Linux One Liner to return eth name, ip, mac and subnet - linux

Question

I have been trying to combine two queries I have into one. I am trying to get an output of IP info which will get compared to another query against the host file and eventually dumped into a database. My commands have to be simple one liners due to how they are deployed. I can get what I need with these two, but is there a way to combined them. The ip show puts out a multiline output and not sure how to combined the lines.
ip -o addr show | awk '/inet/ {print $9, $4}' | grep -v '127.0.0.1'
ip -o addr show | awk '/link/ {print $2, $13}' | grep -v lo
Top gives most of the info and bottom gets the mac. This gives both but it is multi line so not sure how to awk out the values I need. Any good thoughts or tricks? Still new on the linux/bash.
ip -o addr show | grep -i 'ether\|inet'
Example of an ip -o addr show command
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue state UNKNOWN \ link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
1: lo inet 127.0.0.1/8 scope host lo
2: eth0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
2: eth0 inet x.x.x.x/24 brd x.x.x.x scope global eth0
3: eth1: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
3: eth1 inet x.x.x.x/24 brd x.x.x.x scope global eth1
4: eth2: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
4: eth2 inet x.x.x.x/27 brd x.x.x.x scope global eth2
5: eth3: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
6: eth4: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
6: eth4 inet x.x.x.x/24 brd x.x.x.x scope global eth4
7: eth5: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
7: eth5 inet x.x.x.x/24 brd x.x.x.x scope global eth5
8: eth6: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff
8: eth6 inet x.x.x.x/28 brd x.x.x.x scope global eth6
9: eth7: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN qlen 1000\ link/ether xx:xx:xx:xx:xx:xx brd ff:ff:ff:ff:ff:ff

Answer 1

This is not 100% as accurate as the original, but it works with your input:
ip -o addr show | awk '/inet/ && !/127.0.0.1/ {print $9, $4} /link/ && ! /lo/ {print $2, $13}'
If you want the output on one line,
then you can wrap the above command in echo $(...) like this:
echo $(ip -o addr show | awk '/inet/ && !/127.0.0.1/ {print $9, $4} /link/ && ! /lo/ {print $2, $13}')

Answer 2

Try egrep instead of grep
ip -o addr show | egrep -i "ether|inet"