I have the example where I want to write a VBA statement which will select all data in a single column, there are no blanks in the column data. The column position will never change e.g. column A, and the data starts in row 3. However the total number of rows in the column will change regularly.
I want the system to dynamically select all the cells in column and then I can run a method against these selected pieces of data.
As an example of performing an action on your range without selecting it:
Public Sub Test()
Dim rColA As Range
With ThisWorkbook.Worksheets("Sheet1")
Set rColA = .Range(.Cells(3, 1), .Cells(.Rows.Count, 1).End(xlUp))
MsgBox "Column A range is " & rColA.Address 'Delete if you want.
rColA.Interior.Color = RGB(255, 0, 0) 'Turn the back colour red.
rColA.Cells(2, 1).Insert Shift:=xlDown 'Insert a blank row at second cell in range
'So will insert at A4.
'If the first cell in your range is a number then double it.
If IsNumeric(rColA.Cells(1, 1)) Then
rColA.Cells(1, 1) = rColA.Cells(1, 1) * 2
End If
End With
End Sub
Try
Dim LastRow as Long, sht as worksheet
Set sht = ThisWorkbook.Worksheets("My Sheet Name")
LastRow = sht.Cells(sht.Rows.Count, 1).End(xlUp).Row
sht.Range("A3:A" & LastRow).Select
Like Darren Bartrup-Cook says, you may not need to select the data, you can almost always perform actions directly which is much faster.
If your column is "isolated" meaning no other nonblank cells touch your data you can use:
Range("firstCellInYourColumn").CurrentRegion.Select
(this works the same way as Ctrl+* from keyboard)
otherwise use:
Range(Range("firstCellInYourColumn"), Range("firstCellInYourColumn").End(xlDown)).Select
both will work if there are really no blanks within your data.
You should also prepend all Range with worksheet expression, I omitted this.
Related
situation is following:
I have 32 columns with data (various number of rows in columns) and need to delete cells with .value "downloaded" (always last cell in a column).
I have a code looping from column 32 to 1 and searching last_row for "downloaded" value. For 30 columns code seems to be working flawlessly but 2 columns return last_row value 1 even though there are multiple values (in fact hundreds of them) but they are non existent for VBA code.
Code:
Last_Col = ws.Cells(1, ws.Columns.Count).End(xlToLeft).Column
last_row = ws.Cells(Rows.Count & Last_Col).End(xlUp).Row
For R = Last_Col To 1 Step -1
With ws
Last_Col = R
last_row = ws.Cells(.Rows.Count & Last_Col).End(xlUp).Row
If Cells(last_row, Last_Col).Value Like "*Downloaded*" Then
Cells(last_row, Last_Col).ClearContents
End If
End With
Next R
Data is being drained from another worksheets. For 2 columns where I experience an error, I manually deleted values and inserted another, random batch of values and code worked as intended.
Checked columns formatting, worksheets from which data is taken but I struggle to find a solution.
Thank you for your help.
Clear Last Cell If Criteria Is Met
The main mistake was using Cells(.Rows.Count & Last_Col), where .Rows.Count & Last_Col would have resulted in a 8 or 9-digit string, while it should have been ws.Cells(ws.Rows.Count, Last_Col).End(xlUp).Row which was pointed out by chris neilsen in the comments.
Another important issue is using ws. in front of .cells, .rows, .columns, .range, aka qualifying objects. If you don't do it and e.g. the wrong worksheet is active, you may get unexpected results.
There is no need for looping backwards unless you are deleting.
Although it allows wild characters (*, ?), the Like operator is case-sensitive (a<>A) unless you use Option Compare Text.
The first solution, using the End property, will fail if a number of last columns is hidden or if you insert a new first row e.g. for a title.
The second solution, using the Find method (and the first solution), may fail if the data is filtered.
