example for yaml-cpp 0.5.3 in linux - linux

Question

I am pretty new to yaml-cpp. After did tutorials, that tutorials are fine. But When I try to Parse my own yaml file, it's a litte difficult for me. I am confused with "operator" and "node".
yaml file is shown below.
Device:
DeviceName: "/dev/ttyS2"
Baud: 19200
Parity: "N"
DataBits: 8
StopBits: 1
Control:
Kp: 5000
Ki: 8
FVF: 100
VFF: 1962
Could you anyone give me an example to get data from that yaml file? thanks for your help.
Also i followed this question , I can build it. But When I run it, I got Segmentation fault (core dumped)
Code:
#include <yaml-cpp/yaml.h>
#include <string>
#include <iostream>
using namespace std;
int main()
{
YAML::Node config = YAML::LoadFile("init.yaml");
//read device
std::string DeviceName = config["Device"][0]["DeviceName"].as<std::string>();
int Baud = config["Device"][1]["Baud"].as<int>();
std::string Parity = config["Device"][2]["Parity"].as<std::string>();
int DataBits = config["Device"][3]["DataBits"].as<int>();
int StopBits = config["Device"][4]["StopBits"].as<int>();
//read control
int Kp = config["Control"][0]["Kp"].as<int>();
int Ki = config["Control"][1]["Ki"].as<int>();
int FVF = config["Control"][2]["FVF"].as<int>();
int VFF = config["Control"][3]["VFF"].as<int>();
cout <<"DeviceName" << DeviceName << endl;
cout <<"Baud" << Baud << endl;
cout <<"Parity" << Parity << endl;
cout <<"DataBits" << DataBits << endl;
cout <<"StopBits" << StopBits << endl;
cout <<"Kp" << Kp << endl;
cout <<"Ki" << Ki << endl;
cout <<"FVF" << FVF << endl;
cout <<"VFF" << VFF << endl;
return 0;
}

Answer 1

your code above results in a bad conversion exception because you access the map items in a wrong way.
instead of
std::string DeviceName = config["Device"][0]["DeviceName"].as<std::string>();
just write
std::string DeviceName = config["Device"]["DeviceName"].as<std::string>();
best regards
robert