I am able to enter username and password, but not able to press login button in selenium. May you advise? I didn't put the specific website, sorry.
thanks so much for your help!
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.chrome.options import Options
chrome_options = Options()
chrome_options.add_argument("--disable-infobars")
driver = webdriver.Chrome(executable_path = "C:\Python36-32\selenium\chromedriver",chrome_options=chrome_options)
driver.get("website")
elem = driver.find_element_by_name("UserName")
elem.send_keys("test")
elem = driver.find_element_by_name("Password")
elem.send_keys("test")
Above Work
Below, Not Sure Here
elem = driver.find_element_by_type("submit")
elem.click()
Outer HTML
<input value="" class="userid-button" type="submit">
Selector
#online_login > input.userid-button
XPath
//*[#id="online_login"]/input[3]
Element
<input value="" class="userid-button" type="submit">
To click the login button you can use the following block of code:
xpath:
elem = driver.find_element_by_xpath("//input[#class='userid-button'][#type='submit']")
elem.click()
css:
elem = driver.find_element_by_css_selector("input.userid-button[type=submit]")
elem.click()
You're on the right track. elem = driver.find_element_by_type("submit")
elem.click() will only work if the login button is the only "submit" element on the page. Pages usually come with multiple "submit" elements, so it's probably not a great way to do it. The best way to do it, in my opinion, is to use the XPath or the CSSpath for the "submit" element you want. Since both XPath and CSSpath will give you a unique path for each individual element, this will find the exact "submit" button you want to click.
Related
I am trying to click show results button after selecting filter on linkedin. I have correctly found the button element but it is giving me this error:
selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable: [object HTMLDivElement] has no size and location
Here is my piece of code that I have tried:
element = WebDriverWait(self, 10).until(EC.presence_of_element_located((By.CSS_SELECTOR, 'div[class="artdeco-hoverable-content__shell"]')))
box = self.find_element_by_css_selector('div[class="artdeco-hoverable-content__shell"]')
ele = box.find_element_by_css_selector('button[data-control-name="filter_show_results"]')
ActionChains(self).move_to_element(ele).click(ele).perform()
I have also tried:
self.execute_script("arguments[0].click();", ele)
What's the reason behind this?
HTML of the results button:
<div class="reusable-search-filters-buttons display-flex justify-flex-end mt3 ph2">
<button data-test-reusables-filter-cancel-button="true" data-control-name="filter_pill_cancel" aria-label="Cancel Locations filter" id="ember429" class="artdeco-button artdeco-button--muted artdeco-button--2 artdeco-button--tertiary ember-view" type="button"><!---->
<span class="artdeco-button__text">
Cancel
</span></button>
<button data-test-reusables-filter-apply-button="true" data-control-name="filter_show_results" aria-label="Apply current filter to show results" id="ember430" class="artdeco-button artdeco-button--2 artdeco-button--primary ember-view ml2" type="button"><!---->
<span class="artdeco-button__text">
Show results
</span></button>
</div>
Edit 2: Here is the image of the button , I am trying to click.
https://ibb.co/4Y7VN0j
Edit 3: Image with dev tools open : https://ibb.co/CJdtNM1
The desired element is a Ember.js enabled element, so to click on the Show results button instead of presence_of_element_located() you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following locator strategies:
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button[data-control-name='filter_show_results'][aria-label='Apply current filter to show results'] span.artdeco-button__text"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//button[#data-control-name='filter_show_results' and #aria-label='Apply current filter to show results']//span[contains(., 'Show results')]"))).click()
Note: You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Having trouble figuring out how to click the Next button at the bottom of the table on this page:
https://www.zacks.com/stocks/industry-rank/reit-and-equity-trust-other-266/stocks-in-industry
This is what I've tried:
from bs4 import BeautifulSoup
import requests
import csv, random, time
from pandas.io.html import read_html
from selenium import webdriver
from selenium.webdriver.support.ui import Select
url = 'https://www.zacks.com/stocks/industry-rank/reit-and-equity-trust-other-266/stocks-in-industry'
# Open Chrome
driver = webdriver.Chrome()
# Send Chrome to the URL
page = driver.get(url)
# Wait for page to load a few seconds
timeDelay = random.randrange(4, 8)
time.sleep(timeDelay)
# Try to click the darn button
element = driver.find_element_by_xpath('//*[#id="industry_rank_table_next"]')
driver.execute_script("arguments[0].click();", element)
...and
element = driver.find_element_by_xpath('//*[#id="industry_rank_table_next"]')
element.send_keys("\n")
...found from other answers but not working for me. Simply using .click() does not work. I've also tried selecting the button using css_selector, partial_link_text, and class_name but still no success. I've ran into this on a few sites. Any ideas?