The Code
Option Explicit
Sub clearLastEnd()
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("Sheet1")
Dim LastCol As Long
LastCol = ws.Cells(1, ws.Columns.Count).End(xlToLeft).Column
Dim LastRow As Long
Dim c As Long
For c = 1 To LastCol
LastRow = ws.Cells(ws.Rows.Count, c).End(xlUp).Row
With ws.Cells(LastRow, c)
If InStr(1, .Value, "Downloaded", vbTextCompare) > 0 Then
.ClearContents
End If
End With
Next c
End Sub
Sub clearLastFind()
Dim ws As Worksheet
Set ws = ThisWorkbook.Worksheets("Sheet1")
Dim cel As Range
Set cel = ws.Cells.Find(What:="*", _
LookIn:=xlFormulas, _
SearchOrder:=xlByColumns, _
SearchDirection:=xlPrevious)
If Not cel Is Nothing Then
Dim c As Long
For c = 1 To cel.Column
Set cel = Nothing
Set cel = ws.Columns(c).Find(What:="*", _
SearchDirection:=xlPrevious)
If Not cel Is Nothing Then
If InStr(1, cel.Value, "Downloaded", vbTextCompare) > 0 Then
cel.ClearContents
Else
' The current last non-empty cell does not contain criteria.
End If
Else
' Column is empty.
End If
Next c
Else
' Worksheet is empty.
End If
End Sub
EDIT:
So you are curious why it worked at all. The following should shed a light on it:
Sub test()
Dim i As Long
Debug.Print "Right", "Wrong", "Rows.Count & i"
For i = 1 To 32
Debug.Print Cells(Rows.Count, i).Address, _
Cells(Rows.Count & i).Address, Rows.Count & i
Next i
End Sub
In a nutshell, Cells can have 1 or 2 arguments. When 1 argument is used, it refers to the n-th cell of a range, and it 'counts' by row. The more common usage is with 2 arguments: rows, columns. For example:
Cells(5, 10) ' refers to cell `J5`.
Using one argument is inconvenient here:
Cells(16384 * (5-1) + 10)
i.e.
Cells(65546)
It may be convenient when processing a one-column or a one-row range.
Well , let me see if i understand you have a table in worksheet table have 32 columns and X rows (because you only put WS and i can know if is WS=worksheet or WS= Table-range)
for this i am going to say is selection (if you put worksheet only hace to change for it)
in your code put:
Last_Col = ws.Cells(1, ws.Columns.Count).End(xlToLeft).Column
but in this you always wil obtein 1st cell so i dont understand why exist?
WS.columns.count
return number of columns you selection have
.End(xlToLeft)
return last cell if star to move to left (like Ctrl - left key)
so
Last_Col ---first go to cells (1,ws.Columns.Count) then go to left (End(xlToLeft)) and the end return number of column where finish (.Column) in this case you always get cell (1,"first column of your table")
NOTE: because you wrote that you have allways value in your cells (I have 32 columns with data (various number of rows in columns)
And for Row you have same question
Then you Wrote you want "Delete" but in your code you put Erase value (.ClearContents) so what do you want? because both are no equal
BUT if you have a table and want to search in any cells that have "Download" and only want to "clear content" you just may to use ".find" instead; or if you want to do all at same time you can use .replace (need to check before if .find return "nothing" or no , because if return nothing you get error)
If you have a table with 32 columns and each row have one cell where you put "Donloaded" and want to "delete" all row your code only need select column where appear "downloaded" (example Column "status").
If you have a table where any cell can take value "downloaded" and want to "delete" that cell you need to take care to resize your table and "move to" (when you delete cells you need to say where you want to move yor data remain "letf, "rigth", "up", down).
However if you say that "Downloaded" always appear in last row you can use For to change for all columns and use .end(xlDown)
For i=1 to 32
if cells(1,i).end(xlDown).value="downloaded" then cells(1,i).end(xlDown).ClearContents
next
BUT you need put more information because if you cant garantize that all cells have values and exist cells with "nothing" you will need
So I'm working on an excel sheet, and this is something i really can't figure out.
I want it to be that if the contents of a cell match certain criteria, an entire column of cells will be pasted according to that cell. The cell is a drop down with 32 different options (that can be reduced if theres no way to do it) and each option corresponds to a different column of data. The columns that have to be pasted have roughly 32 cells of data each.
My current formula is basically =IFS(A1="Potato",Sheet2!G:G) but this gives me a '0'. The best i can do is change the formula to =IFS(A1="Potato",Sheet2!G1) or =IFS(A1="Potato",Sheet2!G1:G32) but both of these formulas give me the contents of the first cell only (G1).
Any ideas on how I could get this done without having to contact aliens or build a spaceship?
You can use formulas, or VBA.
I have assumed your 32 columns of source data are in Sheet2 with the headers in row 1.
