As it known Apache spark saves files by parts i.e foo.csv/part-r-00000..
I save files on Swift Object storage now I want want to get the files using Openstack swift API but when I do curl on foo.csv I get zero file
How I download the contents of the file.
You can take any REST client and list content of the object store. Don't do curl on 'foo.txt', since it's zero size object. You need to list container with prefix 'foo.txt', this will return you all the parts.
Alternatively you can use Apache Spark and read foo.txt (Spark will automatically list and return all the parts)
Related
We have recently made changes to how we connect to ADLS from Databricks which have removed mount points that were previously established within the environment. We are using databricks to find points in polygons, as laid out in the databricks blog here: https://databricks.com/blog/2019/12/05/processing-geospatial-data-at-scale-with-databricks.html
Previously, a chunk of code read in a GeoJSON file from ADLS into the notebook and then projected it to the cluster(s):
nights = gpd.read_file("/dbfs/mnt/X/X/GeoSpatial/Hex_Nights_400Buffer.geojson")
a_nights = sc.broadcast(nights)
However, the new changes that have been made have removed the mount point and we are now reading files in using the string:
"wasbs://Z#Y.blob.core.windows.net/X/Personnel/*.csv"
This works fine for CSV and Parquet files, but will not load a GeoJSON! When we try this, we get an error saying "File not found". We have checked and the file is still within ADLS.
We then tried to copy the file temporarily to "dbfs" which was the only way we had managed to read files previously, as follows:
dbutils.fs.cp("wasbs://Z#Y.blob.core.windows.net/X/GeoSpatial/Nights_new.geojson", "/dbfs/tmp/temp_nights")
nights = gpd.read_file(filename="/dbfs/tmp/temp_nights")
dbutils.fs.rm("/dbfs/tmp/temp_nights")
a_nights = sc.broadcast(nights)
This works fine on the first use within the code, but then a second GeoJSON run immediately after (which we tried to write to temp_days) fails at the gpd.read_file stage, saying file not found! We have checked with dbutils.fs.ls() and can see the file in the temp location.
So some questions for you kind folks:
Why were we previously having to use "/dbfs/" when reading in GeoJSON but not csv files, pre-changes to our environment?
What is the correct way to read in GeoJSON files into databricks without a mount point set?
Why does our process fail upon trying to read the second created temp GeoJSON file?
Thanks in advance for any assistance - very new to Databricks...!
Pandas uses the local file API for accessing files, and you accessed files on DBFS via /dbfs that provides that local file API. In your specific case, the problem is that even if you use dbutils.fs.cp, you didn't specify that you want to copy file locally, and it's by default was copied onto DBFS with path /dbfs/tmp/temp_nights (actually it's dbfs:/dbfs/tmp/temp_nights), and as result local file API doesn't see it - you will need to use /dbfs/dbfs/tmp/temp_nights instead, or copy file into /tmp/temp_nights.
But the better way would be to copy file locally - you just need to specify that destination is local - that's done with file:// prefix, like this:
dbutils.fs.cp("wasbs://Z#Y.blob.core.windows.net/...Nights_new.geojson",
"file:///tmp/temp_nights")
and then read file from /tmp/temp_nights:
nights = gpd.read_file(filename="/tmp/temp_nights")
For my research I have a dataset of about 20,000 gziped multiline json files (~2TB, all have the same schema). I need to process and clean this data (I should say I'm very new to data analytics tools).
After spending a few days reading about Spark and Apache Beam I'm convinced that the first step would be to first convert this dataset to NDJSONs. In most books and tutorials they always assume you are working with some new line delimited file.
What is the best way to go about converting this data?
I've tried to just launch a large instance on gcloud and just use gunzip and jq to do this. Not surprisingly, it seems that this will take a long time.
Thanks in advance for any help!
Apache Beam supports unzipping file if you use TextIO.
But the delimiter remains to be New Line.
For multiline json you can read complete file using in parallel and then convert the json string to pojo and eventually reshuffle the data to utilize parallelism.
So the steps would be
Get the file list > Read individual files > Parse file content to json objects > Reshuffle > ...
You can get the file list by FileSystems.match("gcs://my_bucker").metadata().
Read individual files by Compression Compression.detect((fileResouceId).getFilename()).readDecompressed(FileSystems.open(fileResouceId))
Converting to NDJSON is not necessary if you use sc.wholeTextFiles. Point this method at a directory, and you'll get back an RDD[(String, String)] where ._1 is the filename and ._2 is the content of the file.
Is there any way one can append two files in GCS, suppose file one is a full
load and second file is an incremental load. Then what's the way we can append
the two?
Secondly, using gsutil compose will append the two files including the attributes
names as well. So, in the final file I want the data of the two files.
