horizontal offset for categorical plot - gnuplot

For the following categorical plot I would like to put some space left of the first category and right of the last:
#abc.dat
a 1
b 2
c 3
In gnuplot:
set yrange [0:4]
plot 'abc.dat' using 2:xticlabels(1) pointtype 7 pointsize 5
Result:
Desired (approximately):
How can this be done? I specifically want points (and not bars).

The command set offsets adds a space between data and axes:
set offsets graph 0.05, graph 0.05
graph ... means a space relative to your plot size.

Related

Gnuplot: fill area bounded by curves left/right?

I have a dataset that defines two curves, and I want to fill the area between them. However, contrary to the standard situation, the abscissa is to be plotted on the vertical axis and the ordinates on the horizontal one; the abscissa indicates depth, this is a common plotting format in geophysics. In other words, I want something like
plot 's.dat' u 1:2:3 w filledcurves
but with swapped axes so that the filled area is bounded not at the top and bottom but to the left and right by the curves as seen in
plot 's.dat' u 2:1,'s.dat' u 3:1
My dataset is like this:
0. -1.776 -0.880
160. -1.775 -0.882
160. -1.692 -0.799
320. -1.692 -0.800
320. -1.531 -0.634
480. -1.534 -0.637
480. -1.286 -0.394
Is this possible in Gnuplot?
Thomas
This is a totally different solution using 3D plot style "with zerror".
You will need current gnuplot (version 5.2) for this. The plot style was really not designed for this so there are some difficulties (e.g. x tic marks invisible because drawn perpendicular to the plane of the plot, all tic labels requiring an offset for readability).
#
# [mis]use 3D plot style "with zerror" to create a plot of the xz
# plane with area fill between two sets of data points with
# equal coordinates on the vertical axis (x) but contrasting
# values on the horizontal axis (z).
#
set view 270, 0
set view azimuth -90
set xyplane at 0
unset ytics
set ztics offset 4, -2 out
set xtics offset 4
splot 's.dat' using 1:(0):(0.5*($2+$3)):2:3 with zerror notitle
If there is some value of x which is guaranteed to lie between the two curves then you can plot in two halves. For the data you show, x=-1 would be a suitable value and the plot command would be:
plot 's.dat' u 2:1 with filledcurve x=-1 lt 3, \
's.dat' u 3:1 with filledcurve x=-1 lt 3
If the requirement for a constant intermediate x value can only be
satisfied piece-wise, e.g.
x=-1 for (0<y<500), x=0 for (500<y<1000)
then it may nevertheless be possible to construct a graph by stacking
the piecewise sections.
A simple way would be to define a closed line and fill it. For this, you take column 2 and add the reversed column 3. You probably need gnuplot >=5.2 for this.
Code:
### fill between vertical curves
reset session
$Data <<EOD
0. -1.776 -0.880
160. -1.775 -0.882
160. -1.692 -0.799
320. -1.692 -0.800
320. -1.531 -0.634
480. -1.534 -0.637
480. -1.286 -0.394
EOD
set print $Outline
do for [i=1:|$Data|] {
print sprintf("%s %s", word($Data[i],2), word($Data[i],1))
}
do for [i=|$Data|:1:-1] {
print sprintf("%s %s", word($Data[i],3), word($Data[i],1))
}
set print
plot $Outline w filledcurve lc rgb "green"
### end of code
Result:

gnuplot: 2D plot of a matrix of data

How can I plot (a 2D plot) a matrix in Gnuplot having such data structure, using the first row and column as a x and y ticks (the first number of the first row is the number of columns) and represent the rest of the values by a colour mapping so it can be seen on a 2D plane ?
4 0.5 0.6 0.7 0.8
1 -6.20 -6.35 -6.59 -6.02
2 -6.39 -6.52 -6.31 -6.00
3 -6.36 -6.48 -6.15 -5.90
4 -5.79 -5.91 -5.87 -5.46
You can plot this data format using matrix nonuniform.
To get a heatmap you can plot either with image (regular grid, no interpolation, one quadrangle for each data point), or splot with pm3d (supports also irregular grids and interpolation, plots one quadrangle for four neighboring data points.
with image
set autoscale xfix
set autoscale yfix
set autoscale cbfix
plot 'data.dat' matrix nonuniform with image notitle
pm3d
set autoscale xfix
set autoscale yfix
set autoscale cbfix
set pm3d map
splot 'data.dat' matrix nonuniform notitle