Formula Solution
In Sheet1 A73, enter:
=INDEX(Sheet2!$A$1:$AF$41,ROW(A1),MATCH($A$1,Sheet2!$A$1:$AF$1,0))
Copy this formula to Sheet1 A74:A105
VBA Solution
Put this code in the Sheet1 module;
Private Sub Worksheet_Change(ByVal Target As Range)
Dim c As Range
If Not Intersect(Target, Range("A1")) Is Nothing Then
Application.EnableEvents = False
With Sheet2
Set c = .Rows(1).Find(what:=Sheet1.Range("A1").Value)
If Not c Is Nothing Then
Set c = Intersect(.UsedRange, c.EntireColumn)
Sheet1.Range("A73").Resize(c.Rows.Count, 1).Delete
c.Copy Sheet1.Range("A73")
End If
End With
Application.EnableEvents = True
End If
End Sub
EDITED ANSWER: (according to comment)
We have the following layout of products
Private Sub CommandButton1_Click()
'first we check the user input
Dim u_input As String
Dim ws As Worksheet: Set ws = Sheets("Sheet1")
u_input = LCase(Trim(ws.Range("A1").Value2))
'now we need to determine how many columns there are so we know when to stop looping
Dim lc As Long, lr As Long
lc = ws.Cells(1, ws.Columns.Count).End(xlToLeft).Column
' loops through all the products
For Each cell In Range(Cells(1, "F"), Cells(1, lc))
' if the product matches the input
If LCase(Trim(cell)) = u_input Then
lr = ws.Cells(ws.Rows.Count, cell.Column).End(xlUp).Row
' copy and paste the active data range to A37
ws.Range(Cells(1, cell.Column), Cells(lr, cell.Column)).Copy
Sheets("Sheet2").Range("A37").PasteSpecial
End If
Next cell
End Sub
So, upon entering cucumber and clicking the button:
We would get the following result:
You can add any number of products there, as long as the first product starts in column F. (though that can also be changed in code).
PS: This will however end up overwriting your data and also cause data to overlap if your data ranges are not the same. It probably would be smarter to paste the data into the next empty row in sheet2 instead of directly to A37
This can be achieved by changing the line
Sheets("Sheet2").Range("A37").PasteSpecial to Sheets("Sheet2").Range(Cells((Rows.Count, "A").End(xlUp).Row, "A")).PasteSpecial
I have been looking around the site for a while for an answer to this question but no luck just yet. I have this code where I loop through a row of numbers and depending on what number is in the cell at the time, determines what I copy and paste to the sheet. I am using Columns for this because it is the only way I can make my code dynamic. It works but when I paste I would like to paste in cells lower than where it's pasting right now. I was wondering if Columns had a way of specifying what column and where to paste my data.
Code:
Dim sh As Worksheet
Dim rw As Range
Dim row As Range
Dim cell As Range
Dim RowCount As Integer
Set rw = Range("A5:CG5")
Set sh = ActiveSheet
For Each row In rw.Rows
For Each cell In row.Cells
Select Case cell.Value
Case "2"
ThisWorkbook.Worksheets("Sheet1").Range("E27:E51").Copy Destination:=Sheets("Sheet2").Columns(4)
End Select
Next cell
Next row
Your problem can be solved as Jeeped said, use Destination:=Sheets("Sheet2").Cells(27, 5) or Destination:=Worksheets(2).Range("E27")
Since you want to learn a little bit more, i made an example explanation:
https://msdn.microsoft.com/en-us/vba/excel-vba/articles/range-column-property-excel
On the link it is explained that .Column:
Column A returns 1, column B returns 2, and so on.
And the same is with the .Rows
Use .Cells https://msdn.microsoft.com/pt-br/library/office/ff194567.aspx So you can use the .Cells(Rows,Columns) or .Cells(Index from a Range) or the entire Object:
With Worksheets("Sheet1").Cells.Font
.Name = "Arial"
.Size = 8
End With
So an example if you want to turn your spreadsheet dynamical: to copy from range $E$27 to last row with something written from column $E on Sheet1 To
the last column with nothing written on row 1 on Sheet2.
