I have around 30 numbers which are either 1, 2 or 3 digits which are codes. These codes are attached in front of other numbers. I want to know what code is in front of a number, for example for the number 35467036 the first two digits matches with the code 35. So I want the output for that to be 1.5.
This is my current setup, I have a table with all the codes followed by the output in the next column. If all the codes were three digits long I could just do this =VLOOKUP((LEFT(E6,3)&"*"),D1:E3,2,FALSE) but they are unfortunately not.
I have also tried using nested IF statements but I can only go so far as 7 levels.
Will this only be possible in VBS or is there anther way?
Edit:
The code column is formatted to text. If I enter the value 3 into LEFT it does not work for two digits. Is there anyway I can make it work for 1, 2 and 3 digit codes? Also the codes do not overlap, for example, there isn't going to be 96 and 965 in the code table.
Seven nested IFs as a limit points to a very old version of Excel. You may want to consider upgrading to a version that is still supported in this millennium.
But your main problem is that the data type of your lookup value is text, because you concatenate a string with a wildcard. Whereas your Lookup Table's first column is probably made up of numbers.
In order to solve this you will need to add a Text column to your lookup table that represents the numeric value as a text value.
IF you want to use Vlookup, that helper column will need to be the first column of your lookup range.
You can use an Index/Match instead of Vlookup to be independent of the column order, as this screenshot shows:
Column H shows the formula that has been applied in column G.
Edit:
According to the screenshot you posted, you want to look up from the table in columns E to F and this table only has the short codes. Therefore, it makes no sense to add a wildcard to the lookup value. You just need to extract the value you want to use for the lookup.
If you want to lookup only two digits, then you need to extract only two digits. Adding a wildcard does nothing to remove the third digit.
In the screenshot below, a helper column feeds the LEFT() function the number of characters to extract, then uses that value in the VLookup.
=VLOOKUP(LEFT(A1,B1),$E$1:$F$5,2,FALSE)
=INDEX($G$2:$G$5,
SMALL(
IF(LEFT(A1,3)*1=$F$2:$F$5,ROW($G$2:$G$5)-1,
IF(LEFT(A1,2)*1=$F$2:$F$5,ROW($G$2:$G$5)-1,
IF(LEFT(A1,1)*1=$F$2:$F$5,ROW($G$2:$G$5)-1))),1))
=INDEX(LookupValues,Small(ArrayOfRowsFromIfStatements,FirstRow))
This is an array formula so you will need to use Ctrl+Shift+Enter while still in the formula bar.
We use If to build an array of Row numbers where the conditions match or return FALSE if not. The Small function then returns the smallest result in the array which will be the first row where conditions match.
We then index the results returning that row number (-1 deducted from rows to offset the headers).
If your numbers in column A are always 6 digits + the code length you can use this:
=VLOOKUP(--LEFT(A1,LEN(A1)-6),E2:F5,2,FALSE)
Related
We use this format in our casino to know where we have to send our employees to certain tables or games. We recently changed the way we do this and we now need to have some checks to make sure we didn't forget certain tables.
Every hour/half hour/20mins we assign a table to a person, everyone else moves one up. We know exactly which tables are open at which times. We fill this in at the top. When we fill in the upcoming timeslot we would like to have some check so we don't forget a table and maybe miss out a employee.
Example:
In the example supplied you can see that we accidentally have two number 6's but no 7 I highlighted the number 7 in the top row but it would be nice if this is doable automatically
I used VLOOKUP and INDEX/MATCH in the formula for Conditional formatting but that does not seem to create the correct outcome.
Here is an example of how it can be done:
The formula used has the array {1;2;3;4;5;6;7} hard written into it, assuming that the number of tables does not vary. The output is 0 when no table is missing, otherwise it returns a list of missing tables separated by commas.
Note: That of course means, the comma separated list is not a numeric value but a string value and cannot be used for further calculations. If further calculations on this output are required, the 'solution' has to be changed accordingly.