Gnuplot: draw error bars of data points outside plotting range

If I set a specific yrange and plot in a pdf terminal with this plot command:
plot "data.dat" u 1:4:5:6 w yerrorbars pt 6 ps 0.5 t "R_t"
errorbars that belong to data points outside the yrange, but end inside the yrange are not shown.
How do I force gnuplot to draw those. I already tried "set clip one/two"
The only workaround I found is to plot the data 3 times, once for the central point and once for each side of the error bar.
Use "-" as symbol for the errorbars and use their own "errorbars" to draw a line to the central point.
You could use multiplot to achieve this.
Set your plot to have zero margins, so the axes are on the border of the canvas, and switch of all tics and borders for the first plot.
Switch on the axes, tics etc. again, and do an empty plot that you set at the correct position using set size and set origin. You'll have to do some math to calculate the exact position.
#MaVo159, you can reduce it to plotting only twice by using with yerrorbars and with vectors (check help vectors). You need to set the proper arrow style, check help arrowstyle.
However, this works only for gnuplot>=5.2.3, for earlier versions there seems to be a bug which plots the arrowhead at the wrong side for some of the vectors extending the graph.
You nevertheless have to plot once with yerrorbars in order to get the proper legend.
Script: (works for gnuplot>=5.2.3, May 2018)
### plot errorbars from points outside the range
reset
$Data <<EOD
1 9 5.11 8.32
2 8 6.20 9.22
3 6 5.31 6.31
4 5 4.41 5.51
5 4 3.31 4.71
6 2.9 2.81 3.71
7 2 1.11 3.41
EOD
set yrange[3:7]
set offsets 1,1,0,0
set style arrow 1 heads size 0.05,90 lw 2 lc 1
set multiplot layout 2,1
plot $Data u 1:2:3:4 w yerrorbars pt 6 ps 2 lw 2
plot $Data u 1:2:3:4 w yerrorbars pt 6 ps 2 lw 2, \
'' u 1:3:(0):($4-$3) w vec as 1 notitle
unset multiplot
### end of script
Result:
You could modify your data file: Because the central value of the data point is outside the plot range you could set it equal to the errorbar's end point that would be still visible in your plot.
Example:
plot range: set yrange[-2:2]
data point: 1, -3, -1, -4 (x, y, ylow, yhigh)
set data point to: 1, -1, -1, -4
Attention: Since you have to edit your data file you should
Make a copy of the original data file
Be very careful when editing the file
Keep in mind, that when changing the plot range such that the central
value of the data point becomes visible you have to use the original data point. Otherwise you will see the correct error bar but there will be no central value plotted. (this is equivalent to setting 'point type' to 0)

How to set the horizontal distance between outliers in gnuplot boxplot

So if i have plotted some data in gnuplot as a boxplot (set style data gnuplot), and I have outliers having the same value, then they are plotted as dots horizontally at the same place.
How can I set that horizontal distance?
So for example I have the datafile data.dat
1
1
1
1
1
1
1
1
1
1
1
1
9
9
and plot it using
set style data boxplot
plot 'data.dat' using (1):1
set yrange [0:10]
How can I set then the distance between the two points at y=9?
No, you cannot change that distance, The position of duplicate outliers depends on the selected pointsize. There is, however, a difference in the point distance between the command
plot 'data.dat' using (1):1
and
plot 'data.dat' using (1):1 pointsize 1.
But I suspect this shouldn't happen and might be categorized as bug.
set style data boxplot
set yrange[0:10]
plot 'data.dat' using (1):1 title 'no explicit point size',\
'' using (2):1 pointsize 1 title 'point size 1'
Christoph, you were on the right track, just didn't go far enough. At least with Ver. 5.0, the following worked for me:
set style boxplot outliers pointtype 6
plot 'data.dat' using (1):2:(0):1 pointsize .1
I was plotting a few thousand points, and this resulted in a much more reasonable plot, given that there could be tens of duplicates.
Outliers that don't overlap

Reduce distance between points in splot

I have this gnuplot script
reset
set palette model RGB defined (0 "gray", 0.1 "white", 0.33 "yellow", 0.66 "orange", 1 "red")
set xlabel "x"
set ylabel "y"
set view map
set border 0
unset xtics
unset ytics
splot file_name u 1:2:5:xtic(3):ytic(4) w points ps 5 pt 5 palette
And this is the result:
How can I remove the distance between the points so that I end up with a set of adjacent squares? I want to plot a heatmap with a square for each point in my grid file.
EDIT
The correct way to plot a "grid" heatmap as per #andyras answer is:
set pm3d map
plot file_name u 1:2:5:xtic(3):ytic(4) with image
Which gives this image:
gnuplot offers a third way to plot a heatmap based on connecting points of a 3d surface, rather than grid cells. That is, the x,y coordinates at columns 1,2 are used as corners, or connecting points, of a surface mesh and the colors used in each region are the average of the RGB/HSV values for the 4 defining corners:
set pm3d map
splot file_name u 1:2:5:xtic(3):ytic(4)
I usually go with the options
set pm3d map
plot file_name u 1:2:5:xtic(3):ytic(4) with image
for gridded data (it makes a smaller file if you use vector formats). I suspect your problem may be to do with the fact that you specify a point style and size for your splot. So, you could try setting the pm3d map option and using splot without the point specification, or plot ... with image.

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