You can append two separate files using compose in the Google Cloud Shell and rename the output file as the first file, like this:
gsutil compose gs://bucket/obj1 [gs://bucket/obj2 ...] gs://bucket/obj1
This command is meant for parallel uploads in which you divide a large object file in smaller objects. They get uploaded to Google Cloud Storage and then you can append them to get the original file. You can find more information on Composite Objects and Parallel Uploads.
I've come up with two possible solutions:
Google Cloud Function solution
The option I would go for is using a Cloud Function. Doing something like the following:
Create an empty bucket like append_bucket.
Upload the first file.
Create a Cloud Function to be triggered by new uploaded files on the
bucket.
Upload the second file.
Read the first and the second file (you will have to download them as string first).
Make the append operation.
Upload the result to the bucket.
Google Dataflow solution
You can also do it with Dataflow for BigQuery (keep in mind it’s still in beta).
Create a BigQuery dataset and table.
Create a Dataflow instance, from the template Cloud Storage Text to BigQuery.
Create a Javascript file with the logic to transform the text.
Upload your files in Json format to the bucket.
Dataflow will read the Json file, execute the Javascript code and append the new data to the BigQuery dataset.
At last, export the BigQuery query result to Cloud Storage.
I have some results from a Spark application saved in the HDFS as files called part-r-0000X (X= 0, 1, etc.). And, because I want to join the whole content in a file, I'm using the following command:
hdfs dfs -getmerge srcDir destLocalFile
The previous command is used in a bash script which makes empty the output directory (where the part-r-... files are saved) and, inside a loop, executes the above getmerge command.
The thing is I need to use the resultant file in another Spark program which need that merged file as input in the HDFS. So I'm saving it as local and then I upload it to the HDFS.
I've thought another option which is write the file from the Spark program in this way:
outputData.coalesce(1, false).saveAsTextFile(outPathHDFS)
But I've read coalesce() doesn't help with the performance.
Any other ideas? suggestions? Thanks!
You wish to merge all the files into a single one so that you can load all the files at once into a Spark rdd, is my guess.
Let the files be in Parts(0,1,....) in HDFS.
Why not load it with wholetextFiles, which actually does what you need.
wholeTextFiles(path, minPartitions=None, use_unicode=True)[source]
Read a directory of text files from HDFS, a local file system (available on all nodes), or any Hadoop-supported file system URI. Each file is read as a single record and returned in a key-value pair, where the key is the path of each file, the value is the content of each file.
If use_unicode is False, the strings will be kept as str (encoding as utf-8), which is faster and smaller than unicode. (Added in Spark 1.2)
For example, if you have the following files:
hdfs://a-hdfs-path/part-00000 hdfs://a-hdfs-path/part-00001 ... hdfs://a-hdfs-path/part-nnnnn
Do rdd = sparkContext.wholeTextFiles(“hdfs://a-hdfs-path”), then rdd contains:
(a-hdfs-path/part-00000, its content) (a-hdfs-path/part-00001, its content) ... (a-hdfs-path/part-nnnnn, its content)
Try SPARK BucketBy.
This is a nice feature via df.write.saveAsTable(), but this format can only be read by SPARK. Data shows up in Hive metastore but cannot be read by Hive, IMPALA.
The best solution that I've found so far was:
outputData.saveAsTextFile(outPath, classOf[org.apache.hadoop.io.compress.GzipCodec])
Which saves the outputData in compressed part-0000X.gz files under the outPath directory.
And, from the other Spark app, it reads those files using this:
val inputData = sc.textFile(inDir + "part-00*", numPartition)
Where inDir corresponds to the outPath.
I am using Stream Analytics to join streaming data (via IoT Hub) and reference data (via blob storage). The reference data blob file is generated every minute with latest data and is in a format "filename-{date} {time}.csv". The reference blob file data is used in the Azure Machine Learning function as parameters in SA job. The output of stream analytics job (into Azure SQL or Power BI) seems to be generating multiple rows instead of one for Azure Machine Learning function's output, one each for parameter values from previous blob files. My understanding is that it should only use the latest blob file content but looks like it is using all the blob files and generating multiple rows from AML output. Here is the query I am using:
SELECT
AMLFunction(Ref.Input1, Ref.Input2), *
FROM IoTInput Stream
LEFT JOIN RefBlobInput Ref ON Stream.DeviceId = Ref.[DeviceID]
Please can you advice if the query or the file path needs changing to avoid duplicating records? Thanks
To take effect of only latest file, you need to store your file in particular folder structure.
If you have note down, whenever you select reference data file as stream input; stream input dialog asks you for folder structure along with date and time format.
Stream always search for reference file from latest {date}/{time} folder. i.e. you need to store your file like,
2018-01-25/07:30/filename.json (YYYY-MM-DD/HH-mm/filename.json)
NOTE: Here your time folder needs to be unique for each minute. Same as, date folder needs to be unique for each date. Whenever you create new file, create it with under new time stamp folder and under current date folder.
You can use any datetime format that stream input supports.