$eq not working with $unwind result mongoose - node.js

i've simple schema where Events.like store objectId of user. i'd like to match a particular user in array (Events.like) and add a flag isLiked according to match.
Events.aggregate([
{ $unwind: '$like'},
{
"$project":{
// "count" : {$size: "$like"},
"like":1,
"isLiked" :{ "$eq": [ "like", "593564b94642650d5b09f16b" ] },
// "isLiked" : { "$cond": [{ "$eq": [ "like", "593564b94642650d5b09f16b" ] }, true, false ] } }
}
}
], function(err, list) { }
this method always give me false. see results
"data": [
{
"_id": "593647ae9e10082982d3f7a2",
"like": "593563f66d2e9f0b84553fc3",
"isLiked": false
},
{
"_id": "593643a5a1e73a2841d3cddb",
"like": "593564b94642650d5b09f16b",
"isLiked": false
},
{
"_id": "593643a5a1e73a2841d3cddb",
"like": "593563f66d2e9f0b84553fc3",
"isLiked": false
}
]
can anyone tell me where i'm mistaking
########## update ##########
{ $unwind: '$like'},
{
"$project":{
"isLiked" :{ "$eq": [ "$like", mongoose.Types.ObjectId("593564b94642650d5b09f16b") ] },
}
},
{
$group: {
_id: '$_id',
'likes': { $sum: 1},
"like": { $push: '$like' },
"isLiked" : 1
}
}
then
MongoError: the group aggregate field 'isLiked' must be defined as an expression inside an object
i simple want below result
"data": [
{
"_id": "593647ae9e10082982d3f7a2",
"like": ["593563f66d2e9f0b84553fc3","593643a5a1e73a2841d3cddb" ],
"likes":2
"isLiked": true
},
{
"_id": "593643a5a1e73a2841d3cddb",
"like": "[593563f66d2e9f0b84553fc3"],
"likes":1,
"isLiked": false
}
]

Hi the user id you are passing is being passed as a string you will need to convert it to objectId. Try this
EDIT: fixed path of the field as pointed by the asker, #ShivShanker
Events.aggregate([
{ $unwind: '$like'},
{
"$project":{
// "count" : {$size: "$like"},
"like":1,
"isLiked" :{ "$eq": [ "$like", mongoose.Types.ObjectId("593564b94642650d5b09f16b") ] }
}
}
], function(err, list) { }

Related

How to update an array in mongodb by using another array as both identifier and value?

