I have this string:
194.44.176.116:8080
I want regex to take everything after the colon ':' but not take : itself. How do I do that?
This is something I did but it grabs numbers and the colon ':' which I don't want.
var portRe = /(?<=:)\d{2,5}$/gi;
I'm using this in NodeJs application.
Your regex to get everything between the : and the end would be:
/[^:]+$/
But as we know,that the port is a number, you can just check for the number at end of string:
/[0-9]+$/
Please note that this does not check if there is a : and so just returns the last digit. If you are sure that you have a string as you provided, those two are the easiest to understand minimalist solutions.
Otherwise refer to the other answers to do a lookahead/lookbehind or work with non capturing / capturing groups.
A general strategy here would be to just use a capture group to isolate what you really want to match:
/.*:(\d{2,5})/gi
Then access what you have captured in the first capture group.
var myString = "194.44.176.116:8080";
var myRegexp = /.*:(\d{2,5})/gi;
var match = myRegexp.exec(myString);
console.log(match[1]);
Related
I am fairly new to Puppet and Ruby. Most likely this question has been asked before but I am not able to find any relevant information.
In my puppet code I will have a string variable retrieved from the fact hostname.
$n="$facts['hostname'].ex-ample.com"
I am expecting to get the values like these
DEV-123456-02B.ex-ample.com,
SCC-123456-02A.ex-ample.com,
DEV-123456-03B.ex-ample.com,
SCC-999999-04A.ex-ample.com
I want to perform the following action. Change the string to lowercase and then replace the
-02, -03 or -04 to -01.
So my output would be like
dev-123456-01b.ex-ample.com,
scc-123456-01a.ex-ample.com,
dev-123456-01b.ex-ample.com,
scc-999999-01a.ex-ample.com
I figured I would need to use .downcase on $n to make everything lowercase. But I am not sure how to replace the digits. I was thinking of .gsub or split but not sure how. I would prefer to make this happen in a oneline code.
If you really want a one-liner, you could run this against each string:
str
.downcase
.split('-')
.map
.with_index { |substr, i| i == 2 ? substr.gsub(/0[0-9]/, '01') : substr }
.join('-')
Without knowing what format your input list is taking, I'm not sure how to advise on how to iterate through it, but maybe you have that covered already. Hope it helps.
Note that Puppet and Ruby are entirely different languages and the other answers are for Ruby and won't work in Puppet.
What you need is:
$h = downcase(regsubst($facts['hostname'], '..(.)$', '01\1'))
$n = "${h}.ex-ample.com"
notice($n)
Note:
The downcase and regsubst functions come from stdlib.
I do a regex search and replace using the regsubst function and replace ..(.)$ - 2 characters followed by another one that I capture at the end of the string and replace that with 01 and the captured string.
All of that is then downcased.
If the -01--04 part is always on the same string index you could use that to replace the content.
original = 'DEV-123456-02B.ex-ample.com'
# 11 -^
string = original.downcase # creates a new downcased string
string[11, 2] = '01' # replace from index 11, 2 characters
string #=> "dev-123456-01b.ex-ample.com"
I am trying to find specific word in a div (id="Test") that starts with "a04" (no case). I can find and replace the words found. But I am unable to correctly use the word found in a "href" link.
I am trying the following working code that correctly identifies my search criteria. My current code is working as expected but I would like help as i do not know how to used the found work as the url id?
var test = document.getElementById("test").innerHTML
function replacetxt(){
var str_rep = document.getElementById("test").innerHTML.replace(/a04(\w)+/g,'TEST');
var temp = str_rep;
//alert(temp);
document.getElementById("test").innerHTML = temp;
}
I would like to wrap the found word in an href but i do not know how to use the found word as the url id (url.com?id=found word).
Can someone help point out how to reference the found work please?
Thanks
If you want to use your pattern with the capturing group, you could move the quantifier + inside the group or else you would only get the value of the last iteration.
\ba04(\w+)
\b word boundary to prevent the match being part of a longer word
a04 Match literally
(\w+) Capture group 1, match 1+ times a word character
Regex demo
Then you could use the first capturing group in the replacement by referring to it with $1
If the string is a04word, you would capture word in group 1.
