How to Handle Encoding a Swift Struct Containing Swift Struct as Property - struct

I have a requirement to persist a preferred Location that has been selected by a user. The Location contains a few properties:
public struct Location {
// MARK: - Properties
public let identifier: Int
public let name: String
public let address: Address?
// MARK: - Initializations
public init(identifier: Int, name: String, address: Address?) {
self.identifier = identifier
self.name = name
self.address = address
}
}
The Address follows:
public struct Address {
// MARK: - Properties
public let city: String?
public let state: String?
public let postalCode: String?
public let country: String?
// MARK: - Initialization
public init(city: String?, state: String?, postalCode: String?, country: String?) {
self.city = city
self.state = state
self.postalCode = postalCode
self.country = country
}
}
Since I only need to persist one Location at any given time, I prefer to use UserDefaults.
I have a type that encapsulates a Location so that it can be encoded and decoded in order to be persisted by UserDefaults. However, I have not created an encapsulating type for encoding and decoding Address.
My question is: Since I want to persist a Location, which contains an Address, do I need to create the encapsulating type to encode and decode an Address as well, or would it be more appropriate to just encode and decode the Address properties inside of the Location when I encode and decode its other properties?
I don't know in advance if Address will be applied to other types as a property that may need persisted in UserDefaults. I am leaning toward creating an encapsulating type to encode and decode Address.

It appears that I should create an encapsulating type to ensure that the address property of my Location instance can be encoded and decoded. That will allow me to simply call coder.encode(address, forKey: "address").
I found a helpful answer after changing my search query terms.

Related

FetchResults<T>.Element cannot convert into T - SwiftUI

I have a problem with databases. I want to pass a user into another view as depicted below:
And as you can see I get an error that I cannot convert this Element into User.
My user strut looks like this:
struct User: Decodable, Identifiable {
public let id: String
public let name: String
public let age: Int16
public let company: String
public let about: String
public let isActive: Bool
public let email: String
public let address: String
public let registered: String
}
and my user database looks like that:
Does anyone know what may be a solution to this problem?
Well, you are fetching CoreData entity objects, but you are trying to cast a CoreData entity object to a struct type.
UserList is a CoreData entity object. The fetching is correct. However, UserView needs a object of User.
Solution 1: Convert your UserList to a User element.
Solution 2: Pass the User object to your UserView
struct UserView : View {
var userList : UserList // << Type of UserList

Struct field with reserved name golang

Hi Im doing an API client and I want to use a struct to pull out the json, the problem is that one of the json fields should be named type, as far as I know it is a reserved keyword, how can I create a struct with a "type" field in it?
Example:
What I want to do:
type Card struct {
cardId string
name string
cardSet string
type string
}
That won't work to begin with, since you're not exporting the fields names.
Otherwise, you can use struct tags to name the json fields as you need
type Card struct {
CardID string `json:"cardId"`
Name string `json:"name"`
CardSet string `json:"cardSet"`
Type string `json:"type"`
}
You have to use json annotations on your model. Also, the fields have to be exported (upper case) or the unmarshaller won't be able to make use of them.
type Card struct {
CardId string `json:"cardId"`
Name string `json:"name"`
CardSet string `json:"cardSet"`
TheType string `json:"type"`
}

Using objects inside objects

Trying to use the serializer of YAMLDOTNET, having some problems when I have and object which is not composed of just strings but also has an special object inside.
When serializing I will just get a {} string. If for example on the Serializing an object graph sample we define a structure Address. Then we create a new object of the class Address inside, which is eventually assign in the receipt, the results will be also a {} on the address field on the yaml file.
The sample code can be also seen here. This will create an output that looks like:
receipt: Oz-Ware Purchase Invoice
date: 2007-08-06T00:00:00.0000000
customer:
given: Dorothy
family: Gale
items:
- part_no: A4786
descrip: Water Bucket (Filled)
price: 1.47
quantity: 4
- part_no: E1628
descrip: High Heeled "Ruby" Slippers
price: 100.27
quantity: 1
bill_to: &o0 {}
ship_to: *o0
So the bill_to will appear as {}
YamlDotNet.Serialization.Serializer does not serialise fields into the YAML output. It works in the example, because that is using a dynamic object and street, city and state are properties of that object.
If you change the fields in your Address to properties they will be serialised e.g.
public struct Address
{
public string street { get; set; }
public string city { get; set; }
public string state { get; set; }
}
Using properties instead of public fields is also best practice.

How can I clone an Object (deep copy) in Dart?

