Count the number of individual entries in a cell - excel
Is it possible to count the number of individual entries in a cell?
For example 2+2+4-1 = 4 entries
Using the count formula counts the entries as 1
I want to calculate the number of adjustments made in a particular period.
Each +/- in an individual cell represents 1 adjustment.
Assuming you're referring to a text cell, the trick is to count the symobols you'd like to find. Before we dig into that, if you want to enter this data as text, you can use the ` symbol (Usually to the left of the 1 key on your keyboard) before entering your text to make sure it gets processed as text.
If you want to verify that it is text, you can use the TYPE function and look for a return result of 2 (check the link for other possible return types)
There are no direct functions to count characters in Excel, so the trick is to find the length of the original text and subtract it from the length of a new text where you have removed all of the special characters. You mentioned you were trying to count the entries (i.e. the numbers), but you said your goal was to ultimately count the number of '+/-' operations. Since counting numbers can be tricky with excel formulas (since we'll get hung up on 2 and 3 digit numbers), I am going to approach this problem from the perspective of counting the operations you are looking for. So here is a basic example:
length("2+1") = 3
- length("21") = 2 (we replaced the + with "" [blank])
= 1
So we know there is 1 '+' since we replaced it. The appropriate functions used to accomplish this are LEN and SUBSTITUTE
Since you can only find one symbol at a time using the SUBSTITUTE function, we must take the output of the first formula, and give it to the second formula, and so on and so forth. Ultimately, we can put together as many functions as we need to achieve the desired result.
So we start with + for your example (And assuming your data is in A1)
=LEN(A1)-LEN(SUBSTITUTE(A1,"+",""))
which gives us a result of 2. But we also need to find the - symbol. So we wrap another SUBSTITUTE:
=LEN(A1)-LEN(SUBSTITUTE(SUBSTITUTE(A1,"+",""),"-",""))
You have said you wanted to count the number of +/- in the cell, and this does accomplish that, but if you want to expand it to more mathematical operators, you simply add more SUBSTITUTE functions (here is a complete function where I've added * and /)
=LEN(A1)-LEN(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A1,"+",""), "-",""),"*",""),"/",""))
Well, this formula would replace all your numbers with "" and then Count the +/- and adds one, should do it, but is ugly:
=LEN(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(A1;"0";"");"1";"");"2";"");"3";"");"4";"");"5";"");"6";"");"7";"");"8";"");"9";""))+1
Could probably be done with RegEx, but I don't know how to do that in formulas
This makes 31+12+3-4 to ++-, Counts the LEN (3) and adds 1
Related
How do I count all the instances where a certain number is between multiple sets of numbers?
I would like to count the number of times a specific number lies between multiple ranges. For instance, Specific number: 2.5 (let's say this one is in AD1) J3=14 K3=22 L3=0 M3=6 N3=6 O3=14 P3=2 Q3=8 I need to find how many times 2.5 is between: J3&K3 L3&M3 N3&O3 P3&Q3 The reason I would like a formula for this is because I have many "specific numbers" that there are many numbers that I need to test within the same range. I know I can combine multiple CountIf, but the formula would be way too long. I remember I can use Sum(CountIf("INSERTFORMULA")) but I think somehow using a combination of Sum(CountIf(Median())) will be simpler to read SUM(Countif(MEDIAN($AD$1,J3,K3)=$AD$1,TRUE),MEDIAN($AD$1,L3,M3)=$AD$1,TRUE),MEDIAN($AD$1,N3,O3)=$AD$1,TRUE),MEDIAN($AD$1,P3,Q3)=$AD$1,TRUE)) Expected result: 2 (i.e. between L3&M3 and between P3&Q3)
Try: (Edited to correct typo) =SUMPRODUCT(($AD$1>=INDEX(J3:Q3,1,N(IF(1,{1,3,5,7}))))*($AD$1<=INDEX(J3:Q3,1,N(IF(1,{2,4,6,8})))))*emphasized text* The N(IF(1,{array})) is a method of returning discontinuous elements of an array using the INDEX function. Depending on whether you want to include/exclude the bounds of the ranges when you write between, you may want to remove the equal = sign from the comparisons.