Your code might look like:
function replacetxt(){
var elm = document.getElementById("test");
if (elm) {
elm.innerHTML = elm.innerHTML.replace(/\ba04(\w+)/g,'TEST');
}
}
replacetxt();
<div id="test">This is text a04word more text here</div>
Note that you don't have to create extra variables like var temp = str_rep;
I am using a regex expression to validate an input. I would like to match the exact strings "spe1" and "spe1.grl".
So far I have written the following code:
'\\b(?!i' + this.stringToIgnore + '\\b)\\w+';
where this.stringToIgnore = 'spe1'
this work if I type:
"spe1 " (note the space)
"spe1."
I would like to have a match as soon as I type:
"spe1" (without the need to add a space or dot at the end)
"spe1.grl" (without the need to add a space or dot at the end)
Thank you for your help
After palying a bit with an online Regex tool I have find the answer to my own question. I am posting it in case someone needs it:
'\\b(?!' + this.stringToIgnore + '\\b)\\w+';
or
''\\b(?!' + this.stringToIgnore + '|' + this.stringToIgnore.toUpperCase + '\\b)\\w+';
in case the user has the uppercase key on.
The problem:
The objective is to convert: "tan(x)*arctan(x)"
Into: "np.tan(x)*np.arctan(x)"
What I've tried:
s = "tan(x)*arctan(x)"
s = s.replace('tan','np.tan')
Out: np.tan(x)*arcnp.tan(x)
However, using pythons replace method resulted in arcnp.tan.
Taking one additional step:
s = s.replace('arcnp.', 'np.arc')
Out: np.tan(x)*np.arctan(x)
Achieves the desired result... but this solution is sloppy and inefficient.
Is there a more efficient solution to this problem?
Any help is appreciated. Thanks in advance.
Here is a way to do the job:
var string = 'tan(x)*arctan(x)';
var res = string.replace(/\b(?:arc)?tan\b/g,'np.$&');
console.log(res);
Explanation:
/ : regex delimiter
\b : word boundary, make sure we don't have any word character before
(?:arc)? : non capture group, literally 'arc', optional
tan : literally 'tan'
\b : word boundary, make sure we don't have any word character after
/g : regex delimiter, global flag
Replace:
$& : means the whole match, ie. tan or arctan
You can use regular expression to solve your issue. Following code is in javascript. Since, u didn't mention the language you are using.
var string = 'tan(x)*arctan(x)*xxxtan(x)';
console.log(string.replace(/([a-z]+)?(tan)/g,'np.$1$2'));
I'm trying to read a string in a specific format
RealSociedad
this is one example of string and what I want to extract is the name of the team.
I've tried something like this,
houseteam = sscanf(str, '%s');
but it does not work, why?
You can use regexprep like you did in your post above to do this for you. Even though your post says to use sscanf and from the comments in your post, you'd like to see this done using regexprep. You would have to do this using two nested regexprep calls, and you can retrieve the team name (i.e. RealSociedad) like so, given that str is in the format that you have provided:
str = 'RealSociedad';
houseteam = regexprep(regexprep(str, '^<a(.*)">', ''), '</a>$', '')
This looks very intimidating, but let's break this up. First, look at this statement:
regexprep(str, '^<a(.*)">', '')
How regexprep works is you specify the string you want to analyze, the pattern you are searching for, then what you want to replace this pattern with. The pattern we are looking for is:
^<a(.*)">
This says you are looking for patterns where the beginning of the string starts with a a<. After this, the (.*)"> is performing a greedy evaluation. This is saying that we want to find the longest sequence of characters until we reach the characters of ">. As such, what the regular expression will match is the following string:
<ahref="/teams/spain/real-sociedad-de-futbol/2028/">
We then replace this with a blank string. As such, the output of the first regexprep call will be this:
RealSociedad</a>
We want to get rid of the </a> string, and so we would make another regexprep call where we look for the </a> at the end of the string, then replace this with the blank string yet again. The pattern you are looking for is thus:
</a>$
The dollar sign ($) symbolizes that this pattern should appear at the end of the string. If we find such a pattern, we will replace it with the blank string. Therefore, what we get in the end is:
RealSociedad
Found a solution. So, %s stops when it finds a space.
str = regexprep(str, '<', ' <');
str = regexprep(str, '>', '> ');
houseteam = sscanf(str, '%*s %s %*s');
This will create a space between my desired string.