To click() on the element with text as Next you have to induce WebDriverWait for the element to be clickable and you can use either of the following solutions:
Using LINK_TEXT:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.LINK_TEXT, "Next"))).click()
Using CSS_SELECTOR:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a.paginate_button next#industry_rank_table_next"))).click()
Using XPATH:
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//a[#class='paginate_button next' and #id='industry_rank_table_next']"))).click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
if the element which you have to click have parent element then you can find parent by findElements method and after than you just need to pass the index of the element like 0 or 1 or so on.. and then you can perform click action on that
Want to click on third li from second ul:
<ul id="select-123" style="width: 1180px; display: none;">
<li class="" style="display:none;">
<li class="">
<li class="">
<li class="">
</ul>
<ul id="select-123" style="width: 1180px; display: none;">
<li class="" style="display:none;">
<li class="">
<li class="">
<li class="">
</ul>
Code I am trying is to select third li from second ul which does not work:
driver.findElements(By.css(ul[id*='select-123'])).then(function(elems) {
elems[2].then(function(lis) {
driver.findElement(By.css("ul[id*='select-123'] li:nth-child(3)")).click();
});
});
Another way if you don't wish to add additional wait(s) to your code and just click the button:
using javascript click:
element = driver.find_element_by_xpath("//a[#class='paginate_button next' and #id='industry_rank_table_next']")
driver.execute_script("arguments[0].click();", element)
UPDATE:
I didn't notice this earlier, but
element = driver.find_element_by_xpath('//*[#id="industry_rank_table_next"]')
driver.execute_script("arguments[0].click();", element)
...works as it clicks the link successfully, but gives me a
selenium.common.exceptions.WebDriverException: Message: unknown error: call function result missing 'value'
...error after it clicks the link. So to get around this, I've just added a try/except to handle the error. ie:
try:
element = driver.find_element_by_xpath('//*[#id="industry_rank_table_next"]')
driver.execute_script("arguments[0].click();", element)
except:
pass
...which seems to work. Seems like such a stupid observation on my part, but thank you to everyone for your help. Hopefully something in here will help someone else in the future.
I have a dropdown element, I want to select the All option, the corresponding HTML code is:
<div class="dataTables_length" id="indicators_length">
<label>
<span class="result-mune">
<span>Results </span>per page:
</span>
<select name="indicators_length" aria-controls="indicators" class="jcf-hidden">
<option value="25">25</option>
<option value="50">50</option>
<option value="100">100</option>
<option value="200">200</option>
<option value="-1">All</option>
</select>
<span class="jcf-select jcf-unselectable">
<span class="jcf-select-text">
<span class="">25</span>
</span>
<span class="jcf-select-opener"></span>
</span>
</label>
</div>
the select element is not highlighted using the browser Inspect method, looks like this drop down is triggered by js.
I tried to use the Select class described here:
select = Select(self._wait.until(EC.presence_of_element_located_by((By.XPATH, "//div[#id = 'indicators_length']//select[#name = 'indicators_length']")))
select.select_by_value('-1')
not working. and ActionChain method and even execute_script method, all not working. This bothers me a lot, hope somebody can help.
you don't really need to select the option just click the span and it will set the option automatically.
driver = webdriver.Chrome()
driver.get("......")