Try: =SUMPRODUCT((J3:P3<=AD1)*(K3:Q3>=AD1))
divide your formula on two parts: first one - just calculate MEDIAN($AD$1,J3,K3) and put it in J4 (for example), then drag and copy this formula on the all raw (so in K4 will be MEDIAN($AD$1,K3,L3), and so on) second one - just summarize raw 4 with formulas - SUM(A4:AA4) it takes more space on the sheet, but more simple for creation and checking.
excel if and if error formula that has used 140 times and it throws an errors saying we can use it only 64 times
I have 140 unique numbers and trying to find that through the list which can be used in vba The formula works fine till 64 ifs are used, later I am having a trouble 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IF(FIND("5079",A2,1)>0,"5079","")),IF(FIND("5080",A2,1)>0,"5080","")),IF(FIND("5081",A2,1)>0,"5081","")),IF(FIND("5082",A2,1)>0,"5082","")),IF(FIND("5083",A2,1)>0,"5083","")),IF(FIND("5090",A2,1)>0,"5090","")),IF(FIND("5094",A2,1)>0,"5094","")),IF(FIND("5095",A2,1)>0,"5095","")),IF(FIND("5100",A2,1)>0,"5100","")),IF(FIND("5106",A2,1)>0,"5106","")),IF(FIND("5124",A2,1)>0,"5124","")),IF(FIND("5125",A2,1)>0,"5125","")),IF(FIND("5126",A2,1)>0,"5126","")),IF(FIND("5147",A2,1)>0,"5147","")),IF(FIND("5150",A2,1)>0,"5150","")),IF(FIND("5151",A2,1)>0,"5151","")),IF(FIND("5155",A2,1)>0,"5155","")),IF(FIND("5156",A2,1)>0,"5156","")),IF(FIND("5157",A2,1)>0,"5157","")),IF(FIND("5158",A2,1)>0,"5158","")),IF(FIND("5159",A2,1)>0,"5159","")),IF(FIND("5194",A2,1)>0,"5194","")),IF(FIND("5195",A2,1)>0,"5195","")),IF(FIND("5196",A2,1)>0,"5196","")),IF(FIND("5205",A2,1)>0,"5205","")),IF(FIND("5227",A2,1)>0,"5227","")),IF(FIND("5228",A2,1)>0,"5228",""))IF(FIND("5229",A2,1)>0,"5229","")),IF(FIND("5234",A2,1)>0,"5234","")),IF(FIND("5241",A2,1)>0,"5241","")),IF(FIND("5242",A2,1)>0,"5242","")),IF(FIND("5243",A2,1)>0,"5243","")),IF(FIND("5244",A2,1)>0,"5244","")),IF(FIND("5254",A2,1)>0,"5254","")),IF(FIND("5255",A2,1)>0,"5255","")),IF(FIND("5267",A2,1)>0,"5267","")),IF(FIND("5269",A2,1)>0,"5269","")),IF(FIND("5271",A2,1)>0,"5271","")),IF(FIND("5278",A2,1)>0,"5278","")),IF(FIND("5280",A2,1)>0,"5280","")),IF(FIND("5286",A2,1)>0,"5286","")),IF(FIND("5297",A2,1)>0,"5297","")),IF(FIND("5305",A2,1)>0,"5305","")),IF(FIND("5306",A2,1)>0,"5306","")),IF(FIND("5310",A2,1)>0,"5310","")),IF(FIND("5315",A2,1)>0,"5315","")),IF(FIND("5316",A2,1)>0,"5316","")),IF(FIND("5318",A2,1)>0,"5318","")),IF(FIND("5321",A2,1)>0,"5321","")),IF(FIND("5322",A2,1)>0,"5322","")),IF(FIND("5324",A2,1)>0,"5324","")),IF(FIND("5325",A2,1)>0,"5325","")),IF(FIND("5326",A2,1)>0,"5326","")),IF(FIND("5327",A2,1)>0,"5327","")),IF(FIND("5328",A2,1)>0,"5328","")),IF(FIND("5336",A2,1)>0,"5336","")),IF(FIND("5337",A2,1)>0,"5337","")),IF(FIND("5339",A2,1)>0,"5339","")),IF(FIND("5341",A2,1)>0,"5341","")),IF(FIND("5350",A2,1)>0,"5350",""))IF(FIND("5351",A2,1)>0,"5351","")),IF(FIND("5352",A2,1)>0,"5352","")),IF(FIND("5353",A2,1)>0,"5353","")),IF(FIND("5356",A2,1)>0,"5356","")),IF(FIND("5357",A2,1)>0,"5357","")),IF(FIND("5358",A2,1)>0,"5358","")),IF(FIND("5359",A2,1)>0,"5359","")),IF(FIND("5360",A2,1)>0,"5360","")),IF(FIND("5361",A2,1)>0,"5361","")),IF(FIND("5362",A2,1)>0,"5362","")),IF(FIND("5363",A2,1)>0,"5363","")),IF(FIND("5378",A2,1)>0,"5378","")