I was not expecting this error ("AttributeError: module 'plotly' has no attribute 'plot'") and have not been able to find the exact error. I am thinking its not the exact error because plotly obviously has plotting abilities and that somewhere along the way my data isnt formatted correctly, for this particular exercise.
I am open to suggestions on new methods. This is just what I used because it was easy to follow, its what I want in the end, and its centralized.
Error occurs on last line py.plot( fig, filename='d3-cloropleth-map' )
I have copied the code from the example: United States Choropleth Map
And here is my code:
import plotly as py
import pandas as pd
import numpy as np
py.tools.set_credentials_file(username='user', api_key='xxxXxxXxxx')
df = pd.DataFrame.from_csv("C:/Users/d/Documents/Personal/Python Scripts/Python/Connect.csv")
for col in df.columns:
df[col] = df[col].astype(str)
df[['Open Balance','Amount', 'Aging']] = df[['Open Balance','Amount',
'Aging']].apply(pd.to_numeric, errors='ignore')
df[['Date', 'Due Date']] = df[['Date','Due Date']].apply(pd.to_datetime)
state_total_byitem = df.groupby(by = ['State', 'Item']).agg({'Open Balance':'sum','Amount':'sum','Paid':'count','Aging':'mean'})
sti = state_total_byitem
sti.reset_index(level=['State', 'Item'], inplace=True)
for col in sti.columns:
sti[col] = sti[col].astype(str)
sti['text'] = 'State ' + sti['State'] + ' Item ' + sti['Item'] + '<br>' +\
' Open Balance ' + sti['Open Balance'] + ' Paid ' + sti['Paid'] + '<br>' +\
' Amount ' + sti['Amount'] + ' Aging ' + sti['Aging']
scl = [[0.0, 'rgb(220,224,225)'],[0.2, 'rgb(204,220,224)'],[0.4, 'rgb(158,192,200)'],\
[0.6, 'rgb(100,166,184)'],[0.8, 'rgb(60,175,206)'],[1.0, 'rgb(10,206,255)']]
data = [ dict(
type='choropleth',
colorscale = scl,
autocolorscale = False,
locations = sti['State'],
z = sti['Amount'].astype(float),
locationmode = 'USA-states',
text = sti['text'],
marker = dict(
line = dict (
color = 'rgb(255,255,255)',
width = 2
) ),
colorbar = dict(
title = "$ in USD")
) ]
layout = dict(
title = 'Invoices by State<br>(Hover for breakdown)',
geo = dict(
scope='usa',
projection=dict( type='albers usa' ),
showlakes = True,
lakecolor = 'rgb(255, 255, 255)'),
)
fig = dict( data=data, layout=layout )
py.plot( fig, filename='d3-cloropleth-map' )
Instead of
import plotly as py
You should have
import plotly.plotly as py
For future reference, try to get a MVCE before posting. Oftentimes it will help you find the error on your own.
Related
i have a directory containing three files, years.csv, 2014.csv and 2015.csv. i want to plot a population pyramid graph for the two files but i want pandas to pick the dataframe from the years.csv with respect to the slider value.
my years.csv looks like, on the slider when i select 2014, from the code you can see, its an int that i convert into a string and append .csv to it. but all i want is that final string interpreted as df = pd.read_csv('2014.csv') so that i can be able to generate graphs of all the years as long as that file is in the directoy.