# click "OK, I Agree" cookies
driver.find_element_by_css_selector('.agree-button.eu-cookie-compliance-default-button').click()
# scroll down to make dropdown option visible
driver.find_element_by_css_selector('h4.pane-title').location_once_scrolled_into_view
select = driver.find_element_by_xpath('//span[#class="result-mune"]/following-sibling::span')
select.click()
# wait until javascript generate fake option element because it actually span
time.sleep(1)
select.find_element_by_css_selector('ul li span[data-index="4"]').click()
try this one:
driver.execute_script('document.getElementsByName("indicators_length")[0].value = 50;
If its created and loaded after page load make sure you add some sleep to let it render;
I tried using the Selenium Select class, it can find the element but it cannot select an option from the element. Not sure whats going on, could be the class "jcf-hidden" on the element.
Having said that, I took a stab at it and below is my approach. Try it out, it worked on my system, you have to handle the clicking of "OK, I Agree" button click, I did that manually.
import time
from selenium.webdriver import Chrome
driver = Chrome()
driver.get('https://www.topuniversities.com/university-rankings/world-university-rankings/2019')
# Remove this nasty time.sleep and implement webdriver wait
# Handle the OK, I Agree
time.sleep(5)
i_agree = driver.find_element_by_css_selector('button[class*="eu-cookie-compliance-default-button"]')
i_agree.click()
time.sleep(5)
# Open the Select
rankings_length = driver.find_element_by_id('qs-rankings_length')
select_opener = rankings_length.find_element_by_class_name('jcf-select-opener')
select_opener.click()
# loop through the list
select_content = rankings_length.find_element_by_class_name('jcf-list-content')
for content in select_content.find_elements_by_tag_name('li'):
if content.text == 'All':
content.click()
I want to show more page by click a button to run a JavaScript function as below:
<div class="loading" style="display:none;">
<p class="btn blue"><span>さらに表示</span></p>
</div>
I tried the code, it doesn't work, what can I do?
more_info_button = driver.find_element_by_tag_name('a').get('href=javascript:void(0);')
more_info_button.click()
If you want to click link that contains attribute #href equal to "javascript:void(0);", try
more_info_button = driver.find_element_by_xpath('//a[#href="javascript:void(0);"]')
more_info_button.click()
Same with CSS selector:
more_info_button = driver.find_element_by_css_selector('a[href="javascript:void(0);"]')
To locate link by text in preceding paragraph:
more_info_button = driver.find_element_by_xpath('//a[preceding-sibling::p[.="さらに表示"]]')
Update
Try below code to get extended topics list after clicking the button:
from selenium.webdriver.support.ui import WebDriverWait
topics_number = len(driver.find_elements_by_class_name('topics'))
more_info_button.click()
WebDriverWait(driver, 10).until(lambda driver: len(driver.find_elements_by_class_name('topics')) > topics_number)
extended_list = driver.find_elements_by_class_name('topics')
I'm trying to check the checkbox on a page: https://www.pkobp.pl/poi/?clients=1,2,3.
<li class="poi-filter-top__el">
<div class="poi-icon poi-icon--facility"></div>
<input type="checkbox" id="poi-legend-facility" class="js-poi-legend" name="type" value="facility"> <label for="poi-legend-facility" class="poi-legend input-checkbox poi-filter-top__label">Oddział</label> Wybierz rodzaj
</li>
I try to do this with:
checkboxes = driver.find_elements_by_id("poi-legend-facility")
for checkbox in checkboxes:
if not checkbox.is_selected():
checkbox.click()
But it doesn't work. Can you help me?
You have only one checkbox with such ID (poi-legend-facility).
You can do like this:
checkbox = driver.find_element_by_id("poi-legend-facility")
if not checkbox.is_selected():
checkbox.click()
Or in your case try this code:
checkboxes = driver.find_elements_by_id("poi-legend-facility")
checkboxes[0].click()
PS: Using ID for finding element faster than finding by XPath.
This is the the only way I could find to check all the boxes in that page and break out of loop. Give this a shot as well.
from selenium import webdriver
import time
driver = webdriver.Chrome()
driver.get('https://www.pkobp.pl/poi/?clients=1,2,3')
for tickbox in driver.find_elements_by_css_selector(".input-checkbox"):
try:
tickbox.click()
time.sleep(7)
except:
break
driver.quit()
Try this xpath
checkElements= driver.find_element_by_xpath("//input[#type='checkbox' and #value='facility']")
checkElements.click()
I don't know python so might be syntax error but path is correct