I need a little help. Basically, I am trying to search a text string in wordpress theme files.
That string is located in wp-content/themes/style.css.
So basically I am trying to search a string in all style.css files on all wordpress installations of home directory.
Is it possible to search all style.css files only and if the string is found display it?
Thanks in advance!
Usage: grep [OPTION]... PATTERN [FILE]...
Search for PATTERN in each FILE or standard input.
PATTERN is, by default, a basic regular expression (BRE).
Example: grep -i 'hello world' menu.h main.c
Use grep to search for text inside files.
grep -rniw '/path/to/somewhere/' -e 'pattern'
-r or -R is recursive,
-n is line number, and
-i - case insensitive search
-w stands for match the whole word.
-l (lower-case L) can be added to just give the file name of matching files.
For you case, use:
grep -rniw '/path/to/somewhere/' -e 'wp-content/themes/style.css'
Use the following commands:
cd /home/
find . -iname "*.css" -exec grep -l "text_string" {} +
Do not forget to replace text_string with the actual text string.
Related
I have a server which runs on centos 7. I need to find a file containing 0774386850 so that I can replace with another string. Kindly give me a Linux command to give me that file
By using grep command, you can achieve what you expected
grep -rlnw '/path/to/somewhere/' -e '0774386850'
-r or -R is recursive,
-n is line number, and
-w stands for match the whole word.
-l (lower-case L) file name of matching files.
grep -r "0774386850 " /path/to/dir
You can use either grep/fgrep or find to achieve your goal.
I would like to know how to search from the command line for a string in various files of type .rb.
And replace:
.delay([ANY OPTIONAL TEXT FOR DELETION]).
with
.delay.
Besides sed an awk are there any other command line tools included in the OS that are better for the task?
Status
So far I have the following regular expression:
.delay\(*.*\)\.
I would like to know how to match only the expression ending on the first closing parenthesis? And avoid replacing:
.delay([ANY OPTIONAL TEXT FOR DELETION]).sometext(param)
Thanks in advance!
If you need to find and replace text in files - sed seems to be the best command line solution.
Search for a string in the text file and replace:
sed -i 's/PATTERN/REPLACEMENT/' file.name
Or, if you need to process multiple occurencies of PATTERN in file, add g key
sed -i 's/PATTERN/REPLACEMENT/g' file.name
For multiple files processing - redirect list of files to sed:
echo "${filesList}" | xargs sed -i ...
You can use find to generate your list of files, and xargs to run sed over the result:
find . -type f -print | xargs sed -i 's/\.delay.*/.delay./'
find will generate a list of files contained in your current directory (., although you can of course pass a different directory), xargs will read that list and then run sed with the list of files as an argument.
Instead of find, which here generates a list of all files, you could use something like grep to generate a list of files that contain a specific term. E.g.:
grep -rl '\.delay' | xargs sed -i ...
For the part of the question where you want to only match and replace until the first ) and not include a second pair of (), here is how to change your regex:
.delay\(*.*\)\.
->
\.delay\([^\)]*\)
I.e. match "actual dot, delay, brace open, everything but brace close and brace close".
E.g. using sed:
>echo .delay([ANY OPTIONAL TEXT FOR DELETION]).sometext(param) | sed -E "s/\.delay\([^\)]*\)/.delay/"
.delay.sometext(param)
I recommend to use grep for finding the right files:
grep -rl --include "*.rb" '\.delay' .
Then feed the list into xargs, as recommended by other answers.
Credits to the other answers for providing a solution for feeding multiple files into sed.
If I have two strings, for example "class" and "btn", what is the linux command that would allow me to search for these two strings in the entire directory.
To be more specific, lets say I have directory that contains few folders with bunch of .php files. My goal is to be able to search throughout those .php files so that it prints out only files that contain "class" and "btn" in one line. Hopefully this clarifies things better.
Thanks,
I normally use the following to search for strings inside my source codes. It searches for string and shows the exact line number where that text appears. Very helpful for searching string in source code files. You can always pipes the output to another grep and filter outputs.
grep -rn "text_to_search" directory_name/
example:
$ grep -rn "angular" menuapp
$ grep -rn "angular" menuapp | grep some_other_string
output would be:
menuapp/public/javascripts/angular.min.js:251://# sourceMappingURL=angular.min.js.map
menuapp/public/javascripts/app.js:1:var app = angular.module("menuApp", []);
grep -r /path/to/directory 'class|btn'
grep is used to search a string in a file. With the -r flag, it searches recursively all files in a directory.
Or, alternatively using the find command to "identify" the files to be searched instead of using grep in recursive mode:
find /path/to/your/directory -type f -exec grep "text_to_search" {} \+;
Can we search a term (eg. "onblur") recursively in some folders only in specific files (html files)?
grep -Rin "onblur" *.html
This returns nothing. But,
grep -Rin "onblur" .
returns "onblur" search result from all available files, like in text(".txt"), .mako, .jinja etc.
Consider checking this answer and that one.
Also this might help you: grep certain file types recursively | commandlinefu.com.
The command is:
grep -r --include="*.[ch]" pattern .
And in your case it is:
grep -r --include="*.html" "onblur" .
grep -r --include "*.html" onblur .
Got it from :
How do I grep recursively?
You might also like ag 'the silver searcher' -
ag --html onblur
it searches by regexp and is recursive in the current directory by default, and has predefined sets of extensions to search - in this case --html maps to .htm, .html, .shtml, .xhtml. Also ignores binary files, prints filenames, line numbers, and colorizes output by default.
Some options -
-Q --literal
Do not parse PATTERN as a regular expression. Try to match it literally.
-S --smart-case
Match case-sensitively if there are any uppercase letters in PATTERN,
case-insensitively otherwise. Enabled by default.
-t --all-text
Search all text files. This doesn't include hidden files.
--hidden
Search hidden files. This option obeys ignored files.
For the list of supported filetypes run ag --list-file-types.
The only thing it seems to lack is being able to specify a filetype with an extension, in which case you need to fall back on grep with --include.
To be able to grep only from .py files by typing grepy mystring I added the following line to my bashrc:
alias grepy='grep -r --include="*.py"'
Also note that grep accepts The following:
grep mystring *.html
for .html search in current folder
grep mystring */*.html
for recursive search (excluding any file in current dir!).
grep mystring .*/*/*.html
for recursive search (all files in current dir and all files in subdirs)
Have a look at this answer instead, to a similar question: grep, but only certain file extensions
This worked for me. In your case just type the following:
grep -inr "onblur" --include \*.html ./
consider that
grep: command
-r: recursively
-i: ignore-case
-n: each output line is preceded by its relative line number in the file
--include \*.html: escape with \ just in case you have a directory with asterisks in the filenames
./: start at current directory.
I want to use grep command to search for files containing the string "/usr/vm/data". For searching a normal string like "how are you", i know i can do:
grep -inr "how are you" *
to search recursively. But i am getting stuck in the cases where i need to search a path like "/usr/vm/data". I tried:
grep -inr "\/usr\/vm\/data" directory1
and also
grep -inr "/usr/vm/data/" directory1
but didn't get any success.
Don't torture yourself, and it is a normal string (especially when you put it in quotes).
echo "/usr/vm/data Hello world" | grep -i "/usr/vm/data"
Your command works fine:
$ cat directory1/somefile
foo
bar
this line contains /usr/vm/data/
$ grep -inr "/usr/vm/data/" directory1
directory1/somefile:3:this line contains /usr/vm/data/
$
Perhaps your file is beyond a symlink which grep doesn't follow, or perhaps you don't have any matching files?