years
0
2014(2014.csv)
1
2015(2015.csv)
from dash import Dash, dcc, html, Input, Output
# import plotly.express as px
import plotly.graph_objects as gp
import pandas as pd
# df = pd.read_csv('https://raw.githubusercontent.com/plotly/datasets/master/gapminderDataFiveYear.csv')
df = pd.read_csv('years.csv')
app = Dash(__name__)
app.layout = html.Div([
dcc.Graph(id='graph-with-slider'),
dcc.Slider(
df['year'].min(),
df['year'].max(),
step=None,
value=df['year'].min(),
marks={str(year): str(year) for year in df['year'].unique()},
id='year-slider'
)
])
#app.callback(
Output('graph-with-slider', 'figure'),
Input('year-slider', 'value'))
def update_figure(selected_year):
new_df = str(df[df.year == selected_year]) + ".csv"
print(new_df)
# fig = px.scatter(filtered_df, x="gdpPercap", y="lifeExp",
# size="pop", color="continent", hover_name="country",
# log_x=True, size_max=55)
y_age = new_df['Age']
x_M = new_df['Male']
x_F = new_df['Female'] * -1
# fig.update_layout(transition_duration=500)
# Creating instance of the figure
fig = gp.Figure()
# Adding Male data to the figure
fig.add_trace(gp.Bar(y= y_age, x = x_M,
name = 'Male',
orientation = 'h'))
# Adding Female data to the figure
fig.add_trace(gp.Bar(y = y_age, x = x_F,
name = 'Female', orientation = 'h'))
# Updating the layoutout for our graph
fig.update_layout(title = 'Population Pyramid of Uganda-2015',
title_font_size = 22, barmode = 'relative',
bargap = 0.0, bargroupgap = 0,
xaxis = dict(tickvals = [-600000, -400000, -200000,
0, 200000, 400000, 600000],
ticktext = ['6k', '4k', '2k', '0',
'2k', '4k', '6k'],
title = 'Population in Thousands',
title_font_size = 14)
)
# fig.show()
return fig
if __name__ == '__main__':
app.run_server(debug=True)
I've been working on getting a select menu and Bokeh plot up and running on a dataset I'm working with. The dataset can be found here. I have no experience with JavaScript, but I believe my select menu isn't connected/-ing to my plot. Therefore, I have a plot outline, but no data displayed. As I run the script from the console with bokeh serve --show test.py, I get the first 7 notifications in my JS console. The last three (those in the red bracket in the screenshot) occur when I try and change to a different item in my select menu.
Goal: Display the plot of data for rows those id number ('ndc' in this example) is selected in the Select menu.
Here's my code (modified from this post) that I used to get started. This one was also used, as were a handful of others, and the Bokeh documentation itself.
import pandas as pd
from bokeh.io import curdoc, output_notebook, output_file
from bokeh.layouts import row, column
from bokeh.models import Select, DataRange1d, ColumnDataSource
from bokeh.plotting import figure
# output_notebook()
output_file('test.html')
def get_dataset(src, drug_id):
src.drop('Unnamed: 0', axis = 1, inplace = True)
df = src[src.ndc == drug_id].copy()
df['date'] = pd.to_datetime(df['date'])
df = df.set_index(['date'])
df.sort_index(inplace=True)
source = ColumnDataSource(data=df)
return source
def make_plot(source, title):
plot = figure(plot_width=800, plot_height = 800, tools="", x_axis_type = 'datetime', toolbar_location=None)
plot.xaxis.axis_label = 'Time'
plot.yaxis.axis_label = 'Price ($)'
plot.axis.axis_label_text_font_style = 'bold'
plot.x_range = DataRange1d(range_padding = 0.0)
plot.grid.grid_line_alpha = 0.3
plot.title.text = title
plot.line(x= 'date', y='nadac_per_unit', source=source)
return plot
def update_plot(attrname, old, new):
ver = vselect.value
plot.title.text = "Drug Prices"
src = get_dataset(df, ver)
source.date.update(src.date)
df = pd.read_csv('data/plotting_data.csv')
ver = '54034808' #Initial id number
cc = df['ndc'].astype(str).unique() #select-menu options
vselect = Select(value=ver, title='Drug ID', options=sorted((cc)))
source = get_dataset(df, ver)
plot = make_plot(source, "Drug Prices")
vselect.on_change('value', update_plot)
controls = row(vselect)
curdoc().add_root(row(plot, controls))
There were some problems in your code:
You want to drop the Unnamed: 0 column. This can only be done once and when you try this again it will throw an error since this column does not exist anymore.