Imagine the is a document like this:
{
_id: ObjectID('someIdblahbla')
users: [
{
_id: 'id1',
name: 'name1',
},
{
_id: 'id2',
name: 'name2',
},
{
_id: 'id3',
name: 'name3'
}
]
}
I have an array like this:
const newData = [
{_id: 'id1', name: 'newName1'},
{_id: 'id2', 'name': 'newName2', family:'newFamily2'}
]
what I want is to update the array in the document using the corresponding _id and using it to add/update each element.
so my end result would be like:
{
_id: ObjectID('someIdblahbla')
users: [
{
_id: 'id1',
name: 'newName1',
},
{
_id: 'id2',
name: 'newName2',
family:'newFamily2'
},
{
_id: 'id3',
name: 'name3'
}
]
}
my guess was using The filtered positional operator but I am not sure if it's the correct way to go and how to do it.
thank you for your kind tips beforehand.
There is no straight way to add/update in array, you can use update with aggregation pipeline starting from MongoDB 4.2,
First of all, you need to convert _id from string to objectId type, if you are using mongoose npm you can use mongoose.Types.ObjectId method or if you are using mongodb npm you can use ObjectId method,
let newData = [
{ _id: 'id1', name: 'newName1' },
{ _id: 'id2', 'name': 'newName2', family:'newFamily2' }
];
let newIds = [];
newData = newData.map(n => {
n._id = ObjectId(n._id); // or mongoose.Types.ObjectId(n._id)
newIds.push(n._id); // for checking conditions
return n;
});
You can put query condition, and do below operations,
$map to iterate loop of users array, check condition if user._id is in input newIds then do update operation otherwise do insert operation
update operation:
$filter to iterate loop of input newData and filter already present object from input so we can update it
$arrayElemAt to get first object from above filtered array
$mergeObjects to merge current object with above input object
insert operation:
$filter to iterate loop of newData array and return not present object means new items in array of objects
$concatArrays to concat above new and updated result array
db.collection.updateOne(
{ _id: ObjectId("someIdblahbla") },
[{
$set: {
users: {
$concatArrays: [
{
$map: {
input: "$users",
as: "u",
in: {
$cond: [
{ $in: ["$$u._id", newIds] },
{
$mergeObjects: [
"$$u",
{
$arrayElemAt: [
{
$filter: {
input: newData,
cond: { $eq: ["$$this._id", "$$u._id"] }
}
},
0
]
}
]
},
"$$u"
]
}
}
},
{
$filter: {
input: newData,
cond: { $not: { $in: ["$$this._id", "$users._id"] } }
}
}
]
}
}
}]
)
Playground
Query1 (update(merge objects) existing members, doesn't add new members)
Test code here
Replace
[{"_id": "id1","name": "newName1"},{"_id": "id2","name": "newName2","family": "newFamily2"}] with you array or the driver variable that hold the array
db.collection.update({
"_id": {
"$eq": "1"
}
},
[
{
"$addFields": {
"users": {
"$map": {
"input": "$users",
"as": "user",
"in": {
"$reduce": {
"input": [
{
"_id": "id1",
"name": "newName1"
},
{
"_id": "id2",
"name": "newName2",
"family": "newFamily2"
}
],
"initialValue": "$$user",
"in": {
"$let": {
"vars": {
"old_user": "$$value",
"new_user": "$$this"
},
"in": {
"$cond": [
{
"$eq": [
"$$old_user._id",
"$$new_user._id"
]
},
{
"$mergeObjects": [
"$$old_user",
"$$new_user"
]
},
"$$old_user"
]
}
}
}
}
}
}
}
}
}
])
Query2 (update(merge) if found, else push in the end)
Its like the above but finds the not-existing members,and push them in the end.Its a bit more slower and complicated
Test code here
Replace
[{"_id": "id1","name": "newName1"},{"_id": "id2","name": "newName2","family": "newFamily2"},{"_id": "id4","name": "newName4"}]
with your array or the driver variable that hold the array
db.collection.update({
"_id": {
"$eq": "1"
}
},
[
{
"$addFields": {
"yourarray": [
{
"_id": "id1",
"name": "newName1"
},
{
"_id": "id2",
"name": "newName2",
"family": "newFamily2"
},
{
"_id": "id4",
"name": "newName4"
}
]
}
},
{
"$addFields": {
"new-ids": {
"$setDifference": [
{
"$map": {
"input": "$yourarray",
"as": "u",
"in": "$$u._id"
}
},
{
"$map": {
"input": "$users",
"as": "u",
"in": "$$u._id"
}
}
]
}
}
},
{
"$addFields": {
"users": {
"$concatArrays": [
{
"$map": {
"input": "$users",
"as": "user",
"in": {
"$reduce": {
"input": "$yourarray",
"initialValue": "$$user",
"in": {
"$let": {
"vars": {
"old_user": "$$value",
"new_user": "$$this"
},
"in": {
"$cond": [
{
"$eq": [
"$$old_user._id",
"$$new_user._id"
]
},
{
"$mergeObjects": [
"$$old_user",
"$$new_user"
]
},
"$$old_user"
]
}
}
}
}
}
}
},
{
"$filter": {
"input": "$yourarray",
"as": "u",
"cond": {
"$in": [
"$$u._id",
"$new-ids"
]
}
}
}
]
}
}
},
{
"$unset": [
"yourarray",
"new-ids"
]
}
])

