I am an occasional Excel user and stuck how to create a dynamic range.
After looking up a text in a table, how can I calculate the range next to this cell, up to the next empty row? Not using VBA.
Thanks for your help.
In H4, formula copied down :
=IFERROR(INDEX(INDEX(C:C,MATCH(F4,A:A,0)):C$1000,MATCH(G4,INDEX(B:B,MATCH(F4,A:A,0)):B$1000,0)),"")
Should you want a dynamic range,
Change C$1000 to INDEX(C:C,MATCH(9.9E+307,B:B)
and
Change B$1000 to INDEX(B:B,MATCH(9.9E+307,B:B))
Then
The H4 copied down formula become :
=IFERROR(INDEX(INDEX(C:C,MATCH(F4,A:A,0)):INDEX(C:C,MATCH(9.9E+307,B:B)),MATCH(G4,INDEX(B:B,MATCH(F4,A:A,0)):INDEX(B:B,MATCH(9.9E+307,B:B)),0)),"")
Edit :
As per Ron Rosenfeld's comment, "should B11 change to 24 and G4 change to 24"
The "Source Table" set up in Excel Table type for dynamic range growing purpose
and
The H4 formula change to :
=IFERROR(LOOKUP(9^9,Table1[price]/(LOOKUP(ROW(Table1[texture]),ROW(Table1[texture])/(Table1[texture]<>""),Table1[texture])=F4)/(Table1[length]=G4)),"")
Combining the Index() and Match() functions usually works well when using two conditions. However, you will need to fill out the entire column A with the "texture" list in order for the below formula to work.
=INDEX(<P1>, MATCH(TRUE, (<T1>=<T2>) + (<L1>=<L2>) > 1,0))
Where <P1> is your entire price column (ex. C2:C15)
Where <T1> is your entire texture column (ex. A2:A15)
Where <T2> is your texture lookup value cell
Where <L1> is your entire length column (ex. B2:B15)
Where <L2> is your length lookup value cell
Let's say that you input your texture value into cell F3, and your length value into cell F4. With the remaining columns remaining as they are in your image, you would use the following formula:
=INDEX(C2:C15, MATCH(TRUE, (A2:A15=F3) + (B2:B15=F4) > 1,0))
Now last time I had to use Index/Match I thought I had to place the formula into an array. However, the above seems to work without it.
If you notice that it's not working as expected, you can place into an array formula by clicking the cell that contains the formula, then clicking the formula box at the top. While in the formula box, simultaneously press Ctrl + Shift + Return. This should then place curly brackets around your entire formula if done properly, as such:
If you have O365 with the SEQUENCE function, you can use, for price:
=IF(G4="","",VLOOKUP(G4,INDEX($B:$C,SEQUENCE(MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)-1,,MATCH(F4,$A:$A,0)),{1,2}),2,FALSE))
explanation:
get starting row:
MATCH(F4,$A:$A,0)
ending row will be the first blank row after the starting row:
MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)
Construct the relevant array:
INDEX($B:$C,SEQUENCE(MATCH(TRUE,ISBLANK(INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX(B:B,ROWS(B:B)-MATCH(F4,$A:$A,0))),0)-1,,MATCH(F4,$A:$A,0)),{1,2})
The above might reduce (with wavy) to:
index(b:c,{9,10,11},{1,2}
Then it's just a matter of applying the VLOOKUP
A more understandable, but longer with more operations, formula available in O365 makes use of LET. The advantage is that one can use names which indicate what each section of the formula does.
For example:
=IF(G4="","",LET(startRow,MATCH(F4,$A:$A,0),numRows,MATCH(TRUE,ISBLANK(INDEX($B:$B,startRow):INDEX($B:$B,ROWS($B:$B)-startRow)),0)-1,
arr,INDEX($B:$C,SEQUENCE(numRows,,startRow),{1,2}),price,XLOOKUP(G4,INDEX(arr,0,1),INDEX(arr,0,2)),price))
Or, using VLOOKUP
=IF(G4="","",VLOOKUP(G4,LET(startRow,MATCH(F4,$A:$A,0),numRows,MATCH(TRUE,ISBLANK(INDEX($B:$B,startRow):INDEX($B:$B,ROWS($B:$B)-startRow)),0)-1,arr,INDEX($B:$C,SEQUENCE(numRows,,startRow),{1,2}),arr),2,FALSE))
Finally, for earlier versions of Excel, you can use this whopper where we replace the SEQUENCE function with a construct like: ROW(INDEX(A:A,firstRow):INDEX(A:A,lastRow))
=IF(G4="","",VLOOKUP(G4,INDEX($B:$C,ROW(INDEX($A:$A,MATCH(F4,$A:$A,0)):INDEX($A:$A,MATCH(F4,$A:$A,0)+MATCH(TRUE,INDEX($B:$B,MATCH(F4,$A:$A,0)):INDEX($B:$B,ROWS($B:$B))="",0)-2)),{1,2}),2,FALSE))
If number from first coulmn is found in the second column, it should return that number.
If number from first coulmn is not found in the secound column, it should return closest possible min value
You can use vlookup() like this, BUT you need to sort the values:
In C1 enter the array formula:
=MAX(IF(B:B<=A1,B:B))
and copy downward:
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key. If this is done correctly, the formula will appear with curly braces around it in the Formula Bar.
NOTE:
Sorting is not required.
