I have tried EVERY " if name=='main' " suggestion and it still fails (or maybe I'm doing it wrong or not understanding it). I am also Not trying to run things from a command line. While testing things out in Pycharm, I am trying to get the main file to pop-up with a gui and then when I click on the button, trying to get the first window to go away and the second file/gui to pop up in its place.
Any help would be greatly appreciated.
this is the main one I am trying to start with but opens up with the second gui first
from tkinter import *
from tryingstuff import EmdMain
class App:
def __init__(self, master):
frame = Frame(master)
frame.pack()
#firebutton
self.fphoto = PhotoImage(file="../icon/fireorig.png")
self.fbutton = Button(frame, image=self.fphoto)
self.fbutton.config( height=228, width=200)
self.fbutton.pack(side=LEFT)
#emsbutton
self.mphoto = PhotoImage(file="../icon/ems.png")
self.emsButton = Button(frame, image=self.mphoto, command=EmdMain)
self.emsButton.config( height=224, width=197)
self.emsButton.pack(side=RIGHT)
root = Tk()
root.title("ProQA Card set")
app = App(root)
root.mainloop()
This is the second file
from tkinter import *
def EmdMain():
frame = Frame()
frame.pack()
abdominalPnB = Button(frame, text="01_Abdominal Pain")
abdominalPnB.config(anchor="w", width=20, height=1)
abdominalPnB.grid(row=0, column=0)
root = Tk()
app = EmdMain()
root.mainloop()
if __name__=='__main__':
EmdMain()
Related
I have 3 modules (small, dont worry).
main_module = it has a combobox and a button. Comobobox list must be update each time a list (in module2) increases in number of names (combo values). Button calls the second window (module2)-->
myapp_second_window.py which has a entry box and another button. We write a name in the entry, push the button...voila..the list increases. In the origina app the list is created automatically when (2) is called.
Now I pass the list to a Pages.variable that is in -->
my_pages_to_connect_modules.
So, when app start I can populate combobox calling (2) to generate a Pages.variable list or populate combobox with json previously written.
The problem? --> how populate combobox while app is running. I mean, we go to (2) create a new name in entry come back to (1) and it is already there.
main_module
import tkinter as tk
from tkinter import*
from tkinter import ttk
import myapp_second_window
from myapp_second_window import SecondClass
root= Tk()
root.geometry("500x500")
root.title('myAPP_Main_Window')
class MainClass:
def __init__(self, parent,myapp_second_window):
self.parent = parent
self.my_widgets1()
def call_second_page (self):
Window2 = tk.Toplevel(root)
Window2.geometry('400x300')
myapp_second_window.SecondClass(Window2)
def my_widgets1(self):
self.field1_value = StringVar()
self.field1 = ttk.Combobox(self.parent, textvariable=self.field1_value)
self.field1['values'] = [1,2] # Pages.variable comes Here
self.field1.grid( row=0, column=0)
self.myButton = tk.Button(self.parent, text = "Call Second module", command = self.call_second_page)
self.myButton.grid(row=2, column=0)
if __name__ == '__main__':
app = MainClass(root, myapp_second_window)
root.mainloop()
myapp_second_window.py
import tkinter as tk
from tkinter import*
from tkinter import ttk
root= Tk()
root.minsize(550,450)
root.maxsize(560,460)
root.title('myAPP_Second_Window')
class SecondClass:
def init(self, parent):
self.parent = parent
self.my_widgets()
self.names = []
def my_widgets(self):
mylabel = Label(self.parent, text='Insert new name in next widget:')
mylabel.grid(column=0, row=0, sticky=W, pady=3)
button1 = tk.Button(self.parent, text="Click to enter Names in list", command=self.addToList)
button1.grid(column=3, row=0, sticky=W, pady=3)
self.name = StringVar()
valueEntry = tk.Entry(self.parent, textvariable= self.name)
valueEntry.grid(row=1, column=0, sticky=W, pady=3)
def addToList(self):
self.names.append(self.name.get())
print('listentries', self.names)
Pages.list_of_names = self.names
my_pages_to_connect_modules.
class Pages():
list_of_names = " "
It`s been challenging to me, every help is welcome. But please dont say just that I must update main window, I need to know how. Thanks to all of you.
from tkinter import *
def first():
root1 = Tk()
Button(root1, text = 'get Second', command= second).pack()
root1.mainloop()
def second():
root2 = Tk()
user_input = StringVar()
Entry(root2, text = user_input).pack()
Button(root2, text = 'submit', command = lambda : print(user_input.get(), '\t printed')).pack()
root2.mainloop()
first()
You are making a few basic mistakes in here -
You if want to use a second window, it should be Toplevel not root Tk window. There should be only one root window in the program. This should act as parent to all the windows.
