I have this hexadecimal in a nodejs Tcp Client
82380000000000000400000000000000
I have used parseint function to convert it to
1.73090408076117e+38
But i need to get its binary representation that is
10000010001110000000000000000000000000000000000000000000000000000000010000000000000000000000000000000000000000000000000000000000
Ho can i get this binary representation from the above hexadecimal format?
Using the toString specifying the base as the parameter should make it. For example, if you want to convert it to a binary string, after parsing it to an integer:
var number = '82380000000000000400000000000000';
console.log(parseInt(number).toString(2));
In case you want an hexadecimal string, just use .toString(16);
If you don't want to parse the string with the number:
var number = 82380000000000000400000000000000;
console.log(number.toString(2));
Hope this helps.
Related
I want to convert 16-digit hexadecimal numbers into doubles. I actually did the reverse of this before which worked fine:
import struct
import wrap
def double_to_hex(doublein):
return hex(struct.unpack('<Q', struct.pack('<d', doublein))[0])
for i in modified_list:
encoded_list.append(double_to_hex(i))
modified_list.clear()
encoded_msg = ''.join(encoded_list).replace('0x', '')
encoded_list.clear()
print_command('encode', encoded_message)
And now I want to sort of do the reverse. I tried this without success:
from textwrap import wrap
import struct
import binascii
MESSAGE = 'c030a85d52ae57eac0129263c4fffc34'
#Splitting up message into n 16-bit strings
MSGLIST = wrap(MESSAGE, 16)
doubles = []
print(MSGLIST)
for msg in MSGLIST:
doubles.append(struct.unpack('d', binascii.unhexlify(msg)))
print(doubles)
However, when I run this, I get crazy values, which are of course not what I put in:
[(-1.8561629252326087e+204,), (1.8922789420412524e-53,)]
Were your original numbers -16.657673995556173 and -4.642958715557189 ?
If so, then the problem is that your hex strings contain the big-endian (most-significant byte first) representation of the double, but the 'd' format string in your unpack call specifies conversion using your system's native format, which happens to be little-endian (least-significant byte first). The result is that unpack reads and processes the bytes of the unhexlify'ed string from the wrong end. Unsurprisingly, that will produce the wrong value.
To fix, do one of:
convert the hex string into little-endian format (reverse the bytes, so c030a85d52ae57ea becomes ea57ae525da830c0) before passing it to binascii.unhexlify, or
reverse the bytes produced by unhexlify (change binascii.unhexlify(msg) to binascii.unhexlify(msg)[::-1]) before you pass them to unpack, or
tell unpack to do the conversion using big-endian order (replace the format string 'd' with '>d')
I'd go with the last one, replacing the format string.
I have this:
function dec2hex(IN)
local OUT
OUT = string.format("%x",IN)
return OUT
end
and need IN to have padded zeros to string length of 6.
I can't use String.Utils or PadLeft. It's within an app called Watchmaker which uses a cut down version of Lua.
String formats in Lua work mostly just like in C. So to pad a number with zeros, just use %0n where n is the number of places. For example
print(string.format("%06x", 16^4-1))
will print 00ffff.
See chapter 20 The String Library of “Programming in Lua”, the reference of string.format, and the C reference for the printf family of functions for details.
If you store your format string locally you can call the format method on to the format string and the example of #Henri results in ("%06x"):format(0xffff)
print(("%06x"):format(0xffff)) -- Prints `00ffff`
You can write numbers in hex format. It is the same as C.
How do i convert hex values to their decimal value using nodejs ?
Suppose i have hex value as bellow
9c63e8e2f6574c197c0626bad843eb47104adf3f01f2901aad1258936feb007e
Any one have any idea the please let me know
JS parseInt function takes base as a second argument.
So you can simply use parseInt(hexString, 16).
For example: parseInt('ff', 16) will return 255.
That may sound like a weird struggle and actually easy to do, but I cannot find a working way to convert an hexidecimal in a string format into a float.
My exemple is for instance: 406ea716
If I convert it using one of the following website, I get 3.728948.
http://www.h-schmidt.net/FloatConverter/IEEE754.html
http://gregstoll.dyndns.org/~gregstoll/floattohex/
I tried every single piece of code I found on the internet, but it won't return the same result.
Does it exist a module in NodeJS to perform the same conversion? If not, what can I do?
Thank you for your help.
I had the same issue. try this.
Buffer('406ea716','hex').readFloatBE(0)
3.7289481163024902
No need for a module:
var hex = '406ea716';
// transform the hexadecimal representation in a proper js hexadecimal representation by prepending `0x` to the string
// parseInt() - because your example was an integer.
var num = parseInt( '0x' + '406ea716');
console.log( num );
Have you tried parseInt?
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/parseInt
$ node
> parseInt('406ea716', 16)
1080993558
I need a function that can convert a string containg numbers to a hexadecimal integer saved in an integer variable,
for example the function atoi(char*) converts the string in that string into a decimal number , what i need is something similar but instead of decimal , hexadecimal
All integers store data in the same format: binary. That is neither decimal or hexadecimal.
If you want to create a string from an integer, that's when you can decide if you want decimal or hexadecimal notation.
You didn't mention what language you are using so I'll just assume C or C++ from the atoi() reference. There is also an itoa() function. It will create a string from an integer, and you can specify if the string will be created using base 16, base 10, or something else.