Is there a Language supported way to make a full (deep) copy of an Object in Dart?
If multiple options exist, what are their differences?
Darts built-in collections use a named constructor called "from" to accomplish this. See this post: Clone a List, Map or Set in Dart
Map mapA = {
'foo': 'bar'
};
Map mapB = new Map.from(mapA);
No as far as open issues seems to suggest:
https://github.com/dart-lang/sdk/issues/3367
And specifically:
... Objects have identity, and you can only pass around references to them. There is no implicit copying.
Late to the party, but I recently faced this problem and had to do something along the lines of :-
class RandomObject {
RandomObject(this.x, this.y);
RandomObject.clone(RandomObject randomObject): this(randomObject.x, randomObject.y);
int x;
int y;
}
Then, you can just call copy with the original, like so:
final RandomObject original = RandomObject(1, 2);
final RandomObject copy = RandomObject.clone(original);
I guess for not-too-complex objects, you could use the convert library:
import 'dart:convert';
and then use the JSON encode/decode functionality
Map clonedObject = JSON.decode(JSON.encode(object));
If you're using a custom class as a value in the object to clone, the class either needs to implement a toJson() method or you have to provide a toEncodable function for the JSON.encode method and a reviver method for the decode call.
Unfortunately no language support. What I did is to create an abstract class called Copyable which I can implement in the classes I want to be able to copy:
abstract class Copyable<T> {
T copy();
T copyWith();
}
I can then use this as follows, e.g. for a Location object:
class Location implements Copyable<Location> {
Location({
required this.longitude,
required this.latitude,
required this.timestamp,
});
final double longitude;
final double latitude;
final DateTime timestamp;
#override
Location copy() => Location(
longitude: longitude,
latitude: latitude,
timestamp: timestamp,
);
#override
Location copyWith({
double? longitude,
double? latitude,
DateTime? timestamp,
}) =>
Location(
longitude: longitude ?? this.longitude,
latitude: latitude ?? this.latitude,
timestamp: timestamp ?? this.timestamp,
);
}
To copy an object without reference, the solution I found was similar to the one posted here, however if the object contains MAP or LIST you have to do it this way:
class Item {
int id;
String nome;
String email;
bool logado;
Map mapa;
List lista;
Item({this.id, this.nome, this.email, this.logado, this.mapa, this.lista});
Item copyWith({ int id, String nome, String email, bool logado, Map mapa, List lista }) {
return Item(
id: id ?? this.id,
nome: nome ?? this.nome,
email: email ?? this.email,
logado: logado ?? this.logado,
mapa: mapa ?? Map.from(this.mapa ?? {}),
lista: lista ?? List.from(this.lista ?? []),
);
}
}
Item item1 = Item(
id: 1,
nome: 'João Silva',
email: 'joaosilva#gmail.com',
logado: true,
mapa: {
'chave1': 'valor1',
'chave2': 'valor2',
},
lista: ['1', '2'],
);
// -----------------
// copy and change data
Item item2 = item1.copyWith(
id: 2,
nome: 'Pedro de Nobrega',
lista: ['4', '5', '6', '7', '8']
);
// -----------------
// copy and not change data
Item item3 = item1.copyWith();
// -----------------
// copy and change a specific key of Map or List
Item item4 = item1.copyWith();
item4.mapa['chave2'] = 'valor2New';
See an example on dartpad
https://dartpad.dev/f114ef18700a41a3aa04a4837c13c70e
With reference to #Phill Wiggins's answer, here is an example with .from constructor and named parameters:
class SomeObject{
String parameter1;
String parameter2;
// Normal Constructor
SomeObject({
this.parameter1,
this.parameter2,
});
// .from Constructor for copying
factory SomeObject.from(SomeObject objectA){
return SomeObject(
parameter1: objectA.parameter1,
parameter2: objectA.parameter2,
);
}
}
Then, do this where you want to copy:
SomeObject a = SomeObject(parameter1: "param1", parameter2: "param2");
SomeObject copyOfA = SomeObject.from(a);
Let's say you a have class
Class DailyInfo
{
String xxx;
}
Make a new clone of the class object dailyInfo by
DailyInfo newDailyInfo = new DailyInfo.fromJson(dailyInfo.toJson());
For this to work your class must have implemented
factory DailyInfo.fromJson(Map<String, dynamic> json) => _$DailyInfoFromJson(json);
Map<String, dynamic> toJson() => _$DailyInfoToJson(this);
which can be done by making class serializable using
#JsonSerializable(fieldRename: FieldRename.snake, includeIfNull: false)
Class DailyInfo{
String xxx;
}
It only works for object types that can be represented by JSON.
ClassName newObj = ClassName.fromMap(obj.toMap());
or
ClassName newObj = ClassName.fromJson(obj.toJson());
Trying using a Copyable interface provided by Dart.
there is an easier way for this issue
just use ... operator
for example, clone a Map
Map p = {'name' : 'parsa','age' : 27};
Map n = {...p};
also, you can do this for class properties.
in my case, I was needed to clone a listed property of a class.
So:
class P1 {
List<String> names = [some data];
}
/// codes
P1 p = P1();
List<String> clonedList = [...p.names]
// now clonedList is an unreferenced type
There is no built-in way of deep cloning an object - you have to provide the method for it yourself.
I often have a need to encode/decode my classes from JSON, so I usually provide MyClass fromMap(Map) and Map<String, dynamic> toJson() methods. These can be used to create a deep clone by first encoding the object to JSON and then decoding it back.
However, for performance reasons, I usually implement a separate clone method instead. It's a few minutes work, but I find that it is often time well spent.
In the example below, cloneSlow uses the JSON-technique, and cloneFast uses the explicitly implemented clone method. The printouts prove that the clone is really a deep clone, and not just a copy of the reference to a.