Its a good practice in most of the cases to define the widgets like Button, Entry separately and then pack() them.
Entry should have 'textvariable' not 'text'
Following is the updated code which may help you -
from tkinter import *
root = Tk()
def first():
button = Button(root, text = 'get Second', command= second)
button.pack()
root.mainloop()
def second():
window2 = Toplevel(root)
user_input = StringVar()
entry = Entry(window2, textvariable=user_input)
entry.pack()
button = Button(window2, text = 'submit', command = lambda: print(user_input.get()))
button.pack()
first()
from tkinter import *
def printSomething():
inputValue=textBox.get("1.0","end-1c")
res=response(inputValue)
label = Label(root, text=res)
#this creates a new label to the GUI
label.pack()
root = Tk()
button = Button(root, text="Print Me", command=printSomething)
button.pack()
textBox=Text(root, height=2, width=10)
textBox.pack()
root.mainloop()
I have written a python code that returns text. and print that in tkinter label.while i try to execute it shows "None" in label.
It would probably be better to create the label in the global namespace once and then just update the label every time you press the button.
I also recommend using import tkinter as tk vs from tkinter import * as it provides better maintainability as your code grows and you do not end up overwriting built in methods.
I have updated your code and changed a few things to better fit the PEP8 standard.
import tkinter as tk
def print_something():
label.config(text=text_box.get("1.0", "end-1c"))
root = tk.Tk()
tk.Button(root, text="Print Me", command=print_something).pack()
text_box = tk.Text(root, height=2, width=10)
text_box.pack()
label = tk.Label(root)
label.pack()
root.mainloop()
Just changing your line:
res = response(inputValue)
to
res = inputValue
worked for me, creating a new label every time I pressed the button.
I am trying to open a second window in tkinter but it always appears as a tab rather than separately. Code showing the problem is as follows:
import tkinter as tk
class MainWindow:
def __init__(self, master):
self.master = master
frame = tk.Frame(self.master)
button = tk.Button(frame, text = 'New Window', width = 25, command = self.new_window)
button.pack()
frame.pack()
def new_window(self):
newWindow = tk.Toplevel(self.master)
SecondWindow(newWindow)
class SecondWindow:
def __init__(self, master):
frame = tk.Frame(master)
quitButton = tk.Label(frame, text = 'Second Window')
quitButton.pack()
frame.pack()
def main():
root = tk.Tk()
app = MainWindow(root)
root.mainloop()
if __name__ == '__main__':
main()
When I run this I get the following output:
Clicking the button gives:
(Ignoring the secondary issue of the size) if we expand it we get the following:
I can get a separate window by dragging the tab. How to I code this so that I get the window displaying as a separate window when I click the button ?
I'm very new to coding and I tried a bunch of different things but none of them are working for me.
Here is my code. With this code everything is working correctly so far, but i'm unsure of how to implement the read function into my code. My main problem is that in everyone's read examples they use the exact filename, whereas I need to use raw input.
Edit: I was able to solve this on my own, by using open(filename, "r") it lets you pick which file to read. Instead of having "6543.txt" which would only open that specific file.
from tkinter import Tk
from tkinter import *
from tkinter.filedialog import askopenfilename
root = Tk()
root.title("Amazon Error Handler")
root.geometry("300x150")
frame = Frame(root)
frame.pack()
bottomframe = Frame(root)
bottomframe.pack( side = BOTTOM )
def getfile():
filename = askopenfilename()
print(filename)
getfile = open(filename,"r")
print(getfile.read(1))
print(getfile.read())
button = Button(frame, text="Choose File", fg="black", command=getfile)
button.pack( side = BOTTOM)
root.mainloop()
This is the code I used to solve my own problem. This program is just a button that reads a chosen file and prints it's contents.
from tkinter import Tk
from tkinter import *
from tkinter.filedialog import askopenfilename
root = Tk()
root.title("Amazon Error Handler")
root.geometry("300x150")
frame = Frame(root)
frame.pack()
bottomframe = Frame(root)
bottomframe.pack( side = BOTTOM )
def getfile():
filename = askopenfilename()
print(filename)
getfile = open(filename,"r")
print(getfile.read(1))
print(getfile.read())
button = Button(frame, text="Choose File", fg="black", command=getfile)
button.pack( side = BOTTOM)
root.mainloop()