Group by the content of array of string with out order in mongo aggregation

i have a problem with aggregation framework in MongoDB (mongoose) this is the problem. i have the following database scheme.so what i want to do is count number of people who has access through Mobile only , Card only, or both. with out any order,
{
'_id': ObjectId,
'user_access_type': ['Mobile' , 'Card']
}
{
'_id': ObjectId,
'user_access_type': ['Card' , 'Mobile']
}
{
'_id': ObjectId,
'user_access_type': ['Mobile']
}
{
'_id': ObjectId,
'user_access_type': ['Card']
}
Now i am using this but it only groups by the order of the user_access_type array,
[ { "$group" : { "_id": {"User" : "$user_access_type"} , "count": {"$sum" : 1} }]
this is the output:
{
"_id": {
"User": [
"Card",
"Mobile"
]
},
"count": 1
},
{
"_id": {
"_id": "5f7dce2359aaf004985f98eb",
"User": [
"Mobile",
"Card"
]
},
"count": 1
},
{
"_id": {
"User": [
"Mobile"
]
},
"count": 1
},
{
"_id": {
"User": [
"Card"
]
},
"count": 1
},
vs what i want:
{
"_id": {
"User": [
"Card",
"Mobile" // we can say both
]
},
"count": 2 // does not depend on order
},
{
"_id": {
"User": [
"Mobile"
]
},
"count": 1
},
{
"_id": {
"User": [
"Card"
]
},
"count": 1
},
You can use other option as well using $function,
$function can allow to add javascript code, you can use sort() to sort the array
db.collection.aggregate([
{
$addFields: {
user_access_type: {
$function: {
body: function(user_access_type){
return user_access_type.sort();
},
args: ["$user_access_type"],
lang: "js"
}
}
}
},
{
$group: {
_id: "$user_access_type",
count: { $sum: 1 }
}
}
])
Second option,
If user_access_type array having always unique elements then you can use $setUnion operator on user_access_type array as self union, some how this will re-order array in same order,
db.collection.aggregate([
{
$addFields: {
user_access_type: {
$setUnion: "$user_access_type"
}
}
},
{
$group: {
_id: "$user_access_type",
count: { $sum: 1 }
}
}
])
Playground