import 'dart:convert';
class A{
String a;
A(this.a);
factory A.fromMap(Map map){
return A(
map['a']
);
}
Map<String, dynamic> toJson(){
return {
'a': a
};
}
A cloneSlow(){
return A.fromMap(jsonDecode(jsonEncode(this)));
}
A cloneFast(){
return A(
a
);
}
#override
String toString() => 'A(a: $a)';
}
void main() {
A a = A('a');
A b = a.cloneFast();
b.a = 'b';
print('a: $a b: $b');
}
There's no API for cloning/deep-copying built into Dart.
We have to write clone() methods ourselves & (for better or worse) the Dart authors want it that way.
Deep copy Object /w List
If the Object we're cloning has a List of Objects as a field, we need to List.generate that field and those Objects need their own clone method.
Example of cloning method (copyWith()) on an Order class with a List field of objects (and those nested objects also have a copyWith()):
Order copyWith({
int? id,
Customer? customer,
List<OrderItem>? items,
}) {
return Order(
id: id ?? this.id,
customer: customer ?? this.customer,
//items: items ?? this.items, // this will NOT work, it references
items: items ?? List.generate(this.items.length, (i) => this.items[i].copyWith()),
);
}
Gunter mentions this here.
Note, we cannot use List.from(items) nor [...items]. These both only make shallow copies.
Dart does not share Memory within multiple threads (isolate), so...
extension Clone<T> on T {
/// in Flutter
Future<T> clone() => compute<T, T>((e) => e, this);
/// in Dart
Future<T> clone() async {
final receive = ReceivePort();
receive.sendPort.send(this);
return receive.first.then((e) => e as T).whenComplete(receive.close);
}
}
An example of Deep copy in dart.
void main() {
Person person1 = Person(
id: 1001,
firstName: 'John',
lastName: 'Doe',
email: 'john.doe#email.com',
alive: true);
Person person2 = Person(
id: person1.id,
firstName: person1.firstName,
lastName: person1.lastName,
email: person1.email,
alive: person1.alive);
print('Object: person1');
print('id : ${person1.id}');
print('fName : ${person1.firstName}');
print('lName : ${person1.lastName}');
print('email : ${person1.email}');
print('alive : ${person1.alive}');
print('=hashCode=: ${person1.hashCode}');
print('Object: person2');
print('id : ${person2.id}');
print('fName : ${person2.firstName}');
print('lName : ${person2.lastName}');
print('email : ${person2.email}');
print('alive : ${person2.alive}');
print('=hashCode=: ${person2.hashCode}');
}
class Person {
int id;
String firstName;
String lastName;
String email;
bool alive;
Person({this.id, this.firstName, this.lastName, this.email, this.alive});
}
And the output below.
id : 1001
fName : John
lName : Doe
email : john.doe#email.com
alive : true
=hashCode=: 515186678
Object: person2
id : 1001
fName : John
lName : Doe
email : john.doe#email.com
alive : true
=hashCode=: 686393765
// Hope this work
void main() {
List newList = [{"top": 179.399, "left": 384.5, "bottom": 362.6, "right": 1534.5}, {"top": 384.4, "left": 656.5, "bottom": 574.6, "right": 1264.5}];
List tempList = cloneMyList(newList);
tempList[0]["top"] = 100;
newList[1]["left"] = 300;
print(newList);
print(tempList);
}
List cloneMyList(List originalList) {
List clonedList = new List();
for(Map data in originalList) {
clonedList.add(Map.from(data));
}
return clonedList;
}
This works for me.
Use the fromJson and toJson from your Object's Class on JSON serializing
var copy = ObjectClass.fromJson(OrigObject.toJson());
make a helper class:
class DeepCopy {
static clone(obj) {
var tempObj = {};
for (var key in obj.keys) {
tempObj[key] = obj[key];
}
return tempObj;
}
}
and copy what you want:
List cloneList = [];
if (existList.length > 0) {
for (var element in existList) {
cloneList.add(DeepCopy.clone(element));
}
}
Let's say, you want to deep copy an object Person which has an attribute that is a list of other objects Skills. By convention, we use the copyWith method with optional parameters for deep copy, but you can name it anything you want.
You can do something like this
class Skills {
final String name;
Skills({required this.name});
Skills copyWith({
String? name,
}) {
return Skills(
name: name ?? this.name,
);
}
}
class Person {
final List<Skills> skills;
const Person({required this.skills});
Person copyWith({
List<Skills>? skills,
}) =>
Person(skills: skills ?? this.skills.map((e) => e.copyWith()).toList());
}
Keep in mind that using only this.skills will only copy the reference of the list. So original object and the copied object will point to the same list of skills.
Person copyWith({
List<Skills>? skills,
}) =>
Person(skills: skills ?? this.skills);
If your list is primitive type you can do it like this. Primitive types are automatically copied so you can use this shorter syntax.
class Person {
final List<int> names;
const Person({required this.names});
Person copyWith({
List<int>? names,
}) =>
Person(names: names ?? []...addAll(names));
}
The accepted answer doesn't provide an answer, and the highest-rated answer 'doesn't work' for more complex Map types.
It also doesn't make a deep copy, it makes a shallow copy which seems to be how most people land on this page. My solution also makes a shallow copy.
JSON-cloning, which a few people suggest, just seems like gross overhead for a shallow-clone.
I had this basically
List <Map<String, dynamic>> source = [{'sampledata', []}];
List <Map<String, dynamic>> destination = [];
This worked, but of course, it's not a clone, it's just a reference, but it proved in my real code that the data types of source and destination were compatible (identical in my case, and this case).
destination[0] = source[0];
This did not work
destination[0] = Map.from(source[0]);
This is the easy solution
destionation[0] = Map<String, dynamic>.from(source[0]);