Formula
=IFERROR(CONCAT(FILTER({1;2;3;4;5;6;7},ISERROR(MATCH({1;2;3;4;5;6;7},H5:H24,0)))&", "),0)
Explanation
The MATCH() function checks which of the numbers 1 to 7 are present in the given range (here H5:H24) and returns the cell index of where it is found. When a number does not appear in the range, the MATCH() function will generate an #N/A error for that number.
Then, the ISERROR() function will output a FALSE value for all numbers found by MATCH() and a TRUE value for those numbers where the MATCH() function lead to an error.
The FILTER() function filters and thereby reduces the number array {1;2;3;4;5;6;7} to only those numbers where the ISERROR() function is TRUE.
The CONCAT() function concatenates the resulting array from the FILTER() function (in case more than 1 number is missing) to a single string of numbers separated by commas.
However, when there are no open tables, i.e. the MATCH() function finds all numbers 1 to 7 in the given range, then the ISERROR() function will only return FALSE values and the thus the FILTER() function returns an 'empty' array, which is not allowed in excel and leads to an #CALC error in excel. This case is captured by the IFERROR() function encapsulating the whole calculation, and instead of showing the error, returning 0.
What about this formula:
=AND(COUNTIF(A$2:A$10,1)=1,COUNTIF(A$2:A$10,2)=1,COUNTIF(A$2:A$10,3)=1,COUNTIF(A$2:A$10,4)=1,COUNTIF(A$2:A$10,5)=1,COUNTIF(A$2:A$10,6)=1,COUNTIF(A$2:A$10,7)=1)
A bit clearer:
=AND(COUNTIF(A$2:A$10,1)=1,
COUNTIF(A$2:A$10,2)=1,
COUNTIF(A$2:A$10,3)=1,
COUNTIF(A$2:A$10,4)=1,
COUNTIF(A$2:A$10,5)=1,
COUNTIF(A$2:A$10,6)=1,
COUNTIF(A$2:A$10,7)=1)
... which means that the number of ones need to be 1, the number of twos need to be 1, ..., up to the number of sevens.
Hereby a screenshot of an Excel sheet, which contains that formula:
In order to understand how this works, you might work with formula auditing, more especially formula evaluating, hereby an extra screenshot, showing formula evaluating after some steps:
Have fun :-)
I need help in writing a formula in cell b7. The formula must look to the right and multiply the nonempty cells by the corresponding value in row 3, and I would like to sum up the results.
File link provided.
FILE LINK
ScreenShot
Please see my comment to your original post.
That said, I will try to explain how to approach this as I think you intend. (This solution will be a Google Sheets solution which will not work in Excel.)
The first thing you will need to do is to delete everything from Row 11 down: all of your examples and notes must be deleted for the following proposed formula to work correctly.
Once you have no superfluous data below your main chart, delete everything from B6:B (including the header "Total").
Then, place the following formula in cell B6:
={"TOTAL"; FILTER(MMULT(C7:G*1, TRANSPOSE(C$3:G$3*1)), A7:A<>"")}
This formula will return the header text "TOTAL" (which you can change within the formula itself if you like) followed by the calculation you want for each row where a name is listed in A7:A.
MMULT is a difficult function to explain, but it multiplies one matrix ("grid") or numbers by another matrix ("grid") and returns the sum of all products per row (or per column, depending on how you set it up) —— which is what you are trying to do.
MMULT must have every element of both matrices be a real number. To convert potential nulls to zeroes, you'll see *1 appended to each range (since null times 1 is zero).
This assumes that all data entered into C7:G and C3:G3 will always be either a number or null. If you enter text, you'll throw the formula into an error. If you think accidental text entries in those ranges are possible, use this version instead:
={"TOTAL"; FILTER(MMULT(IFERROR(C7:G*1, ROW(C7:G)*0), TRANSPOSE(IFERROR(C$3:G$3*1, COLUMN(C$3:G$3)*0))), A7:A<>"")}
The extra bits use IFERROR to exchange error-producing entries with zeroes, since MMULT must have every space in both matrices filled with a real number.