Match two equal fields of arrays of same documents without $unwind

I have below workouts collection
[
{
"receiverWorkout": {
"exercises": [
{ "_id": "1", "reps": 0 },
{ "_id": "2", "reps": 4 }
]
},
"senderWorkout": {
"exercises": [
{ "_id": "2", "reps": 12 },
{ "_id": "1", "reps": 8 }
]
}
}
]
I need to match same _id from receiverWorkout and senderWorkout exercises and want to add a key won true or false whose reps are greater.
If you can see first element of receiverWorkout exercises({ "_id": "1", "reps": 0 }) is matching with the second element of the senderWorkout exercises({ "_id": "1", "reps": 8 }) because both have same _id
Expected output should be something like
[
{
"receiverWorkout": {
"exercises": [
{ "_id": "1", "reps": 0, "won": false },
{ "_id": "2", "reps": 4, "won": false }
]
},
"senderWorkout": {
"exercises": [
{ "_id": "2", "reps": 12, "won": true },
{ "_id": "1", "reps": 8, "won": true }
]
}
}
]
I want to avoid $unwind
Please help!!!
You can use below aggregation.
Single Pass
db.colname.aggregate([
{"$project":{
"exercises":{
"$reduce":{
"input":"$receiverWorkout.exercises",
"initialValue":{"receiverWorkout":[],"senderWorkout":[]},
"in":{"$let":{
"vars":{
"sen":{"$arrayElemAt":["$senderWorkout.exercises",{"$indexOfArray":["$senderWorkout.exercises._id","$$this._id"]}]}
},
"in":{
"receiverWorkout":{
"$concatArrays":[
"$$value.receiverWorkout",
[{"_id":"$$this._id","reps":"$$this.reps","won":{"$gt":["$$this.reps","$$sen.reps"]}}]
]
},
"senderWorkout":{
"$concatArrays":[
"$$value.senderWorkout",
[{"_id":"$$sen._id","reps":"$$sen.reps","won":{"$gt":["$$sen.reps","$$this.reps"]}}]
]
}
}
}}
}
}
}},
{"$project":{
"receiverWorkout.exercises":"$exercises.receiverWorkout",
"senderWorkout.exercises":"$exercises.senderWorkout"
}}
])
Without using $unwind
db.colname.aggregate(
{"$project":{
"receiverWorkout.exercises":{
"$map":{
"input":"$receiverWorkout.exercises",
"in":{
"$let":{
"vars":{"sen":{"$arrayElemAt":["$senderWorkout.exercises",{"$indexOfArray":["$senderWorkout.exercises._id","$$this._id"]}]}},
"in":{
"_id":"$$this._id",
"reps":"$$this.reps",
"won":{"$gt":["$$this.reps","$$sen.reps"]}
}
}
}
}
},
"senderWorkout.exercises":{
"$map":{
"input":"$senderWorkout.exercises",
"in":{
"$let":{
"vars":{"rec":{"$arrayElemAt":["$receiverWorkout.exercises",{"$indexOfArray":["$receiverWorkout.exercises._id","$$this._id"]}]}},
"in":{
"_id":"$$this._id",
"reps":"$$this.reps",
"won":{"$gt":["$$this.reps","$$rec.reps"]}
}
}
}
}
}
}})
With $unwind
db.colname.aggregate([
{"$unwind":"$senderWorkout.exercises"},
{"$unwind":"$receiverWorkout.exercises"},
{"$sort":{"receiverWorkout.exercises._id":1,"senderWorkout.exercises._id":1}},
{"$addFields":{
"receiverWorkout.exercises.won":{
"$cond":[
{"$gt":["$receiverWorkout.exercises.reps","$senderWorkout.exercises.reps"]},
true,
false
]
},
"senderWorkout.exercises.won":{
"$cond":[
{"$gt":["$receiverWorkout.exercises.reps","$senderWorkout.exercises.reps"]},
false,
true
]
}
}},
{"$group":{
"_id":"$_id",
"receiverWorkout":{"$addToSet":"$receiverWorkout.exercises"},
"senderWorkout":{"$addToSet":"$senderWorkout.exercises"}
}}
])
You don't need to use array index to achieve this. If I good understand, you need to know, for each entry in your senderWorkout.exercises array, if an element with the same _id is present in receiverWorkout.exercises array. Here's the way to do this :
db.collection.aggregate([
{
$addFields: {
"senderWorkout.exercises": {
$map: {
input: "$senderWorkout.exercises",
as: "ex",
in: {
$cond: {
if: {
$in: [
"$$ex._id",
"$receiverWorkout.exercises._id"
]
},
then: {
_id: "$$ex._id",
reps: "$$ex.reps",
result: true
},
else: {
_id: "$$ex._id",
reps: "$$ex.reps",
result: false
}
}
}
}
}
}
}
])
you can try it here