Array entry is not required if you are using Excel 365.
Another option is SUMPRODUCT:
=SUMPRODUCT(MAX(--($B$1:$B$12<=A1)*$B$1:$B$12))
It works on Excel 2007 or higher, no need of array entered formula and no need of sorting.
I'm trying to find in a list the lowest unique value.
I tried to find out a way on google, but nothing seem to work like I want.
What i have :
John;5
Leon;7
Mark;5
Bob;3
Peter;3
Louis:4
Desired result: "4" because it's the lower unique value.
Suppose I add in the original list:
Alex;4
The new result is about to be "7" because it's the new lowest unique value.
my excel sheet :
Assuming your data is setup so that names are in column A and values are in column B so that it looks like this:
In cell D2 (or wherever you want the result), use this array formula (Note that array formulas must be confirmed with CTRLSHIFTENTER and not just ENTER):
=MIN(IF(COUNTIF(B2:B20,B2:B20)=1,B2:B20))
You'll know you've entered it as an array formula correctly because you'll see it surrounded by curly braces {=formula}in the formula bar. Do NOT add the curly braces manually.
You'll also notice that I have extra rows in there than just the used rows. Normally I'd suggest using a dynamic named range, but this works for now. So when you add the new line of Alex; 4, you get this:
And you can see the formula now has the new correct value of 7.
With data in columns A and B, in C1 enter:
=COUNTIF(B:B,B1)
and copy down. Then in another cell enter the array formula:
=MIN(IF(C:C=1,B:B))
Array formulas must be entered with Ctrl + Shift + Enter rather than just the Enter key.
To avoid speed problems, make the limits on the ranges as small as possible:
=MIN(IF(C1:C6=1,B1:B6))
I want a formula that will look in a 2D array of cells for the row that has the most blank cells in it. Then I want the number of that row's blank cells returned as shown in the picture. The "Title 2" row has the most blanks at 4 as displayed in B8. I would want the formula to take the whole table into considerations, so cells B2:G5
Or this array formula**:
=MAX(MMULT(0+(LEN(B2:G5)=0),TRANSPOSE(COLUMN(B2:G5)^0)))
Regards
**Array formulas are not entered in the same way as 'standard' formulas. Instead of pressing just ENTER, you first hold down CTRL and SHIFT, and only then press ENTER. If you've done it correctly, you'll notice Excel puts curly brackets {} around the formula (though do not attempt to manually insert these yourself).
Sometimes it's easier to break things up into two tasks:
A formula in Column H that counts blanks by row. Something like: =COUNTIF(B2:G2, "="&"") which you would drag down through row #5.
Then, just make Cell B8 the maximum of that new column: =MAX(H2:H5).
I'd be curious if there is some type of array formula trick to accomplish this is one formula. Nevertheless, personally, I find separating the logic into smaller, more manageable, formulas easier to maintain.
In H2 enter:
=COUNTBLANK(B2:G2)
and copy down. In B8 enter:
=MAX(H2:H5)
For example:
Several great answers already, but I'll throw this out there:
=MAX(COUNTBLANK(INDIRECT("B"&ROW(2:5)&":"&"G"&ROW(2:5))))
Enter as an array formula: Ctrl+Shift+Enter
This:
"B"&ROW(2:5)&":"&"G"&ROW(2:5)
… returns an array of strings {"B2:G2" , "B3:G3" , "B4:G4" , "B5:G5"}:
That array is fed to the INDIRECT function, which changes it into an array of ranges {B2:G2 , B3:G3 , B4:G4 , B5:G5}.
That new array is fed to the COUNTBLANK function, which (using your example) returns the array of numbers {2 , 4 , 1 , 3}.
That's fed to the MAX function, so the end result is the number 4.
It's a bit convoluted, so I'm wondering if my INDIRECT parameter can be simplified.
I have two columns of numbers. Both are 1 to 5. I want to count all the cells where the left column value equals the right column value AND the left column value equals a certain value.
I tried this:
=SUM(IF(W2:W13=X2:X13 AND W2:W13=4,1,0))
I've tried pressing Ctrl+Shift+Enter and it adds {} around the formula but that didn't help either.
I think it's the W2:W13 = 4 part that doesn't work
=COUNTIFS(W2:W13,"=4", X2:X13, "=4")
You can use the sumif() function:
SumIf( range, criteria, sum_range )
it will apply the criteria for each row in the range.
Edit: to count the matches, you can use sum_range = 1 or use the Countif() function suggested by Ben in his answer
Have you considered a third column (C) with the formula IF(A1=B1,1,0) and then summing that third column?
I'm not much of an Excel Expert, but didn't they craeted the COUNTIF(range, criteria) function for this?
Add a third column eg Z2:Z13 with this formula: IF(AND(W2=X2; W2=4); 1; 0)
Then sum that one.
I don't have Excel 2007. So here's how you can do it in Excel 2003:
=COUNT(IF((W2:W14=4)*(X2:X14=4),Y2:Y14))
Since you are looking for a specific value and the column next to it to be the same value, you can just compare both columns to the same value.
The trick to get this to work is after entering the formula you need to hit F2 to go into edit mode and then hit CTRL-SHIFT-ENTER which makes this formula an array formula. This will put {} around the entire formula. Without making this an array formula this formula won't work.
I found this information in the Excel help document titled Count how often a value occurs