I have a large table of 12 digit numbers and associated info
I have a small list of 10 and 11 digit numbers (the first and/or last digits were cut off) - I'm attempting to cross these two lists to identify the items on the small list
normally, I'd use an index match to bring the associated info out of the table into the list, but because today I have only partial numbers in my list, I can't get the formula to work
I've seen other examples here that search for partial text strings contained within a range, but I haven't been able to adapt those formulas to my data. wildcards don't seem to work with numbers.
Many thanks for your input, and apologies in advance if I failed to find an existing solution on the site.
To match partial numbers inside a number range, like you do with strings, you can use an array formula with INDEX/MATCH, by composing a temporary array that converts the numbers into strings.
Say column A is your 12 digit numbers column, and you want to match the sequence 1234567890 and retrieve the value from column B, This CSE formula works:
=INDEX($B$2:$B$9999, MATCH("*1234567890*",""&$A$2:$A$9999,0))
CtrlShiftEnter
Although you can use full columns A:A and B:B, this should be avoided as much as possible with array formulas, because they're slow. Full columns mean computing and operating arrays of more than a million entries, so avoid it. Also note the "expensive" conversion from numbers to strings (all numbers in the $A$2:$A$9999 are converted to strings here).
To use a cell reference, say D2, instead of the harcoded 1234567890, the formula should be used like this:
=INDEX($B$2:$B$9999,MATCH("*"&D2&"*",""&$A$2:$A$9999,0))
I am working on a statistical model where we use sumproduct to generate forecast values by multiplying coefficients in one table with variables in another. Right now it is being done manually and that is taking time. I would like to automate it but I'm not able to figure this out.
We are using concatenate to identify different rows to use for vlookup. The variable columns are the same in number for both tables. I need to multiply each variable cell respectively in both tables and sum them, hence sumproduct.
this is what I am trying to do
Forecast model 1 sales for product A in phones in USA = sumproduct([variables by year from table 1 for USA for phones], [Variables for USA phone product A model 1 from table 2] )
I hope someone can help me.
Proof of Concept
You will need to update the references to suit your spreadsheet table locations.
In cell E21 use the following and copy right and down as required:
=SUMPRODUCT(INDEX($G$3:$I$12,MATCH($B21&$A21&$C21,$A$3:$A$12,0),0),INDEX($F$15:$H$18,MATCH($A21&$C21&$D21&MID(E$20,16,1),$A$15:$A$18,0),0))
This process was simplified because you had a unique ID tag on each of the previous two tables that could be built from the information in the third table. If you ever get into double digit forecast models the MID() function part of the formula will need to be modified. The 16 in the mid function refers to the character location of the number in the forecast model sales header name in Table 3. As such you either need to keep that header format exactly the same or modify the position of the number in the MID() function.
UPDATE 1
Explanation of Formulas
The following formulas were used in this solution:
SUMPRODUCT
INDEX
MATCH
MID
Concatenate
I will start with the assumption that you already understand sumproduct() as you were already using it before you ran into your problem. One thing to note about sumproduct is that it causes array like calculation to occur on the portion within it brackets. In this case we fed it two ranges of equal size. The difficult part was more an issue of determining those ranges.
Using your ID columns as a lookup row we used the match() function to determine which row to use. For the first set of variables we used the following to determine which row to look in:
=MATCH($B21&$A21&$C21,$A$3:$A$12,0)
Match is made up of three arguments inside the brackets:
MATCH(what to look for, where to look, type of match)
What we need to look for in table is a concatenation of various cells in Table 3 to build the ID in Table 1. It could have been written using the full formula:
=CONCATENATE($B21,$A21,$C21)
but the short form using & was used instead:
=$B21&$A21&$C21
Once we had what to look for we needed the range of where to look and supplied the ID column from table 1:
$A$3:$A$12
This now leaves the third and final argument of what type of search to perform. An exact match seemed to be the most appropriate match to perform so the value of 0 was supplied. What match returns is the row within the supplied range. It is relative to the range supplied and not the actual row in the spreadsheet. If it cannot make a match it will return an error instead of a row number.