The way you tried to filter the dataframe didn't work and would result in an empty dataframe. You can select rows based on a column value like this: df.loc[df['column_name'] == some_value]
Updating the ColumnDataSource object can be done by replacing source.data with the new data.
import pandas as pd
from bokeh.io import curdoc, output_notebook, output_file
from bokeh.layouts import row, column
from bokeh.models import Select, DataRange1d, ColumnDataSource
from bokeh.plotting import figure
output_notebook()
output_file('test.html')
def get_dataset(src, drug_id):
src.drop('Unnamed: 0', axis = 1, inplace = True)
df = src.loc[src['ndc'] == int(drug_id)]
df['date'] = pd.to_datetime(df['date'])
df = df.set_index(['date'])
df.sort_index(inplace=True)
source = ColumnDataSource(data=df)
return source
def make_plot(source, title):
plot = figure(plot_width=800, plot_height = 800, tools="", x_axis_type = 'datetime', toolbar_location=None)
plot.xaxis.axis_label = 'Time'
plot.yaxis.axis_label = 'Price ($)'
plot.axis.axis_label_text_font_style = 'bold'
plot.x_range = DataRange1d(range_padding = 0.0)
plot.grid.grid_line_alpha = 0.3
plot.title.text = title
plot.line(x= 'date', y='nadac_per_unit', source=source)
return plot
def update_plot(attrname, old, new):
ver = vselect.value
df1 = df.loc[df['ndc'] == int(new)]
df1['date'] = pd.to_datetime(df1['date'])
df1 = df1.set_index(['date'])
df1.sort_index(inplace=True)
newSource = ColumnDataSource(df1)
source.data = newSource.data
df = pd.read_csv('data/plotting_data.csv')
ver = '54034808' #Initial id number
cc = df['ndc'].astype(str).unique() #select-menu options
vselect = Select(value=ver, title='Drug ID', options=sorted((cc)))
source = get_dataset(df, ver)
plot = make_plot(source, "Drug Prices")
vselect.on_change('value', update_plot)
controls = row(vselect)
curdoc().add_root(row(plot, controls))
I am trying to plot a dataframe I have created from an excel spreadsheet using either matplotlib or matplotlib and pandas ie. df.plot. However, python keeps returning a cannot convert string to float error. This is confusing since when I print the column of the dataframe it appears to be all float values.
I've tried printing the values of the dataframe column and using the pandas.plot syntax. I've also tried saving the column to a new variable.
import pandas as pd
from matplotlib import pyplot as plt
import glob
import openpyxl
import math
from openpyxl.utils.dataframe import dataframe_to_rows
from openpyxl.styles import Border, Side, Alignment
import seaborn as sns
import itertools
directory = 'E:\some directory'
#QA_directory = directory + '**/*COPY.xlsx'
wb = openpyxl.load_workbook(directory + '\\Calcs\\' + "excel file.xlsx", data_only = 'True')
plt.figure(figsize=(16,9))
axes = plt.axes()
plt.title('Drag Amplification', fontsize = 16)
plt.xlabel('Time (s)', fontsize = 14)
plt.ylabel('Cf', fontsize = 14)
d = pd.DataFrame()
n=[]
for sheets in wb.sheetnames:
if '2_1' in sheets and '2%' not in sheets and '44%' not in sheets:
name = sheets[:8]
print(name)
ws = wb[sheets]
data = ws.values
cols = next(data)[1:]
data = list(data)
idx = [r[0] for r in data]
data = (itertools.islice(r, 1, None) for r in data)
df = pd.DataFrame(data, index=idx, columns=cols)
df = df.dropna()
#x = df['x/l']
#y = df.Cf
print(df.columns)
print(df.Cf.values)
x=df['x/l'].values
plt.plot(x, df.Cf.values)
"""x = [wb[sheets].cell(row=row,column=1).value for row in range(1,2000) if wb[sheets].cell(row=row,column=1).value]
print(x)
Cf = [wb[sheets].cell(row=row,column=6).value for row in range(1,2000) if wb[sheets].cell(row=row,column=1).value]
d[name+ 'x'] = pd.DataFrame(x)
d[name + '_Cf'] = pd.Series(Cf, index=d.index)
print(name)"""
print(df)
plt.show()
I'm expecting a plot of line graphs with the values of x/l on the x access and Cf on the 'y' with a line for each of the relevant sheets in the workbook. Any insights as to why i am getting this error would be appreciated!