Sub test()
'Declare variables here
Dim sht1, sht2 As Worksheet
'sht1 has the data and sht2 is the output Worksheet, you can change the names
last_row = Worksheets(1).Range("E65536").End(xlUp).Row
last_column = Worksheets(2).Cells(1, sht1.Columns.Count).End(xlToLeft).Column
'Data add
For i = 27 To last_row
'Start from Row 27
Worksheets(2).Cells(i - 26, last_column + 1) = Worksheets(1).Cells(i, 5)
Next i
MsgBox "Data Updated"
End Sub
And an example of a basic dynamical workbook with i=i+1 and For loops split a single row of data into multiple unique rows into a new sheet to include headers as values and cell contents as values
I've tried various ways and answers to select all of the rows except the header for a certain column and none seem to work.
I've tried using (15 is the column here):
Range(Cells(2, 15), Cells(.Cells(rows.Count, 15).End(xlUp).Row, 15)).Select
I managed to use .Activate on the worksheet with a different statement to select all, but this changes the sheet and you could visibly see all the rows being selected. This isn't possible for what I need it for. Users can't have a bunch of sheets constantly being switched in front of them, makes for a bad experience.
How can I select all of the non-blank columns after the header (first) row without using .Activate?
I need to get these values, put them in an array, and check if the current cell value is in the array. Not asking for this part, but providing it as context if it matters.
You can not select a range on a non-active worksheet.
Here is how you can set a reference to all the cells in a column except the header row.
Dim TargetRange As Range
With Worksheets("Sheet1")
Set TargetRange = .Range(.Cells(2, 15), .Cells(Rows.Count, 15).End(xlUp))
End With
The following code reads the data from the Worksheet (without using Select or Activate), and puts it in a 2-dimensional array.
Option Explicit
Sub Range_WO_Headers()
Dim Sht_Source As Worksheet
Dim Rng As Range
Dim LastRow As Long
Dim LastCol As Long
Dim Rng_Array As Variant
' modify Sheet1 according to your sheet name
Set Sht_Source = ActiveWorkbook.Worksheets("Sheet1")
' assuming the table's data starts from Cell A1
LastRow = Sht_Source.Cells(Sht_Source.Rows.Count, "A").End(xlUp).Row
LastCol = Sht_Source.Cells(1, Sht_Source.Columns.Count).End(xlToLeft).Column
' resize array according to number of columns and number of rows
ReDim Rng_Array(0 To LastRow, 0 To LastCol)
' set dynamic array from Cell A1 to last row and last column found (starting the second row)
Set Rng = Sht_Source.Range(Cells(2, 1), Cells(LastRow, LastCol))
Rng_Array = Application.Transpose(Rng)
End Sub
Was wondering if someone could help me problem solve something with the attached example dataset. I have many more so trying to work out an efficient way to do this:
https://www.dropbox.com/s/fa32ddeh4lbz8lo/Problem%20removing%20blanks%20cells%20and%20corresponding%20left%20cell.xlsx?dl=0
In the attached excel data sheet are sets of 2 columns side-by-side marked by lines (TIME and GLU). I have used conditional formatting to highlight (in red) the blank cells in each GLU columns. What I want to do (without having to go through by hand...) is remove these blank cells (i.e. delete and move that whole column upwards) AND also delete and move upwards the single 'TIME' cell immediately to the left of each of these blank cells (as illustrated for example by the green highlighted TIME cells in column A alongside column B).
Does anyone out there know how this might be achieve via code?? Would be extremely helpful!!
Thanks in advance!
Patrick
Sub RemoveBlank()
Dim sht As Worksheet
Dim LastRow As Long
Dim LastColumn As Long
Dim Column As Long
Application.ScreenUpdating = False
Set sht = ThisWorkbook.Worksheets("Sheet1")
LastColumn = sht.Cells(1, sht.Columns.Count).End(xlToLeft).Column
Column = 2
Do While Column <= LastColumn
LastRow = sht.Range(Cells("1", Column - 1), Cells("1", Column - 1)).CurrentRegion.Rows.Count
Row = LastRow
Do While Row > 1
If sht.Range(Cells(Row, Column), Cells(Row, Column)).Value = "" Then
'Delets the two column row with a blank GLU and moves the rest of the data up.
sht.Range(Cells(Row, Column - 1), Cells(Row, Column)).Select
Selection.delete Shift:=xlUp
Else
'Do nothing
End If
Row = Row - 1
Loop
Column = Column + 2
Loop
Application.ScreenUpdating = True
End Sub