Now that we know what row we want, we can use this information with the INDEX() function. The INDEX() function is made up of 3 arguments as well with the third argument being optional depending on if a 1D or 2D range is being indexed:
INDEX(Range to work with, 2D Row or 1D Position reference, 2D Column reference)
IN the case we are dealing with for the first table, the range to work with was your list of variables:
$G$3:$I$12
This is a 2D range. As such we need to tell INDEX() both what Row to look in as well as which Columns to look in. For the row to look in, we used the previously discussed MATCH() function. Since we want all columns and not just a specific column we use the value of 0. If Match returns an error, or if a number greater than the number of rows or columns selected is supplied, INDEX() will return an error. Based on the information discussed, the index function would look like:
=INDEX($G$3:$I$12,MATCH($B21&$A21&$C21,$A$3:$A$12,0),0)
You can try entering the above in a cell but it will give you an error. if you select three adjacent cells in the same row and use CONTROL+SHIFT+ENTER when entering the formula, Excel will add {} around the formula and it will be an array formula and should show you the three variables being used.
The same process as described above can be used for determining the second range of variable from Table 2. The only difference here is that the forecast model number was not in a column of its own but instead in the header row surrounded by text. As such the MID() function needed to be used to go into the header row, bypass the surrounding text and pull the model number out so it could be used as part of the CONCATENATION() used for the "what to look for" in MATCH():
=MID(E$20,16,1)
The MID() function work again with three arguments:
MID(Text to look in, which character to start at, how many characters to pull)
So in this case we are looking at the header in E20. Note the lock $ on the row number so the formula is always looking in row 20 no matter how far down it gets copied. It is then going to the 16th character. In this case the character "1" and pulling 1 character. If the header had just been 1 and 2, there would be no need for the MID function and the cell (with proper lock) could have been used.
If you look at the image below we are trying to get a formula working, so we can do the following.
In Row 6 we need to locate the last Full in the column that is the date before the current date.
So for Blandc01 we have a full in Row 6 and column UJ6. WE need to find the latest Full in that column and then put the date at the top of that column in the cell that says Last Full in this case it's B12.
If for example you look at Blanbck01, we have our last full on 04/07/2014 in column UF, so the cell B8 has that date in it from Cell UF6.
So how do we use a series of functions to determine the last Full in the respective row, find that date of the column and put this in the relevant cell on the left.
I have updated the image to include the row numbers.
Thanks to pnuts comments, it is apparent that a lookup using just "full" won't work on an unsorted list. So here is one that will
=IFERROR(LOOKUP(2,1/(C5:XD5="full"),$C$3:$XD$3),"")
You will need to change the row references to properly reflect the two vectors. The first array is the row where you are looking for "full", the second is where the dates are located.
The OP has been asking more questions in the comments section. It seems he wants to return the latest dates where either "full" or "syn.full" is seen in the particular line.
If merely looking for the substring "full" will be sufficient (in other words, if there are no other strings that contain "full" that need to be excluded, then one can use:
=IFERROR(LOOKUP(2,1/ISNUMBER(SEARCH("full",C6:XD6)),$C$3:$XD$3),"")
On the other hand, if there might be other strings containing "full" which we want to ignore (e.g. fullness), and if the dates in row 3 are in ascending order, then try the following:
=MAX(IFERROR(LOOKUP(2,1/(C6:Z6="full"),$C$3:$Z$3),0),IFERROR(LOOKUP(2,1/(C6:Z6="syn.full"),$C$3:$Z$3),0))
If you use the latter, you should format the cell to not show 0's (eg: yyyy-mm-dd;; ) or wrap the whole formula in an IF to return the null string if the result is zero.
Finding the last match is always more difficult than the first one but I think I have something that works. This is an array function so has to be entered with ctrl+shift+enter
=indirect("R3C" & max((UB6:UJ6="full")*column(UB6:UJ6)),FALSE)
A break down of the function is as follows
(UB6:UJ6="full") returns an array of 1s and 0s (1 where it evaluates true). This is then multiplied by the column number (given in numbers, not letters). Once these are multiplied together we have a list of all the columns that have the word "full"
The indirect function allows you to use R1C1 style formulas if the second variable is False so the column can be inputted directly as a number. The R3 at the beginning means the value returned with be in row 3.