I am trying to use iplot() within a function within Jupyter so that i can use a filter on the graph and have it change dynamically. The code works in a cell on its own like this
# Code for put by ticker
data = []
opPriceDic = priceToArray(getPuts(getOptionPricesByTicker('ABBV')))
for key, values in opPriceDic.items():
trace = go.Scatter(
x = numberOfDays,
y = values,
name = 'option',
line = dict(
width = 4)
)
data.append(trace)
# Edit the layout
layout = dict(title = 'Call prices for ' ,
xaxis = dict(title = 'Days to Expiration'),
yaxis = dict(title = 'Price '),
)
fig = dict(data=data, layout=layout)
py.iplot(fig, filename='calls For ')
But once this is placed within a function the graph fails to load
def graph(ticker):
# Code for put by ticker
data = []
opPriceDic = priceToArray(getPuts(getOptionPricesByTicker(ticker)))
for key, values in opPriceDic.items():
trace = go.Scatter(
x = numberOfDays,
y = values,
name = 'option',
line = dict(
width = 4)
)
data.append(trace)
# Edit the layout
layout = dict(title = 'Call prices for ' ,
xaxis = dict(title = 'Days to Expiration'),
yaxis = dict(title = 'Price '),
)
fig = dict(data=data, layout=layout)
py.iplot(fig, filename='calls For ')
But if I change the iplot() to plot() it calls the plotly API and opens a new tab with the graph displaying.
I am just wondering if anyone has noticed this before and may have come across a solution?
(if I am in the wrong area I will remove the post)
I have tried to use pandas data.reader calls to pull ticker data between a start and end date. The data.reader seems to work from within the function. In the question code, if the opPriceDic dictionary could be converted to a dataframe, then iplot() could plot it without use of layout and fig as below:
# Import libraries
import datetime
from datetime import date
import pandas as pd
import numpy as np
from plotly import __version__
%matplotlib inline
import cufflinks as cf
from plotly.offline import download_plotlyjs, init_notebook_mode, plot, iplot
init_notebook_mode(connected=True)
init_notebook_mode(connected=True)
cf.go_offline()
# Create function that uses data.reader and iplot()
def graph(ticker):
# create sample data set
start = datetime.datetime(2006, 1, 1)
end = datetime.datetime(2016, 1, 1)
df = data.DataReader(ticker, 'morningstar', start, end)
df = df.reset_index()
df['numberOfDays'] = df.apply(lambda x: abs((datetime.datetime.now() - x['Date']).days), axis=1)
# call iplot within the function graph()
df.iplot(kind='line', x='numberOfDays', y='Close', xTitle='Days', yTitle='Value', title='Prices', width=4)
I am using plotly in Python 3.6.3 and am trying to do a Choropleth map as in here. I would like to change the attributes of what appears when hovering above the map. That is, for example, if we consider the first map and hover of California, it looks like:
I want to change both the font size of the content that appears and the size of the box. Is there a way to access those?
Here is the code that generates it:
import plotly.plotly as py
import pandas as pd
df = pd.read_csv('https://raw.githubusercontent.com/plotly/datasets/master/2011_us_ag_exports.csv')
for col in df.columns:
df[col] = df[col].astype(str)
scl = [[0.0, 'rgb(242,240,247)'],[0.2, 'rgb(218,218,235)'],[0.4, 'rgb(188,189,220)'],\
[0.6, 'rgb(158,154,200)'],[0.8, 'rgb(117,107,177)'],[1.0, 'rgb(84,39,143)']]
df['text'] = df['state'] + '<br>' +\
'Beef '+df['beef']+' Dairy '+df['dairy']+'<br>'+\
'Fruits '+df['total fruits']+' Veggies ' + df['total veggies']+'<br>'+\
'Wheat '+df['wheat']+' Corn '+df['corn']
data = [ dict(
type='choropleth',
colorscale = scl,
autocolorscale = False,
locations = df['code'],
z = df['total exports'].astype(float),
locationmode = 'USA-states',
text = df['text'],
marker = dict(
line = dict (
color = 'rgb(255,255,255)',
width = 2
) ),
colorbar = dict(
title = "Millions USD")
) ]
layout = dict(
title = '2011 US Agriculture Exports by State<br>(Hover for breakdown)',
geo = dict(
scope='usa',
projection=dict( type='albers usa' ),
showlakes = True,
lakecolor = 'rgb(255, 255, 255)'),
)
fig = dict( data=data, layout=layout )
py.iplot( fig, filename='d3-cloropleth-map' )
The chloropleth>hoverlabel function lets you set the background color, border color, and font. The size of the border box is determined by the text within it, however. If the name shows up as truncated it can be expanded with the chloropleth>hoverlabel>namelength function.