I have this Excel cell A2 with the contents USD.EUR[IDEALPRO,CASH,EUR].
I would like to extract the substring EUR from the last part of the string using an Excel formula. The nearest formula I came out with is =RIGHT(A2,4). However, it returns EUR].
What formula can be used to extract the substring?
I am using MS Excel 2013.
If the string that you are searching is only 3 bytes in length, then your simple formula works. But what if it changes? Try the below,
=MID(SUBSTITUTE(F2,",","#",LEN(F2)-LEN(SUBSTITUTE(F2,",",""))),FIND("#",SUBSTITUTE(F2,",","#",LEN(F2)-LEN(SUBSTITUTE(F2,",",""))))+1,FIND("]",SUBSTITUTE(F2,",","#",LEN(F2)-LEN(SUBSTITUTE(F2,",",""))))-FIND("#",SUBSTITUTE(F2,",","#",LEN(F2)-LEN(SUBSTITUTE(F2,",",""))))-1)
Where F2 is your string. This formula unstrings the string between the last delimiter "," and "]". This is too complicated but it might help you.
I will answer my own question. It has been tested to work.
=SUBSTITUTE(RIGHT(A2,4),"]","")
RIGHT(A2,4) returns EUR]. Afterwards, use SUBSTITUTE to remove ].
You can use a combination of MID and REVERSETEXT functions.
Formula
=REVERSETEXT(MID(REVERSETEXT(A1), 2, 3))
Otherwise, if the length is unknown for the part which you want to retrieve. Then use FIND function to find the comma before that particular word.
=REVERSETEXT(MID(REVERSETEXT(A3), 2, FIND(",", REVERSETEXT(A3)) - 2))
Related
I want to split text strings from the below formula in a cell that generates a numeric value.
=RTD($A$1;;"aaa#bbb//ccc////ddd")
Using the mid & search funktion to split certain parts such as =MID(A23; SEARCH("////";A23)+4; 3) only works if text is stored in cells, but not on a formula in the cell.
How to extract strings from a formula?
As per the comment section you can use FORMULATEXT(). If you have TEXTAFTER() available, try:
=LEFT(TEXTAFTER(FORMULATEXT(A1),"////"),3)
If you don't want to use the formulatext function, you can use the find and replace. Replace for exampel the "=" with "#="
Then you can extract what ever you want with the mid function.
When you are done replace "#=" with "="
I'm having difficulties to find a way of getting the string before the last slash in excel 2007 formula.
https://www.example.com/text13611283/url_complement
The string I need is this: text13611283
There are multiple ways to do this task based on input value
Case 1: you can Delimit the column by using menu "DATA/Text to Columns"
Case 2: Assuming your text is in A2 Cell the formula in B2 will be "=LEFT(MID(A2,FIND("/",A2,10)+1,100),FIND("/",MID(A2,FIND("/",A2,10)+1,100),1)-1)"
The String Between the Last Two Occurrences of a Slash (/) in Cell A1
Formula
=MID(A1,FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1))+1,FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))-FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1))-1)
How?
How Formulas
=LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))
=SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/","")))
=FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))
=LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1
=SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1)
=FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1))
=MID(A1,FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1))+1,FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))))-FIND("#",SUBSTITUTE(A1,"/","#",LEN(A1)-LEN(SUBSTITUTE(A1,"/",""))-1))-1)
=INDEX(TRIM(MID(SUBSTITUTE(A1,"/",REPT(" ",99)),IF(ROW(INDEX($A:$A,1):INDEX($A:$A,255))=1,1,(ROW(INDEX($A:$A,1):INDEX($A:$A,255))-1)*99),99)),4)
Replace each / with 99 spaces
Using MID, create an array of each 99-space separated element in the string
=IF(ROW(INDEX($A:$A,1):INDEX($A:$A,255))=1,1,(ROW(INDEX($A:$A,1):INDEX($A:$A,255))-1)*99) creates an array to be used for the start argument of the MID function. It returns an array of {1,99,198,297,...}
TRIM to get rid of the extra spaces
INDEX to extract the correct element. In this case, it would be 4.
I have a column of text values (column C below), they are of varying length. I have a separate array of text values (column A below). I want a formula that will look through the strings in Column C and return the word from Column A that it matches. If there are multiple matches (rare, probably won't happen), it will only return one.