MongoDB Aggregate Pipeline query

I'm using mongoDB 3.6 on node.js 8.11.1 and working with MongoDB Node.js Driver.
I have two collections, 'group' and 'user':
group:
[
{
"_id":1,
"groupName":"group1",
"users":[
{
"userId":1,
"isAdmin":"false"
},
{
"userId":2,
"isAdmin":"true"
}
]
},
{
"_id":2,
"groupName":"group2",
"users":[
{
"userId":2,
"isAdmin":"false"
},
{
"userId":3,
"isAdmin":"true"
}
]
}
]
user:
[
{
"_id":1,
"username":"user1",
"firstname":"a",
"lastname":"aa",
"mobileNo":"+1111111"
},
{
"_id":2,
"username":"user2",
"firstname":"b",
"lastname":"bb",
"mobileNo":"+2222222"
},
{
"_id":3,
"username":"user3",
"firstname":"c",
"lastname":"cc",
"mobileNo":"+3333333"
}
]
I need an aggregate to return something like this:
[
{
"_id":1,
"groupName":"group1",
"members":[
{
"isAdmin":"false",
"username":"user1",
"firstname":"a",
"lastname":"aa"
},
{
"isAdmin":"true",
"username":"user2",
"firstname":"b",
"lastname":"bb"
}
]
},
{
"_id":2,
"groupName":"group2",
"members":[
{
"isAdmin":"false",
"username":"user2",
"firstname":"b",
"lastname":"bb"
},
{
"isAdmin":"true",
"username":"user3",
"firstname":"c",
"lastname":"cc"
}
]
}
]
At "members" in result, "isAdmin" return from "users" at group collection and "username", "firstname" and "lastname" came from user collection
Many thanks,
Milad.
You can try below aggregation from mongodb 3.6 and above
db.group.aggregate([
{ "$unwind": "$users" },
{ "$lookup": {
"from": Users.collection.name,
"let": { "userId": "$users.userId", "isAdmin": "$users.isAdmin" },
"pipeline": [
{ "$match": { "$expr": { "$eq": [ "$_id", "$$userId" ] } } },
{ "$project": { "isAdmin": "$$isAdmin", "username": 1, "firstName": 1, "lastName": 1 }}
],
"as": "members"
}},
{ "$unwind": "$members" },
{ "$group": {
"_id": "$_id",
"members": { "$push": "$members" },
"groupName": { "$first": "$groupName" }
}}
])

add key to nested array with condition

I have a simple datastructure in mongodb:
{
_id: ObjectID,
name: 'Name',
birthday: '25.05.2001'
items: [
{
_id: ObjectID,
name: 'ItemName',
info: 'ItemInfo',
},
{
_id: ObjectID,
name: 'ItemName',
info: 'ItemInfo',
}
]
}
Now i want a query, that takes a ObjectID (_id) of an item as criteria and gives me back the object with all items in the array AND projects a new field "selected" with value true or false into a field in the result of each array item:
I tried that with this query:
{ $unwind: '$items' },
{
$project: {
selected: {
$cond: { if: { 'items._id': itemObjectID }, then: true, else: false },
},
},
},
but MongoDB gives me back an error:
MongoError: FieldPath field names may not contain '.'.
Have no clue why its not working, any help or ideas? Thank you very much!
What you are missing here is $eq aggregation operator which checks the condition for the equality.
You can try below aggregation here if you want to check for ObjectId then you need to put mongoose.Types.ObjectId(_id)
db.collection.aggregate([
{ "$unwind": "$items" },
{ "$addFields": {
"items.selected": {
"$eq": [
1111,
"$items._id"
]
}
}},
{ "$group": {
"_id": "$_id",
"name": { "$first": "$name" },
"items": {
"$push": {
"_id": "$items._id",
"selected": "$items.selected"
}
}
}}
])
Will give following output
[
{
"_id": ObjectId("5a934e000102030405000000"),
"items": [
{
"_id": 1111,
"selected": true
},
{
"_id": 2222,
"selected": false
}
],
"name": "Name"
}
]
You can check it here
#Ashish: Thank you very much for your help! Your answer helped me to build the right query for me:
db.collection.aggregate([
{
$unwind: "$items"
},
{
$project: {
"items.name": 0,
"birthday": 0
}
},
{
"$addFields": {
"items.selected": {
"$eq": [
1111,
"$items._id"
]
}
}
},
{
$group: {
_id: "$_id",
"name": {
"$first": "$name"
},
items: {
$push: "$items"
}
}
},
{
$match: {
"items._id": {
$eq: 1111
}
}
},
])
and leads to a result that looks like:
[
{
"_id": ObjectId("5a934e000102030405000000"),
"items": [
{
"_id": 1111,
"selected": true
},
{
"_id": 2222,
"selected": false
}
],
"name": "Name"
}
]

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