),IF(FIND("5379",A2,1)>0,"5379","")),IF(FIND("5380",A2,1)>0,"5380","")),IF(FIND("5381",A2,1)>0,"5381","")),IF(FIND("5382",A2,1)>0,"5382","")),IF(FIND("5383",A2,1)>0,"5383","")),IF(FIND("5389",A2,1)>0,"5389",""))IF(FIND("5390",A2,1)>0,"5390","")),IF(FIND("5392",A2,1)>0,"5392","")),IF(FIND("6000",A2,1)>0,"6000","")),IF(FIND("6001",A2,1)>0,"6002","""")),IF(FIND("6003",A2,1)>0,"6003","")),IF(FIND("6004",A2,1)>0,"6004","")),IF(FIND("6005",A2,1)>0,"6005","")),IF(FIND("6006",A2,1)>0,"6006","")),IF(FIND("6653",A2,1)>0,"6653","")),IF(FIND("6654",A2,1)>0,"6654","")),IF(FIND("6655",A2,1)>0,"6655","")),IF(FIND("6656",A2,1)>0,"6656","")),IF(FIND("6657",A2,1)>0,"6657","")),IF(FIND("9202",A2,1)>0,"9202","")),IF(FIND("9401",A2,1)>0,"9401","")),RIGHT(A2,3,4))" the result should return the number mentioned and I am planning to sort them in ascending order. The value in A2 looks like PMGAG5216GC, PMG005216GC, PMGVV5140GC, PMG005140GC, PMGVV5148GCW, PMGAG5117GCW, PMG005117GCW, PMGAG5204GCB, PMG005204GCB, PMGAG5238GCB, PMGVV5238GCB, PMG005238GCB, PMGAG5203GCB, etc. these are some sample order numbers that are being updated and the numbers 5238 is a number that I have to find from that order to sort them in ascending order. In the same way, I have 140 numbers that have to found to sort them accordingly. The 4 digit numbers are fixed in the orders and it should be one from the 140 number list that I had mentioned
Rule of thumb, if you see yourself nesting anything deeper than 5 or 6 levels, stop and take the time to see if there wouldn't be a more easily maintainable way to do the same thing. Hitting hard limits (e.g. 64 levels of nesting) is rarely a sign that things are done in an optimal fashion. PMGAG5216GC PMG005216GC PMGVV5140GC PMG005140GC PMGVV5148GCW PMGAG5117GCW PMG005117GCW PMGAG5204GCB PMG005204GCB PMGAG5238GCB PMGVV5238GCB PMG005238GCB PMGAG5203GCB Assuming the format is consistently the same, you can grab the 4 characters starting at the 6th position, and then verify if these 4 characters exist in a lookup table that contains the 140 values you're interested in. The MID function can be used to do this. You could leverage the fact that VLOOKUP in the first column of the lookup table would return the lookup value itself, and a lookup failure would be #N/A, so wrapping it with IFERROR to turn that into an empty string would look like this: =IFERROR(VLOOKUP(MID(A2,6,4),theLookupTable[TheLookupColumn],1,FALSE),"") Now, if looks like some of the values need a prefix e.g. "00000A-"; include that prefix (with the dash, so you don't have to conditionally add it in the formula) in the lookup table (say, in some [Prefix] column) where it's needed, and just concatenate it after the lookup. =IFERROR(VLOOKUP(MID(A2,6,4),theLookupTable[TheLookupColumn],1,FALSE) & VLOOKUP(MID(A2,6,4),theLookupTable[#[TheLookupColumn]:[ThePrefixColumn]],2,FALSE),"") Better if you can turn the MID(A2,6,4) part into a helper cell instead of computing it twice - use that MID function on your source data to populate the lookup table. The lookup table might look like this: TheLookupColumn ThePrefixColumn 5216 00000A- 5140 00000B- 5148 00000C- ... 3901 ... Sort the table by TheLookupColumn, and the lookups should be pretty fast.
