what is the problem?
Could you try this command:
find . -name '*.php' -exec sed -i '/#category/d' {} \;
I think you've missed -i option
It works, but probably not how you expect.
find . -name '*.php' -exec sed -i '/#category/d' {} \;
Will kill the lines in question.
This should be the command for sed so try to add -i :
sed -i ".bak" '/culpa/d' test.txt
find . -name '*.php' -exec sed -i '/#category/d' {} \;
Source of the answer:
Bash - find a keyword in a file and delete its line
How can I replace "abc" with "abcd" on all files of a folder using shell?
Is it possible using sed command?
Try the following command for the file file.txt:
sed -i 's/abc/abcd/g' file.txt
Try the following command for all files in the current folder:
find . -maxdepth 1 -type f -exec sed -i 's/abc/abcd/g' {} \;
For the files in the current directory and all subdirectories:
find . -type f -exec sed -i 's/abc/abcd/g' {} \;
Or if you are fan of xargs:
find . -type f | xargs -I {} sed -i 's/abc/abcd/g' {}
sed -i 's/abc/&d/g' *
should work.
Yes:
find /the/folder -type f -exec sed -i 's,\<abc\>,&d,g' {} \;
I run this command to find and replace all occurrences of 'apple' with 'orange' in all files in root of my site:
find ./ -exec sed -i 's/apple/orange/g' {} \;
But it doesn't go through sub directories.
What is wrong with this command?
Here are some lines of output of find ./:
./index.php
./header.php
./fpd
./fpd/font
./fpd/font/desktop.ini
./fpd/font/courier.php
./fpd/font/symbol.php
Your find should look like that to avoid sending directory names to sed:
find ./ -type f -exec sed -i -e 's/apple/orange/g' {} \;
For larger s&r tasks it's better and faster to use grep and xargs, so, for example;
grep -rl 'apples' /dir_to_search_under | xargs sed -i 's/apples/oranges/g'
Since there are also macOS folks reading this one (as I did), the following code worked for me (on 10.14)
egrep -rl '<pattern>' <dir> | xargs -I# sed -i '' 's/<arg1>/<arg2>/g' #
All other answers using -i and -e do not work on macOS.
Source
This worked for me:
find ./ -type f -exec sed -i '' 's#NEEDLE#REPLACEMENT#' *.php {} \;
grep -e apple your_site_root/**/*.* -s -l | xargs sed -i "" "s|apple|orange|"
Found a great program for this called ruplacer
https://github.com/dmerejkowsky/ruplacer
Usage
ruplacer before_text after_text # prints out list of things it will replace
ruplacer before_text after_text --go # executes the replacements
It also respects .gitignore so it won't mess up your .git or node_modules directories (find . by default will go into your .git directory and can corrupt it!!!)
I think we can do this with one line simple command
for i in `grep -rl eth0 . 2> /dev/null`; do sed -i ‘s/eth0/eth1/’ $i; done
Refer to this page.
In linuxOS:
sed -i 's/textSerch/textReplace/g' namefile
if "sed" not work try :
perl -i -pe 's/textSerch/textReplace/g' namefile
I have this script
#!/bin/sh
for i in `ls -R`
do
echo "Changing $i"
fromdos $i
done
I want to remove "^M" charcaters from many files which are in more subdirectories. I got this:
fromdos: Unable to access file
Is there somethig i'm missing?
Thanks in advance.
ls -R lists everything, including directories. So you're telling fromdos to act on actual directories is some cases.
Try something like this:
find . -type f -exec fromdos {} \;
I guess you don't need a for loop.
Here is a quick panorama of solutions for files with extension ".ext" (such commands shall be somehow restrictive)
note : ^M is obtained with CTRL-V" + "CTRL-M"
# PORTABLE SOLUTION
find /home -type f -name "*.ext" -exec sed -i -e 's/^M$//' {} \;
# GNU-sed
find /home -type f -name "*.ext" -exec sed -i -e "s/\x0D$//g" {} \;
# SED with more recent nux
find /home -type f -name "*.ext" -exec sed -i -e "s/\r$//g" {} \;
# DOS2UNIX
find /home -type f -name "*.ext" -print0 | while read -r -d "$(printf "\000")" -r path; do dos2unix $path $path"_new"; done
# AWK
find /home -type f -name "*.ext" -print0 | while read -r -d "$(printf "\000")" -r path; do awk '{ sub("\r$", ""); print }' $path > $path"_new"; done
# TR
find /home -type f -name "*.ext" -print0 | while read -r -d "$(printf "\000")" -r path; do cat $path | tr -d '\r' > $path"_new"; done
# PERL
find /home -type f -name "*.ext" -exec perl -pi -e 's/\r//g' {} \;