Domain object referring to a reference table in Grails GORM

I have a domain object called User:
class User{
String username;
String firstName;
String lastName;
Zipcode zip;
}
I also have a Zip Code object:
class Zipcode {
String zip;
String city;
String state;
Float lat;
Float long;
}
The zipcode table should never be modified as it contains static reference data prepopulated
A user belongs to one zipcode. The user enters the zipcode as part of the User creation.
How should I model the domain objects relationship? I would like like to make sure that GORM does not attempt to update zipcodes. I would like to make sure that the user only enters valid zipcode numbers. (Which are found in the zipcode table) How do I configure the constraints on the User object? In the controller, I do the following:
def userInstance = new User(params) // where params are form values
How do I set the proper zipcode on the object?
You would not let GORM manage the zip property (and restrict GORM from doing so at a second stage), at all.
That's what mfloryan's approach tells, too; however, his approach doesn't separate concerns, properly (separation of concerns paradigm): In the MVC (Model-View-Controller) pattern, it's not the controllers' task to "model" the data model, but it's the task of the data access layer (which is - in case of GORM - the domain classes theirselves).
Thus, the User class would be implemented like that:
class User {
String userName
String firstName
String lastName
String zip
ZipCode retrieveZipCode() {
ZipCode.findByZip(zip)
}
static constraints = {
zip nullable: false, blank: false, matches: /^\d{5}/,
/* not tested at my machine: */
validator: {
if(!retrieveZipCode(it)) {
return false
}
}
}
}
Note the retrieveZipCode() method. It's not called getZipCode() as, otherwise, Hibernate would throw an exception about a "missing setter method". You can also experiment with adding a zipCode property, a getZipCode() method (that does nothing or, alternatively, throws an exception), and adding the zipCode property to the transinients definition. - Everything of this (in any combination) will not work.
Also note the constraints definition: It matches when the zip consists of exactly five digits. (I believe that's the format of ZIP codes there in the USA.)
It should also make sure that the database contains an entry for the user's ZIP code (syntax not tested).
I've changed the ZipCode class slightly (partly, to avoid a compilation error):
class ZipCode {
String zip;
String city;
String state;
Float latitude;
Float longitude;
}
And finally, there's an integration test:
class UserTests extends GroovyTestCase {
def testUserCreation() {
User user = new User(
userName: "foo", firstName: "bar",
lastName: "baz", zip: "12345")
assert user.validate()
assert user.retrieveZipCode()
user.save()
}
}
Thanks
This sounds like more of an UI issue. Do a Zipcode object lookup in the controller and set the the object located on the user. Otherwise, I can't see how a Zipcode could have been altered upon creation of a user.
save = {
params.zip.id = Zipcode.findByZip(params.zip)
def userInstance = new User(params)
}
or
save = {
def userInstance = new User(params)
userInstance.zip = Zipcode.findByZip(params.zip)
}
You should include some validation logic (if the zip is incorrect) and also consider renaming params.zip to params.userProvidedZip or something like that.
use Domain event callback
transient beforeUpdate = {
// check to make sure that the zip code value remains the same
// and is never changed...
}

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