If you just want to show the first number from your lookup list which is contained in any given order number you can do something like this: It's an array formula so you need to enter it using Ctrl + Shift + Enter Assumes there can be only one match per order number and that none of the items in your lookup list are substrings of another item (though a workaround for that would be to sort your lookup list in descending order of item length)
Excel: generate specific length string reference
I've found some tools that can do what I want, but despite trying various options I can't work out how to put them in my existing formula! I'm trying to generate an invoice reference number, which would look like 'ABC000012' - with the first row being ABC000001 and increasing in number as each row is added. I can currently generate 'ABC1' and so on, but can't work out how to add the preceding 0s. I'm currently using CONCATENATE as follows: =IF(ISBLANK(B2),,CONCATENATE("ABC",(ROW(1:1)))) What do I need to add to this, and where, in order to get the references I'm looking for? I'm also happy to be advised that I should change the whole formula if there's something different that will work better Thanks
Use TEXT() to set the preceding 0: =IF(ISBLANK(B2),"",CONCATENATE("ABC",TEXT(ROW(1:1),"000000")))
=IF(ISBLANK(B2),"","ABC"&RIGHT("000000"&ROW(1:1),6)) This is based off Scott Craner's answer. The difference is that is will limit the number of digits in your invoice to 6 characters. if you want it to always be 8 characters long change the 6 to an 8 and increase the number of 0 between the " ". Alternatively you could also do: =IF(ISBLANK(B2),"","ABC"&RIGHT(rept(0,6)&ROW(1:1),6)) In the above formula to change the number of digits n the invoice number, you would need to change both 6's Caveat: If there is a blank cell in the middle of your list, that number will be skipped for each blank cell. To avoid this, you will need a different counting method than row(1:1).
retrieve part of the info in a cell in EXCEL
I vaguely remember that it is possible to parse the data in a cell and keep only part of the data after setting up certain conditions. But I can't remember what exact commands to use. Any help/suggestion? For example, A1 contains the following info 0/1:47,45:92:99:1319,0,1320 Is there a way to pick up, say, 0/1 or 1319,0,1320 and remove the rest unchosen data? I know I can do text-to-column and set the delimiter, followed by manually removing the "un-needed" data, but my EXCEL spreadsheet contains 100 columns X 500000 rows with each cell looking similar to the data above, so I am afraid EXCEL may crash before finishing the work. (have been trying with LEFT, LEN, RIGHT, MID, but none seems to work the way I had hoped) Any suggestion will be greatly appreciated.
I think what you are looking for is combination of find and mid, but you'll have to work out exactly how you want to split your string: A1 = 0/1:47,45:92:99:1319,0,1320 //your number B1 = Find(“:“,A1) //location of first ":" symbol C1 = LEN(A1) - B1 //character count to copy ( possibly requires +1 or -1 after B1. =Left(A1,B1) //left of your symbol =Mid(A1,B1+1,C1) //right size from your symbol (you can also replace C1 with better defined number to extract only 1 portion //You can also nest the statements to save space, but usually at cost of processing quantity increase This is the concept, you will probably need to do it in multiple cells to split a string as long as yours. For multiple splits you probably want to replicate this command to target the result of previous right/mid command. That way, you will get cell result sequence like: 0/1:47,45:92:99:1319,0,1320; 47,45:92:99:1319,0,1320; 92:99:1319,0,1320; 99:1319,0,1320...... From each of those you can retrieve left side of the string up to ":" to get each portion of a string. If you are working with a large table you probably want to look into VB scripting. To my knowledge there is no single excel command that can take 1 cell and split it into multiple ones.