Please see my example:
Column D is the result I am looking for. As you can see, this will require some kind of fuzzy string matching. The word could appear anywhere in the cell. It doesn't need to be case sensitive. But I need it to pull that word out of the string as the result basically.
Thank you!
Use This:
=INDEX(A:A,AGGREGATE(15,6,ROW($A$2:$A$5)/(ISNUMBER(SEARCH($A$2:$A$5,C2))),1))
One more, slightly simpler:
=IF(COUNTIF($C$1:$C$100," * "&A2&" * ")>0,A2,"")
You can also try this formula =INDEX(A:A,SUMPRODUCT(MATCH(1,NOT(ISERR(SEARCH(A:A,C2)))*1,0))). Enter it using CTRL+SHIFT+ENTER since it is an array formula.
This formula seems to be working for me:
(Please use Ctrl+Shift+Enter for the array formula to take effect)
{=INDEX($A$2:$A$5,MATCH(1,COUNTIF(C2,"*"&$A$2:$A$5&"*"),0))}
Screenshot of Excel sheet
I want to extract Moss Ariel and Murphy from the following strings using text functions in Excel.
Gabriela Moss669.11695-5000-53420000000-1232
Connie Ariel1025.11695-2004-51490000000-1231
Kelly Murphy1040.58695-2200-50630000000-1235
I have a basic grasp with using text functions, but this one has stumped me. Any help is greatly appreciated.
I need to make a formula such that it requires no changes copying it down the list of records.
This would be easier and shorter in Google Sheets or with VBA UDF, but here is another array formula solution (enter it with Ctrl + Shift + Enter) from https://exceljet.net/formula/split-text-and-numbers
=MID(A1,FIND(" ",A1)+1,MIN(FIND(ROW($1:$10)-1,A1&"0123456789"))-FIND(" ",A1)-1)
This might work without array formula:
=MID(A1,FIND(" ",A1)+1,MIN(FIND({0,1,2,3,4,5,6,7,8,9,"."},A1))-FIND(" ",A1)-1)
Say you data begins in A1
First extract the full name with the following formula
[B1] = {LEFT(A1,MATCH(1,--ISNUMBER(--MID(A1,ROW(INDIRECT("A1:A"&LEN(A1))),1)),0)-1)}
This is an array formula, press Ctrl+Shift+Enter after typing formula in B1. Then fill down the formula to the rest of the rows.
Next, simply extract the last name from the full name
[C1] = RIGHT(B1,LEN(B1)-SEARCH(" ",B1))
If you prefer to do it in-one-go here is the formula
[B1] = {MID(A1,SEARCH(" ",A1)+1,MATCH(1,--ISNUMBER(--MID(A1,ROW(INDIRECT("A1:A"&LEN(A1))),1)),0)-1-SEARCH(" ",A1))}
You can use the below formula as it is, no need for array formula to achieve this.
=MID(A1,SEARCH(" ",A1,1)+1,MIN(FIND({0,1,2,3,4,5,6,7,8,9},A1&"0123456789"))-SEARCH(" ",A1,1)-1)
You need to combine the functions instr and mid. instr returns the index in a string of the first appearance of a sub-string (or a single character). mid returns a sub-string starting at a given position and with a length of the extracted sub-string. In your case, something like:
MID(MyString,Index(MyString,"Moss"),Len("Moss"))
where MyString holds your source string.
My Excel spreadsheet has strings with this structure, contained within single cells along column A:
[CELL A1]
DOE_JOHN (123456) Series/Acq=5/1 (2017.01.01 01:01) SOL_TE30 TR/TE/NS=3000/30/64, 1.728E+00mL (M 044Y, 222kg)
From this string I'd like to only extract the subject's initials to place them in a new cell, as such:
JD
So as you can see the order should be the character after the first underscore followed by the first character of the string.
I've tried using LEFT and FIND, however have been unsuccessful.
Do you have any suggestions on how to achieve this using a formula (not VBA)?
Maybe LEFT and FIND with CHAR like this.
=MID(A1, FIND(CHAR(95), A1)+1, 1)&LEFT(A1)
Try this:
=MID(A1,FIND("_",A1)+1,1)&LEFT(A1)