Let me try to help you about this, I am not a professional so you may face some problems. First of all my solution contains 2 columns to be added to the source column as you can see below. However you can improve formulas with this principle. Column B Formula: =LEFT(A2,FIND(":",A2,1)-1) Column C Formula: =RIGHT(A2,LEN(A2)-FIND("|",SUBSTITUTE(A2,":","|",LEN(A2)-LEN(SUBSTITUTE(A2,":","")))))
Given you statement of having 100x columns I imagine in some instances you are needing to isolate characters in the middle of your string, thus Left and Right may not always work. However, where possible use them where you can. Assuming your string is in cell F2: 0/1:47,45:92:99:1319,0,1320 =LEFT(F2,3) This returns 0/1 which are the first 3 characters in the string counting from the left. Likewise, Right functions similarly: =RIGHT(F2,4) This returns 1320, returning the 4 characters starting from the right. You can use a combination of Mid and Find to dynamically find characters or strings based off of defined characters. Here are a few examples of ways to dynamically isloate values in your string. Keep in mind the key to these examples is the nested Find formula, where the inner most Find is the first character to start at in the string. 1) Return 2 characters after the second : character In cell F2 I need to isolate the "92": =MID(F2,FIND(":",F2,FIND(":",F2)+1)+1,2) The inner most Find locates the first : in the string (4 characters in). We add the +1 to move to the 5th character (moving beyond the first : so the second Find will not see it) and move to the next Find which starts looking for : again from that character. This second Find returns 10, as the second : is the 10th character in the string. The Mid formula takes over here. The formula is saying, Starting at the 10th character return the following 2 characters. Returning two characters is dictated by the 2 at the end of the formula (the last part of the Mid formula). 2) In this case I need to find the 2 characters after the 3rd : in the string. In this case "99": =MID(F2,FIND(":",F2,FIND(":",F2,FIND(":",F2)+1)+1)+1,2) You can see we have simply added one more nested Find to the formula in example 1.
Custom validation using IF() and Len()
I made a custom phone format ###-###-#### so that a phone # can be entered only as 5555555555 => 555-555-5555 or as 555-555-55555. I need a non-vba solution i.e one I can enter in the Data Validation window that checks the cell length and validates it if the length is 10 OR 12. I have been trying for a long time but can not get it by trial and error or googling. My best guess is (which does not work) =IF((LEN(E2:E32)=12,0),( LEN(E2:E32)=10,0)) Thanks
This is not easy since Excel does not have a built in pattern matching function - you can only use built in functions in validation checks. There is a solution though! Fortunately you can check validation based on the state of a dependent cell. That's the approach we'll take here. 1) Your first job is to format the telephone number as text (my functions assume you've done this) so Excel doesn't trim leading zeros. In practice you'd format the whole column that way. Let's assume cell A1 will contain the phone number. 2) The validation formula will be ridiculously large if you attempt to put it in one cell and will be difficult to maintain. What we will do is put the validation stuff "off-spreadsheet"; i.e. in a column that's normally not visible to the user. That said, we'll use columns B,C and D for clarity. (Just cut and paste these elsewhere once you're done). 3) In B1 put =OR(C1,D1) 4) In C1 put =IFERROR(IF(LEN(A1)=10,VALUE(A1)*0 + 1,FALSE),FALSE). This validates the format with no dashes. 5) In D1 put =IFERROR(IF(OR(LEN(A1)=12,LEN(A1)=13),IF(AND(MID(A1,4,1)="-",MID(A1,8,1)="-"),VALUE(LEFT(A1,3) & MID(A1,5,3) & MID(A1,9,32767)) * 0 + 1,FALSE),FALSE),FALSE). This validates the format with the dashes. Three tricks I'm using are (i) IFERROR is used to write False if the result would otherwise be #VALUE. This allows me to be more woolly in the programming, and (ii) the VALUE(n) * 0 + 1 pattern returns 1 if n is a number and, conveniently will compute #VALUE and delegate this to the surrounding function if n is not a number. Finally (iii) the 32767 in the MID function allows us to compare the remaining characters in a string without having to use a more clumsy RIGHT expression. 32767 is the limit on the number of characters in a cell. Perhaps I'm out by 1 here; no downvotes due to that please ;-) 6) Lastly, for cell A1, choose custom validation and set =B1 as the validation formula. This does it! It will pass all your three formats: 5555555555, 555-555-5555 or 555-555-55555 where you've used 5 as a wildcard digit.